Find the limit of rational function












0












$begingroup$


I have this rational function



$
lim_{x to2} frac{sqrt{x+2}sqrt{x+7}-2sqrt{x+7}-3sqrt{x+2}+6}{xsqrt{4x+1}-2sqrt{4x+1}-3x+6}
$



And i really don't know where to start to solve it.
So if you can give me some tips on solving this i would really appreciate it.










share|cite|improve this question











$endgroup$

















    0












    $begingroup$


    I have this rational function



    $
    lim_{x to2} frac{sqrt{x+2}sqrt{x+7}-2sqrt{x+7}-3sqrt{x+2}+6}{xsqrt{4x+1}-2sqrt{4x+1}-3x+6}
    $



    And i really don't know where to start to solve it.
    So if you can give me some tips on solving this i would really appreciate it.










    share|cite|improve this question











    $endgroup$















      0












      0








      0


      1



      $begingroup$


      I have this rational function



      $
      lim_{x to2} frac{sqrt{x+2}sqrt{x+7}-2sqrt{x+7}-3sqrt{x+2}+6}{xsqrt{4x+1}-2sqrt{4x+1}-3x+6}
      $



      And i really don't know where to start to solve it.
      So if you can give me some tips on solving this i would really appreciate it.










      share|cite|improve this question











      $endgroup$




      I have this rational function



      $
      lim_{x to2} frac{sqrt{x+2}sqrt{x+7}-2sqrt{x+7}-3sqrt{x+2}+6}{xsqrt{4x+1}-2sqrt{4x+1}-3x+6}
      $



      And i really don't know where to start to solve it.
      So if you can give me some tips on solving this i would really appreciate it.







      real-analysis limits






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      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Jan 29 at 9:23









      YuiTo Cheng

      2,1862937




      2,1862937










      asked Jan 29 at 9:19









      krnekikrneki

      82




      82






















          1 Answer
          1






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          0












          $begingroup$

          Hint:let $sqrt{x+2}=a,sqrt{x+7}=b$ and $sqrt{4x+1}=c$



          $
          lim_{x to2} frac{sqrt{x+2}sqrt{x+7}-2sqrt{x+7}-3sqrt{x+2}+6}{xsqrt{4x+1}-2sqrt{4x+1}-3x+6}=lim_{x to2}frac{(a-2)(b-3)}{(x-2)(c-3)}
          $



          Do you know what to do now?






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            I know now what to do, but can you please explain where did number 6 go?
            $endgroup$
            – krneki
            Jan 29 at 9:36










          • $begingroup$
            Note that (a-2)(b-3)=ab-2b-3a+6
            $endgroup$
            – abc...
            Jan 29 at 20:58












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          0












          $begingroup$

          Hint:let $sqrt{x+2}=a,sqrt{x+7}=b$ and $sqrt{4x+1}=c$



          $
          lim_{x to2} frac{sqrt{x+2}sqrt{x+7}-2sqrt{x+7}-3sqrt{x+2}+6}{xsqrt{4x+1}-2sqrt{4x+1}-3x+6}=lim_{x to2}frac{(a-2)(b-3)}{(x-2)(c-3)}
          $



          Do you know what to do now?






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            I know now what to do, but can you please explain where did number 6 go?
            $endgroup$
            – krneki
            Jan 29 at 9:36










          • $begingroup$
            Note that (a-2)(b-3)=ab-2b-3a+6
            $endgroup$
            – abc...
            Jan 29 at 20:58
















          0












          $begingroup$

          Hint:let $sqrt{x+2}=a,sqrt{x+7}=b$ and $sqrt{4x+1}=c$



          $
          lim_{x to2} frac{sqrt{x+2}sqrt{x+7}-2sqrt{x+7}-3sqrt{x+2}+6}{xsqrt{4x+1}-2sqrt{4x+1}-3x+6}=lim_{x to2}frac{(a-2)(b-3)}{(x-2)(c-3)}
          $



          Do you know what to do now?






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            I know now what to do, but can you please explain where did number 6 go?
            $endgroup$
            – krneki
            Jan 29 at 9:36










          • $begingroup$
            Note that (a-2)(b-3)=ab-2b-3a+6
            $endgroup$
            – abc...
            Jan 29 at 20:58














          0












          0








          0





          $begingroup$

          Hint:let $sqrt{x+2}=a,sqrt{x+7}=b$ and $sqrt{4x+1}=c$



          $
          lim_{x to2} frac{sqrt{x+2}sqrt{x+7}-2sqrt{x+7}-3sqrt{x+2}+6}{xsqrt{4x+1}-2sqrt{4x+1}-3x+6}=lim_{x to2}frac{(a-2)(b-3)}{(x-2)(c-3)}
          $



          Do you know what to do now?






          share|cite|improve this answer









          $endgroup$



          Hint:let $sqrt{x+2}=a,sqrt{x+7}=b$ and $sqrt{4x+1}=c$



          $
          lim_{x to2} frac{sqrt{x+2}sqrt{x+7}-2sqrt{x+7}-3sqrt{x+2}+6}{xsqrt{4x+1}-2sqrt{4x+1}-3x+6}=lim_{x to2}frac{(a-2)(b-3)}{(x-2)(c-3)}
          $



          Do you know what to do now?







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 29 at 9:24









          abc...abc...

          3,237739




          3,237739












          • $begingroup$
            I know now what to do, but can you please explain where did number 6 go?
            $endgroup$
            – krneki
            Jan 29 at 9:36










          • $begingroup$
            Note that (a-2)(b-3)=ab-2b-3a+6
            $endgroup$
            – abc...
            Jan 29 at 20:58


















          • $begingroup$
            I know now what to do, but can you please explain where did number 6 go?
            $endgroup$
            – krneki
            Jan 29 at 9:36










          • $begingroup$
            Note that (a-2)(b-3)=ab-2b-3a+6
            $endgroup$
            – abc...
            Jan 29 at 20:58
















          $begingroup$
          I know now what to do, but can you please explain where did number 6 go?
          $endgroup$
          – krneki
          Jan 29 at 9:36




          $begingroup$
          I know now what to do, but can you please explain where did number 6 go?
          $endgroup$
          – krneki
          Jan 29 at 9:36












          $begingroup$
          Note that (a-2)(b-3)=ab-2b-3a+6
          $endgroup$
          – abc...
          Jan 29 at 20:58




          $begingroup$
          Note that (a-2)(b-3)=ab-2b-3a+6
          $endgroup$
          – abc...
          Jan 29 at 20:58


















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