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C++ assigning integer (containing address) to pointer [duplicate]
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This question already has an answer here:
What is uintptr_t data type
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I am new to C++, I have a function which returns address of a memory location and I want to assign that address to a pointer, just like:
unsigned int address = 0xdeadbeef;
unsigned int* memory_ptr = (unsigned int*) address;
But above code is through warning:
cast to pointer from integer of difference size [-Wint-to-pointer-cast]
Is there anyway to do this task cleanly in C++ ?
c++ pointers
asked Jan 3 at 6:26
Ameer HamzaAmeer Hamza
408
marked as duplicate by R Sahu c++
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Jan 3 at 6:36
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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This question already has an answer here:
What is uintptr_t data type
4 answers
I am new to C++, I have a function which returns address of a memory location and I want to assign that address to a pointer, just like:
unsigned int address = 0xdeadbeef;
unsigned int* memory_ptr = (unsigned int*) address;
But above code is through warning:
cast to pointer from integer of difference size [-Wint-to-pointer-cast]
Is there anyway to do this task cleanly in C++ ?
c++ pointers
asked Jan 3 at 6:26
Ameer HamzaAmeer Hamza
408
marked as duplicate by R Sahu c++
Users with the c++ badge can single-handedly close c++ questions as duplicates and reopen them as needed.
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Jan 3 at 6:36
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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This question already has an answer here:
What is uintptr_t data type
4 answers
I am new to C++, I have a function which returns address of a memory location and I want to assign that address to a pointer, just like:
unsigned int address = 0xdeadbeef;
unsigned int* memory_ptr = (unsigned int*) address;
But above code is through warning:
cast to pointer from integer of difference size [-Wint-to-pointer-cast]
Is there anyway to do this task cleanly in C++ ?
c++ pointers
asked Jan 3 at 6:26
Ameer HamzaAmeer Hamza
408
This question already has an answer here:
What is uintptr_t data type
4 answers
I am new to C++, I have a function which returns address of a memory location and I want to assign that address to a pointer, just like:
unsigned int address = 0xdeadbeef;
unsigned int* memory_ptr = (unsigned int*) address;
But above code is through warning:
cast to pointer from integer of difference size [-Wint-to-pointer-cast]
Is there anyway to do this task cleanly in C++ ?
This question already has an answer here:
What is uintptr_t data type
4 answers
c++ pointers
c++ pointers
asked Jan 3 at 6:26
Ameer HamzaAmeer Hamza
408
asked Jan 3 at 6:26
Ameer HamzaAmeer Hamza
408
asked Jan 3 at 6:26
Ameer HamzaAmeer Hamza
408
asked Jan 3 at 6:26
Ameer HamzaAmeer Hamza
408
asked Jan 3 at 6:26
Ameer HamzaAmeer Hamza
408
408
marked as duplicate by R Sahu c++
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Jan 3 at 6:36
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Instead of unsigned int you can use uintptr_t.
Integer type capable of holding a value converted from a void pointer and then be converted back to that type with a value that compares equal to the original pointer.
answered Jan 3 at 6:32
YolaYola
11.3k64672
add a comment |
1 Answer
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1 Answer
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active
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Instead of unsigned int you can use uintptr_t.
Integer type capable of holding a value converted from a void pointer and then be converted back to that type with a value that compares equal to the original pointer.
answered Jan 3 at 6:32
YolaYola
11.3k64672
add a comment |
Instead of unsigned int you can use uintptr_t.
Integer type capable of holding a value converted from a void pointer and then be converted back to that type with a value that compares equal to the original pointer.
answered Jan 3 at 6:32
YolaYola
11.3k64672
add a comment |
Instead of unsigned int you can use uintptr_t.
Integer type capable of holding a value converted from a void pointer and then be converted back to that type with a value that compares equal to the original pointer.
answered Jan 3 at 6:32
YolaYola
11.3k64672
Instead of unsigned int you can use uintptr_t.
Integer type capable of holding a value converted from a void pointer and then be converted back to that type with a value that compares equal to the original pointer.
answered Jan 3 at 6:32
YolaYola
11.3k64672
answered Jan 3 at 6:32
YolaYola
11.3k64672
answered Jan 3 at 6:32
YolaYola
11.3k64672
answered Jan 3 at 6:32
YolaYola
11.3k64672
11.3k64672
add a comment |
add a comment |
