How get an ArrayList return from the WebService

I have a WebService with a method returns an ArrayList with two values, and in Android I need to save in another ArrayList but when i do the .add(), gives me an ArrayList with one value [string, string].

Here is the code form the WebService method:

@WebMethod(operationName = "mostarNombre")

public ArrayList<String> mostarNombre(@WebParam(name = "id") int id) {

    String nomb = "";

    ArrayList<String> list = new ArrayList<String>();

    try {

        DriverManager.registerDriver(new OracleDriver());

        Connection cn = DriverManager.getConnection("jdbc:oracle:thin:@localhost:xxx:xxx", xxxx, xxxx);



        String query = "select * from ejemplo where id = 1";

        Statement stmt = cn.createStatement();

        ResultSet rs = stmt.executeQuery(query);



        while (rs.next()) {

            nomb = rs.getString("nombre");

            String ids = rs.getString("id");



            list.add(nomb);

            list.add(ids);

        } 



    } catch (SQLException ex) {

        Logger.getLogger(Server.class.getName()).log(Level.SEVERE, null, ex);

    }



    return list;

}

And here is the code from my method in Android:

 public void consultar(View v){

    try {

        StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitNetwork().build();



        StrictMode.setThreadPolicy(policy);



        String resultadoFINAL;



        //Creacion de la Solicitud

        SoapObject request = new SoapObject(NAMESPACE, METHOD2);



        //Creacion del Envelope

        SoapSerializationEnvelope sobre = new SoapSerializationEnvelope(SoapEnvelope.VER11);

        sobre.dotNet = true;

        sobre.setOutputSoapObject(request);



        //Creacion del transporte

        HttpTransportSE transporte = new HttpTransportSE(URL);



        // Paso de parámetro

        PropertyInfo numeroEmp = new PropertyInfo();

        numeroEmp.setName("numero");

        request.addProperty(numeroEmp);



        //Llamada

        transporte.call(SOAPACTION2, sobre);



        //Resultado

        Object resultado = (Object) sobre.getResponse();

        ArrayList<String> lista = new ArrayList<String>();

        lista.add(resultado.toString());

        String a = lista.get(0);



        tvConsulta.setText(lista.get(0));

        tvEj.setText(lista.get(1));



    }catch (Exception e) {

        e.printStackTrace();

    }

}

When I do the lista.get(0) I get one value like [string, string]. How I can solve this ?

EDIT:

The final solution is casting to Vector:

Vector lista = (Vector) sobre.getResponse();

edited Nov 23 '18 at 15:33

asked Nov 21 '18 at 19:31

Beardman

add a comment |

Here is the code form the WebService method:

@WebMethod(operationName = "mostarNombre")

public ArrayList<String> mostarNombre(@WebParam(name = "id") int id) {

    String nomb = "";

    ArrayList<String> list = new ArrayList<String>();

    try {

        DriverManager.registerDriver(new OracleDriver());

        Connection cn = DriverManager.getConnection("jdbc:oracle:thin:@localhost:xxx:xxx", xxxx, xxxx);



        String query = "select * from ejemplo where id = 1";

        Statement stmt = cn.createStatement();

        ResultSet rs = stmt.executeQuery(query);



        while (rs.next()) {

            nomb = rs.getString("nombre");

            String ids = rs.getString("id");



            list.add(nomb);

            list.add(ids);

        } 



    } catch (SQLException ex) {

        Logger.getLogger(Server.class.getName()).log(Level.SEVERE, null, ex);

    }



    return list;

}

And here is the code from my method in Android:

 public void consultar(View v){

    try {

        StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitNetwork().build();



        StrictMode.setThreadPolicy(policy);



        String resultadoFINAL;



        //Creacion de la Solicitud

        SoapObject request = new SoapObject(NAMESPACE, METHOD2);



        //Creacion del Envelope

        SoapSerializationEnvelope sobre = new SoapSerializationEnvelope(SoapEnvelope.VER11);

        sobre.dotNet = true;

        sobre.setOutputSoapObject(request);



        //Creacion del transporte

        HttpTransportSE transporte = new HttpTransportSE(URL);



        // Paso de parámetro

        PropertyInfo numeroEmp = new PropertyInfo();

        numeroEmp.setName("numero");

        request.addProperty(numeroEmp);



        //Llamada

        transporte.call(SOAPACTION2, sobre);



        //Resultado

        Object resultado = (Object) sobre.getResponse();

        ArrayList<String> lista = new ArrayList<String>();

        lista.add(resultado.toString());

        String a = lista.get(0);



        tvConsulta.setText(lista.get(0));

        tvEj.setText(lista.get(1));



    }catch (Exception e) {

        e.printStackTrace();

    }

}

When I do the lista.get(0) I get one value like [string, string]. How I can solve this ?

EDIT:

The final solution is casting to Vector:

Vector lista = (Vector) sobre.getResponse();

edited Nov 23 '18 at 15:33

asked Nov 21 '18 at 19:31

Beardman

add a comment |

Here is the code form the WebService method:

@WebMethod(operationName = "mostarNombre")

public ArrayList<String> mostarNombre(@WebParam(name = "id") int id) {

    String nomb = "";

    ArrayList<String> list = new ArrayList<String>();

    try {

        DriverManager.registerDriver(new OracleDriver());

        Connection cn = DriverManager.getConnection("jdbc:oracle:thin:@localhost:xxx:xxx", xxxx, xxxx);



        String query = "select * from ejemplo where id = 1";

        Statement stmt = cn.createStatement();

        ResultSet rs = stmt.executeQuery(query);



        while (rs.next()) {

            nomb = rs.getString("nombre");

            String ids = rs.getString("id");



            list.add(nomb);

            list.add(ids);

        } 



    } catch (SQLException ex) {

        Logger.getLogger(Server.class.getName()).log(Level.SEVERE, null, ex);

    }



    return list;

}

And here is the code from my method in Android:

 public void consultar(View v){

    try {

        StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitNetwork().build();



        StrictMode.setThreadPolicy(policy);



        String resultadoFINAL;



        //Creacion de la Solicitud

        SoapObject request = new SoapObject(NAMESPACE, METHOD2);



        //Creacion del Envelope

        SoapSerializationEnvelope sobre = new SoapSerializationEnvelope(SoapEnvelope.VER11);

        sobre.dotNet = true;

        sobre.setOutputSoapObject(request);



        //Creacion del transporte

        HttpTransportSE transporte = new HttpTransportSE(URL);



        // Paso de parámetro

        PropertyInfo numeroEmp = new PropertyInfo();

        numeroEmp.setName("numero");

        request.addProperty(numeroEmp);



        //Llamada

        transporte.call(SOAPACTION2, sobre);



        //Resultado

        Object resultado = (Object) sobre.getResponse();

        ArrayList<String> lista = new ArrayList<String>();

        lista.add(resultado.toString());

        String a = lista.get(0);



        tvConsulta.setText(lista.get(0));

        tvEj.setText(lista.get(1));



    }catch (Exception e) {

        e.printStackTrace();

    }

}

When I do the lista.get(0) I get one value like [string, string]. How I can solve this ?

EDIT:

The final solution is casting to Vector:

Vector lista = (Vector) sobre.getResponse();

edited Nov 23 '18 at 15:33

asked Nov 21 '18 at 19:31

Beardman

Here is the code form the WebService method:

@WebMethod(operationName = "mostarNombre")

public ArrayList<String> mostarNombre(@WebParam(name = "id") int id) {

    String nomb = "";

    ArrayList<String> list = new ArrayList<String>();

    try {

        DriverManager.registerDriver(new OracleDriver());

        Connection cn = DriverManager.getConnection("jdbc:oracle:thin:@localhost:xxx:xxx", xxxx, xxxx);



        String query = "select * from ejemplo where id = 1";

        Statement stmt = cn.createStatement();

        ResultSet rs = stmt.executeQuery(query);



        while (rs.next()) {

            nomb = rs.getString("nombre");

            String ids = rs.getString("id");



            list.add(nomb);

            list.add(ids);

        } 



    } catch (SQLException ex) {

        Logger.getLogger(Server.class.getName()).log(Level.SEVERE, null, ex);

    }



    return list;

}

And here is the code from my method in Android:

 public void consultar(View v){

    try {

        StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitNetwork().build();



        StrictMode.setThreadPolicy(policy);



        String resultadoFINAL;



        //Creacion de la Solicitud

        SoapObject request = new SoapObject(NAMESPACE, METHOD2);



        //Creacion del Envelope

        SoapSerializationEnvelope sobre = new SoapSerializationEnvelope(SoapEnvelope.VER11);

        sobre.dotNet = true;

        sobre.setOutputSoapObject(request);



        //Creacion del transporte

        HttpTransportSE transporte = new HttpTransportSE(URL);



        // Paso de parámetro

        PropertyInfo numeroEmp = new PropertyInfo();

        numeroEmp.setName("numero");

        request.addProperty(numeroEmp);



        //Llamada

        transporte.call(SOAPACTION2, sobre);



        //Resultado

        Object resultado = (Object) sobre.getResponse();

        ArrayList<String> lista = new ArrayList<String>();

        lista.add(resultado.toString());

        String a = lista.get(0);



        tvConsulta.setText(lista.get(0));

        tvEj.setText(lista.get(1));



    }catch (Exception e) {

        e.printStackTrace();

    }

}

When I do the lista.get(0) I get one value like [string, string]. How I can solve this ?

EDIT:

The final solution is casting to Vector:

Vector lista = (Vector) sobre.getResponse();

java android

edited Nov 23 '18 at 15:33

asked Nov 21 '18 at 19:31

Beardman

edited Nov 23 '18 at 15:33

asked Nov 21 '18 at 19:31

Beardman

edited Nov 23 '18 at 15:33

asked Nov 21 '18 at 19:31

Beardman

asked Nov 21 '18 at 19:31

Beardman

asked Nov 21 '18 at 19:31

Beardman

add a comment |

1 Answer
1

active

oldest

votes

lista.add(resultado.toString());

first you have to understand what toString do.
toString method return the refrence of object by default if you not override it.That why its store only one value that is reference of array list return from webservice.

do this

1- if its return array list then assign it in arraylist directly.
eg
ArrayList<String> lista=sobre.getResponse();

2- just iterate over result and add in list.there are a no of way to iterate over list.i use simple for each loop.

for(String value:resultdo){

lista.add(value);

}

answered Nov 21 '18 at 19:47

jogendra

945

I can't do ArrayList<String> lista = sobre.getResponse(); Incompatible types, required ArrayList, found Object

– Beardman
Nov 21 '18 at 20:08

As i see your method is returning ArrayList<String> @WebMethod(operationName = "mostarNombre") public ArrayList<String> mostarNombre(@WebParam(name = "id") int id) {} try to cast it explicitly using ArrayList<String> lista = (ArrayList<String>)sobre.getResponse();

– jogendra
Nov 23 '18 at 4:33

Thaaaanks for the idea of cast, but the final solution was Vector lista = (Vector)sobre.getResponse();

– Beardman
Nov 23 '18 at 15:32

add a comment |

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1 Answer
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oldest

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lista.add(resultado.toString());

do this

1- if its return array list then assign it in arraylist directly.
eg
ArrayList<String> lista=sobre.getResponse();

2- just iterate over result and add in list.there are a no of way to iterate over list.i use simple for each loop.

for(String value:resultdo){

lista.add(value);

}

answered Nov 21 '18 at 19:47

jogendra

945

I can't do ArrayList<String> lista = sobre.getResponse(); Incompatible types, required ArrayList, found Object

– Beardman
Nov 21 '18 at 20:08

As i see your method is returning ArrayList<String> @WebMethod(operationName = "mostarNombre") public ArrayList<String> mostarNombre(@WebParam(name = "id") int id) {} try to cast it explicitly using ArrayList<String> lista = (ArrayList<String>)sobre.getResponse();

– jogendra
Nov 23 '18 at 4:33

Thaaaanks for the idea of cast, but the final solution was Vector lista = (Vector)sobre.getResponse();

– Beardman
Nov 23 '18 at 15:32

add a comment |

lista.add(resultado.toString());

do this

1- if its return array list then assign it in arraylist directly.
eg
ArrayList<String> lista=sobre.getResponse();

2- just iterate over result and add in list.there are a no of way to iterate over list.i use simple for each loop.

for(String value:resultdo){

lista.add(value);

}

answered Nov 21 '18 at 19:47

jogendra

945

I can't do ArrayList<String> lista = sobre.getResponse(); Incompatible types, required ArrayList, found Object

– Beardman
Nov 21 '18 at 20:08

As i see your method is returning ArrayList<String> @WebMethod(operationName = "mostarNombre") public ArrayList<String> mostarNombre(@WebParam(name = "id") int id) {} try to cast it explicitly using ArrayList<String> lista = (ArrayList<String>)sobre.getResponse();

– jogendra
Nov 23 '18 at 4:33

Thaaaanks for the idea of cast, but the final solution was Vector lista = (Vector)sobre.getResponse();

– Beardman
Nov 23 '18 at 15:32

add a comment |

lista.add(resultado.toString());

do this

1- if its return array list then assign it in arraylist directly.
eg
ArrayList<String> lista=sobre.getResponse();

2- just iterate over result and add in list.there are a no of way to iterate over list.i use simple for each loop.

for(String value:resultdo){

lista.add(value);

}

answered Nov 21 '18 at 19:47

jogendra

945

lista.add(resultado.toString());

do this

1- if its return array list then assign it in arraylist directly.
eg
ArrayList<String> lista=sobre.getResponse();

2- just iterate over result and add in list.there are a no of way to iterate over list.i use simple for each loop.

for(String value:resultdo){

lista.add(value);

}

answered Nov 21 '18 at 19:47

jogendra

945

answered Nov 21 '18 at 19:47

jogendra

945

answered Nov 21 '18 at 19:47

jogendra

945

answered Nov 21 '18 at 19:47

jogendra

945

I can't do ArrayList<String> lista = sobre.getResponse(); Incompatible types, required ArrayList, found Object

– Beardman
Nov 21 '18 at 20:08

As i see your method is returning ArrayList<String> @WebMethod(operationName = "mostarNombre") public ArrayList<String> mostarNombre(@WebParam(name = "id") int id) {} try to cast it explicitly using ArrayList<String> lista = (ArrayList<String>)sobre.getResponse();

– jogendra
Nov 23 '18 at 4:33

Thaaaanks for the idea of cast, but the final solution was Vector lista = (Vector)sobre.getResponse();

– Beardman
Nov 23 '18 at 15:32

add a comment |

I can't do ArrayList<String> lista = sobre.getResponse(); Incompatible types, required ArrayList, found Object

– Beardman
Nov 21 '18 at 20:08

As i see your method is returning ArrayList<String> @WebMethod(operationName = "mostarNombre") public ArrayList<String> mostarNombre(@WebParam(name = "id") int id) {} try to cast it explicitly using ArrayList<String> lista = (ArrayList<String>)sobre.getResponse();

– jogendra
Nov 23 '18 at 4:33

Thaaaanks for the idea of cast, but the final solution was Vector lista = (Vector)sobre.getResponse();

– Beardman
Nov 23 '18 at 15:32

I can't do ArrayList<String> lista = sobre.getResponse(); Incompatible types, required ArrayList, found Object

– Beardman
Nov 21 '18 at 20:08

As i see your method is returning ArrayList<String> @WebMethod(operationName = "mostarNombre") public ArrayList<String> mostarNombre(@WebParam(name = "id") int id) {} try to cast it explicitly using ArrayList<String> lista = (ArrayList<String>)sobre.getResponse();

– jogendra
Nov 23 '18 at 4:33

Thaaaanks for the idea of cast, but the final solution was Vector lista = (Vector)sobre.getResponse();

– Beardman
Nov 23 '18 at 15:32

add a comment |

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