SQL user defined function not run












2














I have situation where I want to generate invoice_id sequential for different product for multiple cities. I want to get generated invoice id according to different product and city.



My table temp look like



id  |order_id |product|city|invoice_id 
1 | 123 | 1 | 1 | FPU1
2 | 124 | 6 | 1 | PPU1


I want to get next invoice_id for product 1 and city 1 is FPU2.



For product 1 and city 2 is FBN1,product 6 and city 1 is PPU2 and so on ....



I create function but not run.Is anything wrong in function?



  CREATE function generate(p_id INT,  c_id INT) 
returns VARCHAR(50)

BEGIN
-- DECLARE v_new_id VARCHAR(50);
SELECT Concat(( CASE
WHEN t.product = 1 THEN "f"
WHEN t.product = 6 THEN "p" end ),
c.city_name, Cast(RIGHT(t.invoice, Length(t.invoice) - 3) AS UNSIGNED) + 1
) v_new_id
FROM temp AS t
JOIN city c
ON c.city_id = t.city
WHERE t.product = p_id
AND t.city = c_id;

RETURN( v_new_id );
end;


Get syntax error:



#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 15 


###Line 15 is AND t.city = c_id;










share|improve this question


















  • 1




    i advice you to make a view instead where you generate the invoice_id
    – Raymond Nijland
    Nov 19 '18 at 13:31








  • 1




    Perhaps you didn't set delimiters - dev.mysql.com/doc/refman/8.0/en/stored-programs-defining.html
    – P.Salmon
    Nov 19 '18 at 13:42






  • 1




    also you cannot return a result set from a trigger, perhaps ) v_new_id should be ) into v_new_id and the declared variable uncommented.
    – P.Salmon
    Nov 19 '18 at 13:52


















2














I have situation where I want to generate invoice_id sequential for different product for multiple cities. I want to get generated invoice id according to different product and city.



My table temp look like



id  |order_id |product|city|invoice_id 
1 | 123 | 1 | 1 | FPU1
2 | 124 | 6 | 1 | PPU1


I want to get next invoice_id for product 1 and city 1 is FPU2.



For product 1 and city 2 is FBN1,product 6 and city 1 is PPU2 and so on ....



I create function but not run.Is anything wrong in function?



  CREATE function generate(p_id INT,  c_id INT) 
returns VARCHAR(50)

BEGIN
-- DECLARE v_new_id VARCHAR(50);
SELECT Concat(( CASE
WHEN t.product = 1 THEN "f"
WHEN t.product = 6 THEN "p" end ),
c.city_name, Cast(RIGHT(t.invoice, Length(t.invoice) - 3) AS UNSIGNED) + 1
) v_new_id
FROM temp AS t
JOIN city c
ON c.city_id = t.city
WHERE t.product = p_id
AND t.city = c_id;

RETURN( v_new_id );
end;


Get syntax error:



#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 15 


###Line 15 is AND t.city = c_id;










share|improve this question


















  • 1




    i advice you to make a view instead where you generate the invoice_id
    – Raymond Nijland
    Nov 19 '18 at 13:31








  • 1




    Perhaps you didn't set delimiters - dev.mysql.com/doc/refman/8.0/en/stored-programs-defining.html
    – P.Salmon
    Nov 19 '18 at 13:42






  • 1




    also you cannot return a result set from a trigger, perhaps ) v_new_id should be ) into v_new_id and the declared variable uncommented.
    – P.Salmon
    Nov 19 '18 at 13:52
















2












2








2







I have situation where I want to generate invoice_id sequential for different product for multiple cities. I want to get generated invoice id according to different product and city.



My table temp look like



id  |order_id |product|city|invoice_id 
1 | 123 | 1 | 1 | FPU1
2 | 124 | 6 | 1 | PPU1


I want to get next invoice_id for product 1 and city 1 is FPU2.



For product 1 and city 2 is FBN1,product 6 and city 1 is PPU2 and so on ....



I create function but not run.Is anything wrong in function?



  CREATE function generate(p_id INT,  c_id INT) 
returns VARCHAR(50)

BEGIN
-- DECLARE v_new_id VARCHAR(50);
SELECT Concat(( CASE
WHEN t.product = 1 THEN "f"
WHEN t.product = 6 THEN "p" end ),
c.city_name, Cast(RIGHT(t.invoice, Length(t.invoice) - 3) AS UNSIGNED) + 1
) v_new_id
FROM temp AS t
JOIN city c
ON c.city_id = t.city
WHERE t.product = p_id
AND t.city = c_id;

RETURN( v_new_id );
end;


Get syntax error:



#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 15 


###Line 15 is AND t.city = c_id;










share|improve this question













I have situation where I want to generate invoice_id sequential for different product for multiple cities. I want to get generated invoice id according to different product and city.



My table temp look like



id  |order_id |product|city|invoice_id 
1 | 123 | 1 | 1 | FPU1
2 | 124 | 6 | 1 | PPU1


I want to get next invoice_id for product 1 and city 1 is FPU2.



For product 1 and city 2 is FBN1,product 6 and city 1 is PPU2 and so on ....



I create function but not run.Is anything wrong in function?



  CREATE function generate(p_id INT,  c_id INT) 
returns VARCHAR(50)

BEGIN
-- DECLARE v_new_id VARCHAR(50);
SELECT Concat(( CASE
WHEN t.product = 1 THEN "f"
WHEN t.product = 6 THEN "p" end ),
c.city_name, Cast(RIGHT(t.invoice, Length(t.invoice) - 3) AS UNSIGNED) + 1
) v_new_id
FROM temp AS t
JOIN city c
ON c.city_id = t.city
WHERE t.product = p_id
AND t.city = c_id;

RETURN( v_new_id );
end;


Get syntax error:



#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 15 


###Line 15 is AND t.city = c_id;







mysql sql phpmyadmin






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share|improve this question











share|improve this question




share|improve this question










asked Nov 19 '18 at 13:22









Satish

223413




223413








  • 1




    i advice you to make a view instead where you generate the invoice_id
    – Raymond Nijland
    Nov 19 '18 at 13:31








  • 1




    Perhaps you didn't set delimiters - dev.mysql.com/doc/refman/8.0/en/stored-programs-defining.html
    – P.Salmon
    Nov 19 '18 at 13:42






  • 1




    also you cannot return a result set from a trigger, perhaps ) v_new_id should be ) into v_new_id and the declared variable uncommented.
    – P.Salmon
    Nov 19 '18 at 13:52
















  • 1




    i advice you to make a view instead where you generate the invoice_id
    – Raymond Nijland
    Nov 19 '18 at 13:31








  • 1




    Perhaps you didn't set delimiters - dev.mysql.com/doc/refman/8.0/en/stored-programs-defining.html
    – P.Salmon
    Nov 19 '18 at 13:42






  • 1




    also you cannot return a result set from a trigger, perhaps ) v_new_id should be ) into v_new_id and the declared variable uncommented.
    – P.Salmon
    Nov 19 '18 at 13:52










1




1




i advice you to make a view instead where you generate the invoice_id
– Raymond Nijland
Nov 19 '18 at 13:31






i advice you to make a view instead where you generate the invoice_id
– Raymond Nijland
Nov 19 '18 at 13:31






1




1




Perhaps you didn't set delimiters - dev.mysql.com/doc/refman/8.0/en/stored-programs-defining.html
– P.Salmon
Nov 19 '18 at 13:42




Perhaps you didn't set delimiters - dev.mysql.com/doc/refman/8.0/en/stored-programs-defining.html
– P.Salmon
Nov 19 '18 at 13:42




1




1




also you cannot return a result set from a trigger, perhaps ) v_new_id should be ) into v_new_id and the declared variable uncommented.
– P.Salmon
Nov 19 '18 at 13:52






also you cannot return a result set from a trigger, perhaps ) v_new_id should be ) into v_new_id and the declared variable uncommented.
– P.Salmon
Nov 19 '18 at 13:52














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Need to set delimiters .



Thanks @P.Salmon for valuable comment and link



For set delimiter manually follow



For phpmyadmin user follow this link






share|improve this answer





















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    1 Answer
    1






    active

    oldest

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    active

    oldest

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    0














    Need to set delimiters .



    Thanks @P.Salmon for valuable comment and link



    For set delimiter manually follow



    For phpmyadmin user follow this link






    share|improve this answer


























      0














      Need to set delimiters .



      Thanks @P.Salmon for valuable comment and link



      For set delimiter manually follow



      For phpmyadmin user follow this link






      share|improve this answer
























        0












        0








        0






        Need to set delimiters .



        Thanks @P.Salmon for valuable comment and link



        For set delimiter manually follow



        For phpmyadmin user follow this link






        share|improve this answer












        Need to set delimiters .



        Thanks @P.Salmon for valuable comment and link



        For set delimiter manually follow



        For phpmyadmin user follow this link







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 19 '18 at 14:40









        Satish

        223413




        223413






























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