Mixing
Clone Element and Append to end
I have a HTML template which looks like this:
<div id="amznplist">
<div id="amznpitem">
<span>
<img src="%%Produktbild%%" alt="%%Produkttitel%%"><div id="amzntitle">%%Produkttitel%%</div><div id="amzprice">%%Produktpreis%%</div>
</span>
</div>
</div>
What I try to archive is to load the entire html, copy the #amznpitem item, run through my response (data) and populate each li element with the data and add it to the end. What happens is that only one element is added to #amznplist. This is my current code.
var li = html.find('#amznpitem').clone();
html.find('#amznpitem').remove();
var ul = html.find('#amznplist');
$.each(data, function (index, values) {
li.find('#amzntitle').text(values['title'][0]);
li.find('a').attr('href', values['url'][0]);
li.find('img').attr('src', values['img'][0]);
li.find('img').attr('alt', values['title'][0]);
li.find('#amzprice').text(values['lowest_price'][0]);
$(ul).append(li);
});
$('#result').html(html);
javascript jquery
asked Nov 21 '18 at 17:07
SvenSven
1
add a comment |
I have a HTML template which looks like this:
<div id="amznplist">
<div id="amznpitem">
<span>
<img src="%%Produktbild%%" alt="%%Produkttitel%%"><div id="amzntitle">%%Produkttitel%%</div><div id="amzprice">%%Produktpreis%%</div>
</span>
</div>
</div>
What I try to archive is to load the entire html, copy the #amznpitem item, run through my response (data) and populate each li element with the data and add it to the end. What happens is that only one element is added to #amznplist. This is my current code.
var li = html.find('#amznpitem').clone();
html.find('#amznpitem').remove();
var ul = html.find('#amznplist');
$.each(data, function (index, values) {
li.find('#amzntitle').text(values['title'][0]);
li.find('a').attr('href', values['url'][0]);
li.find('img').attr('src', values['img'][0]);
li.find('img').attr('alt', values['title'][0]);
li.find('#amzprice').text(values['lowest_price'][0]);
$(ul).append(li);
});
$('#result').html(html);
javascript jquery
asked Nov 21 '18 at 17:07
SvenSven
1
use classes instead of ids - ids are meant to be unique and as such jquery will only fetch the first element with that id it finds
– Pete
Nov 21 '18 at 17:17
add a comment |
I have a HTML template which looks like this:
<div id="amznplist">
<div id="amznpitem">
<span>
<img src="%%Produktbild%%" alt="%%Produkttitel%%"><div id="amzntitle">%%Produkttitel%%</div><div id="amzprice">%%Produktpreis%%</div>
</span>
</div>
</div>
What I try to archive is to load the entire html, copy the #amznpitem item, run through my response (data) and populate each li element with the data and add it to the end. What happens is that only one element is added to #amznplist. This is my current code.
var li = html.find('#amznpitem').clone();
html.find('#amznpitem').remove();
var ul = html.find('#amznplist');
$.each(data, function (index, values) {
li.find('#amzntitle').text(values['title'][0]);
li.find('a').attr('href', values['url'][0]);
li.find('img').attr('src', values['img'][0]);
li.find('img').attr('alt', values['title'][0]);
li.find('#amzprice').text(values['lowest_price'][0]);
$(ul).append(li);
});
$('#result').html(html);
javascript jquery
asked Nov 21 '18 at 17:07
SvenSven
1
I have a HTML template which looks like this:
<div id="amznplist">
<div id="amznpitem">
<span>
<img src="%%Produktbild%%" alt="%%Produkttitel%%"><div id="amzntitle">%%Produkttitel%%</div><div id="amzprice">%%Produktpreis%%</div>
</span>
</div>
</div>
What I try to archive is to load the entire html, copy the #amznpitem item, run through my response (data) and populate each li element with the data and add it to the end. What happens is that only one element is added to #amznplist. This is my current code.
var li = html.find('#amznpitem').clone();
html.find('#amznpitem').remove();
var ul = html.find('#amznplist');
$.each(data, function (index, values) {
li.find('#amzntitle').text(values['title'][0]);
li.find('a').attr('href', values['url'][0]);
li.find('img').attr('src', values['img'][0]);
li.find('img').attr('alt', values['title'][0]);
li.find('#amzprice').text(values['lowest_price'][0]);
$(ul).append(li);
});
$('#result').html(html);
javascript jquery
javascript jquery
asked Nov 21 '18 at 17:07
SvenSven
1
asked Nov 21 '18 at 17:07
SvenSven
1
asked Nov 21 '18 at 17:07
SvenSven
1
asked Nov 21 '18 at 17:07
SvenSven
1
asked Nov 21 '18 at 17:07
SvenSven
1
1
use classes instead of ids - ids are meant to be unique and as such jquery will only fetch the first element with that id it finds
– Pete
Nov 21 '18 at 17:17
add a comment |
use classes instead of ids - ids are meant to be unique and as such jquery will only fetch the first element with that id it finds
– Pete
Nov 21 '18 at 17:17
use classes instead of ids - ids are meant to be unique and as such jquery will only fetch the first element with that id it finds
– Pete
Nov 21 '18 at 17:17
use classes instead of ids - ids are meant to be unique and as such jquery will only fetch the first element with that id it finds
– Pete
Nov 21 '18 at 17:17
add a comment |
1 Answer
1
active
oldest
votes
You are not iterating over the response data in your loop, you are always accessing the first element - values...[0]. Use the index that you have available in the each function to pass the values from the current iteration
$.each(data, function (index, values) {
li.find('#amzntitle').text(values['title'][index]);
li.find('a').attr('href', values['url'][index]);
li.find('img').attr('src', values['img'][index]);
li.find('img').attr('alt', values['title'][index]);
li.find('#amzprice').text(values['lowest_price'][index]);
$(ul).append(li);
});
answered Nov 21 '18 at 17:15
Velimir TchatchevskyVelimir Tchatchevsky
2,17411118
Thank you, but this is not the problem I try to solve. The [0] is important because the json is kinda weird at this point and I need to get the first child of values['title] and so on.
– Sven
Nov 22 '18 at 5:19
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You are not iterating over the response data in your loop, you are always accessing the first element - values...[0]. Use the index that you have available in the each function to pass the values from the current iteration
$.each(data, function (index, values) {
li.find('#amzntitle').text(values['title'][index]);
li.find('a').attr('href', values['url'][index]);
li.find('img').attr('src', values['img'][index]);
li.find('img').attr('alt', values['title'][index]);
li.find('#amzprice').text(values['lowest_price'][index]);
$(ul).append(li);
});
answered Nov 21 '18 at 17:15
Velimir TchatchevskyVelimir Tchatchevsky
2,17411118
Thank you, but this is not the problem I try to solve. The [0] is important because the json is kinda weird at this point and I need to get the first child of values['title] and so on.
– Sven
Nov 22 '18 at 5:19
add a comment |
You are not iterating over the response data in your loop, you are always accessing the first element - values...[0]. Use the index that you have available in the each function to pass the values from the current iteration
$.each(data, function (index, values) {
li.find('#amzntitle').text(values['title'][index]);
li.find('a').attr('href', values['url'][index]);
li.find('img').attr('src', values['img'][index]);
li.find('img').attr('alt', values['title'][index]);
li.find('#amzprice').text(values['lowest_price'][index]);
$(ul).append(li);
});
answered Nov 21 '18 at 17:15
Velimir TchatchevskyVelimir Tchatchevsky
2,17411118
Thank you, but this is not the problem I try to solve. The [0] is important because the json is kinda weird at this point and I need to get the first child of values['title] and so on.
– Sven
Nov 22 '18 at 5:19
add a comment |
You are not iterating over the response data in your loop, you are always accessing the first element - values...[0]. Use the index that you have available in the each function to pass the values from the current iteration
$.each(data, function (index, values) {
li.find('#amzntitle').text(values['title'][index]);
li.find('a').attr('href', values['url'][index]);
li.find('img').attr('src', values['img'][index]);
li.find('img').attr('alt', values['title'][index]);
li.find('#amzprice').text(values['lowest_price'][index]);
$(ul).append(li);
});
answered Nov 21 '18 at 17:15
Velimir TchatchevskyVelimir Tchatchevsky
2,17411118
You are not iterating over the response data in your loop, you are always accessing the first element - values...[0]. Use the index that you have available in the each function to pass the values from the current iteration
$.each(data, function (index, values) {
li.find('#amzntitle').text(values['title'][index]);
li.find('a').attr('href', values['url'][index]);
li.find('img').attr('src', values['img'][index]);
li.find('img').attr('alt', values['title'][index]);
li.find('#amzprice').text(values['lowest_price'][index]);
$(ul).append(li);
});
answered Nov 21 '18 at 17:15
Velimir TchatchevskyVelimir Tchatchevsky
2,17411118
answered Nov 21 '18 at 17:15
Velimir TchatchevskyVelimir Tchatchevsky
2,17411118
answered Nov 21 '18 at 17:15
Velimir TchatchevskyVelimir Tchatchevsky
2,17411118
answered Nov 21 '18 at 17:15
Velimir TchatchevskyVelimir Tchatchevsky
2,17411118
2,17411118
Thank you, but this is not the problem I try to solve. The [0] is important because the json is kinda weird at this point and I need to get the first child of values['title] and so on.
– Sven
Nov 22 '18 at 5:19
add a comment |
Thank you, but this is not the problem I try to solve. The [0] is important because the json is kinda weird at this point and I need to get the first child of values['title] and so on.
– Sven
Nov 22 '18 at 5:19
Thank you, but this is not the problem I try to solve. The [0] is important because the json is kinda weird at this point and I need to get the first child of values['title] and so on.
– Sven
Nov 22 '18 at 5:19
Thank you, but this is not the problem I try to solve. The [0] is important because the json is kinda weird at this point and I need to get the first child of values['title] and so on.
– Sven
Nov 22 '18 at 5:19
add a comment |
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use classes instead of ids - ids are meant to be unique and as such jquery will only fetch the first element with that id it finds
– Pete
Nov 21 '18 at 17:17