What is the name of a $n$-dimensional space where each dimension contains exactly 3 values?












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$begingroup$


Can someone tell me whether this space has a name?
Each element of the space is an $n$-dimensional point (tuple) (vector, but not sure it's a vector space?) where each element of the tuple may be either $-1$, $0$, or $1$?



It seems to me more or less the corners of a $n$-dimensional hyper cube plus all the midpoints of the edges and $(n-j)$-dimensional faces, for $j=1,ldots,(n-1)$.



I will eventually want to talk about densities of sets of such points in the space, and also about measuring the homogeneity or clustering of a distribution of such a set of points.










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  • 1




    $begingroup$
    It's a bit unclear from your description but it sounds like you're talking about $(Bbb Z/3Bbb Z)^n$
    $endgroup$
    – Alessandro Codenotti
    Feb 1 at 9:39












  • $begingroup$
    I guess you simply mean ${-1,0,1}^n$ as subset of $Bbb R^n$. This doesn't have any individual name, as far as I know..
    $endgroup$
    – Berci
    Feb 1 at 10:04
















0












$begingroup$


Can someone tell me whether this space has a name?
Each element of the space is an $n$-dimensional point (tuple) (vector, but not sure it's a vector space?) where each element of the tuple may be either $-1$, $0$, or $1$?



It seems to me more or less the corners of a $n$-dimensional hyper cube plus all the midpoints of the edges and $(n-j)$-dimensional faces, for $j=1,ldots,(n-1)$.



I will eventually want to talk about densities of sets of such points in the space, and also about measuring the homogeneity or clustering of a distribution of such a set of points.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    It's a bit unclear from your description but it sounds like you're talking about $(Bbb Z/3Bbb Z)^n$
    $endgroup$
    – Alessandro Codenotti
    Feb 1 at 9:39












  • $begingroup$
    I guess you simply mean ${-1,0,1}^n$ as subset of $Bbb R^n$. This doesn't have any individual name, as far as I know..
    $endgroup$
    – Berci
    Feb 1 at 10:04














0












0








0





$begingroup$


Can someone tell me whether this space has a name?
Each element of the space is an $n$-dimensional point (tuple) (vector, but not sure it's a vector space?) where each element of the tuple may be either $-1$, $0$, or $1$?



It seems to me more or less the corners of a $n$-dimensional hyper cube plus all the midpoints of the edges and $(n-j)$-dimensional faces, for $j=1,ldots,(n-1)$.



I will eventually want to talk about densities of sets of such points in the space, and also about measuring the homogeneity or clustering of a distribution of such a set of points.










share|cite|improve this question











$endgroup$




Can someone tell me whether this space has a name?
Each element of the space is an $n$-dimensional point (tuple) (vector, but not sure it's a vector space?) where each element of the tuple may be either $-1$, $0$, or $1$?



It seems to me more or less the corners of a $n$-dimensional hyper cube plus all the midpoints of the edges and $(n-j)$-dimensional faces, for $j=1,ldots,(n-1)$.



I will eventually want to talk about densities of sets of such points in the space, and also about measuring the homogeneity or clustering of a distribution of such a set of points.







general-topology group-theory vector-spaces






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edited Feb 1 at 14:32









Ernie060

2,940719




2,940719










asked Feb 1 at 9:24









Jim NewtonJim Newton

444




444








  • 1




    $begingroup$
    It's a bit unclear from your description but it sounds like you're talking about $(Bbb Z/3Bbb Z)^n$
    $endgroup$
    – Alessandro Codenotti
    Feb 1 at 9:39












  • $begingroup$
    I guess you simply mean ${-1,0,1}^n$ as subset of $Bbb R^n$. This doesn't have any individual name, as far as I know..
    $endgroup$
    – Berci
    Feb 1 at 10:04














  • 1




    $begingroup$
    It's a bit unclear from your description but it sounds like you're talking about $(Bbb Z/3Bbb Z)^n$
    $endgroup$
    – Alessandro Codenotti
    Feb 1 at 9:39












  • $begingroup$
    I guess you simply mean ${-1,0,1}^n$ as subset of $Bbb R^n$. This doesn't have any individual name, as far as I know..
    $endgroup$
    – Berci
    Feb 1 at 10:04








1




1




$begingroup$
It's a bit unclear from your description but it sounds like you're talking about $(Bbb Z/3Bbb Z)^n$
$endgroup$
– Alessandro Codenotti
Feb 1 at 9:39






$begingroup$
It's a bit unclear from your description but it sounds like you're talking about $(Bbb Z/3Bbb Z)^n$
$endgroup$
– Alessandro Codenotti
Feb 1 at 9:39














$begingroup$
I guess you simply mean ${-1,0,1}^n$ as subset of $Bbb R^n$. This doesn't have any individual name, as far as I know..
$endgroup$
– Berci
Feb 1 at 10:04




$begingroup$
I guess you simply mean ${-1,0,1}^n$ as subset of $Bbb R^n$. This doesn't have any individual name, as far as I know..
$endgroup$
– Berci
Feb 1 at 10:04










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$begingroup$

So you have a set of $3^n$ tuples $(x_1, x_2, dots, x_n)$ with $x_i in {-1,0,1}$. You can regard these as representing a set $S_n$ of $3^n$ points in $mathbb R^n$ or as representing the vector space $(mathbb{Z}/3mathbb{Z})^n$ of dimension $n$ over the field $mathbb{Z}/3mathbb{Z}$.



Note that these are not the same thing. For example, in $mathbb R^2$ the points in $S_2$ that lie on the line $sum x_i=1$ are the two points $(1,0)$ and $(0,1)$. But in $(mathbb{Z}/3mathbb{Z})^2$ the line $sum x_i=1$ also includes a third point $(-1,-1)$.






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    $begingroup$

    So you have a set of $3^n$ tuples $(x_1, x_2, dots, x_n)$ with $x_i in {-1,0,1}$. You can regard these as representing a set $S_n$ of $3^n$ points in $mathbb R^n$ or as representing the vector space $(mathbb{Z}/3mathbb{Z})^n$ of dimension $n$ over the field $mathbb{Z}/3mathbb{Z}$.



    Note that these are not the same thing. For example, in $mathbb R^2$ the points in $S_2$ that lie on the line $sum x_i=1$ are the two points $(1,0)$ and $(0,1)$. But in $(mathbb{Z}/3mathbb{Z})^2$ the line $sum x_i=1$ also includes a third point $(-1,-1)$.






    share|cite|improve this answer











    $endgroup$


















      1












      $begingroup$

      So you have a set of $3^n$ tuples $(x_1, x_2, dots, x_n)$ with $x_i in {-1,0,1}$. You can regard these as representing a set $S_n$ of $3^n$ points in $mathbb R^n$ or as representing the vector space $(mathbb{Z}/3mathbb{Z})^n$ of dimension $n$ over the field $mathbb{Z}/3mathbb{Z}$.



      Note that these are not the same thing. For example, in $mathbb R^2$ the points in $S_2$ that lie on the line $sum x_i=1$ are the two points $(1,0)$ and $(0,1)$. But in $(mathbb{Z}/3mathbb{Z})^2$ the line $sum x_i=1$ also includes a third point $(-1,-1)$.






      share|cite|improve this answer











      $endgroup$
















        1












        1








        1





        $begingroup$

        So you have a set of $3^n$ tuples $(x_1, x_2, dots, x_n)$ with $x_i in {-1,0,1}$. You can regard these as representing a set $S_n$ of $3^n$ points in $mathbb R^n$ or as representing the vector space $(mathbb{Z}/3mathbb{Z})^n$ of dimension $n$ over the field $mathbb{Z}/3mathbb{Z}$.



        Note that these are not the same thing. For example, in $mathbb R^2$ the points in $S_2$ that lie on the line $sum x_i=1$ are the two points $(1,0)$ and $(0,1)$. But in $(mathbb{Z}/3mathbb{Z})^2$ the line $sum x_i=1$ also includes a third point $(-1,-1)$.






        share|cite|improve this answer











        $endgroup$



        So you have a set of $3^n$ tuples $(x_1, x_2, dots, x_n)$ with $x_i in {-1,0,1}$. You can regard these as representing a set $S_n$ of $3^n$ points in $mathbb R^n$ or as representing the vector space $(mathbb{Z}/3mathbb{Z})^n$ of dimension $n$ over the field $mathbb{Z}/3mathbb{Z}$.



        Note that these are not the same thing. For example, in $mathbb R^2$ the points in $S_2$ that lie on the line $sum x_i=1$ are the two points $(1,0)$ and $(0,1)$. But in $(mathbb{Z}/3mathbb{Z})^2$ the line $sum x_i=1$ also includes a third point $(-1,-1)$.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited Feb 1 at 15:12









        J. W. Tanner

        4,6621420




        4,6621420










        answered Feb 1 at 10:22









        gandalf61gandalf61

        9,232825




        9,232825






























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