How to replace substring of dictionary values using Re

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I am trying to loop through a dictionary and replace a substring using Re, but my dictionary just ends up with empty values. I've outlined my code below:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}



val = "├─BROKEN─"



for k, v in mydict.iteritems():

  for i, s in enumerate(v):

      v[i] = re.sub(r'.*├─BROKEN─', '', val)

This code results in an dictionary without values:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '',

        '',

        ''

    ],

    'Getting links from: https://www.bar.com/': 

    [

        ''

    ]

}

What I want is:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        'http://www.broken.com/',

        'http://www.set.com/',

        'http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        'http://www.broken.com/'

    ]

}

What am I missing?

asked Jan 3 at 16:24

lane

140113

1

Change this v[i] = re.sub(r'.*├─BROKEN─', '', val) to v[i] = re.sub(r'.*├─BROKEN─', '', s)

– Daniel Mesejo
Jan 3 at 16:27

1

You replace val which is exactly the string to replace. That's probably a typo and you meant to use s instead of val.

– a_guest
Jan 3 at 16:27

add a comment |

I am trying to loop through a dictionary and replace a substring using Re, but my dictionary just ends up with empty values. I've outlined my code below:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}



val = "├─BROKEN─"



for k, v in mydict.iteritems():

  for i, s in enumerate(v):

      v[i] = re.sub(r'.*├─BROKEN─', '', val)

This code results in an dictionary without values:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '',

        '',

        ''

    ],

    'Getting links from: https://www.bar.com/': 

    [

        ''

    ]

}

What I want is:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        'http://www.broken.com/',

        'http://www.set.com/',

        'http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        'http://www.broken.com/'

    ]

}

What am I missing?

asked Jan 3 at 16:24

lane

140113

1

Change this v[i] = re.sub(r'.*├─BROKEN─', '', val) to v[i] = re.sub(r'.*├─BROKEN─', '', s)

– Daniel Mesejo
Jan 3 at 16:27

1

You replace val which is exactly the string to replace. That's probably a typo and you meant to use s instead of val.

– a_guest
Jan 3 at 16:27

add a comment |

I am trying to loop through a dictionary and replace a substring using Re, but my dictionary just ends up with empty values. I've outlined my code below:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}



val = "├─BROKEN─"



for k, v in mydict.iteritems():

  for i, s in enumerate(v):

      v[i] = re.sub(r'.*├─BROKEN─', '', val)

This code results in an dictionary without values:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '',

        '',

        ''

    ],

    'Getting links from: https://www.bar.com/': 

    [

        ''

    ]

}

What I want is:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        'http://www.broken.com/',

        'http://www.set.com/',

        'http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        'http://www.broken.com/'

    ]

}

What am I missing?

asked Jan 3 at 16:24

lane

140113

I am trying to loop through a dictionary and replace a substring using Re, but my dictionary just ends up with empty values. I've outlined my code below:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}



val = "├─BROKEN─"



for k, v in mydict.iteritems():

  for i, s in enumerate(v):

      v[i] = re.sub(r'.*├─BROKEN─', '', val)

This code results in an dictionary without values:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '',

        '',

        ''

    ],

    'Getting links from: https://www.bar.com/': 

    [

        ''

    ]

}

What I want is:

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        'http://www.broken.com/',

        'http://www.set.com/',

        'http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        'http://www.broken.com/'

    ]

}

What am I missing?

python python-2.7 dictionary

asked Jan 3 at 16:24

lane

140113

asked Jan 3 at 16:24

lane

140113

asked Jan 3 at 16:24

lane

140113

asked Jan 3 at 16:24

lane

140113

asked Jan 3 at 16:24

lane

140113

1

Change this v[i] = re.sub(r'.*├─BROKEN─', '', val) to v[i] = re.sub(r'.*├─BROKEN─', '', s)

– Daniel Mesejo
Jan 3 at 16:27

1

You replace val which is exactly the string to replace. That's probably a typo and you meant to use s instead of val.

– a_guest
Jan 3 at 16:27

add a comment |

1

Change this v[i] = re.sub(r'.*├─BROKEN─', '', val) to v[i] = re.sub(r'.*├─BROKEN─', '', s)

– Daniel Mesejo
Jan 3 at 16:27

1

You replace val which is exactly the string to replace. That's probably a typo and you meant to use s instead of val.

– a_guest
Jan 3 at 16:27

Change this v[i] = re.sub(r'.*├─BROKEN─', '', val) to v[i] = re.sub(r'.*├─BROKEN─', '', s)

– Daniel Mesejo
Jan 3 at 16:27

You replace val which is exactly the string to replace. That's probably a typo and you meant to use s instead of val.

– a_guest
Jan 3 at 16:27

add a comment |

2 Answers
2

active

oldest

votes

You don't need a regex here, seems a little expensive. Use string replace() and strip():

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}



val = "├─BROKEN─"



for k, v in mydict.items():

    mydict[k] = [x.replace(val, '').strip() for x in v]



print(mydict)



# {'Getting links from: https://www.foo.com/': ['http://www.broken.com/', 'http://www.set.com/', 'http://www.one.com/'],

#  'Getting links from: https://www.bar.com/': ['http://www.broken.com/']}

answered Jan 3 at 16:27

Austin

13.2k31031

add a comment |

The code with modified regexp.

import re



mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}





for k, v in mydict.iteritems():

  for i, s in enumerate(v):

      v[i] = re.sub(r'├─BROKEN─', '', s)

Output:

{'Getting links from: https://www.bar.com/': [' http://www.broken.com/'],

 'Getting links from: https://www.foo.com/': [' http://www.broken.com/',

                                              ' http://www.set.com/',

                                              ' http://www.one.com/']}

As was stated into the comment | is a special character

answered Jan 3 at 16:39

Dmytro Chasovskyi

856829

Thank you for helping me to understand re better! +1

– lane
Jan 3 at 17:09

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

You don't need a regex here, seems a little expensive. Use string replace() and strip():

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}



val = "├─BROKEN─"



for k, v in mydict.items():

    mydict[k] = [x.replace(val, '').strip() for x in v]



print(mydict)



# {'Getting links from: https://www.foo.com/': ['http://www.broken.com/', 'http://www.set.com/', 'http://www.one.com/'],

#  'Getting links from: https://www.bar.com/': ['http://www.broken.com/']}

answered Jan 3 at 16:27

Austin

13.2k31031

add a comment |

You don't need a regex here, seems a little expensive. Use string replace() and strip():

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}



val = "├─BROKEN─"



for k, v in mydict.items():

    mydict[k] = [x.replace(val, '').strip() for x in v]



print(mydict)



# {'Getting links from: https://www.foo.com/': ['http://www.broken.com/', 'http://www.set.com/', 'http://www.one.com/'],

#  'Getting links from: https://www.bar.com/': ['http://www.broken.com/']}

answered Jan 3 at 16:27

Austin

13.2k31031

add a comment |

You don't need a regex here, seems a little expensive. Use string replace() and strip():

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}



val = "├─BROKEN─"



for k, v in mydict.items():

    mydict[k] = [x.replace(val, '').strip() for x in v]



print(mydict)



# {'Getting links from: https://www.foo.com/': ['http://www.broken.com/', 'http://www.set.com/', 'http://www.one.com/'],

#  'Getting links from: https://www.bar.com/': ['http://www.broken.com/']}

answered Jan 3 at 16:27

Austin

13.2k31031

You don't need a regex here, seems a little expensive. Use string replace() and strip():

mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}



val = "├─BROKEN─"



for k, v in mydict.items():

    mydict[k] = [x.replace(val, '').strip() for x in v]



print(mydict)



# {'Getting links from: https://www.foo.com/': ['http://www.broken.com/', 'http://www.set.com/', 'http://www.one.com/'],

#  'Getting links from: https://www.bar.com/': ['http://www.broken.com/']}

answered Jan 3 at 16:27

Austin

13.2k31031

answered Jan 3 at 16:27

Austin

13.2k31031

answered Jan 3 at 16:27

Austin

13.2k31031

answered Jan 3 at 16:27

Austin

13.2k31031

add a comment |

The code with modified regexp.

import re



mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}





for k, v in mydict.iteritems():

  for i, s in enumerate(v):

      v[i] = re.sub(r'├─BROKEN─', '', s)

Output:

{'Getting links from: https://www.bar.com/': [' http://www.broken.com/'],

 'Getting links from: https://www.foo.com/': [' http://www.broken.com/',

                                              ' http://www.set.com/',

                                              ' http://www.one.com/']}

As was stated into the comment | is a special character

answered Jan 3 at 16:39

Dmytro Chasovskyi

856829

Thank you for helping me to understand re better! +1

– lane
Jan 3 at 17:09

add a comment |

The code with modified regexp.

import re



mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}





for k, v in mydict.iteritems():

  for i, s in enumerate(v):

      v[i] = re.sub(r'├─BROKEN─', '', s)

Output:

{'Getting links from: https://www.bar.com/': [' http://www.broken.com/'],

 'Getting links from: https://www.foo.com/': [' http://www.broken.com/',

                                              ' http://www.set.com/',

                                              ' http://www.one.com/']}

As was stated into the comment | is a special character

answered Jan 3 at 16:39

Dmytro Chasovskyi

856829

Thank you for helping me to understand re better! +1

– lane
Jan 3 at 17:09

add a comment |

The code with modified regexp.

import re



mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}





for k, v in mydict.iteritems():

  for i, s in enumerate(v):

      v[i] = re.sub(r'├─BROKEN─', '', s)

Output:

{'Getting links from: https://www.bar.com/': [' http://www.broken.com/'],

 'Getting links from: https://www.foo.com/': [' http://www.broken.com/',

                                              ' http://www.set.com/',

                                              ' http://www.one.com/']}

As was stated into the comment | is a special character

answered Jan 3 at 16:39

Dmytro Chasovskyi

856829

The code with modified regexp.

import re



mydict = {

    'Getting links from: https://www.foo.com/': 

    [

        '├─BROKEN─ http://www.broken.com/',

        '├─BROKEN─ http://www.set.com/',

        '├─BROKEN─ http://www.one.com/'

    ],

    'Getting links from: https://www.bar.com/': 

    [

        '├─BROKEN─ http://www.broken.com/'

    ]

}





for k, v in mydict.iteritems():

  for i, s in enumerate(v):

      v[i] = re.sub(r'├─BROKEN─', '', s)

Output:

{'Getting links from: https://www.bar.com/': [' http://www.broken.com/'],

 'Getting links from: https://www.foo.com/': [' http://www.broken.com/',

                                              ' http://www.set.com/',

                                              ' http://www.one.com/']}

As was stated into the comment | is a special character

answered Jan 3 at 16:39

Dmytro Chasovskyi

856829

answered Jan 3 at 16:39

Dmytro Chasovskyi

856829

answered Jan 3 at 16:39

Dmytro Chasovskyi

856829

answered Jan 3 at 16:39

Dmytro Chasovskyi

856829

Thank you for helping me to understand re better! +1

– lane
Jan 3 at 17:09

add a comment |

Thank you for helping me to understand re better! +1

– lane
Jan 3 at 17:09

Thank you for helping me to understand re better! +1

– lane
Jan 3 at 17:09

add a comment |

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