Mixing
How to construct a perfect cube in two point perspective
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See the approximate cube in two point perspective below. It is approximate because I eyeballed the horizontal placement of the two vertical lines off-center representing the two far edges of the near faces. I wish to draw a "perfect" cube with all dimensions scaling appropriately given the vanishing points.
Question: Given two arbitrarily located (but restricted by the line segment between them will be perpendicular to the near edge vertical line segment) vanishing points, calculate all line segment dimensions (specifically only need horizontal placement of two off-center vertical line segements) for the cube.
I have tried using similar triangles, law of cosines, etc. without success.
geometry
asked May 22 '12 at 20:43
Jason WaldropJason Waldrop
1308
$endgroup$
add a comment |
$begingroup$
See the approximate cube in two point perspective below. It is approximate because I eyeballed the horizontal placement of the two vertical lines off-center representing the two far edges of the near faces. I wish to draw a "perfect" cube with all dimensions scaling appropriately given the vanishing points.
Question: Given two arbitrarily located (but restricted by the line segment between them will be perpendicular to the near edge vertical line segment) vanishing points, calculate all line segment dimensions (specifically only need horizontal placement of two off-center vertical line segements) for the cube.
I have tried using similar triangles, law of cosines, etc. without success.
geometry
asked May 22 '12 at 20:43
Jason WaldropJason Waldrop
1308
$endgroup$
$begingroup$
Here are some methods how to achieve it.
$endgroup$
– t.b.
May 23 '12 at 1:07
add a comment |
$begingroup$
See the approximate cube in two point perspective below. It is approximate because I eyeballed the horizontal placement of the two vertical lines off-center representing the two far edges of the near faces. I wish to draw a "perfect" cube with all dimensions scaling appropriately given the vanishing points.
Question: Given two arbitrarily located (but restricted by the line segment between them will be perpendicular to the near edge vertical line segment) vanishing points, calculate all line segment dimensions (specifically only need horizontal placement of two off-center vertical line segements) for the cube.
I have tried using similar triangles, law of cosines, etc. without success.
geometry
asked May 22 '12 at 20:43
Jason WaldropJason Waldrop
1308
$endgroup$
See the approximate cube in two point perspective below. It is approximate because I eyeballed the horizontal placement of the two vertical lines off-center representing the two far edges of the near faces. I wish to draw a "perfect" cube with all dimensions scaling appropriately given the vanishing points.
Question: Given two arbitrarily located (but restricted by the line segment between them will be perpendicular to the near edge vertical line segment) vanishing points, calculate all line segment dimensions (specifically only need horizontal placement of two off-center vertical line segements) for the cube.
I have tried using similar triangles, law of cosines, etc. without success.
geometry
geometry
asked May 22 '12 at 20:43
Jason WaldropJason Waldrop
1308
asked May 22 '12 at 20:43
Jason WaldropJason Waldrop
1308
asked May 22 '12 at 20:43
Jason WaldropJason Waldrop
1308
asked May 22 '12 at 20:43
Jason WaldropJason Waldrop
1308
asked May 22 '12 at 20:43
Jason WaldropJason Waldrop
1308
1308
$begingroup$
Here are some methods how to achieve it.
$endgroup$
– t.b.
May 23 '12 at 1:07
add a comment |
$begingroup$
Here are some methods how to achieve it.
$endgroup$
– t.b.
May 23 '12 at 1:07
$begingroup$
Here are some methods how to achieve it.
$endgroup$
– t.b.
May 23 '12 at 1:07
$begingroup$
Here are some methods how to achieve it.
$endgroup$
– t.b.
May 23 '12 at 1:07
add a comment |
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$begingroup$
Here are some methods how to achieve it.
$endgroup$
– t.b.
May 23 '12 at 1:07