Mixing
Applying function to all elements of the list of list
$begingroup$
Let's say we have a following list:
{{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4}, {1,2, 3, 4, 5}}, {{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4,5}}, {{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4,5}}, {{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}}.
Now, I've written this simple function:
TransformToPoints[{a_}] :=
If[First[a] == 1,
{First[a] = 0, Last[a] = Last[a] + 1},
{First[a] = First[a] - 1, Last[a] = Last[a] + 1}]
so basically that function takes in a list and transforms it to the list of 2 elements, where those 2 elements are produced as described in the function. Now, I'd like to apply this function to all the elements of lists inside the big list above (which is usually much, much bigger) so the new list would look as follows:
{{{0,2},{2,4},{4,6},{0,3},{0,6}},{{0,2},{2,4},{4,6},{2,5},{0,6}},...,{{0,2},{2,4},{4,6},{0,5},{0,6}}}
What would be the quickest way to do that?
list-manipulation
edited Jan 14 at 19:35
Mr.Wizard♦
231k294761049
asked Jan 14 at 16:39
amator2357amator2357
997
$endgroup$
add a comment |
$begingroup$
Let's say we have a following list:
{{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4}, {1,2, 3, 4, 5}}, {{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4,5}}, {{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4,5}}, {{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}}.
Now, I've written this simple function:
TransformToPoints[{a_}] :=
If[First[a] == 1,
{First[a] = 0, Last[a] = Last[a] + 1},
{First[a] = First[a] - 1, Last[a] = Last[a] + 1}]
so basically that function takes in a list and transforms it to the list of 2 elements, where those 2 elements are produced as described in the function. Now, I'd like to apply this function to all the elements of lists inside the big list above (which is usually much, much bigger) so the new list would look as follows:
{{{0,2},{2,4},{4,6},{0,3},{0,6}},{{0,2},{2,4},{4,6},{2,5},{0,6}},...,{{0,2},{2,4},{4,6},{0,5},{0,6}}}
What would be the quickest way to do that?
list-manipulation
edited Jan 14 at 19:35
Mr.Wizard♦
231k294761049
asked Jan 14 at 16:39
amator2357amator2357
997
$endgroup$
add a comment |
$begingroup$
Let's say we have a following list:
{{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4}, {1,2, 3, 4, 5}}, {{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4,5}}, {{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4,5}}, {{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}}.
Now, I've written this simple function:
TransformToPoints[{a_}] :=
If[First[a] == 1,
{First[a] = 0, Last[a] = Last[a] + 1},
{First[a] = First[a] - 1, Last[a] = Last[a] + 1}]
so basically that function takes in a list and transforms it to the list of 2 elements, where those 2 elements are produced as described in the function. Now, I'd like to apply this function to all the elements of lists inside the big list above (which is usually much, much bigger) so the new list would look as follows:
{{{0,2},{2,4},{4,6},{0,3},{0,6}},{{0,2},{2,4},{4,6},{2,5},{0,6}},...,{{0,2},{2,4},{4,6},{0,5},{0,6}}}
What would be the quickest way to do that?
list-manipulation
edited Jan 14 at 19:35
Mr.Wizard♦
231k294761049
asked Jan 14 at 16:39
amator2357amator2357
997
$endgroup$
Let's say we have a following list:
{{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4}, {1,2, 3, 4, 5}}, {{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4,5}}, {{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4,5}}, {{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}}.
Now, I've written this simple function:
TransformToPoints[{a_}] :=
If[First[a] == 1,
{First[a] = 0, Last[a] = Last[a] + 1},
{First[a] = First[a] - 1, Last[a] = Last[a] + 1}]
so basically that function takes in a list and transforms it to the list of 2 elements, where those 2 elements are produced as described in the function. Now, I'd like to apply this function to all the elements of lists inside the big list above (which is usually much, much bigger) so the new list would look as follows:
{{{0,2},{2,4},{4,6},{0,3},{0,6}},{{0,2},{2,4},{4,6},{2,5},{0,6}},...,{{0,2},{2,4},{4,6},{0,5},{0,6}}}
What would be the quickest way to do that?
list-manipulation
list-manipulation
edited Jan 14 at 19:35
Mr.Wizard♦
231k294761049
asked Jan 14 at 16:39
amator2357amator2357
997
edited Jan 14 at 19:35
Mr.Wizard♦
231k294761049
asked Jan 14 at 16:39
amator2357amator2357
997
edited Jan 14 at 19:35
Mr.Wizard♦
231k294761049
edited Jan 14 at 19:35
Mr.Wizard♦
231k294761049
edited Jan 14 at 19:35
Mr.Wizard♦
231k294761049
231k294761049
asked Jan 14 at 16:39
amator2357amator2357
997
asked Jan 14 at 16:39
amator2357amator2357
997
asked Jan 14 at 16:39
amator2357amator2357
997
997
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
An alternative way to define your transformation function:
tToP[lst_List] := #[[{1, -1}]] + {-1, 1} & /@ lst;
list = {{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}},
{{1}, {3}, {5}, {3, 4}, {1,2, 3, 4, 5}},
{{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4,5}},
{{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4,5}},
{{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}};
tToP /@ list
{{{0, 2}, {2, 4}, {4, 6}, {0, 3}, {0, 6}},
{{0, 2}, {2, 4}, {4,
6}, {2, 5}, {0, 6}},
{{0, 2}, {2, 4}, {4, 6}, {0, 4}, {0, 6}},
{{0,
2}, {2, 4}, {4, 6}, {2, 6}, {0, 6}},
{{0, 2}, {2, 4}, {4, 6}, {0,
5}, {0, 6}}}
Alternatively, you can use Map[tToP, list, 1].
answered Jan 14 at 17:53
kglrkglr
184k10202418
$endgroup$
$begingroup$
Thank you @kglr, I really like it ! I'll accept your answer since it uses this unintuitive (at least to me) approach.
$endgroup$
– amator2357
Jan 14 at 21:23
$begingroup$
@amator2357, thank you for the accept.
$endgroup$
– kglr
Jan 14 at 21:33
add a comment |
$begingroup$
First of all, you can't do assignment to variables that you entered into the function in this case. It's not necessary either, just define your function as follows (notice that I also fixed your matching pattern):
Clear[TransformToPoints]
TransformToPoints[a_List] := If[First[a] == 1, {0, Last[a] + 1}, {First[a] - 1, Last[a] + 1}]
To apply the function to all elements of the big list, just use Map. However, you don't want to map onto the first level but the second level down, so this is what you do:
Map[
TransformToPoints,
{
{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4}, {1, 2, 3, 4, 5}},
{{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}
},
{2} (* map onto the 2nd level*)
]
{{{0, 2}, {2, 4}, {4, 6}, {0, 3}, {0, 6}}, {{0, 2}, {2, 4}, {4,
6}, {2, 5}, {0, 6}}, {{0, 2}, {2, 4}, {4, 6}, {0, 4}, {0, 6}}, {{0,
2}, {2, 4}, {4, 6}, {2, 6}, {0, 6}}, {{0, 2}, {2, 4}, {4, 6}, {0,
5}, {0, 6}}}
answered Jan 14 at 17:02
Sjoerd SmitSjoerd Smit
3,670715
$endgroup$
$begingroup$
Thank you so much!
$endgroup$
– amator2357
Jan 14 at 17:44
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f189478%2fapplying-function-to-all-elements-of-the-list-of-list%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
An alternative way to define your transformation function:
tToP[lst_List] := #[[{1, -1}]] + {-1, 1} & /@ lst;
list = {{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}},
{{1}, {3}, {5}, {3, 4}, {1,2, 3, 4, 5}},
{{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4,5}},
{{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4,5}},
{{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}};
tToP /@ list
{{{0, 2}, {2, 4}, {4, 6}, {0, 3}, {0, 6}},
{{0, 2}, {2, 4}, {4,
6}, {2, 5}, {0, 6}},
{{0, 2}, {2, 4}, {4, 6}, {0, 4}, {0, 6}},
{{0,
2}, {2, 4}, {4, 6}, {2, 6}, {0, 6}},
{{0, 2}, {2, 4}, {4, 6}, {0,
5}, {0, 6}}}
Alternatively, you can use Map[tToP, list, 1].
answered Jan 14 at 17:53
kglrkglr
184k10202418
$endgroup$
$begingroup$
Thank you @kglr, I really like it ! I'll accept your answer since it uses this unintuitive (at least to me) approach.
$endgroup$
– amator2357
Jan 14 at 21:23
$begingroup$
@amator2357, thank you for the accept.
$endgroup$
– kglr
Jan 14 at 21:33
add a comment |
$begingroup$
An alternative way to define your transformation function:
tToP[lst_List] := #[[{1, -1}]] + {-1, 1} & /@ lst;
list = {{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}},
{{1}, {3}, {5}, {3, 4}, {1,2, 3, 4, 5}},
{{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4,5}},
{{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4,5}},
{{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}};
tToP /@ list
{{{0, 2}, {2, 4}, {4, 6}, {0, 3}, {0, 6}},
{{0, 2}, {2, 4}, {4,
6}, {2, 5}, {0, 6}},
{{0, 2}, {2, 4}, {4, 6}, {0, 4}, {0, 6}},
{{0,
2}, {2, 4}, {4, 6}, {2, 6}, {0, 6}},
{{0, 2}, {2, 4}, {4, 6}, {0,
5}, {0, 6}}}
Alternatively, you can use Map[tToP, list, 1].
answered Jan 14 at 17:53
kglrkglr
184k10202418
$endgroup$
$begingroup$
Thank you @kglr, I really like it ! I'll accept your answer since it uses this unintuitive (at least to me) approach.
$endgroup$
– amator2357
Jan 14 at 21:23
$begingroup$
@amator2357, thank you for the accept.
$endgroup$
– kglr
Jan 14 at 21:33
add a comment |
$begingroup$
An alternative way to define your transformation function:
tToP[lst_List] := #[[{1, -1}]] + {-1, 1} & /@ lst;
list = {{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}},
{{1}, {3}, {5}, {3, 4}, {1,2, 3, 4, 5}},
{{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4,5}},
{{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4,5}},
{{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}};
tToP /@ list
{{{0, 2}, {2, 4}, {4, 6}, {0, 3}, {0, 6}},
{{0, 2}, {2, 4}, {4,
6}, {2, 5}, {0, 6}},
{{0, 2}, {2, 4}, {4, 6}, {0, 4}, {0, 6}},
{{0,
2}, {2, 4}, {4, 6}, {2, 6}, {0, 6}},
{{0, 2}, {2, 4}, {4, 6}, {0,
5}, {0, 6}}}
Alternatively, you can use Map[tToP, list, 1].
answered Jan 14 at 17:53
kglrkglr
184k10202418
$endgroup$
An alternative way to define your transformation function:
tToP[lst_List] := #[[{1, -1}]] + {-1, 1} & /@ lst;
list = {{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}},
{{1}, {3}, {5}, {3, 4}, {1,2, 3, 4, 5}},
{{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4,5}},
{{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4,5}},
{{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}};
tToP /@ list
{{{0, 2}, {2, 4}, {4, 6}, {0, 3}, {0, 6}},
{{0, 2}, {2, 4}, {4,
6}, {2, 5}, {0, 6}},
{{0, 2}, {2, 4}, {4, 6}, {0, 4}, {0, 6}},
{{0,
2}, {2, 4}, {4, 6}, {2, 6}, {0, 6}},
{{0, 2}, {2, 4}, {4, 6}, {0,
5}, {0, 6}}}
Alternatively, you can use Map[tToP, list, 1].
answered Jan 14 at 17:53
kglrkglr
184k10202418
answered Jan 14 at 17:53
kglrkglr
184k10202418
answered Jan 14 at 17:53
kglrkglr
184k10202418
answered Jan 14 at 17:53
kglrkglr
184k10202418
184k10202418
$begingroup$
Thank you @kglr, I really like it ! I'll accept your answer since it uses this unintuitive (at least to me) approach.
$endgroup$
– amator2357
Jan 14 at 21:23
$begingroup$
@amator2357, thank you for the accept.
$endgroup$
– kglr
Jan 14 at 21:33
add a comment |
$begingroup$
Thank you @kglr, I really like it ! I'll accept your answer since it uses this unintuitive (at least to me) approach.
$endgroup$
– amator2357
Jan 14 at 21:23
$begingroup$
@amator2357, thank you for the accept.
$endgroup$
– kglr
Jan 14 at 21:33
$begingroup$
Thank you @kglr, I really like it ! I'll accept your answer since it uses this unintuitive (at least to me) approach.
$endgroup$
– amator2357
Jan 14 at 21:23
$begingroup$
Thank you @kglr, I really like it ! I'll accept your answer since it uses this unintuitive (at least to me) approach.
$endgroup$
– amator2357
Jan 14 at 21:23
$begingroup$
@amator2357, thank you for the accept.
$endgroup$
– kglr
Jan 14 at 21:33
$begingroup$
@amator2357, thank you for the accept.
$endgroup$
– kglr
Jan 14 at 21:33
add a comment |
$begingroup$
First of all, you can't do assignment to variables that you entered into the function in this case. It's not necessary either, just define your function as follows (notice that I also fixed your matching pattern):
Clear[TransformToPoints]
TransformToPoints[a_List] := If[First[a] == 1, {0, Last[a] + 1}, {First[a] - 1, Last[a] + 1}]
To apply the function to all elements of the big list, just use Map. However, you don't want to map onto the first level but the second level down, so this is what you do:
Map[
TransformToPoints,
{
{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4}, {1, 2, 3, 4, 5}},
{{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}
},
{2} (* map onto the 2nd level*)
]
{{{0, 2}, {2, 4}, {4, 6}, {0, 3}, {0, 6}}, {{0, 2}, {2, 4}, {4,
6}, {2, 5}, {0, 6}}, {{0, 2}, {2, 4}, {4, 6}, {0, 4}, {0, 6}}, {{0,
2}, {2, 4}, {4, 6}, {2, 6}, {0, 6}}, {{0, 2}, {2, 4}, {4, 6}, {0,
5}, {0, 6}}}
answered Jan 14 at 17:02
Sjoerd SmitSjoerd Smit
3,670715
$endgroup$
$begingroup$
Thank you so much!
$endgroup$
– amator2357
Jan 14 at 17:44
add a comment |
$begingroup$
First of all, you can't do assignment to variables that you entered into the function in this case. It's not necessary either, just define your function as follows (notice that I also fixed your matching pattern):
Clear[TransformToPoints]
TransformToPoints[a_List] := If[First[a] == 1, {0, Last[a] + 1}, {First[a] - 1, Last[a] + 1}]
To apply the function to all elements of the big list, just use Map. However, you don't want to map onto the first level but the second level down, so this is what you do:
Map[
TransformToPoints,
{
{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4}, {1, 2, 3, 4, 5}},
{{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}
},
{2} (* map onto the 2nd level*)
]
{{{0, 2}, {2, 4}, {4, 6}, {0, 3}, {0, 6}}, {{0, 2}, {2, 4}, {4,
6}, {2, 5}, {0, 6}}, {{0, 2}, {2, 4}, {4, 6}, {0, 4}, {0, 6}}, {{0,
2}, {2, 4}, {4, 6}, {2, 6}, {0, 6}}, {{0, 2}, {2, 4}, {4, 6}, {0,
5}, {0, 6}}}
answered Jan 14 at 17:02
Sjoerd SmitSjoerd Smit
3,670715
$endgroup$
$begingroup$
Thank you so much!
$endgroup$
– amator2357
Jan 14 at 17:44
add a comment |
$begingroup$
First of all, you can't do assignment to variables that you entered into the function in this case. It's not necessary either, just define your function as follows (notice that I also fixed your matching pattern):
Clear[TransformToPoints]
TransformToPoints[a_List] := If[First[a] == 1, {0, Last[a] + 1}, {First[a] - 1, Last[a] + 1}]
To apply the function to all elements of the big list, just use Map. However, you don't want to map onto the first level but the second level down, so this is what you do:
Map[
TransformToPoints,
{
{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4}, {1, 2, 3, 4, 5}},
{{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}
},
{2} (* map onto the 2nd level*)
]
{{{0, 2}, {2, 4}, {4, 6}, {0, 3}, {0, 6}}, {{0, 2}, {2, 4}, {4,
6}, {2, 5}, {0, 6}}, {{0, 2}, {2, 4}, {4, 6}, {0, 4}, {0, 6}}, {{0,
2}, {2, 4}, {4, 6}, {2, 6}, {0, 6}}, {{0, 2}, {2, 4}, {4, 6}, {0,
5}, {0, 6}}}
answered Jan 14 at 17:02
Sjoerd SmitSjoerd Smit
3,670715
$endgroup$
First of all, you can't do assignment to variables that you entered into the function in this case. It's not necessary either, just define your function as follows (notice that I also fixed your matching pattern):
Clear[TransformToPoints]
TransformToPoints[a_List] := If[First[a] == 1, {0, Last[a] + 1}, {First[a] - 1, Last[a] + 1}]
To apply the function to all elements of the big list, just use Map. However, you don't want to map onto the first level but the second level down, so this is what you do:
Map[
TransformToPoints,
{
{{1}, {3}, {5}, {1, 2}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4}, {1, 2, 3, 4, 5}},
{{1}, {3}, {5}, {1, 2, 3}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {3, 4, 5}, {1, 2, 3, 4, 5}}, {{1}, {3}, {5}, {1, 2, 3, 4}, {1, 2, 3, 4, 5}}
},
{2} (* map onto the 2nd level*)
]
{{{0, 2}, {2, 4}, {4, 6}, {0, 3}, {0, 6}}, {{0, 2}, {2, 4}, {4,
6}, {2, 5}, {0, 6}}, {{0, 2}, {2, 4}, {4, 6}, {0, 4}, {0, 6}}, {{0,
2}, {2, 4}, {4, 6}, {2, 6}, {0, 6}}, {{0, 2}, {2, 4}, {4, 6}, {0,
5}, {0, 6}}}
answered Jan 14 at 17:02
Sjoerd SmitSjoerd Smit
3,670715
edited Jan 15 at 9:12
answered Jan 14 at 17:02
Sjoerd SmitSjoerd Smit
3,670715
answered Jan 14 at 17:02
Sjoerd SmitSjoerd Smit
3,670715
answered Jan 14 at 17:02
Sjoerd SmitSjoerd Smit
3,670715
3,670715
$begingroup$
Thank you so much!
$endgroup$
– amator2357
Jan 14 at 17:44
add a comment |
$begingroup$
Thank you so much!
$endgroup$
– amator2357
Jan 14 at 17:44
$begingroup$
Thank you so much!
$endgroup$
– amator2357
Jan 14 at 17:44
$begingroup$
Thank you so much!
$endgroup$
– amator2357
Jan 14 at 17:44
add a comment |
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f189478%2fapplying-function-to-all-elements-of-the-list-of-list%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
