Compute $mathbb{P}{ W_t < 0 , , text{for all} , , 1 < t < 2}$ for a Brownian motion $(W_t)_{t geq...












0












$begingroup$


Let $(W_t)_{t ge 0}$ be a standard one-dimensional Brownian motion.
Calculate $$mathbb{P}{ W_t < 0 , , text{for all} , , 1 < t < 2}.$$
I can only think that this will be conditional on $W_1$. Please tell how to proceed?










share|cite|improve this question











$endgroup$



closed as off-topic by Did, José Carlos Santos, mrtaurho, YiFan, Cesareo Feb 4 at 11:45


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, José Carlos Santos, mrtaurho, YiFan, Cesareo

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    Condition on $W_1$.
    $endgroup$
    – Did
    Feb 3 at 8:23










  • $begingroup$
    @JoséCarlosSantos, Som: Why approve an absurd edit?
    $endgroup$
    – Did
    Feb 3 at 8:24










  • $begingroup$
    @pointguard0 More care with the edits you suggest, please.
    $endgroup$
    – Did
    Feb 3 at 8:25










  • $begingroup$
    P(Wt<0 for all 1<t<2)
    $endgroup$
    – Som
    Feb 3 at 8:40










  • $begingroup$
    Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
    $endgroup$
    – Did
    Feb 3 at 8:43
















0












$begingroup$


Let $(W_t)_{t ge 0}$ be a standard one-dimensional Brownian motion.
Calculate $$mathbb{P}{ W_t < 0 , , text{for all} , , 1 < t < 2}.$$
I can only think that this will be conditional on $W_1$. Please tell how to proceed?










share|cite|improve this question











$endgroup$



closed as off-topic by Did, José Carlos Santos, mrtaurho, YiFan, Cesareo Feb 4 at 11:45


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, José Carlos Santos, mrtaurho, YiFan, Cesareo

If this question can be reworded to fit the rules in the help center, please edit the question.
















  • $begingroup$
    Condition on $W_1$.
    $endgroup$
    – Did
    Feb 3 at 8:23










  • $begingroup$
    @JoséCarlosSantos, Som: Why approve an absurd edit?
    $endgroup$
    – Did
    Feb 3 at 8:24










  • $begingroup$
    @pointguard0 More care with the edits you suggest, please.
    $endgroup$
    – Did
    Feb 3 at 8:25










  • $begingroup$
    P(Wt<0 for all 1<t<2)
    $endgroup$
    – Som
    Feb 3 at 8:40










  • $begingroup$
    Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
    $endgroup$
    – Did
    Feb 3 at 8:43














0












0








0


2



$begingroup$


Let $(W_t)_{t ge 0}$ be a standard one-dimensional Brownian motion.
Calculate $$mathbb{P}{ W_t < 0 , , text{for all} , , 1 < t < 2}.$$
I can only think that this will be conditional on $W_1$. Please tell how to proceed?










share|cite|improve this question











$endgroup$




Let $(W_t)_{t ge 0}$ be a standard one-dimensional Brownian motion.
Calculate $$mathbb{P}{ W_t < 0 , , text{for all} , , 1 < t < 2}.$$
I can only think that this will be conditional on $W_1$. Please tell how to proceed?







probability-theory stochastic-processes brownian-motion






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Feb 3 at 10:07









saz

82.5k862131




82.5k862131










asked Feb 3 at 7:35









SomSom

43




43




closed as off-topic by Did, José Carlos Santos, mrtaurho, YiFan, Cesareo Feb 4 at 11:45


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, José Carlos Santos, mrtaurho, YiFan, Cesareo

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by Did, José Carlos Santos, mrtaurho, YiFan, Cesareo Feb 4 at 11:45


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, José Carlos Santos, mrtaurho, YiFan, Cesareo

If this question can be reworded to fit the rules in the help center, please edit the question.












  • $begingroup$
    Condition on $W_1$.
    $endgroup$
    – Did
    Feb 3 at 8:23










  • $begingroup$
    @JoséCarlosSantos, Som: Why approve an absurd edit?
    $endgroup$
    – Did
    Feb 3 at 8:24










  • $begingroup$
    @pointguard0 More care with the edits you suggest, please.
    $endgroup$
    – Did
    Feb 3 at 8:25










  • $begingroup$
    P(Wt<0 for all 1<t<2)
    $endgroup$
    – Som
    Feb 3 at 8:40










  • $begingroup$
    Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
    $endgroup$
    – Did
    Feb 3 at 8:43


















  • $begingroup$
    Condition on $W_1$.
    $endgroup$
    – Did
    Feb 3 at 8:23










  • $begingroup$
    @JoséCarlosSantos, Som: Why approve an absurd edit?
    $endgroup$
    – Did
    Feb 3 at 8:24










  • $begingroup$
    @pointguard0 More care with the edits you suggest, please.
    $endgroup$
    – Did
    Feb 3 at 8:25










  • $begingroup$
    P(Wt<0 for all 1<t<2)
    $endgroup$
    – Som
    Feb 3 at 8:40










  • $begingroup$
    Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
    $endgroup$
    – Did
    Feb 3 at 8:43
















$begingroup$
Condition on $W_1$.
$endgroup$
– Did
Feb 3 at 8:23




$begingroup$
Condition on $W_1$.
$endgroup$
– Did
Feb 3 at 8:23












$begingroup$
@JoséCarlosSantos, Som: Why approve an absurd edit?
$endgroup$
– Did
Feb 3 at 8:24




$begingroup$
@JoséCarlosSantos, Som: Why approve an absurd edit?
$endgroup$
– Did
Feb 3 at 8:24












$begingroup$
@pointguard0 More care with the edits you suggest, please.
$endgroup$
– Did
Feb 3 at 8:25




$begingroup$
@pointguard0 More care with the edits you suggest, please.
$endgroup$
– Did
Feb 3 at 8:25












$begingroup$
P(Wt<0 for all 1<t<2)
$endgroup$
– Som
Feb 3 at 8:40




$begingroup$
P(Wt<0 for all 1<t<2)
$endgroup$
– Som
Feb 3 at 8:40












$begingroup$
Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
$endgroup$
– Did
Feb 3 at 8:43




$begingroup$
Som: Very much so. Which is not P(Wt<0) for all 1<t<2, yes?
$endgroup$
– Did
Feb 3 at 8:43










1 Answer
1






active

oldest

votes


















3












$begingroup$

Hints: Set $$B_t := W_{1+t}-W_1.$$




  1. Check (or recall) that $(B_t)_{t geq 0}$ is a Brownian motion and that $(B_t)_{t geq 0}$ is independent from $mathcal{F}_1^W:=sigma(W_s; s leq 1)$.

  2. Use the independence of $(B_t)_{t geq 0}$ and $W_1$ to show that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2) mid W_1) = f(W_1)$$ where $$f(x) := mathbb{P}(x+B_t < 0, , text{for all $t in (0,1)$}). tag{1}$$

  3. Prove that $f(x)=0$ for all $x geq 0$. (Hint: What happens close to $t=0$?)

  4. Fix $x<0$. Show that $$f(x) = mathbb{P}(tau_{-x} geq 1)$$ for the stopping time $$tau_{-x} := inf{t>0; B_t geq -x}.$$ Conclude from the reflection principle that $$f(x) = mathbb{P}(|B_1|<-x),$$ and so $$f(x)=1-2Phi(x)$$ where $Phi$ is the cdf of the centered standard Gaussian distribution with density $varphi$.

  5. Combining the above steps gives begin{align*} mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) &= mathbb{E} left[ left( 1- 2Phi(W_1)right) 1_{{W_1<0}} right] \ &= frac{1}{2} - 2 int_{-infty}^0 Phi(x) varphi(x) , dx. end{align*}

  6. Conclude that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) = frac{1}{4}; $$ see e.g. this answer for how to compute the integral in Step 5.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Feb 3 at 12:08










  • $begingroup$
    @Did Thank you.
    $endgroup$
    – saz
    Feb 3 at 12:13


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3












$begingroup$

Hints: Set $$B_t := W_{1+t}-W_1.$$




  1. Check (or recall) that $(B_t)_{t geq 0}$ is a Brownian motion and that $(B_t)_{t geq 0}$ is independent from $mathcal{F}_1^W:=sigma(W_s; s leq 1)$.

  2. Use the independence of $(B_t)_{t geq 0}$ and $W_1$ to show that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2) mid W_1) = f(W_1)$$ where $$f(x) := mathbb{P}(x+B_t < 0, , text{for all $t in (0,1)$}). tag{1}$$

  3. Prove that $f(x)=0$ for all $x geq 0$. (Hint: What happens close to $t=0$?)

  4. Fix $x<0$. Show that $$f(x) = mathbb{P}(tau_{-x} geq 1)$$ for the stopping time $$tau_{-x} := inf{t>0; B_t geq -x}.$$ Conclude from the reflection principle that $$f(x) = mathbb{P}(|B_1|<-x),$$ and so $$f(x)=1-2Phi(x)$$ where $Phi$ is the cdf of the centered standard Gaussian distribution with density $varphi$.

  5. Combining the above steps gives begin{align*} mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) &= mathbb{E} left[ left( 1- 2Phi(W_1)right) 1_{{W_1<0}} right] \ &= frac{1}{2} - 2 int_{-infty}^0 Phi(x) varphi(x) , dx. end{align*}

  6. Conclude that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) = frac{1}{4}; $$ see e.g. this answer for how to compute the integral in Step 5.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Feb 3 at 12:08










  • $begingroup$
    @Did Thank you.
    $endgroup$
    – saz
    Feb 3 at 12:13
















3












$begingroup$

Hints: Set $$B_t := W_{1+t}-W_1.$$




  1. Check (or recall) that $(B_t)_{t geq 0}$ is a Brownian motion and that $(B_t)_{t geq 0}$ is independent from $mathcal{F}_1^W:=sigma(W_s; s leq 1)$.

  2. Use the independence of $(B_t)_{t geq 0}$ and $W_1$ to show that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2) mid W_1) = f(W_1)$$ where $$f(x) := mathbb{P}(x+B_t < 0, , text{for all $t in (0,1)$}). tag{1}$$

  3. Prove that $f(x)=0$ for all $x geq 0$. (Hint: What happens close to $t=0$?)

  4. Fix $x<0$. Show that $$f(x) = mathbb{P}(tau_{-x} geq 1)$$ for the stopping time $$tau_{-x} := inf{t>0; B_t geq -x}.$$ Conclude from the reflection principle that $$f(x) = mathbb{P}(|B_1|<-x),$$ and so $$f(x)=1-2Phi(x)$$ where $Phi$ is the cdf of the centered standard Gaussian distribution with density $varphi$.

  5. Combining the above steps gives begin{align*} mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) &= mathbb{E} left[ left( 1- 2Phi(W_1)right) 1_{{W_1<0}} right] \ &= frac{1}{2} - 2 int_{-infty}^0 Phi(x) varphi(x) , dx. end{align*}

  6. Conclude that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) = frac{1}{4}; $$ see e.g. this answer for how to compute the integral in Step 5.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Feb 3 at 12:08










  • $begingroup$
    @Did Thank you.
    $endgroup$
    – saz
    Feb 3 at 12:13














3












3








3





$begingroup$

Hints: Set $$B_t := W_{1+t}-W_1.$$




  1. Check (or recall) that $(B_t)_{t geq 0}$ is a Brownian motion and that $(B_t)_{t geq 0}$ is independent from $mathcal{F}_1^W:=sigma(W_s; s leq 1)$.

  2. Use the independence of $(B_t)_{t geq 0}$ and $W_1$ to show that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2) mid W_1) = f(W_1)$$ where $$f(x) := mathbb{P}(x+B_t < 0, , text{for all $t in (0,1)$}). tag{1}$$

  3. Prove that $f(x)=0$ for all $x geq 0$. (Hint: What happens close to $t=0$?)

  4. Fix $x<0$. Show that $$f(x) = mathbb{P}(tau_{-x} geq 1)$$ for the stopping time $$tau_{-x} := inf{t>0; B_t geq -x}.$$ Conclude from the reflection principle that $$f(x) = mathbb{P}(|B_1|<-x),$$ and so $$f(x)=1-2Phi(x)$$ where $Phi$ is the cdf of the centered standard Gaussian distribution with density $varphi$.

  5. Combining the above steps gives begin{align*} mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) &= mathbb{E} left[ left( 1- 2Phi(W_1)right) 1_{{W_1<0}} right] \ &= frac{1}{2} - 2 int_{-infty}^0 Phi(x) varphi(x) , dx. end{align*}

  6. Conclude that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) = frac{1}{4}; $$ see e.g. this answer for how to compute the integral in Step 5.






share|cite|improve this answer











$endgroup$



Hints: Set $$B_t := W_{1+t}-W_1.$$




  1. Check (or recall) that $(B_t)_{t geq 0}$ is a Brownian motion and that $(B_t)_{t geq 0}$ is independent from $mathcal{F}_1^W:=sigma(W_s; s leq 1)$.

  2. Use the independence of $(B_t)_{t geq 0}$ and $W_1$ to show that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2) mid W_1) = f(W_1)$$ where $$f(x) := mathbb{P}(x+B_t < 0, , text{for all $t in (0,1)$}). tag{1}$$

  3. Prove that $f(x)=0$ for all $x geq 0$. (Hint: What happens close to $t=0$?)

  4. Fix $x<0$. Show that $$f(x) = mathbb{P}(tau_{-x} geq 1)$$ for the stopping time $$tau_{-x} := inf{t>0; B_t geq -x}.$$ Conclude from the reflection principle that $$f(x) = mathbb{P}(|B_1|<-x),$$ and so $$f(x)=1-2Phi(x)$$ where $Phi$ is the cdf of the centered standard Gaussian distribution with density $varphi$.

  5. Combining the above steps gives begin{align*} mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) &= mathbb{E} left[ left( 1- 2Phi(W_1)right) 1_{{W_1<0}} right] \ &= frac{1}{2} - 2 int_{-infty}^0 Phi(x) varphi(x) , dx. end{align*}

  6. Conclude that $$mathbb{P}(W_t < 0 , , text{for all} , , t in (1,2)) = frac{1}{4}; $$ see e.g. this answer for how to compute the integral in Step 5.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Feb 3 at 18:54

























answered Feb 3 at 9:01









sazsaz

82.5k862131




82.5k862131












  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Feb 3 at 12:08










  • $begingroup$
    @Did Thank you.
    $endgroup$
    – saz
    Feb 3 at 12:13


















  • $begingroup$
    Yep. (+1) $ $ $ $
    $endgroup$
    – Did
    Feb 3 at 12:08










  • $begingroup$
    @Did Thank you.
    $endgroup$
    – saz
    Feb 3 at 12:13
















$begingroup$
Yep. (+1) $ $ $ $
$endgroup$
– Did
Feb 3 at 12:08




$begingroup$
Yep. (+1) $ $ $ $
$endgroup$
– Did
Feb 3 at 12:08












$begingroup$
@Did Thank you.
$endgroup$
– saz
Feb 3 at 12:13




$begingroup$
@Did Thank you.
$endgroup$
– saz
Feb 3 at 12:13



Popular posts from this blog

'app-layout' is not a known element: how to share Component with different Modules

android studio warns about leanback feature tag usage required on manifest while using Unity exported app?

WPF add header to Image with URL pettitions [duplicate]