TikZ: Align array of matrices
The following code:
documentclass[tikz,border=1mm]{standalone}
usepackage{tikz}
usetikzlibrary{matrix, positioning}
tikzset{
matrixstyle/.style={
matrix of nodes,
nodes={
draw
}
}}
begin{document}
begin{tikzpicture}
matrix (M) [matrixstyle]{
.1 & .1 \
.1 & .1 \
};
begin{scope} [local bounding box=MA, shift={(M.west)}, left = 0cm of M.west]
matrix (M11) [matrixstyle]{
.1 & .0 \
.5 & .0 \
};
matrix (M12) [matrixstyle, right = 0cm of M11]{
.2 & .0 \
.3 & .9 \
};
matrix (M21) [matrixstyle, below = 0cm of M11]{
.0 & .0 \
.0 & .2 \
};
matrix (M22) [matrixstyle, right = 0cm of M21]{
.3 & .0 \
.3 & .9 \
};
end{scope}
matrix (N) [matrixstyle, left = 1cm of MA.west]{
.2 & .2 \
.2 & .2 \
};
end{tikzpicture}
end{document}
produces the following output:
The output should show six matrices. Four in the middle. And one matrix each on the right and left side of the matrix array. However, I did not manage to place the matrix M to the right of the matrix array MA. The error is probably in the following line
begin{scope} [local bounding box=MA, shift={(M.west)}, left = 0cm of M.west]
What is the right way to do it? Why does my approach not work?
tikz-pgf
add a comment |
The following code:
documentclass[tikz,border=1mm]{standalone}
usepackage{tikz}
usetikzlibrary{matrix, positioning}
tikzset{
matrixstyle/.style={
matrix of nodes,
nodes={
draw
}
}}
begin{document}
begin{tikzpicture}
matrix (M) [matrixstyle]{
.1 & .1 \
.1 & .1 \
};
begin{scope} [local bounding box=MA, shift={(M.west)}, left = 0cm of M.west]
matrix (M11) [matrixstyle]{
.1 & .0 \
.5 & .0 \
};
matrix (M12) [matrixstyle, right = 0cm of M11]{
.2 & .0 \
.3 & .9 \
};
matrix (M21) [matrixstyle, below = 0cm of M11]{
.0 & .0 \
.0 & .2 \
};
matrix (M22) [matrixstyle, right = 0cm of M21]{
.3 & .0 \
.3 & .9 \
};
end{scope}
matrix (N) [matrixstyle, left = 1cm of MA.west]{
.2 & .2 \
.2 & .2 \
};
end{tikzpicture}
end{document}
produces the following output:
The output should show six matrices. Four in the middle. And one matrix each on the right and left side of the matrix array. However, I did not manage to place the matrix M to the right of the matrix array MA. The error is probably in the following line
begin{scope} [local bounding box=MA, shift={(M.west)}, left = 0cm of M.west]
What is the right way to do it? Why does my approach not work?
tikz-pgf
add a comment |
The following code:
documentclass[tikz,border=1mm]{standalone}
usepackage{tikz}
usetikzlibrary{matrix, positioning}
tikzset{
matrixstyle/.style={
matrix of nodes,
nodes={
draw
}
}}
begin{document}
begin{tikzpicture}
matrix (M) [matrixstyle]{
.1 & .1 \
.1 & .1 \
};
begin{scope} [local bounding box=MA, shift={(M.west)}, left = 0cm of M.west]
matrix (M11) [matrixstyle]{
.1 & .0 \
.5 & .0 \
};
matrix (M12) [matrixstyle, right = 0cm of M11]{
.2 & .0 \
.3 & .9 \
};
matrix (M21) [matrixstyle, below = 0cm of M11]{
.0 & .0 \
.0 & .2 \
};
matrix (M22) [matrixstyle, right = 0cm of M21]{
.3 & .0 \
.3 & .9 \
};
end{scope}
matrix (N) [matrixstyle, left = 1cm of MA.west]{
.2 & .2 \
.2 & .2 \
};
end{tikzpicture}
end{document}
produces the following output:
The output should show six matrices. Four in the middle. And one matrix each on the right and left side of the matrix array. However, I did not manage to place the matrix M to the right of the matrix array MA. The error is probably in the following line
begin{scope} [local bounding box=MA, shift={(M.west)}, left = 0cm of M.west]
What is the right way to do it? Why does my approach not work?
tikz-pgf
The following code:
documentclass[tikz,border=1mm]{standalone}
usepackage{tikz}
usetikzlibrary{matrix, positioning}
tikzset{
matrixstyle/.style={
matrix of nodes,
nodes={
draw
}
}}
begin{document}
begin{tikzpicture}
matrix (M) [matrixstyle]{
.1 & .1 \
.1 & .1 \
};
begin{scope} [local bounding box=MA, shift={(M.west)}, left = 0cm of M.west]
matrix (M11) [matrixstyle]{
.1 & .0 \
.5 & .0 \
};
matrix (M12) [matrixstyle, right = 0cm of M11]{
.2 & .0 \
.3 & .9 \
};
matrix (M21) [matrixstyle, below = 0cm of M11]{
.0 & .0 \
.0 & .2 \
};
matrix (M22) [matrixstyle, right = 0cm of M21]{
.3 & .0 \
.3 & .9 \
};
end{scope}
matrix (N) [matrixstyle, left = 1cm of MA.west]{
.2 & .2 \
.2 & .2 \
};
end{tikzpicture}
end{document}
produces the following output:
The output should show six matrices. Four in the middle. And one matrix each on the right and left side of the matrix array. However, I did not manage to place the matrix M to the right of the matrix array MA. The error is probably in the following line
begin{scope} [local bounding box=MA, shift={(M.west)}, left = 0cm of M.west]
What is the right way to do it? Why does my approach not work?
tikz-pgf
tikz-pgf
edited Jan 11 at 18:35
Bernard
169k773198
169k773198
asked Jan 11 at 18:27
SamuelSamuel
537211
537211
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
like this?
matrices you can consider as nodes, so their positioning is with positioning
library is straightforward:
documentclass[tikz,border=1mm]{standalone}
usetikzlibrary{matrix, positioning}
begin{document}
begin{tikzpicture}[
node distance = 1mm and 2mm,
every matrix/.style = {matrix of nodes,
nodes={draw},
column sep=-pgflinewidth,
row sep=-pgflinewidth}
]
matrix (m1)
{
.2 & .2 \
.2 & .2 \
};
matrix (m11) [above right=of m1.east]
{
.1 & .0 \
.5 & .0 \
};
matrix (m12) [right=of m11]
{
.1 & .1 \
.1 & .1 \
};
matrix (m21) [below right= of m1.east]
{
.0 & .0 \
.0 & .2 \
};
matrix (m22) [right = of m21]{
.3 & .0 \
.3 & .9 \
};
matrix (m2) [right = of m1 -| m12.east]
{
.2 & .0 \
.3 & .9 \
};
end{tikzpicture}
end{document}
What doesright = of m1 -| m12.east
mean? Especially the-|
part.
– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
add a comment |
Although not exactly the same, something very similar can be done with some tabular
and without TiKZ
.
documentclass{article}
newcommand{mytab}[4]{%
begin{tabular}[c]{|c|c|}
hline
#1\hline
#3\hline
end{tabular}}
begin{document}
mytab{.2}{.2}{.2}{.2}
begin{tabular}[c]{cccc}
mytab{.1}{.0}{.5}{.2} & mytab{.1}{.1}{.1}{.1}
\[.5cm]
mytab{.0}{.0}{.0}{.2} & mytab{.3}{.0}{.3}{.9}
end{tabular}
mytab{.2}{.0}{.3}{.9}
end{document}
EDIT: or even better with ytableau
package
documentclass{article}
usepackage{ytableau}
newcommand{mytab}[4]{%
begin{ytableau}
#1\
#3\
end{ytableau}}
begin{document}
ytableausetup{centertableaux}
mytab{.2}{.2}{.2}{.2}
begin{tabular}[c]{cccc}
mytab{.1}{.0}{.5}{.2} & mytab{.1}{.1}{.1}{.1}
\[.5cm]
mytab{.0}{.0}{.0}{.2} & mytab{.3}{.0}{.3}{.9}
end{tabular}
mytab{.2}{.0}{.3}{.9}
end{document}
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
like this?
matrices you can consider as nodes, so their positioning is with positioning
library is straightforward:
documentclass[tikz,border=1mm]{standalone}
usetikzlibrary{matrix, positioning}
begin{document}
begin{tikzpicture}[
node distance = 1mm and 2mm,
every matrix/.style = {matrix of nodes,
nodes={draw},
column sep=-pgflinewidth,
row sep=-pgflinewidth}
]
matrix (m1)
{
.2 & .2 \
.2 & .2 \
};
matrix (m11) [above right=of m1.east]
{
.1 & .0 \
.5 & .0 \
};
matrix (m12) [right=of m11]
{
.1 & .1 \
.1 & .1 \
};
matrix (m21) [below right= of m1.east]
{
.0 & .0 \
.0 & .2 \
};
matrix (m22) [right = of m21]{
.3 & .0 \
.3 & .9 \
};
matrix (m2) [right = of m1 -| m12.east]
{
.2 & .0 \
.3 & .9 \
};
end{tikzpicture}
end{document}
What doesright = of m1 -| m12.east
mean? Especially the-|
part.
– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
add a comment |
like this?
matrices you can consider as nodes, so their positioning is with positioning
library is straightforward:
documentclass[tikz,border=1mm]{standalone}
usetikzlibrary{matrix, positioning}
begin{document}
begin{tikzpicture}[
node distance = 1mm and 2mm,
every matrix/.style = {matrix of nodes,
nodes={draw},
column sep=-pgflinewidth,
row sep=-pgflinewidth}
]
matrix (m1)
{
.2 & .2 \
.2 & .2 \
};
matrix (m11) [above right=of m1.east]
{
.1 & .0 \
.5 & .0 \
};
matrix (m12) [right=of m11]
{
.1 & .1 \
.1 & .1 \
};
matrix (m21) [below right= of m1.east]
{
.0 & .0 \
.0 & .2 \
};
matrix (m22) [right = of m21]{
.3 & .0 \
.3 & .9 \
};
matrix (m2) [right = of m1 -| m12.east]
{
.2 & .0 \
.3 & .9 \
};
end{tikzpicture}
end{document}
What doesright = of m1 -| m12.east
mean? Especially the-|
part.
– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
add a comment |
like this?
matrices you can consider as nodes, so their positioning is with positioning
library is straightforward:
documentclass[tikz,border=1mm]{standalone}
usetikzlibrary{matrix, positioning}
begin{document}
begin{tikzpicture}[
node distance = 1mm and 2mm,
every matrix/.style = {matrix of nodes,
nodes={draw},
column sep=-pgflinewidth,
row sep=-pgflinewidth}
]
matrix (m1)
{
.2 & .2 \
.2 & .2 \
};
matrix (m11) [above right=of m1.east]
{
.1 & .0 \
.5 & .0 \
};
matrix (m12) [right=of m11]
{
.1 & .1 \
.1 & .1 \
};
matrix (m21) [below right= of m1.east]
{
.0 & .0 \
.0 & .2 \
};
matrix (m22) [right = of m21]{
.3 & .0 \
.3 & .9 \
};
matrix (m2) [right = of m1 -| m12.east]
{
.2 & .0 \
.3 & .9 \
};
end{tikzpicture}
end{document}
like this?
matrices you can consider as nodes, so their positioning is with positioning
library is straightforward:
documentclass[tikz,border=1mm]{standalone}
usetikzlibrary{matrix, positioning}
begin{document}
begin{tikzpicture}[
node distance = 1mm and 2mm,
every matrix/.style = {matrix of nodes,
nodes={draw},
column sep=-pgflinewidth,
row sep=-pgflinewidth}
]
matrix (m1)
{
.2 & .2 \
.2 & .2 \
};
matrix (m11) [above right=of m1.east]
{
.1 & .0 \
.5 & .0 \
};
matrix (m12) [right=of m11]
{
.1 & .1 \
.1 & .1 \
};
matrix (m21) [below right= of m1.east]
{
.0 & .0 \
.0 & .2 \
};
matrix (m22) [right = of m21]{
.3 & .0 \
.3 & .9 \
};
matrix (m2) [right = of m1 -| m12.east]
{
.2 & .0 \
.3 & .9 \
};
end{tikzpicture}
end{document}
edited Jan 11 at 19:00
answered Jan 11 at 18:43
ZarkoZarko
124k866163
124k866163
What doesright = of m1 -| m12.east
mean? Especially the-|
part.
– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
add a comment |
What doesright = of m1 -| m12.east
mean? Especially the-|
part.
– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
What does
right = of m1 -| m12.east
mean? Especially the -|
part.– Samuel
Jan 12 at 16:21
What does
right = of m1 -| m12.east
mean? Especially the -|
part.– Samuel
Jan 12 at 16:21
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
Is it possible to define the four matrices in the middle as a single object that can be moved and resized? I want to resize the four matrices in the middle to have the same size as the matrices on the left and on the right.
– Samuel
Jan 12 at 16:27
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
@Samuel, this is new question in which you need to show (by sketch), how you like scale and shift a group of matrices. probably solution require a different solution as is shown in both answers. i think, that both answers perfectly solve the problem described in this question, therefore it is time, that you accept one of them.
– Zarko
Jan 13 at 0:21
add a comment |
Although not exactly the same, something very similar can be done with some tabular
and without TiKZ
.
documentclass{article}
newcommand{mytab}[4]{%
begin{tabular}[c]{|c|c|}
hline
#1\hline
#3\hline
end{tabular}}
begin{document}
mytab{.2}{.2}{.2}{.2}
begin{tabular}[c]{cccc}
mytab{.1}{.0}{.5}{.2} & mytab{.1}{.1}{.1}{.1}
\[.5cm]
mytab{.0}{.0}{.0}{.2} & mytab{.3}{.0}{.3}{.9}
end{tabular}
mytab{.2}{.0}{.3}{.9}
end{document}
EDIT: or even better with ytableau
package
documentclass{article}
usepackage{ytableau}
newcommand{mytab}[4]{%
begin{ytableau}
#1\
#3\
end{ytableau}}
begin{document}
ytableausetup{centertableaux}
mytab{.2}{.2}{.2}{.2}
begin{tabular}[c]{cccc}
mytab{.1}{.0}{.5}{.2} & mytab{.1}{.1}{.1}{.1}
\[.5cm]
mytab{.0}{.0}{.0}{.2} & mytab{.3}{.0}{.3}{.9}
end{tabular}
mytab{.2}{.0}{.3}{.9}
end{document}
add a comment |
Although not exactly the same, something very similar can be done with some tabular
and without TiKZ
.
documentclass{article}
newcommand{mytab}[4]{%
begin{tabular}[c]{|c|c|}
hline
#1\hline
#3\hline
end{tabular}}
begin{document}
mytab{.2}{.2}{.2}{.2}
begin{tabular}[c]{cccc}
mytab{.1}{.0}{.5}{.2} & mytab{.1}{.1}{.1}{.1}
\[.5cm]
mytab{.0}{.0}{.0}{.2} & mytab{.3}{.0}{.3}{.9}
end{tabular}
mytab{.2}{.0}{.3}{.9}
end{document}
EDIT: or even better with ytableau
package
documentclass{article}
usepackage{ytableau}
newcommand{mytab}[4]{%
begin{ytableau}
#1\
#3\
end{ytableau}}
begin{document}
ytableausetup{centertableaux}
mytab{.2}{.2}{.2}{.2}
begin{tabular}[c]{cccc}
mytab{.1}{.0}{.5}{.2} & mytab{.1}{.1}{.1}{.1}
\[.5cm]
mytab{.0}{.0}{.0}{.2} & mytab{.3}{.0}{.3}{.9}
end{tabular}
mytab{.2}{.0}{.3}{.9}
end{document}
add a comment |
Although not exactly the same, something very similar can be done with some tabular
and without TiKZ
.
documentclass{article}
newcommand{mytab}[4]{%
begin{tabular}[c]{|c|c|}
hline
#1\hline
#3\hline
end{tabular}}
begin{document}
mytab{.2}{.2}{.2}{.2}
begin{tabular}[c]{cccc}
mytab{.1}{.0}{.5}{.2} & mytab{.1}{.1}{.1}{.1}
\[.5cm]
mytab{.0}{.0}{.0}{.2} & mytab{.3}{.0}{.3}{.9}
end{tabular}
mytab{.2}{.0}{.3}{.9}
end{document}
EDIT: or even better with ytableau
package
documentclass{article}
usepackage{ytableau}
newcommand{mytab}[4]{%
begin{ytableau}
#1\
#3\
end{ytableau}}
begin{document}
ytableausetup{centertableaux}
mytab{.2}{.2}{.2}{.2}
begin{tabular}[c]{cccc}
mytab{.1}{.0}{.5}{.2} & mytab{.1}{.1}{.1}{.1}
\[.5cm]
mytab{.0}{.0}{.0}{.2} & mytab{.3}{.0}{.3}{.9}
end{tabular}
mytab{.2}{.0}{.3}{.9}
end{document}
Although not exactly the same, something very similar can be done with some tabular
and without TiKZ
.
documentclass{article}
newcommand{mytab}[4]{%
begin{tabular}[c]{|c|c|}
hline
#1\hline
#3\hline
end{tabular}}
begin{document}
mytab{.2}{.2}{.2}{.2}
begin{tabular}[c]{cccc}
mytab{.1}{.0}{.5}{.2} & mytab{.1}{.1}{.1}{.1}
\[.5cm]
mytab{.0}{.0}{.0}{.2} & mytab{.3}{.0}{.3}{.9}
end{tabular}
mytab{.2}{.0}{.3}{.9}
end{document}
EDIT: or even better with ytableau
package
documentclass{article}
usepackage{ytableau}
newcommand{mytab}[4]{%
begin{ytableau}
#1\
#3\
end{ytableau}}
begin{document}
ytableausetup{centertableaux}
mytab{.2}{.2}{.2}{.2}
begin{tabular}[c]{cccc}
mytab{.1}{.0}{.5}{.2} & mytab{.1}{.1}{.1}{.1}
\[.5cm]
mytab{.0}{.0}{.0}{.2} & mytab{.3}{.0}{.3}{.9}
end{tabular}
mytab{.2}{.0}{.3}{.9}
end{document}
edited Jan 11 at 19:44
answered Jan 11 at 19:22
IgnasiIgnasi
93k4167310
93k4167310
add a comment |
add a comment |
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StackExchange.helpers.onClickDraftSave('#login-link');
});
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StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
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Post as a guest
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StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
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Sign up using Google
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Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown