Confusion on a lemma concerning a club of substructures of $V_kappa$












1












$begingroup$


So i've reached this lemma in Kanamori's The higher infinite, which states:






Lemma. Suppose that $kappa$ is inaccessible and that $R subseteq V_kappa$. Then ${ alpha lt kappa mid langle V_alpha, in, Rcap V_alpharangle prec langle V_kappa, in, Rrangle }$ is a club in $kappa$.






Now my confusion arises from the fact that the book says that the reason this set is closed is clear. But for me it isn't because given an elementary embedding for each $ alpha_xi $, $xi lt theta lt kappa $, i don't know how to produce one for $lambda = cup_{xi lt theta}
alpha_xi$
. Then i thought maybe he meant the elementary embeddings are the inclusion functions but that seems to be off aswell. I would really appreciate any help.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    Do you know that the increasing union of elementary models is elementary?
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:16










  • $begingroup$
    No. I haven't studied model theory that much. Can you please provide a reference or proof for this?
    $endgroup$
    – Shervin Sorouri
    Feb 1 at 12:19










  • $begingroup$
    I don't have one off hand. But it's fairly simple to prove directly from the definition. Especially in the case of these structures which are end-extensions of each other.
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:30










  • $begingroup$
    The statement mentioned by Asaf follows directly from the definitions. A reference will likely say no more than that. Better if you prove it on your own.
    $endgroup$
    – Andrés E. Caicedo
    Feb 1 at 12:32






  • 3




    $begingroup$
    You're thinking way too hard about this.
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:38
















1












$begingroup$


So i've reached this lemma in Kanamori's The higher infinite, which states:






Lemma. Suppose that $kappa$ is inaccessible and that $R subseteq V_kappa$. Then ${ alpha lt kappa mid langle V_alpha, in, Rcap V_alpharangle prec langle V_kappa, in, Rrangle }$ is a club in $kappa$.






Now my confusion arises from the fact that the book says that the reason this set is closed is clear. But for me it isn't because given an elementary embedding for each $ alpha_xi $, $xi lt theta lt kappa $, i don't know how to produce one for $lambda = cup_{xi lt theta}
alpha_xi$
. Then i thought maybe he meant the elementary embeddings are the inclusion functions but that seems to be off aswell. I would really appreciate any help.










share|cite|improve this question











$endgroup$








  • 1




    $begingroup$
    Do you know that the increasing union of elementary models is elementary?
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:16










  • $begingroup$
    No. I haven't studied model theory that much. Can you please provide a reference or proof for this?
    $endgroup$
    – Shervin Sorouri
    Feb 1 at 12:19










  • $begingroup$
    I don't have one off hand. But it's fairly simple to prove directly from the definition. Especially in the case of these structures which are end-extensions of each other.
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:30










  • $begingroup$
    The statement mentioned by Asaf follows directly from the definitions. A reference will likely say no more than that. Better if you prove it on your own.
    $endgroup$
    – Andrés E. Caicedo
    Feb 1 at 12:32






  • 3




    $begingroup$
    You're thinking way too hard about this.
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:38














1












1








1





$begingroup$


So i've reached this lemma in Kanamori's The higher infinite, which states:






Lemma. Suppose that $kappa$ is inaccessible and that $R subseteq V_kappa$. Then ${ alpha lt kappa mid langle V_alpha, in, Rcap V_alpharangle prec langle V_kappa, in, Rrangle }$ is a club in $kappa$.






Now my confusion arises from the fact that the book says that the reason this set is closed is clear. But for me it isn't because given an elementary embedding for each $ alpha_xi $, $xi lt theta lt kappa $, i don't know how to produce one for $lambda = cup_{xi lt theta}
alpha_xi$
. Then i thought maybe he meant the elementary embeddings are the inclusion functions but that seems to be off aswell. I would really appreciate any help.










share|cite|improve this question











$endgroup$




So i've reached this lemma in Kanamori's The higher infinite, which states:






Lemma. Suppose that $kappa$ is inaccessible and that $R subseteq V_kappa$. Then ${ alpha lt kappa mid langle V_alpha, in, Rcap V_alpharangle prec langle V_kappa, in, Rrangle }$ is a club in $kappa$.






Now my confusion arises from the fact that the book says that the reason this set is closed is clear. But for me it isn't because given an elementary embedding for each $ alpha_xi $, $xi lt theta lt kappa $, i don't know how to produce one for $lambda = cup_{xi lt theta}
alpha_xi$
. Then i thought maybe he meant the elementary embeddings are the inclusion functions but that seems to be off aswell. I would really appreciate any help.







set-theory






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Feb 1 at 12:45







Shervin Sorouri

















asked Feb 1 at 11:42









Shervin SorouriShervin Sorouri

519212




519212








  • 1




    $begingroup$
    Do you know that the increasing union of elementary models is elementary?
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:16










  • $begingroup$
    No. I haven't studied model theory that much. Can you please provide a reference or proof for this?
    $endgroup$
    – Shervin Sorouri
    Feb 1 at 12:19










  • $begingroup$
    I don't have one off hand. But it's fairly simple to prove directly from the definition. Especially in the case of these structures which are end-extensions of each other.
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:30










  • $begingroup$
    The statement mentioned by Asaf follows directly from the definitions. A reference will likely say no more than that. Better if you prove it on your own.
    $endgroup$
    – Andrés E. Caicedo
    Feb 1 at 12:32






  • 3




    $begingroup$
    You're thinking way too hard about this.
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:38














  • 1




    $begingroup$
    Do you know that the increasing union of elementary models is elementary?
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:16










  • $begingroup$
    No. I haven't studied model theory that much. Can you please provide a reference or proof for this?
    $endgroup$
    – Shervin Sorouri
    Feb 1 at 12:19










  • $begingroup$
    I don't have one off hand. But it's fairly simple to prove directly from the definition. Especially in the case of these structures which are end-extensions of each other.
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:30










  • $begingroup$
    The statement mentioned by Asaf follows directly from the definitions. A reference will likely say no more than that. Better if you prove it on your own.
    $endgroup$
    – Andrés E. Caicedo
    Feb 1 at 12:32






  • 3




    $begingroup$
    You're thinking way too hard about this.
    $endgroup$
    – Asaf Karagila
    Feb 1 at 12:38








1




1




$begingroup$
Do you know that the increasing union of elementary models is elementary?
$endgroup$
– Asaf Karagila
Feb 1 at 12:16




$begingroup$
Do you know that the increasing union of elementary models is elementary?
$endgroup$
– Asaf Karagila
Feb 1 at 12:16












$begingroup$
No. I haven't studied model theory that much. Can you please provide a reference or proof for this?
$endgroup$
– Shervin Sorouri
Feb 1 at 12:19




$begingroup$
No. I haven't studied model theory that much. Can you please provide a reference or proof for this?
$endgroup$
– Shervin Sorouri
Feb 1 at 12:19












$begingroup$
I don't have one off hand. But it's fairly simple to prove directly from the definition. Especially in the case of these structures which are end-extensions of each other.
$endgroup$
– Asaf Karagila
Feb 1 at 12:30




$begingroup$
I don't have one off hand. But it's fairly simple to prove directly from the definition. Especially in the case of these structures which are end-extensions of each other.
$endgroup$
– Asaf Karagila
Feb 1 at 12:30












$begingroup$
The statement mentioned by Asaf follows directly from the definitions. A reference will likely say no more than that. Better if you prove it on your own.
$endgroup$
– Andrés E. Caicedo
Feb 1 at 12:32




$begingroup$
The statement mentioned by Asaf follows directly from the definitions. A reference will likely say no more than that. Better if you prove it on your own.
$endgroup$
– Andrés E. Caicedo
Feb 1 at 12:32




3




3




$begingroup$
You're thinking way too hard about this.
$endgroup$
– Asaf Karagila
Feb 1 at 12:38




$begingroup$
You're thinking way too hard about this.
$endgroup$
– Asaf Karagila
Feb 1 at 12:38










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