Mixing
Length of an edge
$begingroup$
My sister asked me to help her with her homework for mathematics, however frustratingly I was not able to figure out how to solve it.
The assignment is as follows where it was requested to calculate the length between G and I. How should this assignment be solved?
Thanks!
pythagorean-triples
edited Jan 25 at 17:38
hardmath
29.2k953101
asked Jan 25 at 17:28
A. HuijgenA. Huijgen
31
$endgroup$
add a comment |
$begingroup$
My sister asked me to help her with her homework for mathematics, however frustratingly I was not able to figure out how to solve it.
The assignment is as follows where it was requested to calculate the length between G and I. How should this assignment be solved?
Thanks!
pythagorean-triples
edited Jan 25 at 17:38
hardmath
29.2k953101
asked Jan 25 at 17:28
A. HuijgenA. Huijgen
31
$endgroup$
1
$begingroup$
Please include your sister's effort as well as your attempts to solve it.
$endgroup$
– John Douma
Jan 25 at 17:30
$begingroup$
What has this to do withPythagorean-triples?
$endgroup$
– José Carlos Santos
Jan 25 at 17:31
1
$begingroup$
As general advice, always compute what you can compute. Here, $overline {HE}$ is easy. From that you can get $overline {GE}$. Now you've got two right triangles left that you haven't used...
$endgroup$
– lulu
Jan 25 at 17:34
add a comment |
$begingroup$
My sister asked me to help her with her homework for mathematics, however frustratingly I was not able to figure out how to solve it.
The assignment is as follows where it was requested to calculate the length between G and I. How should this assignment be solved?
Thanks!
pythagorean-triples
edited Jan 25 at 17:38
hardmath
29.2k953101
asked Jan 25 at 17:28
A. HuijgenA. Huijgen
31
$endgroup$
My sister asked me to help her with her homework for mathematics, however frustratingly I was not able to figure out how to solve it.
The assignment is as follows where it was requested to calculate the length between G and I. How should this assignment be solved?
Thanks!
pythagorean-triples
pythagorean-triples
edited Jan 25 at 17:38
hardmath
29.2k953101
asked Jan 25 at 17:28
A. HuijgenA. Huijgen
31
edited Jan 25 at 17:38
hardmath
29.2k953101
asked Jan 25 at 17:28
A. HuijgenA. Huijgen
31
edited Jan 25 at 17:38
hardmath
29.2k953101
edited Jan 25 at 17:38
hardmath
29.2k953101
edited Jan 25 at 17:38
hardmath
29.2k953101
29.2k953101
asked Jan 25 at 17:28
A. HuijgenA. Huijgen
31
asked Jan 25 at 17:28
A. HuijgenA. Huijgen
31
asked Jan 25 at 17:28
A. HuijgenA. Huijgen
31
31
1
$begingroup$
Please include your sister's effort as well as your attempts to solve it.
$endgroup$
– John Douma
Jan 25 at 17:30
$begingroup$
What has this to do withPythagorean-triples?
$endgroup$
– José Carlos Santos
Jan 25 at 17:31
1
$begingroup$
As general advice, always compute what you can compute. Here, $overline {HE}$ is easy. From that you can get $overline {GE}$. Now you've got two right triangles left that you haven't used...
$endgroup$
– lulu
Jan 25 at 17:34
add a comment |
1
$begingroup$
Please include your sister's effort as well as your attempts to solve it.
$endgroup$
– John Douma
Jan 25 at 17:30
$begingroup$
What has this to do withPythagorean-triples?
$endgroup$
– José Carlos Santos
Jan 25 at 17:31
1
$begingroup$
As general advice, always compute what you can compute. Here, $overline {HE}$ is easy. From that you can get $overline {GE}$. Now you've got two right triangles left that you haven't used...
$endgroup$
– lulu
Jan 25 at 17:34
1
1
$begingroup$
Please include your sister's effort as well as your attempts to solve it.
$endgroup$
– John Douma
Jan 25 at 17:30
$begingroup$
Please include your sister's effort as well as your attempts to solve it.
$endgroup$
– John Douma
Jan 25 at 17:30
$begingroup$
What has this to do with
Pythagorean-triples?$endgroup$
– José Carlos Santos
Jan 25 at 17:31
$begingroup$
What has this to do with
Pythagorean-triples?$endgroup$
– José Carlos Santos
Jan 25 at 17:31
1
1
$begingroup$
As general advice, always compute what you can compute. Here, $overline {HE}$ is easy. From that you can get $overline {GE}$. Now you've got two right triangles left that you haven't used...
$endgroup$
– lulu
Jan 25 at 17:34
$begingroup$
As general advice, always compute what you can compute. Here, $overline {HE}$ is easy. From that you can get $overline {GE}$. Now you've got two right triangles left that you haven't used...
$endgroup$
– lulu
Jan 25 at 17:34
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
It is a messy plane geometry and algebra problem. All the following using Pythagorean theorem. First $|H-E|=4$, then $|E-G|^2=32$. Let $x=|E-I|$ and $h=|G-I|$. The equation for $x$ and $h$ are $x^2+h^2=32$ and $(5-x)^2+h^2=49$. Solving these equations gives $x=.8$ and $h=5.6$, where $h$ is the answer to the problem.
answered Jan 25 at 18:00
herb steinbergherb steinberg
3,0682310
$endgroup$
$begingroup$
The use of Cartesian coordinates (analytic geometry) may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 18:15
$begingroup$
Thanks herb steinberg, this is indeed the way she was expected to solve it! My sister got some algebra lectures a while ago, so she apparently had to combine it with the current lectures about the pythagorean theorem. Nice ingenious way of solving it, thanks again!
$endgroup$
– A. Huijgen
Jan 25 at 19:05
add a comment |
$begingroup$
Hint: Let $$angle{EFG}=alpha$$ then $$cos(alpha)=frac{3}{5}$$ and $$sin(alpha)=frac{GI}{7}$$
answered Jan 25 at 17:36
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
77.8k42866
$endgroup$
$begingroup$
I'd be concerned that trigonometry may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 17:59
$begingroup$
Thanks Dr. Sonnhard Graubner for your response. So far she hasn't got lectures about trigonometry, but nice to see there are multiple ways to solve it.
$endgroup$
– A. Huijgen
Jan 25 at 19:06
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
It is a messy plane geometry and algebra problem. All the following using Pythagorean theorem. First $|H-E|=4$, then $|E-G|^2=32$. Let $x=|E-I|$ and $h=|G-I|$. The equation for $x$ and $h$ are $x^2+h^2=32$ and $(5-x)^2+h^2=49$. Solving these equations gives $x=.8$ and $h=5.6$, where $h$ is the answer to the problem.
answered Jan 25 at 18:00
herb steinbergherb steinberg
3,0682310
$endgroup$
$begingroup$
The use of Cartesian coordinates (analytic geometry) may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 18:15
$begingroup$
Thanks herb steinberg, this is indeed the way she was expected to solve it! My sister got some algebra lectures a while ago, so she apparently had to combine it with the current lectures about the pythagorean theorem. Nice ingenious way of solving it, thanks again!
$endgroup$
– A. Huijgen
Jan 25 at 19:05
add a comment |
$begingroup$
It is a messy plane geometry and algebra problem. All the following using Pythagorean theorem. First $|H-E|=4$, then $|E-G|^2=32$. Let $x=|E-I|$ and $h=|G-I|$. The equation for $x$ and $h$ are $x^2+h^2=32$ and $(5-x)^2+h^2=49$. Solving these equations gives $x=.8$ and $h=5.6$, where $h$ is the answer to the problem.
answered Jan 25 at 18:00
herb steinbergherb steinberg
3,0682310
$endgroup$
$begingroup$
The use of Cartesian coordinates (analytic geometry) may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 18:15
$begingroup$
Thanks herb steinberg, this is indeed the way she was expected to solve it! My sister got some algebra lectures a while ago, so she apparently had to combine it with the current lectures about the pythagorean theorem. Nice ingenious way of solving it, thanks again!
$endgroup$
– A. Huijgen
Jan 25 at 19:05
add a comment |
$begingroup$
It is a messy plane geometry and algebra problem. All the following using Pythagorean theorem. First $|H-E|=4$, then $|E-G|^2=32$. Let $x=|E-I|$ and $h=|G-I|$. The equation for $x$ and $h$ are $x^2+h^2=32$ and $(5-x)^2+h^2=49$. Solving these equations gives $x=.8$ and $h=5.6$, where $h$ is the answer to the problem.
answered Jan 25 at 18:00
herb steinbergherb steinberg
3,0682310
$endgroup$
It is a messy plane geometry and algebra problem. All the following using Pythagorean theorem. First $|H-E|=4$, then $|E-G|^2=32$. Let $x=|E-I|$ and $h=|G-I|$. The equation for $x$ and $h$ are $x^2+h^2=32$ and $(5-x)^2+h^2=49$. Solving these equations gives $x=.8$ and $h=5.6$, where $h$ is the answer to the problem.
answered Jan 25 at 18:00
herb steinbergherb steinberg
3,0682310
answered Jan 25 at 18:00
herb steinbergherb steinberg
3,0682310
answered Jan 25 at 18:00
herb steinbergherb steinberg
3,0682310
answered Jan 25 at 18:00
herb steinbergherb steinberg
3,0682310
3,0682310
$begingroup$
The use of Cartesian coordinates (analytic geometry) may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 18:15
$begingroup$
Thanks herb steinberg, this is indeed the way she was expected to solve it! My sister got some algebra lectures a while ago, so she apparently had to combine it with the current lectures about the pythagorean theorem. Nice ingenious way of solving it, thanks again!
$endgroup$
– A. Huijgen
Jan 25 at 19:05
add a comment |
$begingroup$
The use of Cartesian coordinates (analytic geometry) may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 18:15
$begingroup$
Thanks herb steinberg, this is indeed the way she was expected to solve it! My sister got some algebra lectures a while ago, so she apparently had to combine it with the current lectures about the pythagorean theorem. Nice ingenious way of solving it, thanks again!
$endgroup$
– A. Huijgen
Jan 25 at 19:05
$begingroup$
The use of Cartesian coordinates (analytic geometry) may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 18:15
$begingroup$
The use of Cartesian coordinates (analytic geometry) may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 18:15
$begingroup$
Thanks herb steinberg, this is indeed the way she was expected to solve it! My sister got some algebra lectures a while ago, so she apparently had to combine it with the current lectures about the pythagorean theorem. Nice ingenious way of solving it, thanks again!
$endgroup$
– A. Huijgen
Jan 25 at 19:05
$begingroup$
Thanks herb steinberg, this is indeed the way she was expected to solve it! My sister got some algebra lectures a while ago, so she apparently had to combine it with the current lectures about the pythagorean theorem. Nice ingenious way of solving it, thanks again!
$endgroup$
– A. Huijgen
Jan 25 at 19:05
add a comment |
$begingroup$
Hint: Let $$angle{EFG}=alpha$$ then $$cos(alpha)=frac{3}{5}$$ and $$sin(alpha)=frac{GI}{7}$$
answered Jan 25 at 17:36
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
77.8k42866
$endgroup$
$begingroup$
I'd be concerned that trigonometry may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 17:59
$begingroup$
Thanks Dr. Sonnhard Graubner for your response. So far she hasn't got lectures about trigonometry, but nice to see there are multiple ways to solve it.
$endgroup$
– A. Huijgen
Jan 25 at 19:06
add a comment |
$begingroup$
Hint: Let $$angle{EFG}=alpha$$ then $$cos(alpha)=frac{3}{5}$$ and $$sin(alpha)=frac{GI}{7}$$
answered Jan 25 at 17:36
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
77.8k42866
$endgroup$
$begingroup$
I'd be concerned that trigonometry may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 17:59
$begingroup$
Thanks Dr. Sonnhard Graubner for your response. So far she hasn't got lectures about trigonometry, but nice to see there are multiple ways to solve it.
$endgroup$
– A. Huijgen
Jan 25 at 19:06
add a comment |
$begingroup$
Hint: Let $$angle{EFG}=alpha$$ then $$cos(alpha)=frac{3}{5}$$ and $$sin(alpha)=frac{GI}{7}$$
answered Jan 25 at 17:36
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
77.8k42866
$endgroup$
Hint: Let $$angle{EFG}=alpha$$ then $$cos(alpha)=frac{3}{5}$$ and $$sin(alpha)=frac{GI}{7}$$
answered Jan 25 at 17:36
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
77.8k42866
answered Jan 25 at 17:36
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
77.8k42866
answered Jan 25 at 17:36
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
77.8k42866
answered Jan 25 at 17:36
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
77.8k42866
77.8k42866
$begingroup$
I'd be concerned that trigonometry may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 17:59
$begingroup$
Thanks Dr. Sonnhard Graubner for your response. So far she hasn't got lectures about trigonometry, but nice to see there are multiple ways to solve it.
$endgroup$
– A. Huijgen
Jan 25 at 19:06
add a comment |
$begingroup$
I'd be concerned that trigonometry may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 17:59
$begingroup$
Thanks Dr. Sonnhard Graubner for your response. So far she hasn't got lectures about trigonometry, but nice to see there are multiple ways to solve it.
$endgroup$
– A. Huijgen
Jan 25 at 19:06
$begingroup$
I'd be concerned that trigonometry may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 17:59
$begingroup$
I'd be concerned that trigonometry may be outside the scope of the course material this exercise was intended to reinforce.
$endgroup$
– hardmath
Jan 25 at 17:59
$begingroup$
Thanks Dr. Sonnhard Graubner for your response. So far she hasn't got lectures about trigonometry, but nice to see there are multiple ways to solve it.
$endgroup$
– A. Huijgen
Jan 25 at 19:06
$begingroup$
Thanks Dr. Sonnhard Graubner for your response. So far she hasn't got lectures about trigonometry, but nice to see there are multiple ways to solve it.
$endgroup$
– A. Huijgen
Jan 25 at 19:06
add a comment |
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1
$begingroup$
Please include your sister's effort as well as your attempts to solve it.
$endgroup$
– John Douma
Jan 25 at 17:30
$begingroup$
What has this to do with
Pythagorean-triples?$endgroup$
– José Carlos Santos
Jan 25 at 17:31
1
$begingroup$
As general advice, always compute what you can compute. Here, $overline {HE}$ is easy. From that you can get $overline {GE}$. Now you've got two right triangles left that you haven't used...
$endgroup$
– lulu
Jan 25 at 17:34