Mixing
How to find the split in the given set of numbers.
$begingroup$
Beforehand I would like to express apologies if this sort of question is not suited here, but I desperately need it answered.
I have a set of numbers:
[2, 5, 6, 2, 2, 81, 72, 77]
From the above set, we can say that certain numbers above can be "grouped" together. Such that:
[2, 5, 6, 2, 2]
and
[81, 72, 77]
My question is how do I obtain the above two groupings? Is there an algorithm or formulae to achieve this?
real-numbers sorting
edited Jan 15 at 14:36
Andrés E. Caicedo
65.5k8158249
asked Jan 15 at 14:31
randem_gen_guyrandem_gen_guy
61
$endgroup$
|
show 4 more comments
$begingroup$
Beforehand I would like to express apologies if this sort of question is not suited here, but I desperately need it answered.
I have a set of numbers:
[2, 5, 6, 2, 2, 81, 72, 77]
From the above set, we can say that certain numbers above can be "grouped" together. Such that:
[2, 5, 6, 2, 2]
and
[81, 72, 77]
My question is how do I obtain the above two groupings? Is there an algorithm or formulae to achieve this?
real-numbers sorting
edited Jan 15 at 14:36
Andrés E. Caicedo
65.5k8158249
asked Jan 15 at 14:31
randem_gen_guyrandem_gen_guy
61
$endgroup$
$begingroup$
Do you know in advance how many groups you will have? If so, you can use some of the standard clustering algorithms like $k$-means clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:37
$begingroup$
The term you should look up is "cluster analysis". In general it's a hard problem to specify, and it's often hard to solve once it's been well-specified.
$endgroup$
– Patrick Stevens
Jan 15 at 14:37
$begingroup$
Suppose there can be any number of samples in the set. But ultimately what I want is to split the set in such a way that the numbers all lie closest to a certain "mean".
$endgroup$
– randem_gen_guy
Jan 15 at 14:43
$begingroup$
@randem_gen_guy: What I'm asking is not how many numbers would be in the set to begin with, nor how many numbers will wind up in each group after you've grouped them. What I'm asking is do you know in advance how many groups you want to group your numbers into? In your example, two groups totally makes sense. Do you know beforehand how many groups you will need?
$endgroup$
– Adrian Keister
Jan 15 at 14:45
1
$begingroup$
Check out en.wikipedia.org/wiki/K-means_clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:47
|
show 4 more comments
$begingroup$
Beforehand I would like to express apologies if this sort of question is not suited here, but I desperately need it answered.
I have a set of numbers:
[2, 5, 6, 2, 2, 81, 72, 77]
From the above set, we can say that certain numbers above can be "grouped" together. Such that:
[2, 5, 6, 2, 2]
and
[81, 72, 77]
My question is how do I obtain the above two groupings? Is there an algorithm or formulae to achieve this?
real-numbers sorting
edited Jan 15 at 14:36
Andrés E. Caicedo
65.5k8158249
asked Jan 15 at 14:31
randem_gen_guyrandem_gen_guy
61
$endgroup$
Beforehand I would like to express apologies if this sort of question is not suited here, but I desperately need it answered.
I have a set of numbers:
[2, 5, 6, 2, 2, 81, 72, 77]
From the above set, we can say that certain numbers above can be "grouped" together. Such that:
[2, 5, 6, 2, 2]
and
[81, 72, 77]
My question is how do I obtain the above two groupings? Is there an algorithm or formulae to achieve this?
real-numbers sorting
real-numbers sorting
edited Jan 15 at 14:36
Andrés E. Caicedo
65.5k8158249
asked Jan 15 at 14:31
randem_gen_guyrandem_gen_guy
61
edited Jan 15 at 14:36
Andrés E. Caicedo
65.5k8158249
asked Jan 15 at 14:31
randem_gen_guyrandem_gen_guy
61
edited Jan 15 at 14:36
Andrés E. Caicedo
65.5k8158249
edited Jan 15 at 14:36
Andrés E. Caicedo
65.5k8158249
edited Jan 15 at 14:36
Andrés E. Caicedo
65.5k8158249
65.5k8158249
asked Jan 15 at 14:31
randem_gen_guyrandem_gen_guy
61
asked Jan 15 at 14:31
randem_gen_guyrandem_gen_guy
61
asked Jan 15 at 14:31
randem_gen_guyrandem_gen_guy
61
61
$begingroup$
Do you know in advance how many groups you will have? If so, you can use some of the standard clustering algorithms like $k$-means clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:37
$begingroup$
The term you should look up is "cluster analysis". In general it's a hard problem to specify, and it's often hard to solve once it's been well-specified.
$endgroup$
– Patrick Stevens
Jan 15 at 14:37
$begingroup$
Suppose there can be any number of samples in the set. But ultimately what I want is to split the set in such a way that the numbers all lie closest to a certain "mean".
$endgroup$
– randem_gen_guy
Jan 15 at 14:43
$begingroup$
@randem_gen_guy: What I'm asking is not how many numbers would be in the set to begin with, nor how many numbers will wind up in each group after you've grouped them. What I'm asking is do you know in advance how many groups you want to group your numbers into? In your example, two groups totally makes sense. Do you know beforehand how many groups you will need?
$endgroup$
– Adrian Keister
Jan 15 at 14:45
1
$begingroup$
Check out en.wikipedia.org/wiki/K-means_clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:47
|
show 4 more comments
$begingroup$
Do you know in advance how many groups you will have? If so, you can use some of the standard clustering algorithms like $k$-means clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:37
$begingroup$
The term you should look up is "cluster analysis". In general it's a hard problem to specify, and it's often hard to solve once it's been well-specified.
$endgroup$
– Patrick Stevens
Jan 15 at 14:37
$begingroup$
Suppose there can be any number of samples in the set. But ultimately what I want is to split the set in such a way that the numbers all lie closest to a certain "mean".
$endgroup$
– randem_gen_guy
Jan 15 at 14:43
$begingroup$
@randem_gen_guy: What I'm asking is not how many numbers would be in the set to begin with, nor how many numbers will wind up in each group after you've grouped them. What I'm asking is do you know in advance how many groups you want to group your numbers into? In your example, two groups totally makes sense. Do you know beforehand how many groups you will need?
$endgroup$
– Adrian Keister
Jan 15 at 14:45
1
$begingroup$
Check out en.wikipedia.org/wiki/K-means_clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:47
$begingroup$
Do you know in advance how many groups you will have? If so, you can use some of the standard clustering algorithms like $k$-means clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:37
$begingroup$
Do you know in advance how many groups you will have? If so, you can use some of the standard clustering algorithms like $k$-means clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:37
$begingroup$
The term you should look up is "cluster analysis". In general it's a hard problem to specify, and it's often hard to solve once it's been well-specified.
$endgroup$
– Patrick Stevens
Jan 15 at 14:37
$begingroup$
The term you should look up is "cluster analysis". In general it's a hard problem to specify, and it's often hard to solve once it's been well-specified.
$endgroup$
– Patrick Stevens
Jan 15 at 14:37
$begingroup$
Suppose there can be any number of samples in the set. But ultimately what I want is to split the set in such a way that the numbers all lie closest to a certain "mean".
$endgroup$
– randem_gen_guy
Jan 15 at 14:43
$begingroup$
Suppose there can be any number of samples in the set. But ultimately what I want is to split the set in such a way that the numbers all lie closest to a certain "mean".
$endgroup$
– randem_gen_guy
Jan 15 at 14:43
$begingroup$
@randem_gen_guy: What I'm asking is not how many numbers would be in the set to begin with, nor how many numbers will wind up in each group after you've grouped them. What I'm asking is do you know in advance how many groups you want to group your numbers into? In your example, two groups totally makes sense. Do you know beforehand how many groups you will need?
$endgroup$
– Adrian Keister
Jan 15 at 14:45
$begingroup$
@randem_gen_guy: What I'm asking is not how many numbers would be in the set to begin with, nor how many numbers will wind up in each group after you've grouped them. What I'm asking is do you know in advance how many groups you want to group your numbers into? In your example, two groups totally makes sense. Do you know beforehand how many groups you will need?
$endgroup$
– Adrian Keister
Jan 15 at 14:45
1
1
$begingroup$
Check out en.wikipedia.org/wiki/K-means_clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:47
$begingroup$
Check out en.wikipedia.org/wiki/K-means_clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:47
|
show 4 more comments
1 Answer
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$begingroup$
Figured it out. As mentioned in the comments below my question, many people were recommending the K-Means algorithm. It worked perfectly!
answered Jan 15 at 23:23
randem_gen_guyrandem_gen_guy
61
$endgroup$
add a comment |
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$begingroup$
Figured it out. As mentioned in the comments below my question, many people were recommending the K-Means algorithm. It worked perfectly!
answered Jan 15 at 23:23
randem_gen_guyrandem_gen_guy
61
$endgroup$
add a comment |
$begingroup$
Figured it out. As mentioned in the comments below my question, many people were recommending the K-Means algorithm. It worked perfectly!
answered Jan 15 at 23:23
randem_gen_guyrandem_gen_guy
61
$endgroup$
add a comment |
$begingroup$
Figured it out. As mentioned in the comments below my question, many people were recommending the K-Means algorithm. It worked perfectly!
answered Jan 15 at 23:23
randem_gen_guyrandem_gen_guy
61
$endgroup$
Figured it out. As mentioned in the comments below my question, many people were recommending the K-Means algorithm. It worked perfectly!
answered Jan 15 at 23:23
randem_gen_guyrandem_gen_guy
61
answered Jan 15 at 23:23
randem_gen_guyrandem_gen_guy
61
answered Jan 15 at 23:23
randem_gen_guyrandem_gen_guy
61
answered Jan 15 at 23:23
randem_gen_guyrandem_gen_guy
61
61
add a comment |
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$begingroup$
Do you know in advance how many groups you will have? If so, you can use some of the standard clustering algorithms like $k$-means clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:37
$begingroup$
The term you should look up is "cluster analysis". In general it's a hard problem to specify, and it's often hard to solve once it's been well-specified.
$endgroup$
– Patrick Stevens
Jan 15 at 14:37
$begingroup$
Suppose there can be any number of samples in the set. But ultimately what I want is to split the set in such a way that the numbers all lie closest to a certain "mean".
$endgroup$
– randem_gen_guy
Jan 15 at 14:43
$begingroup$
@randem_gen_guy: What I'm asking is not how many numbers would be in the set to begin with, nor how many numbers will wind up in each group after you've grouped them. What I'm asking is do you know in advance how many groups you want to group your numbers into? In your example, two groups totally makes sense. Do you know beforehand how many groups you will need?
$endgroup$
– Adrian Keister
Jan 15 at 14:45
1
$begingroup$
Check out en.wikipedia.org/wiki/K-means_clustering.
$endgroup$
– Adrian Keister
Jan 15 at 14:47