Mixing
How to generate an exception in a different thread
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1
good night I am trying to generate an exception in this example code, the exception of generates if at the time of changing the text in the QLineEdit the text could not be converted into a number.
However, when I'm running, I get an error and the program stops
error:
QObject::setParent: Cannot set parent, new parent is in a different thread
this is the code:
from PyQt5.QtWidgets import QMainWindow, QApplication, QMessageBox
from PyQt5 import QtCore
from PyQt5 import uic
import threading
class TheThread(threading.Thread):
def __init__(self,text):
threading.Thread.__init__(self)
self.tx = text
def run(self):
try:
print(int(self.tx),"number")
except:
QMessageBox.critical(None,"Error","Error ",QMessageBox.Ok)
class Principal(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
uic.loadUi("test.ui",self)
self.lineEdit.textChanged.connect(lambda:self.evalNumeros(self.lineEdit.text()))
@QtCore.pyqtSlot(str)
def evalNumeros(self,texto):
print(texto)
try:
threadClass = TheThread(texto)
threadClass.start()
except:
print("error")
app = QApplication()
p = Principal()
p.show()
app.exec_()
this is the filu.ui for this code
test.ui
<?xml version="1.0" encoding="UTF-8"?>
<ui version="4.0">
<class>MainWindow</class>
<widget class="QMainWindow" name="MainWindow">
<property name="geometry">
<rect>
<x>0</x>
<y>0</y>
<width>641</width>
<height>479</height>
</rect>
</property>
<property name="windowTitle">
<string>MainWindow</string>
</property>
<widget class="QWidget" name="centralwidget">
<widget class="QLineEdit" name="lineEdit">
<property name="geometry">
<rect>
<x>200</x>
<y>100</y>
<width>191</width>
<height>20</height>
</rect>
</property>
</widget>
<widget class="QLabel" name="yes">
<property name="geometry">
<rect>
<x>170</x>
<y>150</y>
<width>111</width>
<height>31</height>
</rect>
</property>
<property name="styleSheet">
<string notr="true">color:white;
background:red;</string>
</property>
<property name="text">
<string/>
</property>
</widget>
<widget class="QLabel" name="no">
<property name="geometry">
<rect>
<x>300</x>
<y>150</y>
<width>111</width>
<height>31</height>
</rect>
</property>
<property name="styleSheet">
<string notr="true">color:white;
background:green;</string>
</property>
<property name="text">
<string/>
</property>
</widget>
</widget>
<widget class="QMenuBar" name="menubar">
<property name="geometry">
<rect>
<x>0</x>
<y>0</y>
<width>641</width>
<height>21</height>
</rect>
</property>
</widget>
<widget class="QStatusBar" name="statusbar"/>
</widget>
<resources/>
<connections/>
</ui>
python python-3.x pyqt pyqt5 qthread
edited Jan 3 at 23:15
eyllanesc
86.6k103564
asked Jan 3 at 5:40
Mystic_ForceMystic_Force
1748
add a comment |
1
good night I am trying to generate an exception in this example code, the exception of generates if at the time of changing the text in the QLineEdit the text could not be converted into a number.
However, when I'm running, I get an error and the program stops
error:
QObject::setParent: Cannot set parent, new parent is in a different thread
this is the code:
from PyQt5.QtWidgets import QMainWindow, QApplication, QMessageBox
from PyQt5 import QtCore
from PyQt5 import uic
import threading
class TheThread(threading.Thread):
def __init__(self,text):
threading.Thread.__init__(self)
self.tx = text
def run(self):
try:
print(int(self.tx),"number")
except:
QMessageBox.critical(None,"Error","Error ",QMessageBox.Ok)
class Principal(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
uic.loadUi("test.ui",self)
self.lineEdit.textChanged.connect(lambda:self.evalNumeros(self.lineEdit.text()))
@QtCore.pyqtSlot(str)
def evalNumeros(self,texto):
print(texto)
try:
threadClass = TheThread(texto)
threadClass.start()
except:
print("error")
app = QApplication()
p = Principal()
p.show()
app.exec_()
this is the filu.ui for this code
test.ui
<?xml version="1.0" encoding="UTF-8"?>
<ui version="4.0">
<class>MainWindow</class>
<widget class="QMainWindow" name="MainWindow">
<property name="geometry">
<rect>
<x>0</x>
<y>0</y>
<width>641</width>
<height>479</height>
</rect>
</property>
<property name="windowTitle">
<string>MainWindow</string>
</property>
<widget class="QWidget" name="centralwidget">
<widget class="QLineEdit" name="lineEdit">
<property name="geometry">
<rect>
<x>200</x>
<y>100</y>
<width>191</width>
<height>20</height>
</rect>
</property>
</widget>
<widget class="QLabel" name="yes">
<property name="geometry">
<rect>
<x>170</x>
<y>150</y>
<width>111</width>
<height>31</height>
</rect>
</property>
<property name="styleSheet">
<string notr="true">color:white;
background:red;</string>
</property>
<property name="text">
<string/>
</property>
</widget>
<widget class="QLabel" name="no">
<property name="geometry">
<rect>
<x>300</x>
<y>150</y>
<width>111</width>
<height>31</height>
</rect>
</property>
<property name="styleSheet">
<string notr="true">color:white;
background:green;</string>
</property>
<property name="text">
<string/>
</property>
</widget>
</widget>
<widget class="QMenuBar" name="menubar">
<property name="geometry">
<rect>
<x>0</x>
<y>0</y>
<width>641</width>
<height>21</height>
</rect>
</property>
</widget>
<widget class="QStatusBar" name="statusbar"/>
</widget>
<resources/>
<connections/>
</ui>
python python-3.x pyqt pyqt5 qthread
edited Jan 3 at 23:15
eyllanesc
86.6k103564
asked Jan 3 at 5:40
Mystic_ForceMystic_Force
1748
add a comment |
1
1
1
good night I am trying to generate an exception in this example code, the exception of generates if at the time of changing the text in the QLineEdit the text could not be converted into a number.
However, when I'm running, I get an error and the program stops
error:
QObject::setParent: Cannot set parent, new parent is in a different thread
this is the code:
from PyQt5.QtWidgets import QMainWindow, QApplication, QMessageBox
from PyQt5 import QtCore
from PyQt5 import uic
import threading
class TheThread(threading.Thread):
def __init__(self,text):
threading.Thread.__init__(self)
self.tx = text
def run(self):
try:
print(int(self.tx),"number")
except:
QMessageBox.critical(None,"Error","Error ",QMessageBox.Ok)
class Principal(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
uic.loadUi("test.ui",self)
self.lineEdit.textChanged.connect(lambda:self.evalNumeros(self.lineEdit.text()))
@QtCore.pyqtSlot(str)
def evalNumeros(self,texto):
print(texto)
try:
threadClass = TheThread(texto)
threadClass.start()
except:
print("error")
app = QApplication()
p = Principal()
p.show()
app.exec_()
this is the filu.ui for this code
test.ui
<?xml version="1.0" encoding="UTF-8"?>
<ui version="4.0">
<class>MainWindow</class>
<widget class="QMainWindow" name="MainWindow">
<property name="geometry">
<rect>
<x>0</x>
<y>0</y>
<width>641</width>
<height>479</height>
</rect>
</property>
<property name="windowTitle">
<string>MainWindow</string>
</property>
<widget class="QWidget" name="centralwidget">
<widget class="QLineEdit" name="lineEdit">
<property name="geometry">
<rect>
<x>200</x>
<y>100</y>
<width>191</width>
<height>20</height>
</rect>
</property>
</widget>
<widget class="QLabel" name="yes">
<property name="geometry">
<rect>
<x>170</x>
<y>150</y>
<width>111</width>
<height>31</height>
</rect>
</property>
<property name="styleSheet">
<string notr="true">color:white;
background:red;</string>
</property>
<property name="text">
<string/>
</property>
</widget>
<widget class="QLabel" name="no">
<property name="geometry">
<rect>
<x>300</x>
<y>150</y>
<width>111</width>
<height>31</height>
</rect>
</property>
<property name="styleSheet">
<string notr="true">color:white;
background:green;</string>
</property>
<property name="text">
<string/>
</property>
</widget>
</widget>
<widget class="QMenuBar" name="menubar">
<property name="geometry">
<rect>
<x>0</x>
<y>0</y>
<width>641</width>
<height>21</height>
</rect>
</property>
</widget>
<widget class="QStatusBar" name="statusbar"/>
</widget>
<resources/>
<connections/>
</ui>
python python-3.x pyqt pyqt5 qthread
edited Jan 3 at 23:15
eyllanesc
86.6k103564
asked Jan 3 at 5:40
Mystic_ForceMystic_Force
1748
good night I am trying to generate an exception in this example code, the exception of generates if at the time of changing the text in the QLineEdit the text could not be converted into a number.
However, when I'm running, I get an error and the program stops
error:
QObject::setParent: Cannot set parent, new parent is in a different thread
this is the code:
from PyQt5.QtWidgets import QMainWindow, QApplication, QMessageBox
from PyQt5 import QtCore
from PyQt5 import uic
import threading
class TheThread(threading.Thread):
def __init__(self,text):
threading.Thread.__init__(self)
self.tx = text
def run(self):
try:
print(int(self.tx),"number")
except:
QMessageBox.critical(None,"Error","Error ",QMessageBox.Ok)
class Principal(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
uic.loadUi("test.ui",self)
self.lineEdit.textChanged.connect(lambda:self.evalNumeros(self.lineEdit.text()))
@QtCore.pyqtSlot(str)
def evalNumeros(self,texto):
print(texto)
try:
threadClass = TheThread(texto)
threadClass.start()
except:
print("error")
app = QApplication()
p = Principal()
p.show()
app.exec_()
this is the filu.ui for this code
test.ui
<?xml version="1.0" encoding="UTF-8"?>
<ui version="4.0">
<class>MainWindow</class>
<widget class="QMainWindow" name="MainWindow">
<property name="geometry">
<rect>
<x>0</x>
<y>0</y>
<width>641</width>
<height>479</height>
</rect>
</property>
<property name="windowTitle">
<string>MainWindow</string>
</property>
<widget class="QWidget" name="centralwidget">
<widget class="QLineEdit" name="lineEdit">
<property name="geometry">
<rect>
<x>200</x>
<y>100</y>
<width>191</width>
<height>20</height>
</rect>
</property>
</widget>
<widget class="QLabel" name="yes">
<property name="geometry">
<rect>
<x>170</x>
<y>150</y>
<width>111</width>
<height>31</height>
</rect>
</property>
<property name="styleSheet">
<string notr="true">color:white;
background:red;</string>
</property>
<property name="text">
<string/>
</property>
</widget>
<widget class="QLabel" name="no">
<property name="geometry">
<rect>
<x>300</x>
<y>150</y>
<width>111</width>
<height>31</height>
</rect>
</property>
<property name="styleSheet">
<string notr="true">color:white;
background:green;</string>
</property>
<property name="text">
<string/>
</property>
</widget>
</widget>
<widget class="QMenuBar" name="menubar">
<property name="geometry">
<rect>
<x>0</x>
<y>0</y>
<width>641</width>
<height>21</height>
</rect>
</property>
</widget>
<widget class="QStatusBar" name="statusbar"/>
</widget>
<resources/>
<connections/>
</ui>
python python-3.x pyqt pyqt5 qthread
python python-3.x pyqt pyqt5 qthread
edited Jan 3 at 23:15
eyllanesc
86.6k103564
asked Jan 3 at 5:40
Mystic_ForceMystic_Force
1748
edited Jan 3 at 23:15
eyllanesc
86.6k103564
asked Jan 3 at 5:40
Mystic_ForceMystic_Force
1748
edited Jan 3 at 23:15
eyllanesc
86.6k103564
edited Jan 3 at 23:15
eyllanesc
86.6k103564
edited Jan 3 at 23:15
eyllanesc
86.6k103564
86.6k103564
asked Jan 3 at 5:40
Mystic_ForceMystic_Force
1748
asked Jan 3 at 5:40
Mystic_ForceMystic_Force
1748
asked Jan 3 at 5:40
Mystic_ForceMystic_Force
1748
1748
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
The problem is that you can not invoke the GUI directly in another thread, so there are 2 possible solutions: use a signal to invoke a method that shows the QMessageBox or use QMetaObject.invokeMethod to invoke that method, in this case I will use the second since the first one there are many examples in SO.
from PyQt5 import QtCore, QtWidgets, uic
from PyQt5 import uic
import threading
class TheThread(threading.Thread):
def __init__(self, text, obj):
threading.Thread.__init__(self)
self.tx = text
self.obj = obj
def run(self):
try:
print(int(self.tx),"number")
except:
QtCore.QMetaObject.invokeMethod(self.obj, "onError",
QtCore.Qt.QueuedConnection,
QtCore.Q_ARG(str, "Error"),
QtCore.Q_ARG(str, "Error"))
class Principal(QtWidgets.QMainWindow):
def __init__(self):
super(Principal, self).__init__()
uic.loadUi("test.ui",self)
self.lineEdit.textChanged.connect(self.evalNumeros)
@QtCore.pyqtSlot(str)
def evalNumeros(self,texto):
threadClass = TheThread(texto, self)
threadClass.start()
@QtCore.pyqtSlot(str, str)
def onError(self, title, text):
QtWidgets.QMessageBox.critical(None, title, text, QtWidgets.QMessageBox.Ok)
app = QtWidgets.QApplication()
p = Principal()
p.show()
app.exec_()
answered Jan 3 at 15:49
eyllanesceyllanesc
86.6k103564
,In this case it is not possible to just call theonErrormethod that is in the other class from theTheThread ()class instead of doing this:QtCore.QMetaObject.invokeMethod
– Mystic_Force
Feb 22 at 18:36
@Mystic_Force No, the GUI should only be updated from the main thread. If you call onError in run you would be updating the GUI from another thread and that is not correct, that is, nobody guarantees that its code works correctly
– eyllanesc
Feb 22 at 18:44
,thanks for the explanation
– Mystic_Force
Feb 22 at 18:46
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
The problem is that you can not invoke the GUI directly in another thread, so there are 2 possible solutions: use a signal to invoke a method that shows the QMessageBox or use QMetaObject.invokeMethod to invoke that method, in this case I will use the second since the first one there are many examples in SO.
from PyQt5 import QtCore, QtWidgets, uic
from PyQt5 import uic
import threading
class TheThread(threading.Thread):
def __init__(self, text, obj):
threading.Thread.__init__(self)
self.tx = text
self.obj = obj
def run(self):
try:
print(int(self.tx),"number")
except:
QtCore.QMetaObject.invokeMethod(self.obj, "onError",
QtCore.Qt.QueuedConnection,
QtCore.Q_ARG(str, "Error"),
QtCore.Q_ARG(str, "Error"))
class Principal(QtWidgets.QMainWindow):
def __init__(self):
super(Principal, self).__init__()
uic.loadUi("test.ui",self)
self.lineEdit.textChanged.connect(self.evalNumeros)
@QtCore.pyqtSlot(str)
def evalNumeros(self,texto):
threadClass = TheThread(texto, self)
threadClass.start()
@QtCore.pyqtSlot(str, str)
def onError(self, title, text):
QtWidgets.QMessageBox.critical(None, title, text, QtWidgets.QMessageBox.Ok)
app = QtWidgets.QApplication()
p = Principal()
p.show()
app.exec_()
answered Jan 3 at 15:49
eyllanesceyllanesc
86.6k103564
,In this case it is not possible to just call theonErrormethod that is in the other class from theTheThread ()class instead of doing this:QtCore.QMetaObject.invokeMethod
– Mystic_Force
Feb 22 at 18:36
@Mystic_Force No, the GUI should only be updated from the main thread. If you call onError in run you would be updating the GUI from another thread and that is not correct, that is, nobody guarantees that its code works correctly
– eyllanesc
Feb 22 at 18:44
,thanks for the explanation
– Mystic_Force
Feb 22 at 18:46
add a comment |
1
The problem is that you can not invoke the GUI directly in another thread, so there are 2 possible solutions: use a signal to invoke a method that shows the QMessageBox or use QMetaObject.invokeMethod to invoke that method, in this case I will use the second since the first one there are many examples in SO.
from PyQt5 import QtCore, QtWidgets, uic
from PyQt5 import uic
import threading
class TheThread(threading.Thread):
def __init__(self, text, obj):
threading.Thread.__init__(self)
self.tx = text
self.obj = obj
def run(self):
try:
print(int(self.tx),"number")
except:
QtCore.QMetaObject.invokeMethod(self.obj, "onError",
QtCore.Qt.QueuedConnection,
QtCore.Q_ARG(str, "Error"),
QtCore.Q_ARG(str, "Error"))
class Principal(QtWidgets.QMainWindow):
def __init__(self):
super(Principal, self).__init__()
uic.loadUi("test.ui",self)
self.lineEdit.textChanged.connect(self.evalNumeros)
@QtCore.pyqtSlot(str)
def evalNumeros(self,texto):
threadClass = TheThread(texto, self)
threadClass.start()
@QtCore.pyqtSlot(str, str)
def onError(self, title, text):
QtWidgets.QMessageBox.critical(None, title, text, QtWidgets.QMessageBox.Ok)
app = QtWidgets.QApplication()
p = Principal()
p.show()
app.exec_()
answered Jan 3 at 15:49
eyllanesceyllanesc
86.6k103564
,In this case it is not possible to just call theonErrormethod that is in the other class from theTheThread ()class instead of doing this:QtCore.QMetaObject.invokeMethod
– Mystic_Force
Feb 22 at 18:36
@Mystic_Force No, the GUI should only be updated from the main thread. If you call onError in run you would be updating the GUI from another thread and that is not correct, that is, nobody guarantees that its code works correctly
– eyllanesc
Feb 22 at 18:44
,thanks for the explanation
– Mystic_Force
Feb 22 at 18:46
add a comment |
1
1
1
The problem is that you can not invoke the GUI directly in another thread, so there are 2 possible solutions: use a signal to invoke a method that shows the QMessageBox or use QMetaObject.invokeMethod to invoke that method, in this case I will use the second since the first one there are many examples in SO.
from PyQt5 import QtCore, QtWidgets, uic
from PyQt5 import uic
import threading
class TheThread(threading.Thread):
def __init__(self, text, obj):
threading.Thread.__init__(self)
self.tx = text
self.obj = obj
def run(self):
try:
print(int(self.tx),"number")
except:
QtCore.QMetaObject.invokeMethod(self.obj, "onError",
QtCore.Qt.QueuedConnection,
QtCore.Q_ARG(str, "Error"),
QtCore.Q_ARG(str, "Error"))
class Principal(QtWidgets.QMainWindow):
def __init__(self):
super(Principal, self).__init__()
uic.loadUi("test.ui",self)
self.lineEdit.textChanged.connect(self.evalNumeros)
@QtCore.pyqtSlot(str)
def evalNumeros(self,texto):
threadClass = TheThread(texto, self)
threadClass.start()
@QtCore.pyqtSlot(str, str)
def onError(self, title, text):
QtWidgets.QMessageBox.critical(None, title, text, QtWidgets.QMessageBox.Ok)
app = QtWidgets.QApplication()
p = Principal()
p.show()
app.exec_()
answered Jan 3 at 15:49
eyllanesceyllanesc
86.6k103564
The problem is that you can not invoke the GUI directly in another thread, so there are 2 possible solutions: use a signal to invoke a method that shows the QMessageBox or use QMetaObject.invokeMethod to invoke that method, in this case I will use the second since the first one there are many examples in SO.
from PyQt5 import QtCore, QtWidgets, uic
from PyQt5 import uic
import threading
class TheThread(threading.Thread):
def __init__(self, text, obj):
threading.Thread.__init__(self)
self.tx = text
self.obj = obj
def run(self):
try:
print(int(self.tx),"number")
except:
QtCore.QMetaObject.invokeMethod(self.obj, "onError",
QtCore.Qt.QueuedConnection,
QtCore.Q_ARG(str, "Error"),
QtCore.Q_ARG(str, "Error"))
class Principal(QtWidgets.QMainWindow):
def __init__(self):
super(Principal, self).__init__()
uic.loadUi("test.ui",self)
self.lineEdit.textChanged.connect(self.evalNumeros)
@QtCore.pyqtSlot(str)
def evalNumeros(self,texto):
threadClass = TheThread(texto, self)
threadClass.start()
@QtCore.pyqtSlot(str, str)
def onError(self, title, text):
QtWidgets.QMessageBox.critical(None, title, text, QtWidgets.QMessageBox.Ok)
app = QtWidgets.QApplication()
p = Principal()
p.show()
app.exec_()
answered Jan 3 at 15:49
eyllanesceyllanesc
86.6k103564
answered Jan 3 at 15:49
eyllanesceyllanesc
86.6k103564
answered Jan 3 at 15:49
eyllanesceyllanesc
86.6k103564
answered Jan 3 at 15:49
eyllanesceyllanesc
86.6k103564
86.6k103564
,In this case it is not possible to just call theonErrormethod that is in the other class from theTheThread ()class instead of doing this:QtCore.QMetaObject.invokeMethod
– Mystic_Force
Feb 22 at 18:36
@Mystic_Force No, the GUI should only be updated from the main thread. If you call onError in run you would be updating the GUI from another thread and that is not correct, that is, nobody guarantees that its code works correctly
– eyllanesc
Feb 22 at 18:44
,thanks for the explanation
– Mystic_Force
Feb 22 at 18:46
add a comment |
,In this case it is not possible to just call theonErrormethod that is in the other class from theTheThread ()class instead of doing this:QtCore.QMetaObject.invokeMethod
– Mystic_Force
Feb 22 at 18:36
@Mystic_Force No, the GUI should only be updated from the main thread. If you call onError in run you would be updating the GUI from another thread and that is not correct, that is, nobody guarantees that its code works correctly
– eyllanesc
Feb 22 at 18:44
,thanks for the explanation
– Mystic_Force
Feb 22 at 18:46
,In this case it is not possible to just call the
onError method that is in the other class from the TheThread () class instead of doing this: QtCore.QMetaObject.invokeMethod– Mystic_Force
Feb 22 at 18:36
,In this case it is not possible to just call the
onError method that is in the other class from the TheThread () class instead of doing this: QtCore.QMetaObject.invokeMethod– Mystic_Force
Feb 22 at 18:36
@Mystic_Force No, the GUI should only be updated from the main thread. If you call onError in run you would be updating the GUI from another thread and that is not correct, that is, nobody guarantees that its code works correctly
– eyllanesc
Feb 22 at 18:44
@Mystic_Force No, the GUI should only be updated from the main thread. If you call onError in run you would be updating the GUI from another thread and that is not correct, that is, nobody guarantees that its code works correctly
– eyllanesc
Feb 22 at 18:44
,thanks for the explanation
– Mystic_Force
Feb 22 at 18:46
,thanks for the explanation
– Mystic_Force
Feb 22 at 18:46
add a comment |
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