Why is this series given by this Taylor expansion?
$begingroup$
So I am doing some graph theory stuff and I know that, given $4$ axes that I can walk along in both directions, the number of reached points after $n$ steps is:
$$ N(n) = sum_{k=0}^{mathrm{min}(4,n)}2^k ,{4choose k},{nchoose k}, $$
i.e. $N(0) = 1 $,
and $N(1) = 1 + 8 = 9$
etc.
By accident I found that the formula also happens to work for the coefficients for the Taylor expansion of the function:
$$ frac{(1+x)^4}{(1-x)^5}. $$
I am trying to understand whether there is any physical meaning of this function in the context of my graph theory application.
Does anyone know whether this is a known result? Does that function ring a bell?
sequences-and-series graph-theory taylor-expansion generating-functions
$endgroup$
add a comment |
$begingroup$
So I am doing some graph theory stuff and I know that, given $4$ axes that I can walk along in both directions, the number of reached points after $n$ steps is:
$$ N(n) = sum_{k=0}^{mathrm{min}(4,n)}2^k ,{4choose k},{nchoose k}, $$
i.e. $N(0) = 1 $,
and $N(1) = 1 + 8 = 9$
etc.
By accident I found that the formula also happens to work for the coefficients for the Taylor expansion of the function:
$$ frac{(1+x)^4}{(1-x)^5}. $$
I am trying to understand whether there is any physical meaning of this function in the context of my graph theory application.
Does anyone know whether this is a known result? Does that function ring a bell?
sequences-and-series graph-theory taylor-expansion generating-functions
$endgroup$
add a comment |
$begingroup$
So I am doing some graph theory stuff and I know that, given $4$ axes that I can walk along in both directions, the number of reached points after $n$ steps is:
$$ N(n) = sum_{k=0}^{mathrm{min}(4,n)}2^k ,{4choose k},{nchoose k}, $$
i.e. $N(0) = 1 $,
and $N(1) = 1 + 8 = 9$
etc.
By accident I found that the formula also happens to work for the coefficients for the Taylor expansion of the function:
$$ frac{(1+x)^4}{(1-x)^5}. $$
I am trying to understand whether there is any physical meaning of this function in the context of my graph theory application.
Does anyone know whether this is a known result? Does that function ring a bell?
sequences-and-series graph-theory taylor-expansion generating-functions
$endgroup$
So I am doing some graph theory stuff and I know that, given $4$ axes that I can walk along in both directions, the number of reached points after $n$ steps is:
$$ N(n) = sum_{k=0}^{mathrm{min}(4,n)}2^k ,{4choose k},{nchoose k}, $$
i.e. $N(0) = 1 $,
and $N(1) = 1 + 8 = 9$
etc.
By accident I found that the formula also happens to work for the coefficients for the Taylor expansion of the function:
$$ frac{(1+x)^4}{(1-x)^5}. $$
I am trying to understand whether there is any physical meaning of this function in the context of my graph theory application.
Does anyone know whether this is a known result? Does that function ring a bell?
sequences-and-series graph-theory taylor-expansion generating-functions
sequences-and-series graph-theory taylor-expansion generating-functions
edited Feb 2 at 3:57
Alex Ravsky
42.9k32483
42.9k32483
asked Jan 31 at 16:40
SuperCiociaSuperCiocia
295213
295213
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add a comment |
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