php 7.2 upgrade error “Cannot assign an empty string to a string offset”

I'm working with an aged wordpress theme which I really like and I only have some basic coding skills. My provider forcably upgraded my server php version to 7.2 and of course some of my scripts are breaking down.

public function localize( $handle, $object_name, $l10n ) {

    if ( $handle === 'jquery' )

        $handle = 'jquery-core';



    if ( is_array($l10n) && isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

        unset($l10n['l10n_print_after']);

    }



    foreach ( (array) $l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }``

According to the log the error is in the last line because in that like apparently it "Cannot assign an empty string to a string offset"

Maybe this is a lot more complicated than changing one simple thing....any solutions for that?

asked Jan 2 at 21:28

EaZy

what is $l10n is it an array? public function localize( $handle, $object_name, array $l10n ) It looks like it could be mixed data type is_array($l10n) and (array) $l10n if you try to set a key on a string, you get an error like that.

– ArtisticPhoenix
Jan 2 at 21:33

add a comment |

public function localize( $handle, $object_name, $l10n ) {

    if ( $handle === 'jquery' )

        $handle = 'jquery-core';



    if ( is_array($l10n) && isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

        unset($l10n['l10n_print_after']);

    }



    foreach ( (array) $l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }``

According to the log the error is in the last line because in that like apparently it "Cannot assign an empty string to a string offset"

Maybe this is a lot more complicated than changing one simple thing....any solutions for that?

asked Jan 2 at 21:28

EaZy

what is $l10n is it an array? public function localize( $handle, $object_name, array $l10n ) It looks like it could be mixed data type is_array($l10n) and (array) $l10n if you try to set a key on a string, you get an error like that.

– ArtisticPhoenix
Jan 2 at 21:33

add a comment |

public function localize( $handle, $object_name, $l10n ) {

    if ( $handle === 'jquery' )

        $handle = 'jquery-core';



    if ( is_array($l10n) && isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

        unset($l10n['l10n_print_after']);

    }



    foreach ( (array) $l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }``

According to the log the error is in the last line because in that like apparently it "Cannot assign an empty string to a string offset"

Maybe this is a lot more complicated than changing one simple thing....any solutions for that?

asked Jan 2 at 21:28

EaZy

public function localize( $handle, $object_name, $l10n ) {

    if ( $handle === 'jquery' )

        $handle = 'jquery-core';



    if ( is_array($l10n) && isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

        unset($l10n['l10n_print_after']);

    }



    foreach ( (array) $l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }``

According to the log the error is in the last line because in that like apparently it "Cannot assign an empty string to a string offset"

Maybe this is a lot more complicated than changing one simple thing....any solutions for that?

php wordpress

asked Jan 2 at 21:28

EaZy

asked Jan 2 at 21:28

EaZy

asked Jan 2 at 21:28

EaZy

asked Jan 2 at 21:28

EaZy

asked Jan 2 at 21:28

EaZy

what is $l10n is it an array? public function localize( $handle, $object_name, array $l10n ) It looks like it could be mixed data type is_array($l10n) and (array) $l10n if you try to set a key on a string, you get an error like that.

– ArtisticPhoenix
Jan 2 at 21:33

add a comment |

what is $l10n is it an array? public function localize( $handle, $object_name, array $l10n ) It looks like it could be mixed data type is_array($l10n) and (array) $l10n if you try to set a key on a string, you get an error like that.

– ArtisticPhoenix
Jan 2 at 21:33

what is $l10n is it an array? public function localize( $handle, $object_name, array $l10n ) It looks like it could be mixed data type is_array($l10n) and (array) $l10n if you try to set a key on a string, you get an error like that.

– ArtisticPhoenix
Jan 2 at 21:33

add a comment |

2 Answers
2

active

oldest

votes

The most logical thing to do here is to change it to update in the in_array condition:

if ( is_array($l10n){

    if(isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

         unset($l10n['l10n_print_after']);

    }

    foreach ($l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }

}

Even if you cast (array)$l10n to an array, this doesn't set the variable itself to be an array ( like $l10n = (array)$l10n).

That said, working with mixed types can be really cumbersome. It's better to send it only arrays or deal with the array bit first, that way you have a consistent type. Like this:

public function localize( $handle, $object_name, $l10n ) {

    //normalize arguments

    if(!is_array($l10n)) $l10n = [$l10n];



    if ( $handle === 'jquery' )

        $handle = 'jquery-core';



    if ( isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

        unset($l10n['l10n_print_after']);

    }



    foreach ($l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }

}

edited Jan 2 at 21:45

answered Jan 2 at 21:38

ArtisticPhoenix

18.2k11226

Thank you @ArtisticPhoenix. This got rid of the Error

– EaZy
Jan 2 at 21:49

Hi everyone. Any suggestions as to how to change the last line in this code so it won't throw a "deprecated function" alert in the log? function make_plural_form_function($nplurals, $expression) { $expression = str_replace('n', '$n', $expression); $func_body = " $index = (int)($expression); return ($index < $nplurals)? $index : $nplurals - 1;"; return create_function('$n', $func_body); Thank you for your help

– EaZy
Jan 2 at 22:12

1

If you have another different problem I suggest posting it as a proper question. It will be much easier to deal with that way, instead of muddying the waters.

– ArtisticPhoenix
Jan 2 at 22:19

@EaZy: if Phoenix's answer helped you fix the issue, it'd be nice if in return you accepted his answer: What should I do if someone answers my question?

– cabrerahector
Jan 2 at 23:33

OK thank you I did accept it. even though my upvotes don't count until I reach 15

– EaZy
Jan 3 at 11:38

add a comment |

-1

Another possible route to fixing this is to force your server to run an older version of php if they can do that. For example with pantheon.io you can force the server to run a certain version of php in the server config file.

Unless you would like to modernize all your scripts, then ignore this.

answered Jan 3 at 0:55

NickC

345

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

The most logical thing to do here is to change it to update in the in_array condition:

if ( is_array($l10n){

    if(isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

         unset($l10n['l10n_print_after']);

    }

    foreach ($l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }

}

Even if you cast (array)$l10n to an array, this doesn't set the variable itself to be an array ( like $l10n = (array)$l10n).

That said, working with mixed types can be really cumbersome. It's better to send it only arrays or deal with the array bit first, that way you have a consistent type. Like this:

public function localize( $handle, $object_name, $l10n ) {

    //normalize arguments

    if(!is_array($l10n)) $l10n = [$l10n];



    if ( $handle === 'jquery' )

        $handle = 'jquery-core';



    if ( isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

        unset($l10n['l10n_print_after']);

    }



    foreach ($l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }

}

edited Jan 2 at 21:45

answered Jan 2 at 21:38

ArtisticPhoenix

18.2k11226

Thank you @ArtisticPhoenix. This got rid of the Error

– EaZy
Jan 2 at 21:49

Hi everyone. Any suggestions as to how to change the last line in this code so it won't throw a "deprecated function" alert in the log? function make_plural_form_function($nplurals, $expression) { $expression = str_replace('n', '$n', $expression); $func_body = " $index = (int)($expression); return ($index < $nplurals)? $index : $nplurals - 1;"; return create_function('$n', $func_body); Thank you for your help

– EaZy
Jan 2 at 22:12

1

If you have another different problem I suggest posting it as a proper question. It will be much easier to deal with that way, instead of muddying the waters.

– ArtisticPhoenix
Jan 2 at 22:19

@EaZy: if Phoenix's answer helped you fix the issue, it'd be nice if in return you accepted his answer: What should I do if someone answers my question?

– cabrerahector
Jan 2 at 23:33

OK thank you I did accept it. even though my upvotes don't count until I reach 15

– EaZy
Jan 3 at 11:38

add a comment |

The most logical thing to do here is to change it to update in the in_array condition:

if ( is_array($l10n){

    if(isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

         unset($l10n['l10n_print_after']);

    }

    foreach ($l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }

}

Even if you cast (array)$l10n to an array, this doesn't set the variable itself to be an array ( like $l10n = (array)$l10n).

That said, working with mixed types can be really cumbersome. It's better to send it only arrays or deal with the array bit first, that way you have a consistent type. Like this:

public function localize( $handle, $object_name, $l10n ) {

    //normalize arguments

    if(!is_array($l10n)) $l10n = [$l10n];



    if ( $handle === 'jquery' )

        $handle = 'jquery-core';



    if ( isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

        unset($l10n['l10n_print_after']);

    }



    foreach ($l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }

}

edited Jan 2 at 21:45

answered Jan 2 at 21:38

ArtisticPhoenix

18.2k11226

Thank you @ArtisticPhoenix. This got rid of the Error

– EaZy
Jan 2 at 21:49

Hi everyone. Any suggestions as to how to change the last line in this code so it won't throw a "deprecated function" alert in the log? function make_plural_form_function($nplurals, $expression) { $expression = str_replace('n', '$n', $expression); $func_body = " $index = (int)($expression); return ($index < $nplurals)? $index : $nplurals - 1;"; return create_function('$n', $func_body); Thank you for your help

– EaZy
Jan 2 at 22:12

1

If you have another different problem I suggest posting it as a proper question. It will be much easier to deal with that way, instead of muddying the waters.

– ArtisticPhoenix
Jan 2 at 22:19

@EaZy: if Phoenix's answer helped you fix the issue, it'd be nice if in return you accepted his answer: What should I do if someone answers my question?

– cabrerahector
Jan 2 at 23:33

OK thank you I did accept it. even though my upvotes don't count until I reach 15

– EaZy
Jan 3 at 11:38

add a comment |

The most logical thing to do here is to change it to update in the in_array condition:

if ( is_array($l10n){

    if(isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

         unset($l10n['l10n_print_after']);

    }

    foreach ($l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }

}

Even if you cast (array)$l10n to an array, this doesn't set the variable itself to be an array ( like $l10n = (array)$l10n).

That said, working with mixed types can be really cumbersome. It's better to send it only arrays or deal with the array bit first, that way you have a consistent type. Like this:

public function localize( $handle, $object_name, $l10n ) {

    //normalize arguments

    if(!is_array($l10n)) $l10n = [$l10n];



    if ( $handle === 'jquery' )

        $handle = 'jquery-core';



    if ( isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

        unset($l10n['l10n_print_after']);

    }



    foreach ($l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }

}

edited Jan 2 at 21:45

answered Jan 2 at 21:38

ArtisticPhoenix

18.2k11226

The most logical thing to do here is to change it to update in the in_array condition:

if ( is_array($l10n){

    if(isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

         unset($l10n['l10n_print_after']);

    }

    foreach ($l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }

}

Even if you cast (array)$l10n to an array, this doesn't set the variable itself to be an array ( like $l10n = (array)$l10n).

That said, working with mixed types can be really cumbersome. It's better to send it only arrays or deal with the array bit first, that way you have a consistent type. Like this:

public function localize( $handle, $object_name, $l10n ) {

    //normalize arguments

    if(!is_array($l10n)) $l10n = [$l10n];



    if ( $handle === 'jquery' )

        $handle = 'jquery-core';



    if ( isset($l10n['l10n_print_after']) ) { // back compat, preserve the code in 'l10n_print_after' if present

        $after = $l10n['l10n_print_after'];

        unset($l10n['l10n_print_after']);

    }



    foreach ($l10n as $key => $value ) {

        if ( !is_scalar($value) )

            continue;



        $l10n[$key] = html_entity_decode( (string) $value, ENT_QUOTES, 'UTF-8');

    }

}

edited Jan 2 at 21:45

answered Jan 2 at 21:38

ArtisticPhoenix

18.2k11226

edited Jan 2 at 21:45

answered Jan 2 at 21:38

ArtisticPhoenix

18.2k11226

answered Jan 2 at 21:38

ArtisticPhoenix

18.2k11226

answered Jan 2 at 21:38

ArtisticPhoenix

18.2k11226

Thank you @ArtisticPhoenix. This got rid of the Error

– EaZy
Jan 2 at 21:49

Hi everyone. Any suggestions as to how to change the last line in this code so it won't throw a "deprecated function" alert in the log? function make_plural_form_function($nplurals, $expression) { $expression = str_replace('n', '$n', $expression); $func_body = " $index = (int)($expression); return ($index < $nplurals)? $index : $nplurals - 1;"; return create_function('$n', $func_body); Thank you for your help

– EaZy
Jan 2 at 22:12

1

If you have another different problem I suggest posting it as a proper question. It will be much easier to deal with that way, instead of muddying the waters.

– ArtisticPhoenix
Jan 2 at 22:19

@EaZy: if Phoenix's answer helped you fix the issue, it'd be nice if in return you accepted his answer: What should I do if someone answers my question?

– cabrerahector
Jan 2 at 23:33

OK thank you I did accept it. even though my upvotes don't count until I reach 15

– EaZy
Jan 3 at 11:38

add a comment |

Thank you @ArtisticPhoenix. This got rid of the Error

– EaZy
Jan 2 at 21:49

Hi everyone. Any suggestions as to how to change the last line in this code so it won't throw a "deprecated function" alert in the log? function make_plural_form_function($nplurals, $expression) { $expression = str_replace('n', '$n', $expression); $func_body = " $index = (int)($expression); return ($index < $nplurals)? $index : $nplurals - 1;"; return create_function('$n', $func_body); Thank you for your help

– EaZy
Jan 2 at 22:12

1

If you have another different problem I suggest posting it as a proper question. It will be much easier to deal with that way, instead of muddying the waters.

– ArtisticPhoenix
Jan 2 at 22:19

@EaZy: if Phoenix's answer helped you fix the issue, it'd be nice if in return you accepted his answer: What should I do if someone answers my question?

– cabrerahector
Jan 2 at 23:33

OK thank you I did accept it. even though my upvotes don't count until I reach 15

– EaZy
Jan 3 at 11:38

Thank you @ArtisticPhoenix. This got rid of the Error

– EaZy
Jan 2 at 21:49

Hi everyone. Any suggestions as to how to change the last line in this code so it won't throw a "deprecated function" alert in the log? function make_plural_form_function($nplurals, $expression) { $expression = str_replace('n', '$n', $expression); $func_body = " $index = (int)($expression); return ($index < $nplurals)? $index : $nplurals - 1;"; return create_function('$n', $func_body); Thank you for your help

– EaZy
Jan 2 at 22:12

If you have another different problem I suggest posting it as a proper question. It will be much easier to deal with that way, instead of muddying the waters.

– ArtisticPhoenix
Jan 2 at 22:19

@EaZy: if Phoenix's answer helped you fix the issue, it'd be nice if in return you accepted his answer: What should I do if someone answers my question?

– cabrerahector
Jan 2 at 23:33

OK thank you I did accept it. even though my upvotes don't count until I reach 15

– EaZy
Jan 3 at 11:38

add a comment |

-1

Unless you would like to modernize all your scripts, then ignore this.

answered Jan 3 at 0:55

NickC

345

add a comment |

-1

Unless you would like to modernize all your scripts, then ignore this.

answered Jan 3 at 0:55

NickC

345

add a comment |

-1

Unless you would like to modernize all your scripts, then ignore this.

answered Jan 3 at 0:55

NickC

345

Unless you would like to modernize all your scripts, then ignore this.

answered Jan 3 at 0:55

NickC

345

answered Jan 3 at 0:55

NickC

345

answered Jan 3 at 0:55

NickC

345

answered Jan 3 at 0:55

NickC

345

add a comment |

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