Mixing
Interpretation of a game on public good contribution
"Consider 2 identical players (i.e. i = 1, 2) with utility function:
πi = b(qi + q-i) - cqi.
Where qi is equal to one if player i contributes to the provision of a public good and zero if she does not, q-i is the sum of the contributions by all other players, b is the constant marginal benefit of contributing to the public good, and c is the cost of contributing to the good.
Suppose that player 2 will always play C (ie, will always cooperate). For
what values of “b” will player 1 play C?"
My question is how is it possible to compute the values of "b" for which Player 1 will play C (provided that Player 2 always plays C) when cqi is not given nor is it any other way through which it can be calculated?
game-theory utility
asked Nov 20 '18 at 20:53
Alex Simion
204
add a comment |
"Consider 2 identical players (i.e. i = 1, 2) with utility function:
πi = b(qi + q-i) - cqi.
Where qi is equal to one if player i contributes to the provision of a public good and zero if she does not, q-i is the sum of the contributions by all other players, b is the constant marginal benefit of contributing to the public good, and c is the cost of contributing to the good.
Suppose that player 2 will always play C (ie, will always cooperate). For
what values of “b” will player 1 play C?"
My question is how is it possible to compute the values of "b" for which Player 1 will play C (provided that Player 2 always plays C) when cqi is not given nor is it any other way through which it can be calculated?
game-theory utility
asked Nov 20 '18 at 20:53
Alex Simion
204
add a comment |
"Consider 2 identical players (i.e. i = 1, 2) with utility function:
πi = b(qi + q-i) - cqi.
Where qi is equal to one if player i contributes to the provision of a public good and zero if she does not, q-i is the sum of the contributions by all other players, b is the constant marginal benefit of contributing to the public good, and c is the cost of contributing to the good.
Suppose that player 2 will always play C (ie, will always cooperate). For
what values of “b” will player 1 play C?"
My question is how is it possible to compute the values of "b" for which Player 1 will play C (provided that Player 2 always plays C) when cqi is not given nor is it any other way through which it can be calculated?
game-theory utility
asked Nov 20 '18 at 20:53
Alex Simion
204
"Consider 2 identical players (i.e. i = 1, 2) with utility function:
πi = b(qi + q-i) - cqi.
Where qi is equal to one if player i contributes to the provision of a public good and zero if she does not, q-i is the sum of the contributions by all other players, b is the constant marginal benefit of contributing to the public good, and c is the cost of contributing to the good.
Suppose that player 2 will always play C (ie, will always cooperate). For
what values of “b” will player 1 play C?"
My question is how is it possible to compute the values of "b" for which Player 1 will play C (provided that Player 2 always plays C) when cqi is not given nor is it any other way through which it can be calculated?
game-theory utility
game-theory utility
asked Nov 20 '18 at 20:53
Alex Simion
204
asked Nov 20 '18 at 20:53
Alex Simion
204
asked Nov 20 '18 at 20:53
Alex Simion
204
asked Nov 20 '18 at 20:53
Alex Simion
204
asked Nov 20 '18 at 20:53
Alex Simion
204
204
add a comment |
add a comment |
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