TypeError: process() takes 1 positional argument but 2 were given [duplicate]

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So, i'm trying to make a barcode generator. The process() function 'translate' the decimals into 7-bits that EAN-13 barcode use. But i got TypeError instead.

class App(Frame):

    encoded = 

    def __init__(self,master):

        Frame.__init__(self,master)



        ##################

        text_1 = Label(self,text='Save Barcode to PS file [eg: EAN13.eps]:')



        text_2 = Label(self,text='Enter code (first 12 decimal digits):')



        self.file_entry = Entry(self)



        self.code_entry = Entry(self)

        self.code_entry.bind('<Return>',self.process)

        ###################

        text_1.grid(row = 0, column = 1,columnspan = 3)

        self.file_entry.grid(row = 1, column = 1,columnspan = 3)

        text_2.grid(row = 2, column = 1,columnspan = 3)

        self.code_entry.grid(row = 3, column = 1,columnspan = 3)



    def process(self):

        num = self.code_entry.get()

        checksum = (num[0]+num[2]+num[4]+num[6]+num[8]+num[10])+(3*(num[1]+num[3]+num[5]+num[7]+num[9]+num[11]))

        .......

What i get in the end is TypeError in process(), i thought there's only one argument, self.

Where did i go wrong?

python oop tkinter

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asked Nov 21 '18 at 15:00

Lil StudentLil Student

42

marked as duplicate by Lafexlos, Bryan Oakley python
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Nov 21 '18 at 15:09

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's not clear for me where process is activated, please add the actual line where the error is coming from. and if you can, the error stack trace. from what you are saying, it seems like you use my_app.process(variable), but process only need self, so, you need to use it like this: my_app.process()
  
  – Avishay Cohen
  Nov 21 '18 at 15:06
  

  
  
  
  

add a comment | 

0

This question already has an answer here:

• 
  TypeError: quit() takes 1 positional argument but 2 were given (keyboard bind)
  
  2 answers
  
  


• 
  Keyboard Shortcut “Takes 1 positional argument but 2 were given”
  
  1 answer
  
  

So, i'm trying to make a barcode generator. The process() function 'translate' the decimals into 7-bits that EAN-13 barcode use. But i got TypeError instead.

class App(Frame):

    encoded = 

    def __init__(self,master):

        Frame.__init__(self,master)



        ##################

        text_1 = Label(self,text='Save Barcode to PS file [eg: EAN13.eps]:')



        text_2 = Label(self,text='Enter code (first 12 decimal digits):')



        self.file_entry = Entry(self)



        self.code_entry = Entry(self)

        self.code_entry.bind('<Return>',self.process)

        ###################

        text_1.grid(row = 0, column = 1,columnspan = 3)

        self.file_entry.grid(row = 1, column = 1,columnspan = 3)

        text_2.grid(row = 2, column = 1,columnspan = 3)

        self.code_entry.grid(row = 3, column = 1,columnspan = 3)



    def process(self):

        num = self.code_entry.get()

        checksum = (num[0]+num[2]+num[4]+num[6]+num[8]+num[10])+(3*(num[1]+num[3]+num[5]+num[7]+num[9]+num[11]))

        .......

What i get in the end is TypeError in process(), i thought there's only one argument, self.

Where did i go wrong?

python oop tkinter

share|improve this question

asked Nov 21 '18 at 15:00

Lil StudentLil Student

42

marked as duplicate by Lafexlos, Bryan Oakley python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

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Nov 21 '18 at 15:09

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's not clear for me where process is activated, please add the actual line where the error is coming from. and if you can, the error stack trace. from what you are saying, it seems like you use my_app.process(variable), but process only need self, so, you need to use it like this: my_app.process()
  
  – Avishay Cohen
  Nov 21 '18 at 15:06
  

  
  
  
  

add a comment | 

0

0

0

This question already has an answer here:

• 
  TypeError: quit() takes 1 positional argument but 2 were given (keyboard bind)
  
  2 answers
  
  


• 
  Keyboard Shortcut “Takes 1 positional argument but 2 were given”
  
  1 answer
  
  

So, i'm trying to make a barcode generator. The process() function 'translate' the decimals into 7-bits that EAN-13 barcode use. But i got TypeError instead.

class App(Frame):

    encoded = 

    def __init__(self,master):

        Frame.__init__(self,master)



        ##################

        text_1 = Label(self,text='Save Barcode to PS file [eg: EAN13.eps]:')



        text_2 = Label(self,text='Enter code (first 12 decimal digits):')



        self.file_entry = Entry(self)



        self.code_entry = Entry(self)

        self.code_entry.bind('<Return>',self.process)

        ###################

        text_1.grid(row = 0, column = 1,columnspan = 3)

        self.file_entry.grid(row = 1, column = 1,columnspan = 3)

        text_2.grid(row = 2, column = 1,columnspan = 3)

        self.code_entry.grid(row = 3, column = 1,columnspan = 3)



    def process(self):

        num = self.code_entry.get()

        checksum = (num[0]+num[2]+num[4]+num[6]+num[8]+num[10])+(3*(num[1]+num[3]+num[5]+num[7]+num[9]+num[11]))

        .......

What i get in the end is TypeError in process(), i thought there's only one argument, self.

Where did i go wrong?

python oop tkinter

share|improve this question

asked Nov 21 '18 at 15:00

Lil StudentLil Student

42

This question already has an answer here:

• 
  TypeError: quit() takes 1 positional argument but 2 were given (keyboard bind)
  
  2 answers
  
  


• 
  Keyboard Shortcut “Takes 1 positional argument but 2 were given”
  
  1 answer
  
  

So, i'm trying to make a barcode generator. The process() function 'translate' the decimals into 7-bits that EAN-13 barcode use. But i got TypeError instead.

class App(Frame):

    encoded = 

    def __init__(self,master):

        Frame.__init__(self,master)



        ##################

        text_1 = Label(self,text='Save Barcode to PS file [eg: EAN13.eps]:')



        text_2 = Label(self,text='Enter code (first 12 decimal digits):')



        self.file_entry = Entry(self)



        self.code_entry = Entry(self)

        self.code_entry.bind('<Return>',self.process)

        ###################

        text_1.grid(row = 0, column = 1,columnspan = 3)

        self.file_entry.grid(row = 1, column = 1,columnspan = 3)

        text_2.grid(row = 2, column = 1,columnspan = 3)

        self.code_entry.grid(row = 3, column = 1,columnspan = 3)



    def process(self):

        num = self.code_entry.get()

        checksum = (num[0]+num[2]+num[4]+num[6]+num[8]+num[10])+(3*(num[1]+num[3]+num[5]+num[7]+num[9]+num[11]))

        .......

What i get in the end is TypeError in process(), i thought there's only one argument, self.

Where did i go wrong?

This question already has an answer here:

• 
  TypeError: quit() takes 1 positional argument but 2 were given (keyboard bind)
  
  2 answers
  
  


• 
  Keyboard Shortcut “Takes 1 positional argument but 2 were given”
  
  1 answer
  
  

python oop tkinter

python oop tkinter

share|improve this question

asked Nov 21 '18 at 15:00

Lil StudentLil Student

42

share|improve this question

asked Nov 21 '18 at 15:00

Lil StudentLil Student

42

share|improve this question

share|improve this question

asked Nov 21 '18 at 15:00

Lil StudentLil Student

42

asked Nov 21 '18 at 15:00

Lil StudentLil Student

42

asked Nov 21 '18 at 15:00

Lil StudentLil Student

42

42

marked as duplicate by Lafexlos, Bryan Oakley python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

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Nov 21 '18 at 15:09

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by Lafexlos, Bryan Oakley python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

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Nov 21 '18 at 15:09

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's not clear for me where process is activated, please add the actual line where the error is coming from. and if you can, the error stack trace. from what you are saying, it seems like you use my_app.process(variable), but process only need self, so, you need to use it like this: my_app.process()
  
  – Avishay Cohen
  Nov 21 '18 at 15:06
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It's not clear for me where process is activated, please add the actual line where the error is coming from. and if you can, the error stack trace. from what you are saying, it seems like you use my_app.process(variable), but process only need self, so, you need to use it like this: my_app.process()
  
  – Avishay Cohen
  Nov 21 '18 at 15:06
  

  
  
  
  

It's not clear for me where process is activated, please add the actual line where the error is coming from. and if you can, the error stack trace. from what you are saying, it seems like you use my_app.process(variable), but process only need self, so, you need to use it like this: my_app.process()

– Avishay Cohen
Nov 21 '18 at 15:06

It's not clear for me where process is activated, please add the actual line where the error is coming from. and if you can, the error stack trace. from what you are saying, it seems like you use my_app.process(variable), but process only need self, so, you need to use it like this: my_app.process()

– Avishay Cohen
Nov 21 '18 at 15:06

add a comment | 

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