QT延長症候群（QTえんちょうしょうこうぐん、long QT syndrome; LQTS）は、心臓の収縮後の再分極の遅延がおき、心室頻拍（Torsades de Pointes:TdP、心室性不整脈の一種）のリスクを増大させる心臓疾患である。
目次
1概要
2分類
3問診・検査
4治療
5脚注
概要
心臓の収縮後の再分極の遅延によって生じる心室頻拍は動悸、失神や心室細動による突然死につながる可能性がある。症状は、条件のサブタイプに応じて、様々な刺激によって誘発される。心臓に器質的疾患を持たないにもかかわらず、心電図上でQT時間の延長を認める病態である。QT時間が0.46秒以上、またはRR間隔で補正したQTc時間では0.44秒以上である場合を指す。Torsades de pointes（TdP）と呼ばれる心室頻拍を惹起することがある。より簡略にはT波の終点がRRの中点を越えていれば明らかにQTの延長とする。この方法はスクリーニング診察時に用いることがある。
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Per the Font of Magic feature, sorcerer can use Flexible Casting to create 5th-level spell slots at level 7, even though they are not typically available until level 9. You can transform unexpended sorcery points into one spell slot as a bonus action on your turn. The Creating Spell Slots table shows the cost of creating a spell slot of [5th level is 7] If such a sorcerer levels up while still having this 5th-level spell slot, can they choose a 5th-level spell as the spell they gain upon levelling up? The Spellcasting feature states: Additionally, when you gain a level in this class, you can choose one of the sorcerer spells you know and replace it with another spell from the sorcerer spell list, which also must be of a level for which you have spell slots.
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After the 2018 errata, the disintegrate spell description now reads: A creature targeted by this spell must make a Dexterity saving throw. On a failed save, the target takes 10d6 + 40 force damage. The target is disintegrated if this damage leaves it with 0 hit points. If you were to polymorph an enemy into a rat and then disintegrate it, would the enemy be disintegrated or would it just return to its original form? I know that for Druids, it’s not an instant kill anymore, but is this the case for polymorph as well?
dnd-5e spells polymorph errata
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Recently, I saw a construction of topological invariant for $pi_3(U(n))$ with $ngeq 2$ : $$ N=frac{1}{24pi^2}int_{S^3} d^3x epsilon^{ijk} Tr[(U^{-1}partial_{x_i}U)(U^{-1}partial_{x_j}U)(U^{-1}partial_{x_k}U)] , $$ where $Uin U(n)$ depends on $boldsymbol{x}=(x_1,x_2,x_3)in S^3$ , $epsilon^{ijk}$ is the Levi-Civita symbol, $i,j,k=1,2,3$ , and the duplicated indexes are summed over. It is claimed that $N$ is an integer, but why? Update 02/02/2019 I think I got an argument for $n=2$ . In this case, $U=e^{i varphi} q$ with $qin SU(2)$ . Due to the trace and the Levi-Civita symbol in $N$ , $varphi$ does not contribute to $N$ . As $Tr[q^{dagger}partial_i q]=0$ and $(q^{dagger}partial_i q)^{dagger}=-q^{dagger}partial_i q$ , $q^{dagger}partial_i q$ in geneeral has the form $q^{dagger}partia
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