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How to use PyMongo find() to search nested array attribute?
Using PyMongo, how would one find/search for the documents where the nested array json object matches a given string.
Given the following 2 Product JSON documents in a MongoDB collection..
[{
"_id" : ObjectId("5be1a1b2aa21bb3ceac339b0"),
"id" : "1",
"prod_attr" : [
{
"name" : "Branded X 1 Sneaker"
},
{
"hierarchy" : {
"dept" : "10",
"class" : "101",
"subclass" : "1011"
}
}
]
},
{
"_id" : ObjectId("7be1a1b2aa21bb3ceac339xx"),
"id" : "2",
"prod_attr" : [
{
"name" : "Branded Y 2 Sneaker"
},
{
"hierarchy" : {
"dept" : "10",
"class" : "101",
"subclass" : "2022"
}
}
]
}
]
I would like to
1. return all documents where prod_att.hierarchy.subclass = "2022"
2. return all documents where prod_attr.name contains "Sneaker"
I appreciate the JSON could be structured differently, unfortunately that is not within my control to change.
python json mongodb pymongo
asked Nov 21 '18 at 15:30
user3927078user3927078
294
add a comment |
Using PyMongo, how would one find/search for the documents where the nested array json object matches a given string.
Given the following 2 Product JSON documents in a MongoDB collection..
[{
"_id" : ObjectId("5be1a1b2aa21bb3ceac339b0"),
"id" : "1",
"prod_attr" : [
{
"name" : "Branded X 1 Sneaker"
},
{
"hierarchy" : {
"dept" : "10",
"class" : "101",
"subclass" : "1011"
}
}
]
},
{
"_id" : ObjectId("7be1a1b2aa21bb3ceac339xx"),
"id" : "2",
"prod_attr" : [
{
"name" : "Branded Y 2 Sneaker"
},
{
"hierarchy" : {
"dept" : "10",
"class" : "101",
"subclass" : "2022"
}
}
]
}
]
I would like to
1. return all documents where prod_att.hierarchy.subclass = "2022"
2. return all documents where prod_attr.name contains "Sneaker"
I appreciate the JSON could be structured differently, unfortunately that is not within my control to change.
python json mongodb pymongo
asked Nov 21 '18 at 15:30
user3927078user3927078
294
add a comment |
Using PyMongo, how would one find/search for the documents where the nested array json object matches a given string.
Given the following 2 Product JSON documents in a MongoDB collection..
[{
"_id" : ObjectId("5be1a1b2aa21bb3ceac339b0"),
"id" : "1",
"prod_attr" : [
{
"name" : "Branded X 1 Sneaker"
},
{
"hierarchy" : {
"dept" : "10",
"class" : "101",
"subclass" : "1011"
}
}
]
},
{
"_id" : ObjectId("7be1a1b2aa21bb3ceac339xx"),
"id" : "2",
"prod_attr" : [
{
"name" : "Branded Y 2 Sneaker"
},
{
"hierarchy" : {
"dept" : "10",
"class" : "101",
"subclass" : "2022"
}
}
]
}
]
I would like to
1. return all documents where prod_att.hierarchy.subclass = "2022"
2. return all documents where prod_attr.name contains "Sneaker"
I appreciate the JSON could be structured differently, unfortunately that is not within my control to change.
python json mongodb pymongo
asked Nov 21 '18 at 15:30
user3927078user3927078
294
Using PyMongo, how would one find/search for the documents where the nested array json object matches a given string.
Given the following 2 Product JSON documents in a MongoDB collection..
[{
"_id" : ObjectId("5be1a1b2aa21bb3ceac339b0"),
"id" : "1",
"prod_attr" : [
{
"name" : "Branded X 1 Sneaker"
},
{
"hierarchy" : {
"dept" : "10",
"class" : "101",
"subclass" : "1011"
}
}
]
},
{
"_id" : ObjectId("7be1a1b2aa21bb3ceac339xx"),
"id" : "2",
"prod_attr" : [
{
"name" : "Branded Y 2 Sneaker"
},
{
"hierarchy" : {
"dept" : "10",
"class" : "101",
"subclass" : "2022"
}
}
]
}
]
I would like to
1. return all documents where prod_att.hierarchy.subclass = "2022"
2. return all documents where prod_attr.name contains "Sneaker"
I appreciate the JSON could be structured differently, unfortunately that is not within my control to change.
python json mongodb pymongo
python json mongodb pymongo
asked Nov 21 '18 at 15:30
user3927078user3927078
294
asked Nov 21 '18 at 15:30
user3927078user3927078
294
asked Nov 21 '18 at 15:30
user3927078user3927078
294
asked Nov 21 '18 at 15:30
user3927078user3927078
294
asked Nov 21 '18 at 15:30
user3927078user3927078
294
294
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1. Return all documents where prod_attr.hierarchy.subclass = "2022"
Based on the Query an Array of Embedded Documents documentation of MongoDB you can use dot notation concatenating the name of the array field (prod_attr), with a dot (.) and the name of the field in the nested document (hierarchy.subclass):
collection.find({"prod_attr.hierarchy.subclass": "2022"})
2. Return all documents where prod_attr.name contains "Sneaker"
As before, you can use the dot notation to query a field of a nested element inside an array.
To perform the "contains" query you have to use the $regex operator:
collection.find({"prod_attr.name": {"$regex": "Sneaker"}})
Another option is to use the MongoDB Aggregation framework:
collection.aggregate([
{"$unwind": "$prod_attr"},
{"$match": {"prod_attr.hierarchy.subclass": "2022"}}
])
the $unwind operator creates a new object for each object inside the prod_attr array, so you will have only nested documents and no array (check the documentation for details).
The next step is the $match operator that actually perform a query on the nested object.
This is a simple example but playing with the Aggregators Operators you have a lot of flexibility.
answered Nov 21 '18 at 16:10
vinscevinsce
14511
great response - thanks
– user3927078
Nov 30 '18 at 11:20
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1. Return all documents where prod_attr.hierarchy.subclass = "2022"
Based on the Query an Array of Embedded Documents documentation of MongoDB you can use dot notation concatenating the name of the array field (prod_attr), with a dot (.) and the name of the field in the nested document (hierarchy.subclass):
collection.find({"prod_attr.hierarchy.subclass": "2022"})
2. Return all documents where prod_attr.name contains "Sneaker"
As before, you can use the dot notation to query a field of a nested element inside an array.
To perform the "contains" query you have to use the $regex operator:
collection.find({"prod_attr.name": {"$regex": "Sneaker"}})
Another option is to use the MongoDB Aggregation framework:
collection.aggregate([
{"$unwind": "$prod_attr"},
{"$match": {"prod_attr.hierarchy.subclass": "2022"}}
])
the $unwind operator creates a new object for each object inside the prod_attr array, so you will have only nested documents and no array (check the documentation for details).
The next step is the $match operator that actually perform a query on the nested object.
This is a simple example but playing with the Aggregators Operators you have a lot of flexibility.
answered Nov 21 '18 at 16:10
vinscevinsce
14511
great response - thanks
– user3927078
Nov 30 '18 at 11:20
add a comment |
1. Return all documents where prod_attr.hierarchy.subclass = "2022"
Based on the Query an Array of Embedded Documents documentation of MongoDB you can use dot notation concatenating the name of the array field (prod_attr), with a dot (.) and the name of the field in the nested document (hierarchy.subclass):
collection.find({"prod_attr.hierarchy.subclass": "2022"})
2. Return all documents where prod_attr.name contains "Sneaker"
As before, you can use the dot notation to query a field of a nested element inside an array.
To perform the "contains" query you have to use the $regex operator:
collection.find({"prod_attr.name": {"$regex": "Sneaker"}})
Another option is to use the MongoDB Aggregation framework:
collection.aggregate([
{"$unwind": "$prod_attr"},
{"$match": {"prod_attr.hierarchy.subclass": "2022"}}
])
the $unwind operator creates a new object for each object inside the prod_attr array, so you will have only nested documents and no array (check the documentation for details).
The next step is the $match operator that actually perform a query on the nested object.
This is a simple example but playing with the Aggregators Operators you have a lot of flexibility.
answered Nov 21 '18 at 16:10
vinscevinsce
14511
great response - thanks
– user3927078
Nov 30 '18 at 11:20
add a comment |
1. Return all documents where prod_attr.hierarchy.subclass = "2022"
Based on the Query an Array of Embedded Documents documentation of MongoDB you can use dot notation concatenating the name of the array field (prod_attr), with a dot (.) and the name of the field in the nested document (hierarchy.subclass):
collection.find({"prod_attr.hierarchy.subclass": "2022"})
2. Return all documents where prod_attr.name contains "Sneaker"
As before, you can use the dot notation to query a field of a nested element inside an array.
To perform the "contains" query you have to use the $regex operator:
collection.find({"prod_attr.name": {"$regex": "Sneaker"}})
Another option is to use the MongoDB Aggregation framework:
collection.aggregate([
{"$unwind": "$prod_attr"},
{"$match": {"prod_attr.hierarchy.subclass": "2022"}}
])
the $unwind operator creates a new object for each object inside the prod_attr array, so you will have only nested documents and no array (check the documentation for details).
The next step is the $match operator that actually perform a query on the nested object.
This is a simple example but playing with the Aggregators Operators you have a lot of flexibility.
answered Nov 21 '18 at 16:10
vinscevinsce
14511
1. Return all documents where prod_attr.hierarchy.subclass = "2022"
Based on the Query an Array of Embedded Documents documentation of MongoDB you can use dot notation concatenating the name of the array field (prod_attr), with a dot (.) and the name of the field in the nested document (hierarchy.subclass):
collection.find({"prod_attr.hierarchy.subclass": "2022"})
2. Return all documents where prod_attr.name contains "Sneaker"
As before, you can use the dot notation to query a field of a nested element inside an array.
To perform the "contains" query you have to use the $regex operator:
collection.find({"prod_attr.name": {"$regex": "Sneaker"}})
Another option is to use the MongoDB Aggregation framework:
collection.aggregate([
{"$unwind": "$prod_attr"},
{"$match": {"prod_attr.hierarchy.subclass": "2022"}}
])
the $unwind operator creates a new object for each object inside the prod_attr array, so you will have only nested documents and no array (check the documentation for details).
The next step is the $match operator that actually perform a query on the nested object.
This is a simple example but playing with the Aggregators Operators you have a lot of flexibility.
answered Nov 21 '18 at 16:10
vinscevinsce
14511
edited Nov 21 '18 at 16:29
answered Nov 21 '18 at 16:10
vinscevinsce
14511
answered Nov 21 '18 at 16:10
vinscevinsce
14511
answered Nov 21 '18 at 16:10
vinscevinsce
14511
14511
great response - thanks
– user3927078
Nov 30 '18 at 11:20
add a comment |
great response - thanks
– user3927078
Nov 30 '18 at 11:20
great response - thanks
– user3927078
Nov 30 '18 at 11:20
great response - thanks
– user3927078
Nov 30 '18 at 11:20
add a comment |
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