How to get a whole sqlite3 query onto a tkinter page
I am making a program where you can search a name, and everything from the sqlite3 database will show up.
def search():
tk = Tk()
tk.geometry('500x500')
labe = Label(tk, text="Search all: fullname, major, gender, class one, class two, class three")
labe.pack()
ent = Entry(tk, bd=5)
ent.pack()
def dog():
getted = ent.get()
conn = sqlite3.connect('friend.db')
if getted == "fullname":
with conn:
cursor = conn.cursor()
cursor.execute('SELECT name1 FROM Photos')
conn.commit()
result = cursor.fetchall()
for r in result:
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=r)
lab.pack()
tkee.mainloop()
buty = Button(tk, text="Submit", command=dog)
buty.pack()
The program works fine when I enter that I want all the full names, but only one name comes up on the slide. It is only until I exit all the other tabs that the other names show up. If anyone knows how to do this, that would be greatly appreciated. Thanks, Jamal
python tkinter sqlite3
add a comment |
I am making a program where you can search a name, and everything from the sqlite3 database will show up.
def search():
tk = Tk()
tk.geometry('500x500')
labe = Label(tk, text="Search all: fullname, major, gender, class one, class two, class three")
labe.pack()
ent = Entry(tk, bd=5)
ent.pack()
def dog():
getted = ent.get()
conn = sqlite3.connect('friend.db')
if getted == "fullname":
with conn:
cursor = conn.cursor()
cursor.execute('SELECT name1 FROM Photos')
conn.commit()
result = cursor.fetchall()
for r in result:
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=r)
lab.pack()
tkee.mainloop()
buty = Button(tk, text="Submit", command=dog)
buty.pack()
The program works fine when I enter that I want all the full names, but only one name comes up on the slide. It is only until I exit all the other tabs that the other names show up. If anyone knows how to do this, that would be greatly appreciated. Thanks, Jamal
python tkinter sqlite3
add a comment |
I am making a program where you can search a name, and everything from the sqlite3 database will show up.
def search():
tk = Tk()
tk.geometry('500x500')
labe = Label(tk, text="Search all: fullname, major, gender, class one, class two, class three")
labe.pack()
ent = Entry(tk, bd=5)
ent.pack()
def dog():
getted = ent.get()
conn = sqlite3.connect('friend.db')
if getted == "fullname":
with conn:
cursor = conn.cursor()
cursor.execute('SELECT name1 FROM Photos')
conn.commit()
result = cursor.fetchall()
for r in result:
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=r)
lab.pack()
tkee.mainloop()
buty = Button(tk, text="Submit", command=dog)
buty.pack()
The program works fine when I enter that I want all the full names, but only one name comes up on the slide. It is only until I exit all the other tabs that the other names show up. If anyone knows how to do this, that would be greatly appreciated. Thanks, Jamal
python tkinter sqlite3
I am making a program where you can search a name, and everything from the sqlite3 database will show up.
def search():
tk = Tk()
tk.geometry('500x500')
labe = Label(tk, text="Search all: fullname, major, gender, class one, class two, class three")
labe.pack()
ent = Entry(tk, bd=5)
ent.pack()
def dog():
getted = ent.get()
conn = sqlite3.connect('friend.db')
if getted == "fullname":
with conn:
cursor = conn.cursor()
cursor.execute('SELECT name1 FROM Photos')
conn.commit()
result = cursor.fetchall()
for r in result:
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=r)
lab.pack()
tkee.mainloop()
buty = Button(tk, text="Submit", command=dog)
buty.pack()
The program works fine when I enter that I want all the full names, but only one name comes up on the slide. It is only until I exit all the other tabs that the other names show up. If anyone knows how to do this, that would be greatly appreciated. Thanks, Jamal
python tkinter sqlite3
python tkinter sqlite3
asked Nov 20 '18 at 0:53
JamalTheCoolKidJamalTheCoolKid
497
497
add a comment |
add a comment |
1 Answer
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The problem that is occurring is that you are using a for loop.
result = cursor.fetchall()
for r in result:
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=r)
lab.pack()
tkee.mainloop()
If you change it just to.
result = cursor.fetchall()
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=result)
lab.pack()
tkee.mainloop()
Then it will work
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The problem that is occurring is that you are using a for loop.
result = cursor.fetchall()
for r in result:
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=r)
lab.pack()
tkee.mainloop()
If you change it just to.
result = cursor.fetchall()
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=result)
lab.pack()
tkee.mainloop()
Then it will work
add a comment |
The problem that is occurring is that you are using a for loop.
result = cursor.fetchall()
for r in result:
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=r)
lab.pack()
tkee.mainloop()
If you change it just to.
result = cursor.fetchall()
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=result)
lab.pack()
tkee.mainloop()
Then it will work
add a comment |
The problem that is occurring is that you are using a for loop.
result = cursor.fetchall()
for r in result:
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=r)
lab.pack()
tkee.mainloop()
If you change it just to.
result = cursor.fetchall()
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=result)
lab.pack()
tkee.mainloop()
Then it will work
The problem that is occurring is that you are using a for loop.
result = cursor.fetchall()
for r in result:
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=r)
lab.pack()
tkee.mainloop()
If you change it just to.
result = cursor.fetchall()
tkee = Tk()
tkee.geometry('500x500')
lab = Label(tkee, text=result)
lab.pack()
tkee.mainloop()
Then it will work
answered Nov 20 '18 at 1:19
JamalTheCoolKidJamalTheCoolKid
497
497
add a comment |
add a comment |
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