Mixing
FILE INPUT INSERT INTO BD WITH MOVE_TO_FILE
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
0
This is more of a question to gain a more clear understanding. If I insert from a form like:
<form action="upload.php" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload Image" name="submit">
</form>
into the DB for a link and it's successful:
$file = "INSERT INTO ('foo') VALUES ('FOO', NOW())";
just an example:
yet in the php script:
$_FILE['fileToUpload']['name'];
$_FILE['fileToUpload']['tmp_name'];
since the tmp_name folder only holds upload files in an array, which than I would have to use either a foreach or for loop search the loop of files, this than makes the INSERT INTO db difficult.
Question is how can I separate the search results from the array and than insert each one into the database?
HERE"S THE CODE:
<?php
$con = mysqli_connect("localhost","root","","acc1");
if(mysqli_connect_errno()){
echo 'Failed to connect to MySQL:' . mysqli_connect_error();
}else{
echo 'Connected!';
}
if(isset($_POST['submit']) && !empty($_FILES['fileBC']['name'] && !empty($_FILES['fileB']['name'] && !empty($_FILES['fileBR']['name']) ))){
$file = "image/";
$name = $_FILES['fileBC']['name'];
$data = $_FILES['fileBC']['tmp_name'];
$fileV = "video/";
$nameV = $_FILES['fileBR']['name'];
$dataV = $_FILES['fileBR']['tmp_name'];
$fileB = "book/";
$nameB = $_FILES['fileB']['name'];
$dataB = $_FILES['fileB']['tmp_name'];
if(move_uploaded_file($data,$file.$name)){
$ins_name = $con->query("INSERT INTO fileimages (fileBC, fileBR, fileB) VALUES ('$name','$nameB', '$nameV')");
}if($ins_name){
echo 'success!';
}else{
echo 'error';
}
}
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="css/bootstrap.css">
<link rel="stylesheet" href="css/fontawesome.css">
<script src="js/jquery.js"></script>
<script src="js/bootstrap.js"></script>
</head>
<script>
function mymodal(){
$('#myModal').modal('show');
}
</script>
<body>
<form method="post" action="index.php" enctype="multipart/form-data">
<div class="form-group">
<label class="text-primary">Book Cover:</label>
<input class="form-control" type="file" name="fileBC" accept="image/*" >
</div>
<div class="form-group">
<label class="text-primary">Book:</label>
<input class="form-control" type="file" name="fileB" accept=".epub, .mobi, .pdf, .prc, .azw, .bbeb" >
</div>
<div class="form-group">
<label class="text-primary">Book Reading:</label>
<input class="form-control" type="file" name="fileBR" accept="video/*" >
</div>
<button name="submit">upload</button>
</form>
<p></p>
<ol>
</ol>
</body>
</html>
php html
asked Jan 3 at 6:22
Damian MitchellDamian Mitchell
177
add a comment |
0
This is more of a question to gain a more clear understanding. If I insert from a form like:
<form action="upload.php" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload Image" name="submit">
</form>
into the DB for a link and it's successful:
$file = "INSERT INTO ('foo') VALUES ('FOO', NOW())";
just an example:
yet in the php script:
$_FILE['fileToUpload']['name'];
$_FILE['fileToUpload']['tmp_name'];
since the tmp_name folder only holds upload files in an array, which than I would have to use either a foreach or for loop search the loop of files, this than makes the INSERT INTO db difficult.
Question is how can I separate the search results from the array and than insert each one into the database?
HERE"S THE CODE:
<?php
$con = mysqli_connect("localhost","root","","acc1");
if(mysqli_connect_errno()){
echo 'Failed to connect to MySQL:' . mysqli_connect_error();
}else{
echo 'Connected!';
}
if(isset($_POST['submit']) && !empty($_FILES['fileBC']['name'] && !empty($_FILES['fileB']['name'] && !empty($_FILES['fileBR']['name']) ))){
$file = "image/";
$name = $_FILES['fileBC']['name'];
$data = $_FILES['fileBC']['tmp_name'];
$fileV = "video/";
$nameV = $_FILES['fileBR']['name'];
$dataV = $_FILES['fileBR']['tmp_name'];
$fileB = "book/";
$nameB = $_FILES['fileB']['name'];
$dataB = $_FILES['fileB']['tmp_name'];
if(move_uploaded_file($data,$file.$name)){
$ins_name = $con->query("INSERT INTO fileimages (fileBC, fileBR, fileB) VALUES ('$name','$nameB', '$nameV')");
}if($ins_name){
echo 'success!';
}else{
echo 'error';
}
}
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="css/bootstrap.css">
<link rel="stylesheet" href="css/fontawesome.css">
<script src="js/jquery.js"></script>
<script src="js/bootstrap.js"></script>
</head>
<script>
function mymodal(){
$('#myModal').modal('show');
}
</script>
<body>
<form method="post" action="index.php" enctype="multipart/form-data">
<div class="form-group">
<label class="text-primary">Book Cover:</label>
<input class="form-control" type="file" name="fileBC" accept="image/*" >
</div>
<div class="form-group">
<label class="text-primary">Book:</label>
<input class="form-control" type="file" name="fileB" accept=".epub, .mobi, .pdf, .prc, .azw, .bbeb" >
</div>
<div class="form-group">
<label class="text-primary">Book Reading:</label>
<input class="form-control" type="file" name="fileBR" accept="video/*" >
</div>
<button name="submit">upload</button>
</form>
<p></p>
<ol>
</ol>
</body>
</html>
php html
asked Jan 3 at 6:22
Damian MitchellDamian Mitchell
177
Why do you want to do this in such way?
– Amit Rajput
Jan 3 at 6:30
because this creates a link or url in the database in one form input if I can move the other contents to the other folders
– Damian Mitchell
Jan 3 at 6:33
allowing me to just place certain info in the link or url
– Damian Mitchell
Jan 3 at 6:34
You have twoid="fileToUpload"in your code, which is invalid,idneeds to be unique. The php manual itself has documentation on uploading multiple files
– kerbholz
Jan 3 at 7:26
add a comment |
0
0
0
This is more of a question to gain a more clear understanding. If I insert from a form like:
<form action="upload.php" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload Image" name="submit">
</form>
into the DB for a link and it's successful:
$file = "INSERT INTO ('foo') VALUES ('FOO', NOW())";
just an example:
yet in the php script:
$_FILE['fileToUpload']['name'];
$_FILE['fileToUpload']['tmp_name'];
since the tmp_name folder only holds upload files in an array, which than I would have to use either a foreach or for loop search the loop of files, this than makes the INSERT INTO db difficult.
Question is how can I separate the search results from the array and than insert each one into the database?
HERE"S THE CODE:
<?php
$con = mysqli_connect("localhost","root","","acc1");
if(mysqli_connect_errno()){
echo 'Failed to connect to MySQL:' . mysqli_connect_error();
}else{
echo 'Connected!';
}
if(isset($_POST['submit']) && !empty($_FILES['fileBC']['name'] && !empty($_FILES['fileB']['name'] && !empty($_FILES['fileBR']['name']) ))){
$file = "image/";
$name = $_FILES['fileBC']['name'];
$data = $_FILES['fileBC']['tmp_name'];
$fileV = "video/";
$nameV = $_FILES['fileBR']['name'];
$dataV = $_FILES['fileBR']['tmp_name'];
$fileB = "book/";
$nameB = $_FILES['fileB']['name'];
$dataB = $_FILES['fileB']['tmp_name'];
if(move_uploaded_file($data,$file.$name)){
$ins_name = $con->query("INSERT INTO fileimages (fileBC, fileBR, fileB) VALUES ('$name','$nameB', '$nameV')");
}if($ins_name){
echo 'success!';
}else{
echo 'error';
}
}
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="css/bootstrap.css">
<link rel="stylesheet" href="css/fontawesome.css">
<script src="js/jquery.js"></script>
<script src="js/bootstrap.js"></script>
</head>
<script>
function mymodal(){
$('#myModal').modal('show');
}
</script>
<body>
<form method="post" action="index.php" enctype="multipart/form-data">
<div class="form-group">
<label class="text-primary">Book Cover:</label>
<input class="form-control" type="file" name="fileBC" accept="image/*" >
</div>
<div class="form-group">
<label class="text-primary">Book:</label>
<input class="form-control" type="file" name="fileB" accept=".epub, .mobi, .pdf, .prc, .azw, .bbeb" >
</div>
<div class="form-group">
<label class="text-primary">Book Reading:</label>
<input class="form-control" type="file" name="fileBR" accept="video/*" >
</div>
<button name="submit">upload</button>
</form>
<p></p>
<ol>
</ol>
</body>
</html>
php html
asked Jan 3 at 6:22
Damian MitchellDamian Mitchell
177
This is more of a question to gain a more clear understanding. If I insert from a form like:
<form action="upload.php" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="file" name="fileToUpload" id="fileToUpload">
<input type="submit" value="Upload Image" name="submit">
</form>
into the DB for a link and it's successful:
$file = "INSERT INTO ('foo') VALUES ('FOO', NOW())";
just an example:
yet in the php script:
$_FILE['fileToUpload']['name'];
$_FILE['fileToUpload']['tmp_name'];
since the tmp_name folder only holds upload files in an array, which than I would have to use either a foreach or for loop search the loop of files, this than makes the INSERT INTO db difficult.
Question is how can I separate the search results from the array and than insert each one into the database?
HERE"S THE CODE:
<?php
$con = mysqli_connect("localhost","root","","acc1");
if(mysqli_connect_errno()){
echo 'Failed to connect to MySQL:' . mysqli_connect_error();
}else{
echo 'Connected!';
}
if(isset($_POST['submit']) && !empty($_FILES['fileBC']['name'] && !empty($_FILES['fileB']['name'] && !empty($_FILES['fileBR']['name']) ))){
$file = "image/";
$name = $_FILES['fileBC']['name'];
$data = $_FILES['fileBC']['tmp_name'];
$fileV = "video/";
$nameV = $_FILES['fileBR']['name'];
$dataV = $_FILES['fileBR']['tmp_name'];
$fileB = "book/";
$nameB = $_FILES['fileB']['name'];
$dataB = $_FILES['fileB']['tmp_name'];
if(move_uploaded_file($data,$file.$name)){
$ins_name = $con->query("INSERT INTO fileimages (fileBC, fileBR, fileB) VALUES ('$name','$nameB', '$nameV')");
}if($ins_name){
echo 'success!';
}else{
echo 'error';
}
}
?>
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="css/bootstrap.css">
<link rel="stylesheet" href="css/fontawesome.css">
<script src="js/jquery.js"></script>
<script src="js/bootstrap.js"></script>
</head>
<script>
function mymodal(){
$('#myModal').modal('show');
}
</script>
<body>
<form method="post" action="index.php" enctype="multipart/form-data">
<div class="form-group">
<label class="text-primary">Book Cover:</label>
<input class="form-control" type="file" name="fileBC" accept="image/*" >
</div>
<div class="form-group">
<label class="text-primary">Book:</label>
<input class="form-control" type="file" name="fileB" accept=".epub, .mobi, .pdf, .prc, .azw, .bbeb" >
</div>
<div class="form-group">
<label class="text-primary">Book Reading:</label>
<input class="form-control" type="file" name="fileBR" accept="video/*" >
</div>
<button name="submit">upload</button>
</form>
<p></p>
<ol>
</ol>
</body>
</html>
php html
php html
asked Jan 3 at 6:22
Damian MitchellDamian Mitchell
177
asked Jan 3 at 6:22
Damian MitchellDamian Mitchell
177
edited Jan 3 at 7:51
Damian Mitchell
asked Jan 3 at 6:22
Damian MitchellDamian Mitchell
177
asked Jan 3 at 6:22
Damian MitchellDamian Mitchell
177
asked Jan 3 at 6:22
Damian MitchellDamian Mitchell
177
177
Why do you want to do this in such way?
– Amit Rajput
Jan 3 at 6:30
because this creates a link or url in the database in one form input if I can move the other contents to the other folders
– Damian Mitchell
Jan 3 at 6:33
allowing me to just place certain info in the link or url
– Damian Mitchell
Jan 3 at 6:34
You have twoid="fileToUpload"in your code, which is invalid,idneeds to be unique. The php manual itself has documentation on uploading multiple files
– kerbholz
Jan 3 at 7:26
add a comment |
Why do you want to do this in such way?
– Amit Rajput
Jan 3 at 6:30
because this creates a link or url in the database in one form input if I can move the other contents to the other folders
– Damian Mitchell
Jan 3 at 6:33
allowing me to just place certain info in the link or url
– Damian Mitchell
Jan 3 at 6:34
You have twoid="fileToUpload"in your code, which is invalid,idneeds to be unique. The php manual itself has documentation on uploading multiple files
– kerbholz
Jan 3 at 7:26
Why do you want to do this in such way?
– Amit Rajput
Jan 3 at 6:30
Why do you want to do this in such way?
– Amit Rajput
Jan 3 at 6:30
because this creates a link or url in the database in one form input if I can move the other contents to the other folders
– Damian Mitchell
Jan 3 at 6:33
because this creates a link or url in the database in one form input if I can move the other contents to the other folders
– Damian Mitchell
Jan 3 at 6:33
allowing me to just place certain info in the link or url
– Damian Mitchell
Jan 3 at 6:34
allowing me to just place certain info in the link or url
– Damian Mitchell
Jan 3 at 6:34
You have two
id="fileToUpload" in your code, which is invalid, id needs to be unique. The php manual itself has documentation on uploading multiple files– kerbholz
Jan 3 at 7:26
You have two
id="fileToUpload" in your code, which is invalid, id needs to be unique. The php manual itself has documentation on uploading multiple files– kerbholz
Jan 3 at 7:26
add a comment |
1 Answer
1
active
oldest
votes
0
This is an example you can adept it as per your need.
<form action="file_reciever.php" enctype="multipart/form-data" method="post">
<input type="file" name="files" multiple/>
<input type="submit" name="submission" value="Upload"/>
</form>
PHP code is like
<?php
if (isset($_POST['submission'] && $_POST['submission'] != null) {
for ($i = 0; $i < count($_FILES['files']['name']); $i++) {
//Get the temp file path
$tmpFilePath = $_FILES['files']['tmp_name'][$i];
//Make sure we have a filepath
if ($tmpFilePath != "") {
//Setup our new file path
$newFilePath = "./uploadFiles/" . $_FILES['files']['name'][$i];
//Upload the file into the temp dir
if (move_uploaded_file($tmpFilePath, $newFilePath)) {
//Your insert statement goes here
}
}
}
}
?>
edited Jan 3 at 12:29
Tanmay Patel
919920
answered Jan 3 at 6:34
RajeshRajesh
1258
I'm still stuck with the tmp file as being the folder and turning this into an array which means that my results will output $_FILES['files']['name'][0], $_FILES['files']['name'][1], $_FILES['files']['name'][2],...etc
– Damian Mitchell
Jan 3 at 6:40
which than makes the insert into three variables that have to be placed into the database yet that doesn't match the html
– Damian Mitchell
Jan 3 at 6:40
What you have wrote in insert statement?
– Rajesh
Jan 3 at 6:44
the problem I ran across is that when I use INSERT I no longer have the name or values from the html form. Now I have had a two file success on the INSERT yet not the move_to_file. when I have success on one there's no success on the other
– Damian Mitchell
Jan 3 at 6:46
Could you please add your code for better understanding?
– Rajesh
Jan 3 at 6:58
|
show 3 more comments
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
votes
active
oldest
votes
0
This is an example you can adept it as per your need.
<form action="file_reciever.php" enctype="multipart/form-data" method="post">
<input type="file" name="files" multiple/>
<input type="submit" name="submission" value="Upload"/>
</form>
PHP code is like
<?php
if (isset($_POST['submission'] && $_POST['submission'] != null) {
for ($i = 0; $i < count($_FILES['files']['name']); $i++) {
//Get the temp file path
$tmpFilePath = $_FILES['files']['tmp_name'][$i];
//Make sure we have a filepath
if ($tmpFilePath != "") {
//Setup our new file path
$newFilePath = "./uploadFiles/" . $_FILES['files']['name'][$i];
//Upload the file into the temp dir
if (move_uploaded_file($tmpFilePath, $newFilePath)) {
//Your insert statement goes here
}
}
}
}
?>
edited Jan 3 at 12:29
Tanmay Patel
919920
answered Jan 3 at 6:34
RajeshRajesh
1258
I'm still stuck with the tmp file as being the folder and turning this into an array which means that my results will output $_FILES['files']['name'][0], $_FILES['files']['name'][1], $_FILES['files']['name'][2],...etc
– Damian Mitchell
Jan 3 at 6:40
which than makes the insert into three variables that have to be placed into the database yet that doesn't match the html
– Damian Mitchell
Jan 3 at 6:40
What you have wrote in insert statement?
– Rajesh
Jan 3 at 6:44
the problem I ran across is that when I use INSERT I no longer have the name or values from the html form. Now I have had a two file success on the INSERT yet not the move_to_file. when I have success on one there's no success on the other
– Damian Mitchell
Jan 3 at 6:46
Could you please add your code for better understanding?
– Rajesh
Jan 3 at 6:58
|
show 3 more comments
0
This is an example you can adept it as per your need.
<form action="file_reciever.php" enctype="multipart/form-data" method="post">
<input type="file" name="files" multiple/>
<input type="submit" name="submission" value="Upload"/>
</form>
PHP code is like
<?php
if (isset($_POST['submission'] && $_POST['submission'] != null) {
for ($i = 0; $i < count($_FILES['files']['name']); $i++) {
//Get the temp file path
$tmpFilePath = $_FILES['files']['tmp_name'][$i];
//Make sure we have a filepath
if ($tmpFilePath != "") {
//Setup our new file path
$newFilePath = "./uploadFiles/" . $_FILES['files']['name'][$i];
//Upload the file into the temp dir
if (move_uploaded_file($tmpFilePath, $newFilePath)) {
//Your insert statement goes here
}
}
}
}
?>
edited Jan 3 at 12:29
Tanmay Patel
919920
answered Jan 3 at 6:34
RajeshRajesh
1258
I'm still stuck with the tmp file as being the folder and turning this into an array which means that my results will output $_FILES['files']['name'][0], $_FILES['files']['name'][1], $_FILES['files']['name'][2],...etc
– Damian Mitchell
Jan 3 at 6:40
which than makes the insert into three variables that have to be placed into the database yet that doesn't match the html
– Damian Mitchell
Jan 3 at 6:40
What you have wrote in insert statement?
– Rajesh
Jan 3 at 6:44
the problem I ran across is that when I use INSERT I no longer have the name or values from the html form. Now I have had a two file success on the INSERT yet not the move_to_file. when I have success on one there's no success on the other
– Damian Mitchell
Jan 3 at 6:46
Could you please add your code for better understanding?
– Rajesh
Jan 3 at 6:58
|
show 3 more comments
0
0
0
This is an example you can adept it as per your need.
<form action="file_reciever.php" enctype="multipart/form-data" method="post">
<input type="file" name="files" multiple/>
<input type="submit" name="submission" value="Upload"/>
</form>
PHP code is like
<?php
if (isset($_POST['submission'] && $_POST['submission'] != null) {
for ($i = 0; $i < count($_FILES['files']['name']); $i++) {
//Get the temp file path
$tmpFilePath = $_FILES['files']['tmp_name'][$i];
//Make sure we have a filepath
if ($tmpFilePath != "") {
//Setup our new file path
$newFilePath = "./uploadFiles/" . $_FILES['files']['name'][$i];
//Upload the file into the temp dir
if (move_uploaded_file($tmpFilePath, $newFilePath)) {
//Your insert statement goes here
}
}
}
}
?>
edited Jan 3 at 12:29
Tanmay Patel
919920
answered Jan 3 at 6:34
RajeshRajesh
1258
This is an example you can adept it as per your need.
<form action="file_reciever.php" enctype="multipart/form-data" method="post">
<input type="file" name="files" multiple/>
<input type="submit" name="submission" value="Upload"/>
</form>
PHP code is like
<?php
if (isset($_POST['submission'] && $_POST['submission'] != null) {
for ($i = 0; $i < count($_FILES['files']['name']); $i++) {
//Get the temp file path
$tmpFilePath = $_FILES['files']['tmp_name'][$i];
//Make sure we have a filepath
if ($tmpFilePath != "") {
//Setup our new file path
$newFilePath = "./uploadFiles/" . $_FILES['files']['name'][$i];
//Upload the file into the temp dir
if (move_uploaded_file($tmpFilePath, $newFilePath)) {
//Your insert statement goes here
}
}
}
}
?>
edited Jan 3 at 12:29
Tanmay Patel
919920
answered Jan 3 at 6:34
RajeshRajesh
1258
edited Jan 3 at 12:29
Tanmay Patel
919920
edited Jan 3 at 12:29
Tanmay Patel
919920
edited Jan 3 at 12:29
Tanmay Patel
919920
919920
answered Jan 3 at 6:34
RajeshRajesh
1258
answered Jan 3 at 6:34
RajeshRajesh
1258
answered Jan 3 at 6:34
RajeshRajesh
1258
1258
I'm still stuck with the tmp file as being the folder and turning this into an array which means that my results will output $_FILES['files']['name'][0], $_FILES['files']['name'][1], $_FILES['files']['name'][2],...etc
– Damian Mitchell
Jan 3 at 6:40
which than makes the insert into three variables that have to be placed into the database yet that doesn't match the html
– Damian Mitchell
Jan 3 at 6:40
What you have wrote in insert statement?
– Rajesh
Jan 3 at 6:44
the problem I ran across is that when I use INSERT I no longer have the name or values from the html form. Now I have had a two file success on the INSERT yet not the move_to_file. when I have success on one there's no success on the other
– Damian Mitchell
Jan 3 at 6:46
Could you please add your code for better understanding?
– Rajesh
Jan 3 at 6:58
|
show 3 more comments
I'm still stuck with the tmp file as being the folder and turning this into an array which means that my results will output $_FILES['files']['name'][0], $_FILES['files']['name'][1], $_FILES['files']['name'][2],...etc
– Damian Mitchell
Jan 3 at 6:40
which than makes the insert into three variables that have to be placed into the database yet that doesn't match the html
– Damian Mitchell
Jan 3 at 6:40
What you have wrote in insert statement?
– Rajesh
Jan 3 at 6:44
the problem I ran across is that when I use INSERT I no longer have the name or values from the html form. Now I have had a two file success on the INSERT yet not the move_to_file. when I have success on one there's no success on the other
– Damian Mitchell
Jan 3 at 6:46
Could you please add your code for better understanding?
– Rajesh
Jan 3 at 6:58
I'm still stuck with the tmp file as being the folder and turning this into an array which means that my results will output $_FILES['files']['name'][0], $_FILES['files']['name'][1], $_FILES['files']['name'][2],...etc
– Damian Mitchell
Jan 3 at 6:40
I'm still stuck with the tmp file as being the folder and turning this into an array which means that my results will output $_FILES['files']['name'][0], $_FILES['files']['name'][1], $_FILES['files']['name'][2],...etc
– Damian Mitchell
Jan 3 at 6:40
which than makes the insert into three variables that have to be placed into the database yet that doesn't match the html
– Damian Mitchell
Jan 3 at 6:40
which than makes the insert into three variables that have to be placed into the database yet that doesn't match the html
– Damian Mitchell
Jan 3 at 6:40
What you have wrote in insert statement?
– Rajesh
Jan 3 at 6:44
What you have wrote in insert statement?
– Rajesh
Jan 3 at 6:44
the problem I ran across is that when I use INSERT I no longer have the name or values from the html form. Now I have had a two file success on the INSERT yet not the move_to_file. when I have success on one there's no success on the other
– Damian Mitchell
Jan 3 at 6:46
the problem I ran across is that when I use INSERT I no longer have the name or values from the html form. Now I have had a two file success on the INSERT yet not the move_to_file. when I have success on one there's no success on the other
– Damian Mitchell
Jan 3 at 6:46
Could you please add your code for better understanding?
– Rajesh
Jan 3 at 6:58
Could you please add your code for better understanding?
– Rajesh
Jan 3 at 6:58
|
show 3 more comments
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Why do you want to do this in such way?
– Amit Rajput
Jan 3 at 6:30
because this creates a link or url in the database in one form input if I can move the other contents to the other folders
– Damian Mitchell
Jan 3 at 6:33
allowing me to just place certain info in the link or url
– Damian Mitchell
Jan 3 at 6:34
You have two
id="fileToUpload"in your code, which is invalid,idneeds to be unique. The php manual itself has documentation on uploading multiple files– kerbholz
Jan 3 at 7:26