Is $sup_{xin mathbb R} sqrt{|x|} sin x = + infty$?
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The graph of $sqrt{|x|} sin x$ seems like staying around the $x$-axis, but $lim_{xto infty} sqrt{|x|} = +infty$ and $sin x$ is bounded.
real-analysis analysis proof-explanation intuition
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add a comment |
$begingroup$
The graph of $sqrt{|x|} sin x$ seems like staying around the $x$-axis, but $lim_{xto infty} sqrt{|x|} = +infty$ and $sin x$ is bounded.
real-analysis analysis proof-explanation intuition
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Perhaps a more interesting question is if you restrict $x$ to be an integer.
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– MathematicsStudent1122
Feb 1 at 5:53
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$begingroup$
The graph of $sqrt{|x|} sin x$ seems like staying around the $x$-axis, but $lim_{xto infty} sqrt{|x|} = +infty$ and $sin x$ is bounded.
real-analysis analysis proof-explanation intuition
$endgroup$
The graph of $sqrt{|x|} sin x$ seems like staying around the $x$-axis, but $lim_{xto infty} sqrt{|x|} = +infty$ and $sin x$ is bounded.
real-analysis analysis proof-explanation intuition
real-analysis analysis proof-explanation intuition
asked Feb 1 at 5:47
user398843user398843
708316
708316
$begingroup$
Perhaps a more interesting question is if you restrict $x$ to be an integer.
$endgroup$
– MathematicsStudent1122
Feb 1 at 5:53
add a comment |
$begingroup$
Perhaps a more interesting question is if you restrict $x$ to be an integer.
$endgroup$
– MathematicsStudent1122
Feb 1 at 5:53
$begingroup$
Perhaps a more interesting question is if you restrict $x$ to be an integer.
$endgroup$
– MathematicsStudent1122
Feb 1 at 5:53
$begingroup$
Perhaps a more interesting question is if you restrict $x$ to be an integer.
$endgroup$
– MathematicsStudent1122
Feb 1 at 5:53
add a comment |
1 Answer
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$begingroup$
Let $x = frac{pi}2 +2npi$,
Then, $$sqrt{|x|} sin x=sqrt{frac{pi}2+2npi}$$
Now, let $nto infty$ to get your result.
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add a comment |
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1 Answer
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1 Answer
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$begingroup$
Let $x = frac{pi}2 +2npi$,
Then, $$sqrt{|x|} sin x=sqrt{frac{pi}2+2npi}$$
Now, let $nto infty$ to get your result.
$endgroup$
add a comment |
$begingroup$
Let $x = frac{pi}2 +2npi$,
Then, $$sqrt{|x|} sin x=sqrt{frac{pi}2+2npi}$$
Now, let $nto infty$ to get your result.
$endgroup$
add a comment |
$begingroup$
Let $x = frac{pi}2 +2npi$,
Then, $$sqrt{|x|} sin x=sqrt{frac{pi}2+2npi}$$
Now, let $nto infty$ to get your result.
$endgroup$
Let $x = frac{pi}2 +2npi$,
Then, $$sqrt{|x|} sin x=sqrt{frac{pi}2+2npi}$$
Now, let $nto infty$ to get your result.
answered Feb 1 at 5:52


Siong Thye GohSiong Thye Goh
104k1468120
104k1468120
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$begingroup$
Perhaps a more interesting question is if you restrict $x$ to be an integer.
$endgroup$
– MathematicsStudent1122
Feb 1 at 5:53