Calculation Error or?

Is it a calculation error or am I missing something? A popular company like Plimus that handles thousands of payments daily can't make this mistake, I thought.
arithmetic
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Is it a calculation error or am I missing something? A popular company like Plimus that handles thousands of payments daily can't make this mistake, I thought.
arithmetic
1
Yes, it's a calculation error (or, more likely, a typo), about on the same level as ending your question with "everymade can't make".
– Gerry Myerson
Nov 18 '12 at 11:25
Ha! :) I did correct it but it somehow used the older version after I logged in.
– Nimbuz
Nov 18 '12 at 11:29
@GerryMyerson Could you please convert your comment into an answer so this question can be removed from the "Unanswered" queue? I don't think there's much else that an answer could contain than what you said in your comment.
– Robert Howard
Nov 20 '18 at 3:39
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Is it a calculation error or am I missing something? A popular company like Plimus that handles thousands of payments daily can't make this mistake, I thought.
arithmetic

Is it a calculation error or am I missing something? A popular company like Plimus that handles thousands of payments daily can't make this mistake, I thought.
arithmetic
arithmetic
edited Nov 18 '12 at 11:27
asked Nov 18 '12 at 11:10
Nimbuz
1163
1163
1
Yes, it's a calculation error (or, more likely, a typo), about on the same level as ending your question with "everymade can't make".
– Gerry Myerson
Nov 18 '12 at 11:25
Ha! :) I did correct it but it somehow used the older version after I logged in.
– Nimbuz
Nov 18 '12 at 11:29
@GerryMyerson Could you please convert your comment into an answer so this question can be removed from the "Unanswered" queue? I don't think there's much else that an answer could contain than what you said in your comment.
– Robert Howard
Nov 20 '18 at 3:39
add a comment |
1
Yes, it's a calculation error (or, more likely, a typo), about on the same level as ending your question with "everymade can't make".
– Gerry Myerson
Nov 18 '12 at 11:25
Ha! :) I did correct it but it somehow used the older version after I logged in.
– Nimbuz
Nov 18 '12 at 11:29
@GerryMyerson Could you please convert your comment into an answer so this question can be removed from the "Unanswered" queue? I don't think there's much else that an answer could contain than what you said in your comment.
– Robert Howard
Nov 20 '18 at 3:39
1
1
Yes, it's a calculation error (or, more likely, a typo), about on the same level as ending your question with "everymade can't make".
– Gerry Myerson
Nov 18 '12 at 11:25
Yes, it's a calculation error (or, more likely, a typo), about on the same level as ending your question with "everymade can't make".
– Gerry Myerson
Nov 18 '12 at 11:25
Ha! :) I did correct it but it somehow used the older version after I logged in.
– Nimbuz
Nov 18 '12 at 11:29
Ha! :) I did correct it but it somehow used the older version after I logged in.
– Nimbuz
Nov 18 '12 at 11:29
@GerryMyerson Could you please convert your comment into an answer so this question can be removed from the "Unanswered" queue? I don't think there's much else that an answer could contain than what you said in your comment.
– Robert Howard
Nov 20 '18 at 3:39
@GerryMyerson Could you please convert your comment into an answer so this question can be removed from the "Unanswered" queue? I don't think there's much else that an answer could contain than what you said in your comment.
– Robert Howard
Nov 20 '18 at 3:39
add a comment |
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Yes, it's a calculation error, or, more likely, a typo; if you change the number of orders to 100, then everything works out.
What worries me is that on a $49.90 transaction, there's a commission of $4.99, while on a $50 transaction, the commission drops to $4.50. So, if the transaction is $49.90, it pays you to lie and report it as $50, and come out of the deal 49 cents better. Similarly at all the other percentage breakpoints.
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1 Answer
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Yes, it's a calculation error, or, more likely, a typo; if you change the number of orders to 100, then everything works out.
What worries me is that on a $49.90 transaction, there's a commission of $4.99, while on a $50 transaction, the commission drops to $4.50. So, if the transaction is $49.90, it pays you to lie and report it as $50, and come out of the deal 49 cents better. Similarly at all the other percentage breakpoints.
add a comment |
Yes, it's a calculation error, or, more likely, a typo; if you change the number of orders to 100, then everything works out.
What worries me is that on a $49.90 transaction, there's a commission of $4.99, while on a $50 transaction, the commission drops to $4.50. So, if the transaction is $49.90, it pays you to lie and report it as $50, and come out of the deal 49 cents better. Similarly at all the other percentage breakpoints.
add a comment |
Yes, it's a calculation error, or, more likely, a typo; if you change the number of orders to 100, then everything works out.
What worries me is that on a $49.90 transaction, there's a commission of $4.99, while on a $50 transaction, the commission drops to $4.50. So, if the transaction is $49.90, it pays you to lie and report it as $50, and come out of the deal 49 cents better. Similarly at all the other percentage breakpoints.
Yes, it's a calculation error, or, more likely, a typo; if you change the number of orders to 100, then everything works out.
What worries me is that on a $49.90 transaction, there's a commission of $4.99, while on a $50 transaction, the commission drops to $4.50. So, if the transaction is $49.90, it pays you to lie and report it as $50, and come out of the deal 49 cents better. Similarly at all the other percentage breakpoints.
answered Nov 20 '18 at 4:12
Gerry Myerson
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146k8147298
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1
Yes, it's a calculation error (or, more likely, a typo), about on the same level as ending your question with "everymade can't make".
– Gerry Myerson
Nov 18 '12 at 11:25
Ha! :) I did correct it but it somehow used the older version after I logged in.
– Nimbuz
Nov 18 '12 at 11:29
@GerryMyerson Could you please convert your comment into an answer so this question can be removed from the "Unanswered" queue? I don't think there's much else that an answer could contain than what you said in your comment.
– Robert Howard
Nov 20 '18 at 3:39