If $E$ is a locally compact separable metric space, then $E$ is the union of a sequence of compact
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I have difficulty understanding the following passage.
Let $E$ be a locally compact separable metric space. Let $(x_p)_{pgeq 0}$ be a dense sequence in $E$. Define
$$I:={(p,k)in mathbb{N}^2:bar{B}(x_p,2^{-k}) text{ is compact}},$$
where $bar{B}(x,r)$ is the closed ball with center $x$ and radius $r$. Using the fact that $E$ is locally compact and the density of $(x_p)$ it is easy to see that
$$E=bigcup_{(p,k)in I} bar{B}(x_p,2^{-k}).$$
I don't know why the last sentence is true. If I take $xin E$, then I need to show that $x$ is in some $bar{B}(x_p,2^{-k})$ for $(p,k)in I$. Since $E$ is locally compact, I know that there exists $r>0$ such that $bar{B}(x,r)$ is compact, since $(x_p)$ is dense in $E$, there exist $n$ such that $x_nin bar{B}(x,r)$. But this does not get me to where I need to prove.
I appreciate any help!
general-topology
$endgroup$
add a comment |
$begingroup$
I have difficulty understanding the following passage.
Let $E$ be a locally compact separable metric space. Let $(x_p)_{pgeq 0}$ be a dense sequence in $E$. Define
$$I:={(p,k)in mathbb{N}^2:bar{B}(x_p,2^{-k}) text{ is compact}},$$
where $bar{B}(x,r)$ is the closed ball with center $x$ and radius $r$. Using the fact that $E$ is locally compact and the density of $(x_p)$ it is easy to see that
$$E=bigcup_{(p,k)in I} bar{B}(x_p,2^{-k}).$$
I don't know why the last sentence is true. If I take $xin E$, then I need to show that $x$ is in some $bar{B}(x_p,2^{-k})$ for $(p,k)in I$. Since $E$ is locally compact, I know that there exists $r>0$ such that $bar{B}(x,r)$ is compact, since $(x_p)$ is dense in $E$, there exist $n$ such that $x_nin bar{B}(x,r)$. But this does not get me to where I need to prove.
I appreciate any help!
general-topology
$endgroup$
add a comment |
$begingroup$
I have difficulty understanding the following passage.
Let $E$ be a locally compact separable metric space. Let $(x_p)_{pgeq 0}$ be a dense sequence in $E$. Define
$$I:={(p,k)in mathbb{N}^2:bar{B}(x_p,2^{-k}) text{ is compact}},$$
where $bar{B}(x,r)$ is the closed ball with center $x$ and radius $r$. Using the fact that $E$ is locally compact and the density of $(x_p)$ it is easy to see that
$$E=bigcup_{(p,k)in I} bar{B}(x_p,2^{-k}).$$
I don't know why the last sentence is true. If I take $xin E$, then I need to show that $x$ is in some $bar{B}(x_p,2^{-k})$ for $(p,k)in I$. Since $E$ is locally compact, I know that there exists $r>0$ such that $bar{B}(x,r)$ is compact, since $(x_p)$ is dense in $E$, there exist $n$ such that $x_nin bar{B}(x,r)$. But this does not get me to where I need to prove.
I appreciate any help!
general-topology
$endgroup$
I have difficulty understanding the following passage.
Let $E$ be a locally compact separable metric space. Let $(x_p)_{pgeq 0}$ be a dense sequence in $E$. Define
$$I:={(p,k)in mathbb{N}^2:bar{B}(x_p,2^{-k}) text{ is compact}},$$
where $bar{B}(x,r)$ is the closed ball with center $x$ and radius $r$. Using the fact that $E$ is locally compact and the density of $(x_p)$ it is easy to see that
$$E=bigcup_{(p,k)in I} bar{B}(x_p,2^{-k}).$$
I don't know why the last sentence is true. If I take $xin E$, then I need to show that $x$ is in some $bar{B}(x_p,2^{-k})$ for $(p,k)in I$. Since $E$ is locally compact, I know that there exists $r>0$ such that $bar{B}(x,r)$ is compact, since $(x_p)$ is dense in $E$, there exist $n$ such that $x_nin bar{B}(x,r)$. But this does not get me to where I need to prove.
I appreciate any help!
general-topology
general-topology
asked Feb 3 at 3:41


JiuJiu
552113
552113
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1 Answer
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$begingroup$
Let $xin E$ be given.
Choose $varepsilongt0$ so that $overline B(x,varepsilon)$ is compact.
Choose $kinmathbb N$ so that $2^{-k}ltfracvarepsilon3$.
Choose $pinmathbb N$ so that $operatorname d(x_p,x)lt2^{-k}$.
Then $xinoverline B(x_p,2^{-k})subseteqoverline B(x,varepsilon)$, so $overline B(x_p,2^{-k})$ is compact.
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$begingroup$
Let $xin E$ be given.
Choose $varepsilongt0$ so that $overline B(x,varepsilon)$ is compact.
Choose $kinmathbb N$ so that $2^{-k}ltfracvarepsilon3$.
Choose $pinmathbb N$ so that $operatorname d(x_p,x)lt2^{-k}$.
Then $xinoverline B(x_p,2^{-k})subseteqoverline B(x,varepsilon)$, so $overline B(x_p,2^{-k})$ is compact.
$endgroup$
add a comment |
$begingroup$
Let $xin E$ be given.
Choose $varepsilongt0$ so that $overline B(x,varepsilon)$ is compact.
Choose $kinmathbb N$ so that $2^{-k}ltfracvarepsilon3$.
Choose $pinmathbb N$ so that $operatorname d(x_p,x)lt2^{-k}$.
Then $xinoverline B(x_p,2^{-k})subseteqoverline B(x,varepsilon)$, so $overline B(x_p,2^{-k})$ is compact.
$endgroup$
add a comment |
$begingroup$
Let $xin E$ be given.
Choose $varepsilongt0$ so that $overline B(x,varepsilon)$ is compact.
Choose $kinmathbb N$ so that $2^{-k}ltfracvarepsilon3$.
Choose $pinmathbb N$ so that $operatorname d(x_p,x)lt2^{-k}$.
Then $xinoverline B(x_p,2^{-k})subseteqoverline B(x,varepsilon)$, so $overline B(x_p,2^{-k})$ is compact.
$endgroup$
Let $xin E$ be given.
Choose $varepsilongt0$ so that $overline B(x,varepsilon)$ is compact.
Choose $kinmathbb N$ so that $2^{-k}ltfracvarepsilon3$.
Choose $pinmathbb N$ so that $operatorname d(x_p,x)lt2^{-k}$.
Then $xinoverline B(x_p,2^{-k})subseteqoverline B(x,varepsilon)$, so $overline B(x_p,2^{-k})$ is compact.
answered Feb 3 at 3:56
bofbof
52.6k559121
52.6k559121
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