Mixing
React + Redux-Observable + Typescript - Compilation, Argument Not Assignable Error
I am creating an app using React and Redux-Observable. I am new to this and I am trying to create an epic to execute the user login.
My epic is below:
export const loginUserEpic = (action$: ActionsObservable<Action>) =>
action$.pipe(
ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION),
switchMap((action: LoginAction) =>
ajax({
url,
method: 'POST',
headers: { 'Content-Type': 'application/json' },
body: { email: action.payload.username, password: action.payload.password },
}).pipe(
map((response: AjaxResponse) => loginSuccess(response.response.token)),
catchError((error: Error) => of(loginFailed(error))),
),
),
);
The problema is that I am getting a Typescript error on this line: ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION) saying this:
Argument of type '(source: Observable<LoginAction>) => Observable<LoginAction>' is not assignable to parameter of type 'OperatorFunction<Action<any>, LoginAction>'.
Types of parameters 'source' and 'source' are incompatible.
Type 'Observable<Action<any>>' is not assignable to type 'Observable<LoginAction>'.
Type 'Action<any>' is not assignable to type 'LoginAction'.
Property 'payload' is missing in type 'Action<any>'.
My actions are here:
export enum LoginActionTypes {
LOGIN_ACTION = 'login',
LOGIN_SUCCESS_ACTION = 'login-sucesss',
LOGIN_FAILED_ACTION = 'login-failed',
}
export interface LoginAction extends Action {
type: LoginActionTypes.LOGIN_ACTION;
payload: {
username: string;
password: string;
};
}
export function login(username: string, password: string): LoginAction {
return {
type: LoginActionTypes.LOGIN_ACTION,
payload: { username, password },
};
}
export interface LoginSuccessAction extends Action {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION;
payload: {
loginToken: string;
};
}
export function loginSuccess(loginToken: string): LoginSuccessAction {
return {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION,
payload: { loginToken },
};
}
export interface LoginFailedAction extends Action {
type: LoginActionTypes.LOGIN_FAILED_ACTION;
payload: {
error: Error;
};
}
export function loginFailed(error: Error): LoginFailedAction {
return {
type: LoginActionTypes.LOGIN_FAILED_ACTION,
payload: { error },
};
}
export type LoginActions = LoginAction | LoginSuccessAction | LoginFailedAction;
How can I fix this without using any types on the Epic?
reactjs typescript rxjs redux-observable
asked Nov 21 '18 at 15:28
FelipeFelipe
1,21911731
add a comment |
I am creating an app using React and Redux-Observable. I am new to this and I am trying to create an epic to execute the user login.
My epic is below:
export const loginUserEpic = (action$: ActionsObservable<Action>) =>
action$.pipe(
ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION),
switchMap((action: LoginAction) =>
ajax({
url,
method: 'POST',
headers: { 'Content-Type': 'application/json' },
body: { email: action.payload.username, password: action.payload.password },
}).pipe(
map((response: AjaxResponse) => loginSuccess(response.response.token)),
catchError((error: Error) => of(loginFailed(error))),
),
),
);
The problema is that I am getting a Typescript error on this line: ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION) saying this:
Argument of type '(source: Observable<LoginAction>) => Observable<LoginAction>' is not assignable to parameter of type 'OperatorFunction<Action<any>, LoginAction>'.
Types of parameters 'source' and 'source' are incompatible.
Type 'Observable<Action<any>>' is not assignable to type 'Observable<LoginAction>'.
Type 'Action<any>' is not assignable to type 'LoginAction'.
Property 'payload' is missing in type 'Action<any>'.
My actions are here:
export enum LoginActionTypes {
LOGIN_ACTION = 'login',
LOGIN_SUCCESS_ACTION = 'login-sucesss',
LOGIN_FAILED_ACTION = 'login-failed',
}
export interface LoginAction extends Action {
type: LoginActionTypes.LOGIN_ACTION;
payload: {
username: string;
password: string;
};
}
export function login(username: string, password: string): LoginAction {
return {
type: LoginActionTypes.LOGIN_ACTION,
payload: { username, password },
};
}
export interface LoginSuccessAction extends Action {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION;
payload: {
loginToken: string;
};
}
export function loginSuccess(loginToken: string): LoginSuccessAction {
return {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION,
payload: { loginToken },
};
}
export interface LoginFailedAction extends Action {
type: LoginActionTypes.LOGIN_FAILED_ACTION;
payload: {
error: Error;
};
}
export function loginFailed(error: Error): LoginFailedAction {
return {
type: LoginActionTypes.LOGIN_FAILED_ACTION,
payload: { error },
};
}
export type LoginActions = LoginAction | LoginSuccessAction | LoginFailedAction;
How can I fix this without using any types on the Epic?
reactjs typescript rxjs redux-observable
asked Nov 21 '18 at 15:28
FelipeFelipe
1,21911731
add a comment |
I am creating an app using React and Redux-Observable. I am new to this and I am trying to create an epic to execute the user login.
My epic is below:
export const loginUserEpic = (action$: ActionsObservable<Action>) =>
action$.pipe(
ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION),
switchMap((action: LoginAction) =>
ajax({
url,
method: 'POST',
headers: { 'Content-Type': 'application/json' },
body: { email: action.payload.username, password: action.payload.password },
}).pipe(
map((response: AjaxResponse) => loginSuccess(response.response.token)),
catchError((error: Error) => of(loginFailed(error))),
),
),
);
The problema is that I am getting a Typescript error on this line: ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION) saying this:
Argument of type '(source: Observable<LoginAction>) => Observable<LoginAction>' is not assignable to parameter of type 'OperatorFunction<Action<any>, LoginAction>'.
Types of parameters 'source' and 'source' are incompatible.
Type 'Observable<Action<any>>' is not assignable to type 'Observable<LoginAction>'.
Type 'Action<any>' is not assignable to type 'LoginAction'.
Property 'payload' is missing in type 'Action<any>'.
My actions are here:
export enum LoginActionTypes {
LOGIN_ACTION = 'login',
LOGIN_SUCCESS_ACTION = 'login-sucesss',
LOGIN_FAILED_ACTION = 'login-failed',
}
export interface LoginAction extends Action {
type: LoginActionTypes.LOGIN_ACTION;
payload: {
username: string;
password: string;
};
}
export function login(username: string, password: string): LoginAction {
return {
type: LoginActionTypes.LOGIN_ACTION,
payload: { username, password },
};
}
export interface LoginSuccessAction extends Action {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION;
payload: {
loginToken: string;
};
}
export function loginSuccess(loginToken: string): LoginSuccessAction {
return {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION,
payload: { loginToken },
};
}
export interface LoginFailedAction extends Action {
type: LoginActionTypes.LOGIN_FAILED_ACTION;
payload: {
error: Error;
};
}
export function loginFailed(error: Error): LoginFailedAction {
return {
type: LoginActionTypes.LOGIN_FAILED_ACTION,
payload: { error },
};
}
export type LoginActions = LoginAction | LoginSuccessAction | LoginFailedAction;
How can I fix this without using any types on the Epic?
reactjs typescript rxjs redux-observable
asked Nov 21 '18 at 15:28
FelipeFelipe
1,21911731
I am creating an app using React and Redux-Observable. I am new to this and I am trying to create an epic to execute the user login.
My epic is below:
export const loginUserEpic = (action$: ActionsObservable<Action>) =>
action$.pipe(
ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION),
switchMap((action: LoginAction) =>
ajax({
url,
method: 'POST',
headers: { 'Content-Type': 'application/json' },
body: { email: action.payload.username, password: action.payload.password },
}).pipe(
map((response: AjaxResponse) => loginSuccess(response.response.token)),
catchError((error: Error) => of(loginFailed(error))),
),
),
);
The problema is that I am getting a Typescript error on this line: ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION) saying this:
Argument of type '(source: Observable<LoginAction>) => Observable<LoginAction>' is not assignable to parameter of type 'OperatorFunction<Action<any>, LoginAction>'.
Types of parameters 'source' and 'source' are incompatible.
Type 'Observable<Action<any>>' is not assignable to type 'Observable<LoginAction>'.
Type 'Action<any>' is not assignable to type 'LoginAction'.
Property 'payload' is missing in type 'Action<any>'.
My actions are here:
export enum LoginActionTypes {
LOGIN_ACTION = 'login',
LOGIN_SUCCESS_ACTION = 'login-sucesss',
LOGIN_FAILED_ACTION = 'login-failed',
}
export interface LoginAction extends Action {
type: LoginActionTypes.LOGIN_ACTION;
payload: {
username: string;
password: string;
};
}
export function login(username: string, password: string): LoginAction {
return {
type: LoginActionTypes.LOGIN_ACTION,
payload: { username, password },
};
}
export interface LoginSuccessAction extends Action {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION;
payload: {
loginToken: string;
};
}
export function loginSuccess(loginToken: string): LoginSuccessAction {
return {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION,
payload: { loginToken },
};
}
export interface LoginFailedAction extends Action {
type: LoginActionTypes.LOGIN_FAILED_ACTION;
payload: {
error: Error;
};
}
export function loginFailed(error: Error): LoginFailedAction {
return {
type: LoginActionTypes.LOGIN_FAILED_ACTION,
payload: { error },
};
}
export type LoginActions = LoginAction | LoginSuccessAction | LoginFailedAction;
How can I fix this without using any types on the Epic?
reactjs typescript rxjs redux-observable
reactjs typescript rxjs redux-observable
asked Nov 21 '18 at 15:28
FelipeFelipe
1,21911731
asked Nov 21 '18 at 15:28
FelipeFelipe
1,21911731
asked Nov 21 '18 at 15:28
FelipeFelipe
1,21911731
asked Nov 21 '18 at 15:28
FelipeFelipe
1,21911731
asked Nov 21 '18 at 15:28
FelipeFelipe
1,21911731
1,21911731
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
The ofType operator offered by redux-observable is not the best way to discriminate union types. A much better way is to use the isOfType function provided by typesafe-actions.
import { filter } from 'rxjs/operators';
import { isOfType } from 'typesafe-actions';
First, let's tell TypeScript about the possible actions used in your application. Your action stream should not be defined as ActionsObservable<Action>, but as a stream of your actions: ActionsObservable<LoginActions>.
export const loginUserEpic = (action$: ActionsObservable<LoginActions>) =>
Now we can use the isOfType predicate together with the filter operator. Replace this:
ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION)
with this:
filter(isOfType(LoginActionTypes.LOGIN_ACTION))
The action passed down the stream will be correctly recognized as LoginAction.
answered Jan 20 at 18:02
Karol MajewskiKarol Majewski
3,156213
add a comment |
You can checkout https://github.com/piotrwitek/react-redux-typescript-guide for the details in here for all the standard way of doing when using React, Redux and Redux-Observable.
I would suggest using typesafe-actions library to achieve the types.
Some pseudo codes:
Actions
Instead of this
export interface LoginSuccessAction extends Action {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION;
payload: {
loginToken: string;
};
}
export function loginSuccess(loginToken: string): LoginSuccessAction {
return {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION,
payload: { loginToken },
};
}
use typesafe-actions, without interface
actions/login/LoginActions.ts
import {action} from "typesafe-actions"
export function loginSuccess(loginToken: string) {
return action(LoginActionTypes.LOGIN_SUCCESS_ACTION, { loginToken });
}
actions/login/LoginActionsModel.ts
import * LoginActions from "./LoginActions";
import { ActionCreator } from "typesafe-actions";
export type LoginActionCreator = ActionCreator<typeof LoginActions>
Then export out All Actions.
actions/index.ts
import { LoginActionCreator } from "./login/LoginActionModel";
export default type AllActions = LoginActionCreator
Epics
import { Epic } from "redux-observable";
import { isOfType } from "typesafe-actions";
import { filter } from "rxjs/operators";
export const loginUserEpic: Epic<AllActions> = (action$) =>
action$.pipe(
filter(isOfType((LoginActionTypes.LOGIN_ACTION))),
switchMap((action: LoginAction) =>
ajax({
url,
method: 'POST',
headers: { 'Content-Type': 'application/json' },
body: { email: action.payload.username, password: action.payload.password },
}).pipe(
map((response: AjaxResponse) => loginSuccess(response.response.token)),
catchError((error: Error) => of(loginFailed(error))),
),
),
);
Where the Epics is from redux-observable library, AllActions are the actions that is input and output of the epics.
The types is as follows:
Epic<InputActions, OutputActions, Store>
Epic<Actions(Input&Output)>
In case you want to use store from redux, you need a RootState (from root reducer)
export const someEpic: Epic<AllActions, AllActions, RootState> = (action$, store$)
=> action$.pipe(
filter(isOfType(SOMETYPE)),
mergeMap(action => {
const a = store$.value.a;
return someActions(a, action.payload.b);
})
answered Jan 22 at 10:32
johnson laijohnson lai
194110
add a comment |
Typescript gives an error because you have set to ActionsObservable action generic a redux Action that is an interface with form of { type: string }. So Typescript thinks that all the actions coming will have only type, but you are setting to ofType filtering operator another type of Action, even if it extends redux Action interface Typescript will require bivarianceHack to allow you pass anything that implements that interface. One of the simplest workarounds is to change ActionsObservable<Action> to ActionsObservable<AnyAction>, with AnyAction which is imported from redux.
answered Jan 25 at 6:49
iamawebgeekiamawebgeek
1,325728
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
The ofType operator offered by redux-observable is not the best way to discriminate union types. A much better way is to use the isOfType function provided by typesafe-actions.
import { filter } from 'rxjs/operators';
import { isOfType } from 'typesafe-actions';
First, let's tell TypeScript about the possible actions used in your application. Your action stream should not be defined as ActionsObservable<Action>, but as a stream of your actions: ActionsObservable<LoginActions>.
export const loginUserEpic = (action$: ActionsObservable<LoginActions>) =>
Now we can use the isOfType predicate together with the filter operator. Replace this:
ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION)
with this:
filter(isOfType(LoginActionTypes.LOGIN_ACTION))
The action passed down the stream will be correctly recognized as LoginAction.
answered Jan 20 at 18:02
Karol MajewskiKarol Majewski
3,156213
add a comment |
The ofType operator offered by redux-observable is not the best way to discriminate union types. A much better way is to use the isOfType function provided by typesafe-actions.
import { filter } from 'rxjs/operators';
import { isOfType } from 'typesafe-actions';
First, let's tell TypeScript about the possible actions used in your application. Your action stream should not be defined as ActionsObservable<Action>, but as a stream of your actions: ActionsObservable<LoginActions>.
export const loginUserEpic = (action$: ActionsObservable<LoginActions>) =>
Now we can use the isOfType predicate together with the filter operator. Replace this:
ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION)
with this:
filter(isOfType(LoginActionTypes.LOGIN_ACTION))
The action passed down the stream will be correctly recognized as LoginAction.
answered Jan 20 at 18:02
Karol MajewskiKarol Majewski
3,156213
add a comment |
The ofType operator offered by redux-observable is not the best way to discriminate union types. A much better way is to use the isOfType function provided by typesafe-actions.
import { filter } from 'rxjs/operators';
import { isOfType } from 'typesafe-actions';
First, let's tell TypeScript about the possible actions used in your application. Your action stream should not be defined as ActionsObservable<Action>, but as a stream of your actions: ActionsObservable<LoginActions>.
export const loginUserEpic = (action$: ActionsObservable<LoginActions>) =>
Now we can use the isOfType predicate together with the filter operator. Replace this:
ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION)
with this:
filter(isOfType(LoginActionTypes.LOGIN_ACTION))
The action passed down the stream will be correctly recognized as LoginAction.
answered Jan 20 at 18:02
Karol MajewskiKarol Majewski
3,156213
The ofType operator offered by redux-observable is not the best way to discriminate union types. A much better way is to use the isOfType function provided by typesafe-actions.
import { filter } from 'rxjs/operators';
import { isOfType } from 'typesafe-actions';
First, let's tell TypeScript about the possible actions used in your application. Your action stream should not be defined as ActionsObservable<Action>, but as a stream of your actions: ActionsObservable<LoginActions>.
export const loginUserEpic = (action$: ActionsObservable<LoginActions>) =>
Now we can use the isOfType predicate together with the filter operator. Replace this:
ofType<LoginAction>(LoginActionTypes.LOGIN_ACTION)
with this:
filter(isOfType(LoginActionTypes.LOGIN_ACTION))
The action passed down the stream will be correctly recognized as LoginAction.
answered Jan 20 at 18:02
Karol MajewskiKarol Majewski
3,156213
answered Jan 20 at 18:02
Karol MajewskiKarol Majewski
3,156213
answered Jan 20 at 18:02
Karol MajewskiKarol Majewski
3,156213
answered Jan 20 at 18:02
Karol MajewskiKarol Majewski
3,156213
3,156213
add a comment |
add a comment |
You can checkout https://github.com/piotrwitek/react-redux-typescript-guide for the details in here for all the standard way of doing when using React, Redux and Redux-Observable.
I would suggest using typesafe-actions library to achieve the types.
Some pseudo codes:
Actions
Instead of this
export interface LoginSuccessAction extends Action {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION;
payload: {
loginToken: string;
};
}
export function loginSuccess(loginToken: string): LoginSuccessAction {
return {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION,
payload: { loginToken },
};
}
use typesafe-actions, without interface
actions/login/LoginActions.ts
import {action} from "typesafe-actions"
export function loginSuccess(loginToken: string) {
return action(LoginActionTypes.LOGIN_SUCCESS_ACTION, { loginToken });
}
actions/login/LoginActionsModel.ts
import * LoginActions from "./LoginActions";
import { ActionCreator } from "typesafe-actions";
export type LoginActionCreator = ActionCreator<typeof LoginActions>
Then export out All Actions.
actions/index.ts
import { LoginActionCreator } from "./login/LoginActionModel";
export default type AllActions = LoginActionCreator
Epics
import { Epic } from "redux-observable";
import { isOfType } from "typesafe-actions";
import { filter } from "rxjs/operators";
export const loginUserEpic: Epic<AllActions> = (action$) =>
action$.pipe(
filter(isOfType((LoginActionTypes.LOGIN_ACTION))),
switchMap((action: LoginAction) =>
ajax({
url,
method: 'POST',
headers: { 'Content-Type': 'application/json' },
body: { email: action.payload.username, password: action.payload.password },
}).pipe(
map((response: AjaxResponse) => loginSuccess(response.response.token)),
catchError((error: Error) => of(loginFailed(error))),
),
),
);
Where the Epics is from redux-observable library, AllActions are the actions that is input and output of the epics.
The types is as follows:
Epic<InputActions, OutputActions, Store>
Epic<Actions(Input&Output)>
In case you want to use store from redux, you need a RootState (from root reducer)
export const someEpic: Epic<AllActions, AllActions, RootState> = (action$, store$)
=> action$.pipe(
filter(isOfType(SOMETYPE)),
mergeMap(action => {
const a = store$.value.a;
return someActions(a, action.payload.b);
})
answered Jan 22 at 10:32
johnson laijohnson lai
194110
add a comment |
You can checkout https://github.com/piotrwitek/react-redux-typescript-guide for the details in here for all the standard way of doing when using React, Redux and Redux-Observable.
I would suggest using typesafe-actions library to achieve the types.
Some pseudo codes:
Actions
Instead of this
export interface LoginSuccessAction extends Action {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION;
payload: {
loginToken: string;
};
}
export function loginSuccess(loginToken: string): LoginSuccessAction {
return {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION,
payload: { loginToken },
};
}
use typesafe-actions, without interface
actions/login/LoginActions.ts
import {action} from "typesafe-actions"
export function loginSuccess(loginToken: string) {
return action(LoginActionTypes.LOGIN_SUCCESS_ACTION, { loginToken });
}
actions/login/LoginActionsModel.ts
import * LoginActions from "./LoginActions";
import { ActionCreator } from "typesafe-actions";
export type LoginActionCreator = ActionCreator<typeof LoginActions>
Then export out All Actions.
actions/index.ts
import { LoginActionCreator } from "./login/LoginActionModel";
export default type AllActions = LoginActionCreator
Epics
import { Epic } from "redux-observable";
import { isOfType } from "typesafe-actions";
import { filter } from "rxjs/operators";
export const loginUserEpic: Epic<AllActions> = (action$) =>
action$.pipe(
filter(isOfType((LoginActionTypes.LOGIN_ACTION))),
switchMap((action: LoginAction) =>
ajax({
url,
method: 'POST',
headers: { 'Content-Type': 'application/json' },
body: { email: action.payload.username, password: action.payload.password },
}).pipe(
map((response: AjaxResponse) => loginSuccess(response.response.token)),
catchError((error: Error) => of(loginFailed(error))),
),
),
);
Where the Epics is from redux-observable library, AllActions are the actions that is input and output of the epics.
The types is as follows:
Epic<InputActions, OutputActions, Store>
Epic<Actions(Input&Output)>
In case you want to use store from redux, you need a RootState (from root reducer)
export const someEpic: Epic<AllActions, AllActions, RootState> = (action$, store$)
=> action$.pipe(
filter(isOfType(SOMETYPE)),
mergeMap(action => {
const a = store$.value.a;
return someActions(a, action.payload.b);
})
answered Jan 22 at 10:32
johnson laijohnson lai
194110
add a comment |
You can checkout https://github.com/piotrwitek/react-redux-typescript-guide for the details in here for all the standard way of doing when using React, Redux and Redux-Observable.
I would suggest using typesafe-actions library to achieve the types.
Some pseudo codes:
Actions
Instead of this
export interface LoginSuccessAction extends Action {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION;
payload: {
loginToken: string;
};
}
export function loginSuccess(loginToken: string): LoginSuccessAction {
return {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION,
payload: { loginToken },
};
}
use typesafe-actions, without interface
actions/login/LoginActions.ts
import {action} from "typesafe-actions"
export function loginSuccess(loginToken: string) {
return action(LoginActionTypes.LOGIN_SUCCESS_ACTION, { loginToken });
}
actions/login/LoginActionsModel.ts
import * LoginActions from "./LoginActions";
import { ActionCreator } from "typesafe-actions";
export type LoginActionCreator = ActionCreator<typeof LoginActions>
Then export out All Actions.
actions/index.ts
import { LoginActionCreator } from "./login/LoginActionModel";
export default type AllActions = LoginActionCreator
Epics
import { Epic } from "redux-observable";
import { isOfType } from "typesafe-actions";
import { filter } from "rxjs/operators";
export const loginUserEpic: Epic<AllActions> = (action$) =>
action$.pipe(
filter(isOfType((LoginActionTypes.LOGIN_ACTION))),
switchMap((action: LoginAction) =>
ajax({
url,
method: 'POST',
headers: { 'Content-Type': 'application/json' },
body: { email: action.payload.username, password: action.payload.password },
}).pipe(
map((response: AjaxResponse) => loginSuccess(response.response.token)),
catchError((error: Error) => of(loginFailed(error))),
),
),
);
Where the Epics is from redux-observable library, AllActions are the actions that is input and output of the epics.
The types is as follows:
Epic<InputActions, OutputActions, Store>
Epic<Actions(Input&Output)>
In case you want to use store from redux, you need a RootState (from root reducer)
export const someEpic: Epic<AllActions, AllActions, RootState> = (action$, store$)
=> action$.pipe(
filter(isOfType(SOMETYPE)),
mergeMap(action => {
const a = store$.value.a;
return someActions(a, action.payload.b);
})
answered Jan 22 at 10:32
johnson laijohnson lai
194110
You can checkout https://github.com/piotrwitek/react-redux-typescript-guide for the details in here for all the standard way of doing when using React, Redux and Redux-Observable.
I would suggest using typesafe-actions library to achieve the types.
Some pseudo codes:
Actions
Instead of this
export interface LoginSuccessAction extends Action {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION;
payload: {
loginToken: string;
};
}
export function loginSuccess(loginToken: string): LoginSuccessAction {
return {
type: LoginActionTypes.LOGIN_SUCCESS_ACTION,
payload: { loginToken },
};
}
use typesafe-actions, without interface
actions/login/LoginActions.ts
import {action} from "typesafe-actions"
export function loginSuccess(loginToken: string) {
return action(LoginActionTypes.LOGIN_SUCCESS_ACTION, { loginToken });
}
actions/login/LoginActionsModel.ts
import * LoginActions from "./LoginActions";
import { ActionCreator } from "typesafe-actions";
export type LoginActionCreator = ActionCreator<typeof LoginActions>
Then export out All Actions.
actions/index.ts
import { LoginActionCreator } from "./login/LoginActionModel";
export default type AllActions = LoginActionCreator
Epics
import { Epic } from "redux-observable";
import { isOfType } from "typesafe-actions";
import { filter } from "rxjs/operators";
export const loginUserEpic: Epic<AllActions> = (action$) =>
action$.pipe(
filter(isOfType((LoginActionTypes.LOGIN_ACTION))),
switchMap((action: LoginAction) =>
ajax({
url,
method: 'POST',
headers: { 'Content-Type': 'application/json' },
body: { email: action.payload.username, password: action.payload.password },
}).pipe(
map((response: AjaxResponse) => loginSuccess(response.response.token)),
catchError((error: Error) => of(loginFailed(error))),
),
),
);
Where the Epics is from redux-observable library, AllActions are the actions that is input and output of the epics.
The types is as follows:
Epic<InputActions, OutputActions, Store>
Epic<Actions(Input&Output)>
In case you want to use store from redux, you need a RootState (from root reducer)
export const someEpic: Epic<AllActions, AllActions, RootState> = (action$, store$)
=> action$.pipe(
filter(isOfType(SOMETYPE)),
mergeMap(action => {
const a = store$.value.a;
return someActions(a, action.payload.b);
})
answered Jan 22 at 10:32
johnson laijohnson lai
194110
edited Jan 22 at 10:37
answered Jan 22 at 10:32
johnson laijohnson lai
194110
answered Jan 22 at 10:32
johnson laijohnson lai
194110
answered Jan 22 at 10:32
johnson laijohnson lai
194110
194110
add a comment |
add a comment |
Typescript gives an error because you have set to ActionsObservable action generic a redux Action that is an interface with form of { type: string }. So Typescript thinks that all the actions coming will have only type, but you are setting to ofType filtering operator another type of Action, even if it extends redux Action interface Typescript will require bivarianceHack to allow you pass anything that implements that interface. One of the simplest workarounds is to change ActionsObservable<Action> to ActionsObservable<AnyAction>, with AnyAction which is imported from redux.
answered Jan 25 at 6:49
iamawebgeekiamawebgeek
1,325728
add a comment |
Typescript gives an error because you have set to ActionsObservable action generic a redux Action that is an interface with form of { type: string }. So Typescript thinks that all the actions coming will have only type, but you are setting to ofType filtering operator another type of Action, even if it extends redux Action interface Typescript will require bivarianceHack to allow you pass anything that implements that interface. One of the simplest workarounds is to change ActionsObservable<Action> to ActionsObservable<AnyAction>, with AnyAction which is imported from redux.
answered Jan 25 at 6:49
iamawebgeekiamawebgeek
1,325728
add a comment |
Typescript gives an error because you have set to ActionsObservable action generic a redux Action that is an interface with form of { type: string }. So Typescript thinks that all the actions coming will have only type, but you are setting to ofType filtering operator another type of Action, even if it extends redux Action interface Typescript will require bivarianceHack to allow you pass anything that implements that interface. One of the simplest workarounds is to change ActionsObservable<Action> to ActionsObservable<AnyAction>, with AnyAction which is imported from redux.
answered Jan 25 at 6:49
iamawebgeekiamawebgeek
1,325728
Typescript gives an error because you have set to ActionsObservable action generic a redux Action that is an interface with form of { type: string }. So Typescript thinks that all the actions coming will have only type, but you are setting to ofType filtering operator another type of Action, even if it extends redux Action interface Typescript will require bivarianceHack to allow you pass anything that implements that interface. One of the simplest workarounds is to change ActionsObservable<Action> to ActionsObservable<AnyAction>, with AnyAction which is imported from redux.
answered Jan 25 at 6:49
iamawebgeekiamawebgeek
1,325728
answered Jan 25 at 6:49
iamawebgeekiamawebgeek
1,325728
answered Jan 25 at 6:49
iamawebgeekiamawebgeek
1,325728
answered Jan 25 at 6:49
iamawebgeekiamawebgeek
1,325728
1,325728
add a comment |
add a comment |
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