Compute $mathbb{P}{ W_t < 0 , , text{for all} , , 1 < t < 2}$ for a Brownian motion $(W_t)_{t geq...












0












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Let $(W_t)_{t ge 0}$ be a standard one-dimensional Brownian motion.
Calculate $$mathbb{P}{ W_t < 0 , , text{for all} , , 1 < t < 2}.$$
I can only think that this will be conditional on $W_1$. Please tell how to proceed?










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closed as off-topic by Did, José Carlos Santos, mrtaurho, YiFan, Cesareo Feb 4 at 11:45


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, José Carlos Santos, mrtaurho, YiFan, Cesareo

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    Condition on $W_1$.
    $endgroup$
    – Did
    Feb 3 at 8:23










  • $begingroup$
    @JoséCarlosSantos, Som: Why approve an absurd edit?
    $endgroup$
    – Did
    Feb 3 at 8:24










  • $begingroup$
    @pointguard0 More care with the edits you suggest, please.
    $endgroup$
    – Did
    Feb 3 at 8:25










  • $begingroup$
    P(Wt<0 for all 1<t<2)
    $endgroup$
    – Som
    Feb 3 at 8:40










  • $begingroup$
    Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
    $endgroup$
    – Did
    Feb 3 at 8:43
















0












$begingroup$


Let $(W_t)_{t ge 0}$ be a standard one-dimensional Brownian motion.
Calculate $$mathbb{P}{ W_t < 0 , , text{for all} , , 1 < t < 2}.$$
I can only think that this will be conditional on $W_1$. Please tell how to proceed?










share|cite|improve this question











$endgroup$



closed as off-topic by Did, José Carlos Santos, mrtaurho, YiFan, Cesareo Feb 4 at 11:45


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, José Carlos Santos, mrtaurho, YiFan, Cesareo

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    Condition on $W_1$.
    $endgroup$
    – Did
    Feb 3 at 8:23










  • $begingroup$
    @JoséCarlosSantos, Som: Why approve an absurd edit?
    $endgroup$
    – Did
    Feb 3 at 8:24










  • $begingroup$
    @pointguard0 More care with the edits you suggest, please.
    $endgroup$
    – Did
    Feb 3 at 8:25










  • $begingroup$
    P(Wt<0 for all 1<t<2)
    $endgroup$
    – Som
    Feb 3 at 8:40










  • $begingroup$
    Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
    $endgroup$
    – Did
    Feb 3 at 8:43














0












0








0


2



$begingroup$


Let $(W_t)_{t ge 0}$ be a standard one-dimensional Brownian motion.
Calculate $$mathbb{P}{ W_t < 0 , , text{for all} , , 1 < t < 2}.$$
I can only think that this will be conditional on $W_1$. Please tell how to proceed?










share|cite|improve this question











$endgroup$




Let $(W_t)_{t ge 0}$ be a standard one-dimensional Brownian motion.
Calculate $$mathbb{P}{ W_t < 0 , , text{for all} , , 1 < t < 2}.$$
I can only think that this will be conditional on $W_1$. Please tell how to proceed?







probability-theory stochastic-processes brownian-motion






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share|cite|improve this question













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share|cite|improve this question








edited Feb 3 at 10:07









saz

82.5k862131




82.5k862131










asked Feb 3 at 7:35









SomSom

43




43




closed as off-topic by Did, José Carlos Santos, mrtaurho, YiFan, Cesareo Feb 4 at 11:45


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, José Carlos Santos, mrtaurho, YiFan, Cesareo

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by Did, José Carlos Santos, mrtaurho, YiFan, Cesareo Feb 4 at 11:45


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, José Carlos Santos, mrtaurho, YiFan, Cesareo

If this question can be reworded to fit the rules in the help center, please edit the question.












  • $begingroup$
    Condition on $W_1$.
    $endgroup$
    – Did
    Feb 3 at 8:23










  • $begingroup$
    @JoséCarlosSantos, Som: Why approve an absurd edit?
    $endgroup$
    – Did
    Feb 3 at 8:24










  • $begingroup$
    @pointguard0 More care with the edits you suggest, please.
    $endgroup$
    – Did
    Feb 3 at 8:25










  • $begingroup$
    P(Wt<0 for all 1<t<2)
    $endgroup$
    – Som
    Feb 3 at 8:40










  • $begingroup$
    Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
    $endgroup$
    – Did
    Feb 3 at 8:43


















  • $begingroup$
    Condition on $W_1$.
    $endgroup$
    – Did
    Feb 3 at 8:23










  • $begingroup$
    @JoséCarlosSantos, Som: Why approve an absurd edit?
    $endgroup$
    – Did
    Feb 3 at 8:24










  • $begingroup$
    @pointguard0 More care with the edits you suggest, please.
    $endgroup$
    – Did
    Feb 3 at 8:25










  • $begingroup$
    P(Wt<0 for all 1<t<2)
    $endgroup$
    – Som
    Feb 3 at 8:40










  • $begingroup$
    Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
    $endgroup$
    – Did
    Feb 3 at 8:43
















$begingroup$
Condition on $W_1$.
$endgroup$
– Did
Feb 3 at 8:23




$begingroup$
Condition on $W_1$.
$endgroup$
– Did
Feb 3 at 8:23












$begingroup$
@JoséCarlosSantos, Som: Why approve an absurd edit?
$endgroup$
– Did
Feb 3 at 8:24




$begingroup$
@JoséCarlosSantos, Som: Why approve an absurd edit?
$endgroup$
– Did
Feb 3 at 8:24












$begingroup$
@pointguard0 More care with the edits you suggest, please.
$endgroup$
– Did
Feb 3 at 8:25




$begingroup$
@pointguard0 More care with the edits you suggest, please.
$endgroup$
– Did
Feb 3 at 8:25












$begingroup$
P(Wt<0 for all 1<t<2)
$endgroup$
– Som
Feb 3 at 8:40




$begingroup$
P(Wt<0 for all 1<t<2)
$endgroup$
– Som
Feb 3 at 8:40












$begingroup$
Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
$endgroup$
– Did
Feb 3 at 8:43




$begingroup$
Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
$endgroup$
– Did
Feb 3 at 8:43










1 Answer
1






active

oldest

votes


















3












$begingroup$

Hints: Set $$B_t := W_{1+t}-W_1.$$




  1. Check (or recall) that $(B_t)_{t geq 0}$ is a Brownian motion and that $(B_t)_{t geq 0}$ is independent from $mathcal{F}_1^W:=sigma(W_s; s leq 1)$.

  2. Use the independence of $(B_t)_{t geq 0}$ and $W_1$ to show that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2) mid W_1) = f(W_1)$$ where $$f(x) := mathbb{P}(x+B_t < 0, , text{for all $t in (0,1)$}). tag{1}$$

  3. Prove that $f(x)=0$ for all $x geq 0$. (Hint: What happens close to $t=0$?)

  4. Fix $x<0$. Show that $$f(x) = mathbb{P}(tau_{-x} geq 1)$$ for the stopping time $$tau_{-x} := inf{t>0; B_t geq -x}.$$ Conclude from the reflection principle that $$f(x) = mathbb{P}(|B_1|<-x),$$ and so $$f(x)=1-2Phi(x)$$ where $Phi$ is the cdf of the centered standard Gaussian distribution with density $varphi$.

  5. Combining the above steps gives begin{align*} mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) &= mathbb{E} left[ left( 1- 2Phi(W_1)right) 1_{{W_1<0}} right] \ &= frac{1}{2} - 2 int_{-infty}^0 Phi(x) varphi(x) , dx. end{align*}

  6. Conclude that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) = frac{1}{4}; $$ see e.g. this answer for how to compute the integral in Step 5.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Feb 3 at 12:08










  • $begingroup$
    @Did Thank you.
    $endgroup$
    – saz
    Feb 3 at 12:13


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3












$begingroup$

Hints: Set $$B_t := W_{1+t}-W_1.$$




  1. Check (or recall) that $(B_t)_{t geq 0}$ is a Brownian motion and that $(B_t)_{t geq 0}$ is independent from $mathcal{F}_1^W:=sigma(W_s; s leq 1)$.

  2. Use the independence of $(B_t)_{t geq 0}$ and $W_1$ to show that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2) mid W_1) = f(W_1)$$ where $$f(x) := mathbb{P}(x+B_t < 0, , text{for all $t in (0,1)$}). tag{1}$$

  3. Prove that $f(x)=0$ for all $x geq 0$. (Hint: What happens close to $t=0$?)

  4. Fix $x<0$. Show that $$f(x) = mathbb{P}(tau_{-x} geq 1)$$ for the stopping time $$tau_{-x} := inf{t>0; B_t geq -x}.$$ Conclude from the reflection principle that $$f(x) = mathbb{P}(|B_1|<-x),$$ and so $$f(x)=1-2Phi(x)$$ where $Phi$ is the cdf of the centered standard Gaussian distribution with density $varphi$.

  5. Combining the above steps gives begin{align*} mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) &= mathbb{E} left[ left( 1- 2Phi(W_1)right) 1_{{W_1<0}} right] \ &= frac{1}{2} - 2 int_{-infty}^0 Phi(x) varphi(x) , dx. end{align*}

  6. Conclude that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) = frac{1}{4}; $$ see e.g. this answer for how to compute the integral in Step 5.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Feb 3 at 12:08










  • $begingroup$
    @Did Thank you.
    $endgroup$
    – saz
    Feb 3 at 12:13
















3












$begingroup$

Hints: Set $$B_t := W_{1+t}-W_1.$$




  1. Check (or recall) that $(B_t)_{t geq 0}$ is a Brownian motion and that $(B_t)_{t geq 0}$ is independent from $mathcal{F}_1^W:=sigma(W_s; s leq 1)$.

  2. Use the independence of $(B_t)_{t geq 0}$ and $W_1$ to show that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2) mid W_1) = f(W_1)$$ where $$f(x) := mathbb{P}(x+B_t < 0, , text{for all $t in (0,1)$}). tag{1}$$

  3. Prove that $f(x)=0$ for all $x geq 0$. (Hint: What happens close to $t=0$?)

  4. Fix $x<0$. Show that $$f(x) = mathbb{P}(tau_{-x} geq 1)$$ for the stopping time $$tau_{-x} := inf{t>0; B_t geq -x}.$$ Conclude from the reflection principle that $$f(x) = mathbb{P}(|B_1|<-x),$$ and so $$f(x)=1-2Phi(x)$$ where $Phi$ is the cdf of the centered standard Gaussian distribution with density $varphi$.

  5. Combining the above steps gives begin{align*} mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) &= mathbb{E} left[ left( 1- 2Phi(W_1)right) 1_{{W_1<0}} right] \ &= frac{1}{2} - 2 int_{-infty}^0 Phi(x) varphi(x) , dx. end{align*}

  6. Conclude that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) = frac{1}{4}; $$ see e.g. this answer for how to compute the integral in Step 5.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Feb 3 at 12:08










  • $begingroup$
    @Did Thank you.
    $endgroup$
    – saz
    Feb 3 at 12:13














3












3








3





$begingroup$

Hints: Set $$B_t := W_{1+t}-W_1.$$




  1. Check (or recall) that $(B_t)_{t geq 0}$ is a Brownian motion and that $(B_t)_{t geq 0}$ is independent from $mathcal{F}_1^W:=sigma(W_s; s leq 1)$.

  2. Use the independence of $(B_t)_{t geq 0}$ and $W_1$ to show that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2) mid W_1) = f(W_1)$$ where $$f(x) := mathbb{P}(x+B_t < 0, , text{for all $t in (0,1)$}). tag{1}$$

  3. Prove that $f(x)=0$ for all $x geq 0$. (Hint: What happens close to $t=0$?)

  4. Fix $x<0$. Show that $$f(x) = mathbb{P}(tau_{-x} geq 1)$$ for the stopping time $$tau_{-x} := inf{t>0; B_t geq -x}.$$ Conclude from the reflection principle that $$f(x) = mathbb{P}(|B_1|<-x),$$ and so $$f(x)=1-2Phi(x)$$ where $Phi$ is the cdf of the centered standard Gaussian distribution with density $varphi$.

  5. Combining the above steps gives begin{align*} mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) &= mathbb{E} left[ left( 1- 2Phi(W_1)right) 1_{{W_1<0}} right] \ &= frac{1}{2} - 2 int_{-infty}^0 Phi(x) varphi(x) , dx. end{align*}

  6. Conclude that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) = frac{1}{4}; $$ see e.g. this answer for how to compute the integral in Step 5.






share|cite|improve this answer











$endgroup$



Hints: Set $$B_t := W_{1+t}-W_1.$$




  1. Check (or recall) that $(B_t)_{t geq 0}$ is a Brownian motion and that $(B_t)_{t geq 0}$ is independent from $mathcal{F}_1^W:=sigma(W_s; s leq 1)$.

  2. Use the independence of $(B_t)_{t geq 0}$ and $W_1$ to show that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2) mid W_1) = f(W_1)$$ where $$f(x) := mathbb{P}(x+B_t < 0, , text{for all $t in (0,1)$}). tag{1}$$

  3. Prove that $f(x)=0$ for all $x geq 0$. (Hint: What happens close to $t=0$?)

  4. Fix $x<0$. Show that $$f(x) = mathbb{P}(tau_{-x} geq 1)$$ for the stopping time $$tau_{-x} := inf{t>0; B_t geq -x}.$$ Conclude from the reflection principle that $$f(x) = mathbb{P}(|B_1|<-x),$$ and so $$f(x)=1-2Phi(x)$$ where $Phi$ is the cdf of the centered standard Gaussian distribution with density $varphi$.

  5. Combining the above steps gives begin{align*} mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) &= mathbb{E} left[ left( 1- 2Phi(W_1)right) 1_{{W_1<0}} right] \ &= frac{1}{2} - 2 int_{-infty}^0 Phi(x) varphi(x) , dx. end{align*}

  6. Conclude that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) = frac{1}{4}; $$ see e.g. this answer for how to compute the integral in Step 5.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Feb 3 at 18:54

























answered Feb 3 at 9:01









sazsaz

82.5k862131




82.5k862131












  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Feb 3 at 12:08










  • $begingroup$
    @Did Thank you.
    $endgroup$
    – saz
    Feb 3 at 12:13


















  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Feb 3 at 12:08










  • $begingroup$
    @Did Thank you.
    $endgroup$
    – saz
    Feb 3 at 12:13
















$begingroup$
Yep. (+1) $ $ $ $
$endgroup$
– Did
Feb 3 at 12:08




$begingroup$
Yep. (+1) $ $ $ $
$endgroup$
– Did
Feb 3 at 12:08












$begingroup$
@Did Thank you.
$endgroup$
– saz
Feb 3 at 12:13




$begingroup$
@Did Thank you.
$endgroup$
– saz
Feb 3 at 12:13



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