Bounded linear functional separating a hyperplane and a point
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I want to find examples of normed linear space, a convex subset $C$ of $X$ and a point $x_0in Xsetminus C$ such that for all bounded linear functionals $f:Xto mathbb{K}$, Re$f(x_0)<sup{text{Re}f(x):xin C}$.
If I start with a proper dense subspace $C$ of $X$, then there exists a sequence $(x_n)$ in $C$ such that $x_nto x_0$. Thus for all bounded linear functional $f$ on $X$, Re$f(x_n)to text{Re}f(x_0)$. Thus Re$f(x_0)leq sup{text{Re}f(x):xin C}$. But how to show the strict inequality?
functional-analysis convex-analysis
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add a comment |
$begingroup$
I want to find examples of normed linear space, a convex subset $C$ of $X$ and a point $x_0in Xsetminus C$ such that for all bounded linear functionals $f:Xto mathbb{K}$, Re$f(x_0)<sup{text{Re}f(x):xin C}$.
If I start with a proper dense subspace $C$ of $X$, then there exists a sequence $(x_n)$ in $C$ such that $x_nto x_0$. Thus for all bounded linear functional $f$ on $X$, Re$f(x_n)to text{Re}f(x_0)$. Thus Re$f(x_0)leq sup{text{Re}f(x):xin C}$. But how to show the strict inequality?
functional-analysis convex-analysis
$endgroup$
add a comment |
$begingroup$
I want to find examples of normed linear space, a convex subset $C$ of $X$ and a point $x_0in Xsetminus C$ such that for all bounded linear functionals $f:Xto mathbb{K}$, Re$f(x_0)<sup{text{Re}f(x):xin C}$.
If I start with a proper dense subspace $C$ of $X$, then there exists a sequence $(x_n)$ in $C$ such that $x_nto x_0$. Thus for all bounded linear functional $f$ on $X$, Re$f(x_n)to text{Re}f(x_0)$. Thus Re$f(x_0)leq sup{text{Re}f(x):xin C}$. But how to show the strict inequality?
functional-analysis convex-analysis
$endgroup$
I want to find examples of normed linear space, a convex subset $C$ of $X$ and a point $x_0in Xsetminus C$ such that for all bounded linear functionals $f:Xto mathbb{K}$, Re$f(x_0)<sup{text{Re}f(x):xin C}$.
If I start with a proper dense subspace $C$ of $X$, then there exists a sequence $(x_n)$ in $C$ such that $x_nto x_0$. Thus for all bounded linear functional $f$ on $X$, Re$f(x_n)to text{Re}f(x_0)$. Thus Re$f(x_0)leq sup{text{Re}f(x):xin C}$. But how to show the strict inequality?
functional-analysis convex-analysis
functional-analysis convex-analysis
asked Feb 3 at 3:38
AnupamAnupam
2,5741925
2,5741925
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