Cannot construct instance of `java.security.Timestamp` Error in spring Rest












0















I have a simple Rest controller as follow :



@PostMapping(value = "/DepositBalance")
public DepositBalanceResponse DepositBalance(@Valid @RequestBody DepositBalanceRequest requestDto) throws Exception {
return depositService.GetDepositBalance(requestDto);
}


Here is the DepositBalanceRequest fields :



private String profileId;
private String userName;
@JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
private Timestamp timestamp;


When I invoke the service via Postman like this :



{
"profileId":"asdfasdf",
"userName":"username",
"timestamp":"2018-12-30 20:12:20",
}


I get the following error :



"Type definition error: [simple type, class java.security.Timestamp]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `java.security.Timestamp` (no Creators, like default construct, exist): no String-argument constructor/factory method to deserialize from String value ('2018-12-30 20:12:20')n at [Source: (PushbackInputStream); line: 4, column: 14] (through reference chain: com.api.v1.deposit.DepositBalanceRequest["timestamp"])"


I'm wondering do I miss something?










share|improve this question




















  • 1





    You probably want to use a Java Time version of that, like LocalDateTime or DateTime instead of the java.security or javax.sql one.

    – M. Deinum
    Dec 30 '18 at 17:48











  • `@M.Deinum Thanks, LocalDateTime worked

    – Mostafa
    Dec 30 '18 at 17:59
















0















I have a simple Rest controller as follow :



@PostMapping(value = "/DepositBalance")
public DepositBalanceResponse DepositBalance(@Valid @RequestBody DepositBalanceRequest requestDto) throws Exception {
return depositService.GetDepositBalance(requestDto);
}


Here is the DepositBalanceRequest fields :



private String profileId;
private String userName;
@JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
private Timestamp timestamp;


When I invoke the service via Postman like this :



{
"profileId":"asdfasdf",
"userName":"username",
"timestamp":"2018-12-30 20:12:20",
}


I get the following error :



"Type definition error: [simple type, class java.security.Timestamp]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `java.security.Timestamp` (no Creators, like default construct, exist): no String-argument constructor/factory method to deserialize from String value ('2018-12-30 20:12:20')n at [Source: (PushbackInputStream); line: 4, column: 14] (through reference chain: com.api.v1.deposit.DepositBalanceRequest["timestamp"])"


I'm wondering do I miss something?










share|improve this question




















  • 1





    You probably want to use a Java Time version of that, like LocalDateTime or DateTime instead of the java.security or javax.sql one.

    – M. Deinum
    Dec 30 '18 at 17:48











  • `@M.Deinum Thanks, LocalDateTime worked

    – Mostafa
    Dec 30 '18 at 17:59














0












0








0








I have a simple Rest controller as follow :



@PostMapping(value = "/DepositBalance")
public DepositBalanceResponse DepositBalance(@Valid @RequestBody DepositBalanceRequest requestDto) throws Exception {
return depositService.GetDepositBalance(requestDto);
}


Here is the DepositBalanceRequest fields :



private String profileId;
private String userName;
@JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
private Timestamp timestamp;


When I invoke the service via Postman like this :



{
"profileId":"asdfasdf",
"userName":"username",
"timestamp":"2018-12-30 20:12:20",
}


I get the following error :



"Type definition error: [simple type, class java.security.Timestamp]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `java.security.Timestamp` (no Creators, like default construct, exist): no String-argument constructor/factory method to deserialize from String value ('2018-12-30 20:12:20')n at [Source: (PushbackInputStream); line: 4, column: 14] (through reference chain: com.api.v1.deposit.DepositBalanceRequest["timestamp"])"


I'm wondering do I miss something?










share|improve this question
















I have a simple Rest controller as follow :



@PostMapping(value = "/DepositBalance")
public DepositBalanceResponse DepositBalance(@Valid @RequestBody DepositBalanceRequest requestDto) throws Exception {
return depositService.GetDepositBalance(requestDto);
}


Here is the DepositBalanceRequest fields :



private String profileId;
private String userName;
@JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
private Timestamp timestamp;


When I invoke the service via Postman like this :



{
"profileId":"asdfasdf",
"userName":"username",
"timestamp":"2018-12-30 20:12:20",
}


I get the following error :



"Type definition error: [simple type, class java.security.Timestamp]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `java.security.Timestamp` (no Creators, like default construct, exist): no String-argument constructor/factory method to deserialize from String value ('2018-12-30 20:12:20')n at [Source: (PushbackInputStream); line: 4, column: 14] (through reference chain: com.api.v1.deposit.DepositBalanceRequest["timestamp"])"


I'm wondering do I miss something?







json spring jackson timestamp spring-rest






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edited Dec 30 '18 at 17:48







Mostafa

















asked Dec 30 '18 at 17:46









MostafaMostafa

1,59963565




1,59963565








  • 1





    You probably want to use a Java Time version of that, like LocalDateTime or DateTime instead of the java.security or javax.sql one.

    – M. Deinum
    Dec 30 '18 at 17:48











  • `@M.Deinum Thanks, LocalDateTime worked

    – Mostafa
    Dec 30 '18 at 17:59














  • 1





    You probably want to use a Java Time version of that, like LocalDateTime or DateTime instead of the java.security or javax.sql one.

    – M. Deinum
    Dec 30 '18 at 17:48











  • `@M.Deinum Thanks, LocalDateTime worked

    – Mostafa
    Dec 30 '18 at 17:59








1




1





You probably want to use a Java Time version of that, like LocalDateTime or DateTime instead of the java.security or javax.sql one.

– M. Deinum
Dec 30 '18 at 17:48





You probably want to use a Java Time version of that, like LocalDateTime or DateTime instead of the java.security or javax.sql one.

– M. Deinum
Dec 30 '18 at 17:48













`@M.Deinum Thanks, LocalDateTime worked

– Mostafa
Dec 30 '18 at 17:59





`@M.Deinum Thanks, LocalDateTime worked

– Mostafa
Dec 30 '18 at 17:59












1 Answer
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Thanks to M.Deinum,
It's required to use LocalDateTime instead of Timestamp



private String profileId;
private String userName;
@JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
private LocalDateTime timestamp;





share|improve this answer























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    1 Answer
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    active

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    0














    Thanks to M.Deinum,
    It's required to use LocalDateTime instead of Timestamp



    private String profileId;
    private String userName;
    @JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
    private LocalDateTime timestamp;





    share|improve this answer




























      0














      Thanks to M.Deinum,
      It's required to use LocalDateTime instead of Timestamp



      private String profileId;
      private String userName;
      @JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
      private LocalDateTime timestamp;





      share|improve this answer


























        0












        0








        0







        Thanks to M.Deinum,
        It's required to use LocalDateTime instead of Timestamp



        private String profileId;
        private String userName;
        @JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
        private LocalDateTime timestamp;





        share|improve this answer













        Thanks to M.Deinum,
        It's required to use LocalDateTime instead of Timestamp



        private String profileId;
        private String userName;
        @JsonFormat(pattern = "yyyy-MM-dd HH:mm:ss")
        private LocalDateTime timestamp;






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 1 at 13:13









        MostafaMostafa

        1,59963565




        1,59963565
































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