Mixing
Probability of a whole group being corrupt [closed]
$begingroup$
Thank you guys in advance for answering.
I can't find the right computation for my question, your help would be so appreciated!
1 group is 24 people
Total people is 1000
Let's say I choose randomly 24 people (to make a group) (minimum people #1, maximum people # 1000), I can't choose the same number both, those people (numbers) are the one I will let decide on this specific law.
So for this election, those 24 people will decide what to do.
What are the odds that those 24 people (this group) (on 1000 people) know each other and will give away the same decision (corrupt)?
============================
let's say those 24 people ALREADY know each other and plan an attack: 1, 5, 8, 10, 12, 14, 15, 16, 18, 50, 840, 720, 40, 41, 42, 43, 44, 48, 60, 70, 80, 81, 82, 83 What is the odd that I WILL choose them?
probability
asked Jan 30 at 8:52
AlbertBrenamanAlbertBrenaman
62
$endgroup$
closed as unclear what you're asking by José Carlos Santos, Riccardo.Alestra, Jyrki Lahtonen, Adrian Keister, drhab Jan 30 at 14:41
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
Thank you guys in advance for answering.
I can't find the right computation for my question, your help would be so appreciated!
1 group is 24 people
Total people is 1000
Let's say I choose randomly 24 people (to make a group) (minimum people #1, maximum people # 1000), I can't choose the same number both, those people (numbers) are the one I will let decide on this specific law.
So for this election, those 24 people will decide what to do.
What are the odds that those 24 people (this group) (on 1000 people) know each other and will give away the same decision (corrupt)?
============================
let's say those 24 people ALREADY know each other and plan an attack: 1, 5, 8, 10, 12, 14, 15, 16, 18, 50, 840, 720, 40, 41, 42, 43, 44, 48, 60, 70, 80, 81, 82, 83 What is the odd that I WILL choose them?
probability
asked Jan 30 at 8:52
AlbertBrenamanAlbertBrenaman
62
$endgroup$
closed as unclear what you're asking by José Carlos Santos, Riccardo.Alestra, Jyrki Lahtonen, Adrian Keister, drhab Jan 30 at 14:41
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
Please make your question clearer. How do we know whether those 24 people know each other or not?
$endgroup$
– abc...
Jan 30 at 8:59
$begingroup$
let's say those 24 people ALREADY know each other and plan an attack: 1, 5, 8, 10, 12, 14, 15, 16, 18, 50, 840, 720, 40, 41, 42, 43, 44, 48, 60, 70, 80, 81, 82, 83 What is the odd that I WILL choose them?
$endgroup$
– AlbertBrenaman
Jan 30 at 9:03
$begingroup$
We cannot answer the question unless you provide more information. How likely is it that two people in the population of 1000 know each other ? For example, if everyone knows everyone else then any set of 24 people that you choose will all know each other.
$endgroup$
– gandalf61
Jan 30 at 9:12
$begingroup$
In this case, it's a maximum of 24 people who knows each other.
$endgroup$
– AlbertBrenaman
Jan 30 at 9:12
$begingroup$
24/1000 maximum
$endgroup$
– AlbertBrenaman
Jan 30 at 10:22
add a comment |
$begingroup$
Thank you guys in advance for answering.
I can't find the right computation for my question, your help would be so appreciated!
1 group is 24 people
Total people is 1000
Let's say I choose randomly 24 people (to make a group) (minimum people #1, maximum people # 1000), I can't choose the same number both, those people (numbers) are the one I will let decide on this specific law.
So for this election, those 24 people will decide what to do.
What are the odds that those 24 people (this group) (on 1000 people) know each other and will give away the same decision (corrupt)?
============================
let's say those 24 people ALREADY know each other and plan an attack: 1, 5, 8, 10, 12, 14, 15, 16, 18, 50, 840, 720, 40, 41, 42, 43, 44, 48, 60, 70, 80, 81, 82, 83 What is the odd that I WILL choose them?
probability
asked Jan 30 at 8:52
AlbertBrenamanAlbertBrenaman
62
$endgroup$
Thank you guys in advance for answering.
I can't find the right computation for my question, your help would be so appreciated!
1 group is 24 people
Total people is 1000
Let's say I choose randomly 24 people (to make a group) (minimum people #1, maximum people # 1000), I can't choose the same number both, those people (numbers) are the one I will let decide on this specific law.
So for this election, those 24 people will decide what to do.
What are the odds that those 24 people (this group) (on 1000 people) know each other and will give away the same decision (corrupt)?
============================
let's say those 24 people ALREADY know each other and plan an attack: 1, 5, 8, 10, 12, 14, 15, 16, 18, 50, 840, 720, 40, 41, 42, 43, 44, 48, 60, 70, 80, 81, 82, 83 What is the odd that I WILL choose them?
probability
probability
asked Jan 30 at 8:52
AlbertBrenamanAlbertBrenaman
62
asked Jan 30 at 8:52
AlbertBrenamanAlbertBrenaman
62
edited Jan 30 at 9:03
AlbertBrenaman
asked Jan 30 at 8:52
AlbertBrenamanAlbertBrenaman
62
asked Jan 30 at 8:52
AlbertBrenamanAlbertBrenaman
62
asked Jan 30 at 8:52
AlbertBrenamanAlbertBrenaman
62
62
closed as unclear what you're asking by José Carlos Santos, Riccardo.Alestra, Jyrki Lahtonen, Adrian Keister, drhab Jan 30 at 14:41
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as unclear what you're asking by José Carlos Santos, Riccardo.Alestra, Jyrki Lahtonen, Adrian Keister, drhab Jan 30 at 14:41
Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
Please make your question clearer. How do we know whether those 24 people know each other or not?
$endgroup$
– abc...
Jan 30 at 8:59
$begingroup$
let's say those 24 people ALREADY know each other and plan an attack: 1, 5, 8, 10, 12, 14, 15, 16, 18, 50, 840, 720, 40, 41, 42, 43, 44, 48, 60, 70, 80, 81, 82, 83 What is the odd that I WILL choose them?
$endgroup$
– AlbertBrenaman
Jan 30 at 9:03
$begingroup$
We cannot answer the question unless you provide more information. How likely is it that two people in the population of 1000 know each other ? For example, if everyone knows everyone else then any set of 24 people that you choose will all know each other.
$endgroup$
– gandalf61
Jan 30 at 9:12
$begingroup$
In this case, it's a maximum of 24 people who knows each other.
$endgroup$
– AlbertBrenaman
Jan 30 at 9:12
$begingroup$
24/1000 maximum
$endgroup$
– AlbertBrenaman
Jan 30 at 10:22
add a comment |
$begingroup$
Please make your question clearer. How do we know whether those 24 people know each other or not?
$endgroup$
– abc...
Jan 30 at 8:59
$begingroup$
let's say those 24 people ALREADY know each other and plan an attack: 1, 5, 8, 10, 12, 14, 15, 16, 18, 50, 840, 720, 40, 41, 42, 43, 44, 48, 60, 70, 80, 81, 82, 83 What is the odd that I WILL choose them?
$endgroup$
– AlbertBrenaman
Jan 30 at 9:03
$begingroup$
We cannot answer the question unless you provide more information. How likely is it that two people in the population of 1000 know each other ? For example, if everyone knows everyone else then any set of 24 people that you choose will all know each other.
$endgroup$
– gandalf61
Jan 30 at 9:12
$begingroup$
In this case, it's a maximum of 24 people who knows each other.
$endgroup$
– AlbertBrenaman
Jan 30 at 9:12
$begingroup$
24/1000 maximum
$endgroup$
– AlbertBrenaman
Jan 30 at 10:22
$begingroup$
Please make your question clearer. How do we know whether those 24 people know each other or not?
$endgroup$
– abc...
Jan 30 at 8:59
$begingroup$
Please make your question clearer. How do we know whether those 24 people know each other or not?
$endgroup$
– abc...
Jan 30 at 8:59
$begingroup$
let's say those 24 people ALREADY know each other and plan an attack: 1, 5, 8, 10, 12, 14, 15, 16, 18, 50, 840, 720, 40, 41, 42, 43, 44, 48, 60, 70, 80, 81, 82, 83 What is the odd that I WILL choose them?
$endgroup$
– AlbertBrenaman
Jan 30 at 9:03
$begingroup$
let's say those 24 people ALREADY know each other and plan an attack: 1, 5, 8, 10, 12, 14, 15, 16, 18, 50, 840, 720, 40, 41, 42, 43, 44, 48, 60, 70, 80, 81, 82, 83 What is the odd that I WILL choose them?
$endgroup$
– AlbertBrenaman
Jan 30 at 9:03
$begingroup$
We cannot answer the question unless you provide more information. How likely is it that two people in the population of 1000 know each other ? For example, if everyone knows everyone else then any set of 24 people that you choose will all know each other.
$endgroup$
– gandalf61
Jan 30 at 9:12
$begingroup$
We cannot answer the question unless you provide more information. How likely is it that two people in the population of 1000 know each other ? For example, if everyone knows everyone else then any set of 24 people that you choose will all know each other.
$endgroup$
– gandalf61
Jan 30 at 9:12
$begingroup$
In this case, it's a maximum of 24 people who knows each other.
$endgroup$
– AlbertBrenaman
Jan 30 at 9:12
$begingroup$
In this case, it's a maximum of 24 people who knows each other.
$endgroup$
– AlbertBrenaman
Jan 30 at 9:12
$begingroup$
24/1000 maximum
$endgroup$
– AlbertBrenaman
Jan 30 at 10:22
$begingroup$
24/1000 maximum
$endgroup$
– AlbertBrenaman
Jan 30 at 10:22
add a comment |
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$begingroup$
Please make your question clearer. How do we know whether those 24 people know each other or not?
$endgroup$
– abc...
Jan 30 at 8:59
$begingroup$
let's say those 24 people ALREADY know each other and plan an attack: 1, 5, 8, 10, 12, 14, 15, 16, 18, 50, 840, 720, 40, 41, 42, 43, 44, 48, 60, 70, 80, 81, 82, 83 What is the odd that I WILL choose them?
$endgroup$
– AlbertBrenaman
Jan 30 at 9:03
$begingroup$
We cannot answer the question unless you provide more information. How likely is it that two people in the population of 1000 know each other ? For example, if everyone knows everyone else then any set of 24 people that you choose will all know each other.
$endgroup$
– gandalf61
Jan 30 at 9:12
$begingroup$
In this case, it's a maximum of 24 people who knows each other.
$endgroup$
– AlbertBrenaman
Jan 30 at 9:12
$begingroup$
24/1000 maximum
$endgroup$
– AlbertBrenaman
Jan 30 at 10:22