How to get all the text separately from the bracket using javascript regular expression

I have a sentence stored in a variable.That sentence I need to extract into 4 parts depends on sentence which I have put into variables in my code,I can able to extract here and get into console but I am not getting the whole text of inside the bracket,only I am getting first words.Here is the code below.Can anyone please help me.

HTML

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul class="messages">

SCRIPT

$(document).ready(function() {

  regex = /.+(|d. w+/g;

  maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";

  matches = maintext.match(regex);

  text_split0 = matches[0].slice(0, -1);

  text_split1 = matches[1];

  text_split2 = matches[2];

  text_split3 = matches[3];

  text_split4 = matches[4];

  console.log(text_split0);

  console.log(text_split1);

  console.log(text_split2);

  console.log(text_split3);

  console.log(text_split4);

  $(".messages").append('<li>'+text_split0+'</li><li>'+text_split1+'</li><li>'+text_split2+'</li><li>'+text_split3+'</li><li>'+text_split4+'</li>');

 // $("li:contains('undefined')").remove()

});

edited Nov 21 '18 at 19:58

asked Nov 21 '18 at 19:30

carreankush

1587

add a comment |

HTML

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul class="messages">

SCRIPT

$(document).ready(function() {

  regex = /.+(|d. w+/g;

  maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";

  matches = maintext.match(regex);

  text_split0 = matches[0].slice(0, -1);

  text_split1 = matches[1];

  text_split2 = matches[2];

  text_split3 = matches[3];

  text_split4 = matches[4];

  console.log(text_split0);

  console.log(text_split1);

  console.log(text_split2);

  console.log(text_split3);

  console.log(text_split4);

  $(".messages").append('<li>'+text_split0+'</li><li>'+text_split1+'</li><li>'+text_split2+'</li><li>'+text_split3+'</li><li>'+text_split4+'</li>');

 // $("li:contains('undefined')").remove()

});

edited Nov 21 '18 at 19:58

asked Nov 21 '18 at 19:30

carreankush

1587

add a comment |

HTML

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul class="messages">

SCRIPT

$(document).ready(function() {

  regex = /.+(|d. w+/g;

  maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";

  matches = maintext.match(regex);

  text_split0 = matches[0].slice(0, -1);

  text_split1 = matches[1];

  text_split2 = matches[2];

  text_split3 = matches[3];

  text_split4 = matches[4];

  console.log(text_split0);

  console.log(text_split1);

  console.log(text_split2);

  console.log(text_split3);

  console.log(text_split4);

  $(".messages").append('<li>'+text_split0+'</li><li>'+text_split1+'</li><li>'+text_split2+'</li><li>'+text_split3+'</li><li>'+text_split4+'</li>');

 // $("li:contains('undefined')").remove()

});

edited Nov 21 '18 at 19:58

asked Nov 21 '18 at 19:30

carreankush

1587

HTML

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<ul class="messages">

SCRIPT

$(document).ready(function() {

  regex = /.+(|d. w+/g;

  maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";

  matches = maintext.match(regex);

  text_split0 = matches[0].slice(0, -1);

  text_split1 = matches[1];

  text_split2 = matches[2];

  text_split3 = matches[3];

  text_split4 = matches[4];

  console.log(text_split0);

  console.log(text_split1);

  console.log(text_split2);

  console.log(text_split3);

  console.log(text_split4);

  $(".messages").append('<li>'+text_split0+'</li><li>'+text_split1+'</li><li>'+text_split2+'</li><li>'+text_split3+'</li><li>'+text_split4+'</li>');

 // $("li:contains('undefined')").remove()

});

javascript jquery html

edited Nov 21 '18 at 19:58

asked Nov 21 '18 at 19:30

carreankush

1587

edited Nov 21 '18 at 19:58

asked Nov 21 '18 at 19:30

carreankush

1587

edited Nov 21 '18 at 19:58

asked Nov 21 '18 at 19:30

carreankush

1587

asked Nov 21 '18 at 19:30

carreankush

1587

asked Nov 21 '18 at 19:30

carreankush

1587

add a comment |

2 Answers
2

active

oldest

votes

function buildMessages(text) {

    let messages = text.split(/d.s/);

    messages.shift();

    messages.forEach((v)=>{

        let msg = v.replace(/,/,'').replace(/sors/,'').trim();

        $('.messages').append(`<li>${msg}</li>`);

        // console.log(`<li>${msg}</li>`);

    });

}



let sentenceToParse = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";



buildMessages(sentenceToParse);

Use the split function on the String, keying on the digits (e.g. 1.), you will get the preface and each of the steps into an array.

Use the shift function on the Array removes the unneeded preface.

Use forEach to iterate over the values in the array, clean up the text.

Using replace to first remove commas, then remove or with spaces on either side.

Use trim to remove leading and training whitespace.

At this point, your array will have sanitized copy for use in your <li> elements.

If you're only concerned with working through a regex and not re-factoring, the easiest way may be to use an online regex tool where you provide a few different string samples. Look at https://www.regextester.com/

edited Nov 21 '18 at 21:56

answered Nov 21 '18 at 20:02

CodeTheInternet

1

If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.

– Stephen P
Nov 21 '18 at 20:05

can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue

– carreankush
Nov 21 '18 at 20:23

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:34

add a comment |

Ok, Try another approach, cause regex for this isn't the best way. Try this:

$(document).ready(function() {

  // First part of sentence.

  var mainText = "Welcome to project, are you a here(";

  // Users array.

  var USERS = ['new user', 'test user', 'minor Accident', 'Major Accident'];

  var uSize = USERS.length;



  // Construct string & user list dynamically.

  for(var i = 0; i < uSize; i++) {

    var li = $('<li/>').text(USERS[i]);



    if(i === uSize - 1)

      mainText += (i+1) + ". " + USERS[i] + ")";

    else if(i === uSize - 2)

      mainText += (i+1) + ". " + USERS[i] + " or ";

    else

      mainText += (i+1) + ". " + USERS[i] + " , ";



    $(".messages").append(li);

  }

  console.log(mainText); // You will have you complete sentence.

}

Why that way is better? Simple, you can add or remove users inside the user array. String together with your user list will be updated automatically. I hope that help you.

edited Nov 22 '18 at 20:34

answered Nov 21 '18 at 20:10

Hexxefir

46849

I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major

– carreankush
Nov 21 '18 at 20:19

We need to fix only regular expression here regex = /.+(|d. w+/g;

– carreankush
Nov 21 '18 at 20:21

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:35

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

function buildMessages(text) {

    let messages = text.split(/d.s/);

    messages.shift();

    messages.forEach((v)=>{

        let msg = v.replace(/,/,'').replace(/sors/,'').trim();

        $('.messages').append(`<li>${msg}</li>`);

        // console.log(`<li>${msg}</li>`);

    });

}



let sentenceToParse = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";



buildMessages(sentenceToParse);

Use the split function on the String, keying on the digits (e.g. 1.), you will get the preface and each of the steps into an array.

Use the shift function on the Array removes the unneeded preface.

Use forEach to iterate over the values in the array, clean up the text.

Using replace to first remove commas, then remove or with spaces on either side.

Use trim to remove leading and training whitespace.

At this point, your array will have sanitized copy for use in your <li> elements.

edited Nov 21 '18 at 21:56

answered Nov 21 '18 at 20:02

CodeTheInternet

1

If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.

– Stephen P
Nov 21 '18 at 20:05

can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue

– carreankush
Nov 21 '18 at 20:23

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:34

add a comment |

function buildMessages(text) {

    let messages = text.split(/d.s/);

    messages.shift();

    messages.forEach((v)=>{

        let msg = v.replace(/,/,'').replace(/sors/,'').trim();

        $('.messages').append(`<li>${msg}</li>`);

        // console.log(`<li>${msg}</li>`);

    });

}



let sentenceToParse = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";



buildMessages(sentenceToParse);

Use the split function on the String, keying on the digits (e.g. 1.), you will get the preface and each of the steps into an array.

Use the shift function on the Array removes the unneeded preface.

Use forEach to iterate over the values in the array, clean up the text.

Using replace to first remove commas, then remove or with spaces on either side.

Use trim to remove leading and training whitespace.

At this point, your array will have sanitized copy for use in your <li> elements.

edited Nov 21 '18 at 21:56

answered Nov 21 '18 at 20:02

CodeTheInternet

1

If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.

– Stephen P
Nov 21 '18 at 20:05

can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue

– carreankush
Nov 21 '18 at 20:23

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:34

add a comment |

function buildMessages(text) {

    let messages = text.split(/d.s/);

    messages.shift();

    messages.forEach((v)=>{

        let msg = v.replace(/,/,'').replace(/sors/,'').trim();

        $('.messages').append(`<li>${msg}</li>`);

        // console.log(`<li>${msg}</li>`);

    });

}



let sentenceToParse = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";



buildMessages(sentenceToParse);

Use the split function on the String, keying on the digits (e.g. 1.), you will get the preface and each of the steps into an array.

Use the shift function on the Array removes the unneeded preface.

Use forEach to iterate over the values in the array, clean up the text.

Using replace to first remove commas, then remove or with spaces on either side.

Use trim to remove leading and training whitespace.

At this point, your array will have sanitized copy for use in your <li> elements.

edited Nov 21 '18 at 21:56

answered Nov 21 '18 at 20:02

CodeTheInternet

function buildMessages(text) {

    let messages = text.split(/d.s/);

    messages.shift();

    messages.forEach((v)=>{

        let msg = v.replace(/,/,'').replace(/sors/,'').trim();

        $('.messages').append(`<li>${msg}</li>`);

        // console.log(`<li>${msg}</li>`);

    });

}



let sentenceToParse = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)";



buildMessages(sentenceToParse);

Use the split function on the String, keying on the digits (e.g. 1.), you will get the preface and each of the steps into an array.

Use the shift function on the Array removes the unneeded preface.

Use forEach to iterate over the values in the array, clean up the text.

Using replace to first remove commas, then remove or with spaces on either side.

Use trim to remove leading and training whitespace.

At this point, your array will have sanitized copy for use in your <li> elements.

edited Nov 21 '18 at 21:56

answered Nov 21 '18 at 20:02

CodeTheInternet

edited Nov 21 '18 at 21:56

answered Nov 21 '18 at 20:02

CodeTheInternet

answered Nov 21 '18 at 20:02

CodeTheInternet

answered Nov 21 '18 at 20:02

CodeTheInternet

1

If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.

– Stephen P
Nov 21 '18 at 20:05

can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue

– carreankush
Nov 21 '18 at 20:23

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:34

add a comment |

1

If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.

– Stephen P
Nov 21 '18 at 20:05

can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue

– carreankush
Nov 21 '18 at 20:23

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:34

If you explain what you changed and why yours works this could be a good answer. As it is, a code-dump with no explanation is not particularly useful to future readers.

– Stephen P
Nov 21 '18 at 20:05

can you please use simple way,I think we need to fix only regular expression here regex = /.+(|d. w+/g; to resolve this issue

– carreankush
Nov 21 '18 at 20:23

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:34

add a comment |

Ok, Try another approach, cause regex for this isn't the best way. Try this:

$(document).ready(function() {

  // First part of sentence.

  var mainText = "Welcome to project, are you a here(";

  // Users array.

  var USERS = ['new user', 'test user', 'minor Accident', 'Major Accident'];

  var uSize = USERS.length;



  // Construct string & user list dynamically.

  for(var i = 0; i < uSize; i++) {

    var li = $('<li/>').text(USERS[i]);



    if(i === uSize - 1)

      mainText += (i+1) + ". " + USERS[i] + ")";

    else if(i === uSize - 2)

      mainText += (i+1) + ". " + USERS[i] + " or ";

    else

      mainText += (i+1) + ". " + USERS[i] + " , ";



    $(".messages").append(li);

  }

  console.log(mainText); // You will have you complete sentence.

}

Why that way is better? Simple, you can add or remove users inside the user array. String together with your user list will be updated automatically. I hope that help you.

edited Nov 22 '18 at 20:34

answered Nov 21 '18 at 20:10

Hexxefir

46849

I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major

– carreankush
Nov 21 '18 at 20:19

We need to fix only regular expression here regex = /.+(|d. w+/g;

– carreankush
Nov 21 '18 at 20:21

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:35

add a comment |

Ok, Try another approach, cause regex for this isn't the best way. Try this:

$(document).ready(function() {

  // First part of sentence.

  var mainText = "Welcome to project, are you a here(";

  // Users array.

  var USERS = ['new user', 'test user', 'minor Accident', 'Major Accident'];

  var uSize = USERS.length;



  // Construct string & user list dynamically.

  for(var i = 0; i < uSize; i++) {

    var li = $('<li/>').text(USERS[i]);



    if(i === uSize - 1)

      mainText += (i+1) + ". " + USERS[i] + ")";

    else if(i === uSize - 2)

      mainText += (i+1) + ". " + USERS[i] + " or ";

    else

      mainText += (i+1) + ". " + USERS[i] + " , ";



    $(".messages").append(li);

  }

  console.log(mainText); // You will have you complete sentence.

}

Why that way is better? Simple, you can add or remove users inside the user array. String together with your user list will be updated automatically. I hope that help you.

edited Nov 22 '18 at 20:34

answered Nov 21 '18 at 20:10

Hexxefir

46849

I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major

– carreankush
Nov 21 '18 at 20:19

We need to fix only regular expression here regex = /.+(|d. w+/g;

– carreankush
Nov 21 '18 at 20:21

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:35

add a comment |

Ok, Try another approach, cause regex for this isn't the best way. Try this:

$(document).ready(function() {

  // First part of sentence.

  var mainText = "Welcome to project, are you a here(";

  // Users array.

  var USERS = ['new user', 'test user', 'minor Accident', 'Major Accident'];

  var uSize = USERS.length;



  // Construct string & user list dynamically.

  for(var i = 0; i < uSize; i++) {

    var li = $('<li/>').text(USERS[i]);



    if(i === uSize - 1)

      mainText += (i+1) + ". " + USERS[i] + ")";

    else if(i === uSize - 2)

      mainText += (i+1) + ". " + USERS[i] + " or ";

    else

      mainText += (i+1) + ". " + USERS[i] + " , ";



    $(".messages").append(li);

  }

  console.log(mainText); // You will have you complete sentence.

}

Why that way is better? Simple, you can add or remove users inside the user array. String together with your user list will be updated automatically. I hope that help you.

edited Nov 22 '18 at 20:34

answered Nov 21 '18 at 20:10

Hexxefir

46849

Ok, Try another approach, cause regex for this isn't the best way. Try this:

$(document).ready(function() {

  // First part of sentence.

  var mainText = "Welcome to project, are you a here(";

  // Users array.

  var USERS = ['new user', 'test user', 'minor Accident', 'Major Accident'];

  var uSize = USERS.length;



  // Construct string & user list dynamically.

  for(var i = 0; i < uSize; i++) {

    var li = $('<li/>').text(USERS[i]);



    if(i === uSize - 1)

      mainText += (i+1) + ". " + USERS[i] + ")";

    else if(i === uSize - 2)

      mainText += (i+1) + ". " + USERS[i] + " or ";

    else

      mainText += (i+1) + ". " + USERS[i] + " , ";



    $(".messages").append(li);

  }

  console.log(mainText); // You will have you complete sentence.

}

Why that way is better? Simple, you can add or remove users inside the user array. String together with your user list will be updated automatically. I hope that help you.

edited Nov 22 '18 at 20:34

answered Nov 21 '18 at 20:10

Hexxefir

46849

edited Nov 22 '18 at 20:34

answered Nov 21 '18 at 20:10

Hexxefir

46849

answered Nov 21 '18 at 20:10

Hexxefir

46849

answered Nov 21 '18 at 20:10

Hexxefir

46849

I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major

– carreankush
Nov 21 '18 at 20:19

We need to fix only regular expression here regex = /.+(|d. w+/g;

– carreankush
Nov 21 '18 at 20:21

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:35

add a comment |

I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major

– carreankush
Nov 21 '18 at 20:19

We need to fix only regular expression here regex = /.+(|d. w+/g;

– carreankush
Nov 21 '18 at 20:21

We need to fix only regular expression here regex = /.+(|d. w+/g;No need to use loop here that will create problem in my application.just I need to get whole value like - Welcome to project, are you a here 1. new user 2. test user 3. minor Accident 4. Major Accident

– carreankush
Nov 21 '18 at 20:35

I replaced my script with your code $(document).ready(function() { regex = /.+(|d. w+/g; maintext = "Welcome to project, are you a here(1. new user , 2. test user , 3. minor Accident or 4. Major Accident)"; matches = maintext.match(regex); matches[0] = matches[0].slice(0, -1); $.each(matches, function(idx, match) { var li = $('<li/>').text(match); $('.messages').append(li); }); }); still I am getting same output,I am getting only first word of text inside brackets Welcome to project, are you a here 1. new 2. test 3. minor 4. Major

– carreankush
Nov 21 '18 at 20:19

We need to fix only regular expression here regex = /.+(|d. w+/g;

– carreankush
Nov 21 '18 at 20:21

add a comment |

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