How do I select this element using xpath?
I'm having a problem selecting a "delete" button that has to be linked to a certain element.
So I have to click the "x" icon, but it has to be related to the text "teste"...
Here's the HTML code:
The button I have to click is the span whose class is "fa fa-times" and it has to be related to the div containing the text "teste" because there are other spans with the same class but they are hidden.
Thanks!
selenium xpath
add a comment |
I'm having a problem selecting a "delete" button that has to be linked to a certain element.
So I have to click the "x" icon, but it has to be related to the text "teste"...
Here's the HTML code:
The button I have to click is the span whose class is "fa fa-times" and it has to be related to the div containing the text "teste" because there are other spans with the same class but they are hidden.
Thanks!
selenium xpath
2
its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 '18 at 18:54
add a comment |
I'm having a problem selecting a "delete" button that has to be linked to a certain element.
So I have to click the "x" icon, but it has to be related to the text "teste"...
Here's the HTML code:
The button I have to click is the span whose class is "fa fa-times" and it has to be related to the div containing the text "teste" because there are other spans with the same class but they are hidden.
Thanks!
selenium xpath
I'm having a problem selecting a "delete" button that has to be linked to a certain element.
So I have to click the "x" icon, but it has to be related to the text "teste"...
Here's the HTML code:
The button I have to click is the span whose class is "fa fa-times" and it has to be related to the div containing the text "teste" because there are other spans with the same class but they are hidden.
Thanks!
selenium xpath
selenium xpath
edited Nov 21 '18 at 19:54
Dev
649415
649415
asked Nov 21 '18 at 18:49


Bruno MuramatsuBruno Muramatsu
252
252
2
its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 '18 at 18:54
add a comment |
2
its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 '18 at 18:54
2
2
its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 '18 at 18:54
its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 '18 at 18:54
add a comment |
1 Answer
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Use below XPath to select required element:
//div[div[text()="teste"]]/following-sibling::div//span[@class="fa fa-times"]
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1 Answer
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1 Answer
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oldest
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active
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Use below XPath to select required element:
//div[div[text()="teste"]]/following-sibling::div//span[@class="fa fa-times"]
add a comment |
Use below XPath to select required element:
//div[div[text()="teste"]]/following-sibling::div//span[@class="fa fa-times"]
add a comment |
Use below XPath to select required element:
//div[div[text()="teste"]]/following-sibling::div//span[@class="fa fa-times"]
Use below XPath to select required element:
//div[div[text()="teste"]]/following-sibling::div//span[@class="fa fa-times"]
answered Nov 21 '18 at 19:14


JaSONJaSON
5109
5109
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its better to get answers if you share link where you tried this so that others can try, no buddy willing to type code from your shared images, if not possible to share link share html snip at least, also follow MCVE
– Dev
Nov 21 '18 at 18:54