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191

I want to run a script, which basicly shows things like:

Installing XXX...               [DONE]

Now, at the moment, I use print to print the whole line AFTER the function has succeeded. However, I now want it to print "Installing xxx..." first, and AFTER the function has run, to add the "DONE" tag; but on the same line.

Any ideas?

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

asked Apr 8 '11 at 16:38

user697108

1,19631214

Possible duplicate of How do I keep Python print from adding newlines or spaces?

– Cees Timmerman
Dec 9 '16 at 2:21

Answers to this question don't mention that sometimes you want to clear the line, see: stackoverflow.com/questions/45263205

– ideasman42
Jul 23 '17 at 9:44

add a comment |

191

I want to run a script, which basicly shows things like:

Installing XXX...               [DONE]

Any ideas?

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

asked Apr 8 '11 at 16:38

user697108

1,19631214

Possible duplicate of How do I keep Python print from adding newlines or spaces?

– Cees Timmerman
Dec 9 '16 at 2:21

Answers to this question don't mention that sometimes you want to clear the line, see: stackoverflow.com/questions/45263205

– ideasman42
Jul 23 '17 at 9:44

add a comment |

191

I want to run a script, which basicly shows things like:

Installing XXX...               [DONE]

Any ideas?

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

asked Apr 8 '11 at 16:38

user697108

1,19631214

I want to run a script, which basicly shows things like:

Installing XXX...               [DONE]

Any ideas?

python printing

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

asked Apr 8 '11 at 16:38

user697108

1,19631214

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

asked Apr 8 '11 at 16:38

user697108

1,19631214

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

asked Apr 8 '11 at 16:38

user697108

1,19631214

asked Apr 8 '11 at 16:38

user697108

1,19631214

asked Apr 8 '11 at 16:38

user697108

1,19631214

Possible duplicate of How do I keep Python print from adding newlines or spaces?

– Cees Timmerman
Dec 9 '16 at 2:21

Answers to this question don't mention that sometimes you want to clear the line, see: stackoverflow.com/questions/45263205

– ideasman42
Jul 23 '17 at 9:44

add a comment |

Possible duplicate of How do I keep Python print from adding newlines or spaces?

– Cees Timmerman
Dec 9 '16 at 2:21

Answers to this question don't mention that sometimes you want to clear the line, see: stackoverflow.com/questions/45263205

– ideasman42
Jul 23 '17 at 9:44

Possible duplicate of How do I keep Python print from adding newlines or spaces?

– Cees Timmerman
Dec 9 '16 at 2:21

Answers to this question don't mention that sometimes you want to clear the line, see: stackoverflow.com/questions/45263205

– ideasman42
Jul 23 '17 at 9:44

add a comment |

14 Answers
14

active

oldest

votes

242

You can use the print statement to do this without importing sys.

def install_xxx():

   print "Installing XXX...      ",



install_xxx()

print "[DONE]"

The comma on the end of the print line prevents print from issuing a new line (you should note that there will be an extra space at the end of the output).

The Python 3 Solution

Since the above does not work in Python 3, you can do this instead (again, without importing sys):

def install_xxx():

    print("Installing XXX...      ", end="", flush=True)



install_xxx()

print("[DONE]")

The print function accepts an end parameter which defaults to "n". Setting it to an empty string prevents it from issuing a new line at the end of the line.

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

answered Apr 8 '11 at 16:56

multipleinterfaces

6,55642331

1

It works perfectly. Had only seen stdout solutions so far. Really good to know that.

– Prometheus
Jan 8 '15 at 7:59

4

This doesn't work if you have both prints and a time consuming action in between (all in the same function / indentation level). Before the action starts, there is no output at all and after it is finished the output appears as whole

– Paddre
Feb 20 '15 at 15:08

2

That is probably more a function of the output buffering preformed by the OS for the process as a whole, which is not a python-specific problem. See stackoverflow.com/questions/107705 for a python-specific workaround.

– multipleinterfaces
Feb 20 '15 at 16:48

11

Without a newline, you probably want to explicitly flush the buffer. Use print("...", end="", flush=True) in Python 3, in Python 2 add a sys.stdout.flush() call.

– Martijn Pieters♦
Nov 3 '16 at 12:53

2

in python 3.x you'll want to add a "r" to end to replace the printed line VS appending to the end of it print("Progress: {}%".format(var), end="r", flush=True)

– John
Jan 6 '18 at 22:42

|
show 2 more comments

You can simply use this:

print 'something',

...

print ' else',

and the output will be

something else

no need to overkill by import sys. Pay attention to comma symbol at the end.

Python 3+
print("some string", end=""); to remove the newline insert at the end. Read more by help(print);

edited Jan 4 '17 at 11:41

answered Mar 14 '13 at 13:35

boldnik

1,69211422

15

you should point out the comma

– kommradHomer
Jul 24 '13 at 10:25

3

Note there are two spaces by using this method

– ethanjyx
Nov 12 '13 at 3:20

1

This is the simplest and the most efficient answer.

– gixxer
May 22 '15 at 4:45

This does not work when arguments of print are in parentheses. This works: <print "hello",; print("hello")> but this doesnt work <print("hello",); print("hello")>

– Mayank Jaiswal
Nov 27 '15 at 7:46

1

print function has slightly different syntax in python 2 VS 3.

– boldnik
Feb 7 '16 at 4:24

|
show 4 more comments

Use sys.stdout.write('Installing XXX... ') and sys.stdout.write('Done'). In this way, you have to add the new line by hand with "n" if you want to recreate the print functionality. I think that it might be unnecessary to use curses just for this.

edited Jan 31 '13 at 14:27

mgilson

214k40424535

answered Apr 8 '11 at 16:42

ferostar

6,02963359

1

Thanks! This works fine.

– user697108
Apr 8 '11 at 16:50

4

I personally prefer this solution to the higher voted one because it works the exact same way on python2.x and python3.x without needing to rely on __future__ imports or anything like that.

– mgilson
Jan 31 '13 at 14:29

add a comment |

You should use backspace 'r' or ('x08') char to go back on previous position in console output

Python 2+:

import time

import sys



def backspace(n):

    sys.stdout.write((b'x08' * n).decode()) # use x08 char to go back   



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    sys.stdout.write(s)                     # just print

    sys.stdout.flush()                      # needed for flush when using x08

    backspace(len(s))                       # back n chars    

    time.sleep(0.2)                         # sleep for 200ms

Python 3:

import time   



def backline():        

    print('r', end='')                     # use 'r' to go back





for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print(s, end='')                        # just print and flush

    backline()                              # back to the beginning of line    

    time.sleep(0.2)                         # sleep for 200ms

This code will count from 0% to 100% on one line. Final value will be:

> python test.py

100%

Additional info about flush in this case here: Why do python print statements that contain 'end=' arguments behave differently in while-loops?

edited Apr 10 at 9:28

Francesco Boccardo

632220

answered Mar 31 '14 at 8:57

Vadim Zin4uk

1,2051513

1

To clarify, it looks like the commented-out code in this example is for Python 2, and the non-commented lines are for Python 3.

– Turtles Are Cute
Mar 9 '15 at 23:05

1

bouth lines will work fine in Python 3. If you use 'x08' as a backspace you need to flush the output stream - print((b'x08' * n).decode(), end='', flush=True)

– Vadim Zin4uk
Mar 10 '15 at 9:43

1

no chance with python 2.7 on linux. :(

– obayhan
Nov 5 '15 at 13:08

1

The carriage return 'r' goes back to the beginning of the line, so the '* n' is unnecessary

– bjnortier
May 8 '17 at 8:02

@bjnortier, right, corrected

– ideasman42
Jul 23 '17 at 8:33

|
show 1 more comment

None of the answers worked for me since they all paused until a new line was encountered. I wrote a simple helper:

def print_no_newline(string):

    import sys

    sys.stdout.write(string)

    sys.stdout.flush()

To test it:

import time

print_no_newline('hello ')

# Simulate a long task

time.sleep(2)

print('world')

"hello " will first print out and flush to the screen before the sleep. After that you can use standard print.

answered Jul 22 '13 at 18:23

incognick

1,69821514

1

Thank you! Exactly what i needed aka .flush()

– MrNice
Oct 20 '16 at 12:28

add a comment |

sys.stdout.write will print without return carriage

import sys

sys.stdout.write("installing xxx")

sys.stdout.write(".")

http://en.wikibooks.org/wiki/Python_Programming/Input_and_output#printing_without_commas_or_newlines

answered Apr 8 '11 at 16:43

John Giotta

12.4k43871

add a comment |

This simple example will print 1-10 on the same line.

for i in range(1,11):

    print (i, end=" ")

answered May 15 '18 at 7:01

Umali Leonard

7111

add a comment |

Print has an optional end argument, it is what printed in the end.
The default is newline but you can change it to empty string. eg: print("hello world!", end="")

answered Feb 27 '15 at 16:44

TulkinRB

41258

it gives a syntax error

– thedp
Jul 13 '15 at 14:37

2

This is in python 3. In python 2 you can simply print 'something',. The comma at the end prevents the addition of a newline.

– arjoonn
Sep 6 '15 at 5:37

add a comment |

Most simple:

Python 3

    print(‘r’+’something to be override’,end=‘’)

It means it will back the cursor to beginning, than will print something and will end in the same line. If in a loop it will start printing in the same place it starts.

edited Jan 3 at 15:53

answered Nov 6 '18 at 19:15

Octavius

9327

Cool! Works in Windows as well.

– Shital Shah
Feb 13 at 11:59

Thanks this works fine for me! I think that print(’something to be override’, end=‘r’) is simpler, though.

– Francesco Boccardo
Apr 10 at 9:00

add a comment |

If you want to overwrite the previous line (rather than continually adding to it), you can combine r with print(), at the end of the print statement. For example,

from time import sleep



for i in xrange(0, 10):

    print("r{0}".format(i)),

    sleep(.5)



print("...DONE!")

will count 0 to 9, replacing the old number in the console. The "...DONE!" will print on the same line as the last counter, 9.

In your case for the OP, this would allow the console to display percent complete of the install as a "progress bar", where you can define a begin and end character position, and update the markers in between.

print("Installing |XXXXXX              | 30%"),

edited Oct 9 '15 at 17:50

answered Oct 9 '15 at 16:18

Brian Bunker

7516

add a comment |

Here a 2.7-compatible version derived from the 3.0 version by @Vadim-Zin4uk:

Python 2

import time



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print '{0}r'.format(s),                # just print and flush



    time.sleep(0.2)

For that matter, the 3.0 solution provided looks a little bloated. For example, the backspace method doesn't make use of the integer argument and could probably be done away with altogether.

Python 3

import time



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print('{0}r'.format(s), end='')        # just print and flush



    time.sleep(0.2)                         # sleep for 200ms

Both have been tested and work.

answered Jan 10 '18 at 19:47

Dannid

7781014

add a comment |

This is a very old thread, but here's a very thorough answer and sample code.

r is the string representation of Carriage Return from the ASCII character set. It's the same as octal 015 [chr(0o15)] or hexidecimal 0d [chr(0x0d)] or decimal 13 [chr(13)]. See man ascii for a boring read. It (r) is a pretty portable representation and is easy enough for people to read. It very simply means to move the carriage on the typewriter all the way back to the start without advancing the paper. It's the CR part of CRLF which means Carriage Return and Line Feed.

print() is a function in Python 3. In Python 2 (any version that you'd be interested in using), print can be forced into a function by importing its definition from the __future__ module. The benefit of the print function is that you can specify what to print at the end, overriding the default behavior of n to print a newline at the end of every print() call.

sys.stdout.flush tells Python to flush the output of standard output, which is where you send output with print() unless you specify otherwise. You can also get the same behavior by running with python -u or setting environment variable PYTHONUNBUFFERED=1, thereby skipping the import sys and sys.stdout.flush() calls. The amount you gain by doing that is almost exactly zero and isn't very easy to debug if you conveniently forget that you have to do that step before your application behaves properly.

And a sample. Note that this runs perfectly in Python 2 or 3.

from __future__ import print_function



import sys

import time



ANS = 42

FACTORS = {n for n in range(1, ANS + 1) if ANS % n == 0}



for i in range(1, ANS + 1):

    if i in FACTORS:

        print('r{0:d}'.format(i), end='')

        sys.stdout.flush()

        time.sleep(ANS / 100.0)

else:

    print()

answered Oct 25 '17 at 18:20

Chris Cosby

234

I think your answer is more suitable for: stackoverflow.com/questions/45263205/…

– Marc Cayuela Rafols
Oct 25 '17 at 19:06

add a comment |

Just in case you have pre-stored the values in an array, you can call them in the following format:

for i in range(0,n):

       print arr[i],

answered Oct 16 '16 at 23:20

k20392

111

add a comment |

-3

I found this solution, and it's working on Python 2.7

# Working on Python 2.7 Linux



import time

import sys





def backspace(n):

    print('r', end='')                     # use 'r' to go back





for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    sys.stdout.write(string)

    backspace(len(s))                       # back for n chars

    sys.stdout.flush()

    time.sleep(0.2)                         # sleep for 200ms

edited Jul 23 '17 at 8:34

ideasman42

13.3k673140

answered Dec 7 '16 at 12:51

Luis Silva

1

That print is incorrect syntax for Python 2.7 and the code doesn't work even with correct syntax.

– Cory Madden
Aug 6 '17 at 20:47

add a comment |

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14 Answers
14

active

oldest

votes

14 Answers
14

active

oldest

votes

242

You can use the print statement to do this without importing sys.

def install_xxx():

   print "Installing XXX...      ",



install_xxx()

print "[DONE]"

The comma on the end of the print line prevents print from issuing a new line (you should note that there will be an extra space at the end of the output).

The Python 3 Solution

Since the above does not work in Python 3, you can do this instead (again, without importing sys):

def install_xxx():

    print("Installing XXX...      ", end="", flush=True)



install_xxx()

print("[DONE]")

The print function accepts an end parameter which defaults to "n". Setting it to an empty string prevents it from issuing a new line at the end of the line.

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

answered Apr 8 '11 at 16:56

multipleinterfaces

6,55642331

1

It works perfectly. Had only seen stdout solutions so far. Really good to know that.

– Prometheus
Jan 8 '15 at 7:59

4

This doesn't work if you have both prints and a time consuming action in between (all in the same function / indentation level). Before the action starts, there is no output at all and after it is finished the output appears as whole

– Paddre
Feb 20 '15 at 15:08

2

That is probably more a function of the output buffering preformed by the OS for the process as a whole, which is not a python-specific problem. See stackoverflow.com/questions/107705 for a python-specific workaround.

– multipleinterfaces
Feb 20 '15 at 16:48

11

Without a newline, you probably want to explicitly flush the buffer. Use print("...", end="", flush=True) in Python 3, in Python 2 add a sys.stdout.flush() call.

– Martijn Pieters♦
Nov 3 '16 at 12:53

2

in python 3.x you'll want to add a "r" to end to replace the printed line VS appending to the end of it print("Progress: {}%".format(var), end="r", flush=True)

– John
Jan 6 '18 at 22:42

|
show 2 more comments

242

You can use the print statement to do this without importing sys.

def install_xxx():

   print "Installing XXX...      ",



install_xxx()

print "[DONE]"

The comma on the end of the print line prevents print from issuing a new line (you should note that there will be an extra space at the end of the output).

The Python 3 Solution

Since the above does not work in Python 3, you can do this instead (again, without importing sys):

def install_xxx():

    print("Installing XXX...      ", end="", flush=True)



install_xxx()

print("[DONE]")

The print function accepts an end parameter which defaults to "n". Setting it to an empty string prevents it from issuing a new line at the end of the line.

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

answered Apr 8 '11 at 16:56

multipleinterfaces

6,55642331

1

It works perfectly. Had only seen stdout solutions so far. Really good to know that.

– Prometheus
Jan 8 '15 at 7:59

4

This doesn't work if you have both prints and a time consuming action in between (all in the same function / indentation level). Before the action starts, there is no output at all and after it is finished the output appears as whole

– Paddre
Feb 20 '15 at 15:08

2

That is probably more a function of the output buffering preformed by the OS for the process as a whole, which is not a python-specific problem. See stackoverflow.com/questions/107705 for a python-specific workaround.

– multipleinterfaces
Feb 20 '15 at 16:48

11

Without a newline, you probably want to explicitly flush the buffer. Use print("...", end="", flush=True) in Python 3, in Python 2 add a sys.stdout.flush() call.

– Martijn Pieters♦
Nov 3 '16 at 12:53

2

in python 3.x you'll want to add a "r" to end to replace the printed line VS appending to the end of it print("Progress: {}%".format(var), end="r", flush=True)

– John
Jan 6 '18 at 22:42

|
show 2 more comments

242

You can use the print statement to do this without importing sys.

def install_xxx():

   print "Installing XXX...      ",



install_xxx()

print "[DONE]"

The comma on the end of the print line prevents print from issuing a new line (you should note that there will be an extra space at the end of the output).

The Python 3 Solution

Since the above does not work in Python 3, you can do this instead (again, without importing sys):

def install_xxx():

    print("Installing XXX...      ", end="", flush=True)



install_xxx()

print("[DONE]")

The print function accepts an end parameter which defaults to "n". Setting it to an empty string prevents it from issuing a new line at the end of the line.

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

answered Apr 8 '11 at 16:56

multipleinterfaces

6,55642331

You can use the print statement to do this without importing sys.

def install_xxx():

   print "Installing XXX...      ",



install_xxx()

print "[DONE]"

The comma on the end of the print line prevents print from issuing a new line (you should note that there will be an extra space at the end of the output).

The Python 3 Solution

Since the above does not work in Python 3, you can do this instead (again, without importing sys):

def install_xxx():

    print("Installing XXX...      ", end="", flush=True)



install_xxx()

print("[DONE]")

The print function accepts an end parameter which defaults to "n". Setting it to an empty string prevents it from issuing a new line at the end of the line.

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

answered Apr 8 '11 at 16:56

multipleinterfaces

6,55642331

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

edited Mar 7 '18 at 21:57

Marco Bonelli

24k116475

answered Apr 8 '11 at 16:56

multipleinterfaces

6,55642331

answered Apr 8 '11 at 16:56

multipleinterfaces

6,55642331

answered Apr 8 '11 at 16:56

multipleinterfaces

6,55642331

1

It works perfectly. Had only seen stdout solutions so far. Really good to know that.

– Prometheus
Jan 8 '15 at 7:59

4

This doesn't work if you have both prints and a time consuming action in between (all in the same function / indentation level). Before the action starts, there is no output at all and after it is finished the output appears as whole

– Paddre
Feb 20 '15 at 15:08

2

That is probably more a function of the output buffering preformed by the OS for the process as a whole, which is not a python-specific problem. See stackoverflow.com/questions/107705 for a python-specific workaround.

– multipleinterfaces
Feb 20 '15 at 16:48

11

Without a newline, you probably want to explicitly flush the buffer. Use print("...", end="", flush=True) in Python 3, in Python 2 add a sys.stdout.flush() call.

– Martijn Pieters♦
Nov 3 '16 at 12:53

2

in python 3.x you'll want to add a "r" to end to replace the printed line VS appending to the end of it print("Progress: {}%".format(var), end="r", flush=True)

– John
Jan 6 '18 at 22:42

|
show 2 more comments

1

It works perfectly. Had only seen stdout solutions so far. Really good to know that.

– Prometheus
Jan 8 '15 at 7:59

4

This doesn't work if you have both prints and a time consuming action in between (all in the same function / indentation level). Before the action starts, there is no output at all and after it is finished the output appears as whole

– Paddre
Feb 20 '15 at 15:08

2

That is probably more a function of the output buffering preformed by the OS for the process as a whole, which is not a python-specific problem. See stackoverflow.com/questions/107705 for a python-specific workaround.

– multipleinterfaces
Feb 20 '15 at 16:48

11

Without a newline, you probably want to explicitly flush the buffer. Use print("...", end="", flush=True) in Python 3, in Python 2 add a sys.stdout.flush() call.

– Martijn Pieters♦
Nov 3 '16 at 12:53

2

in python 3.x you'll want to add a "r" to end to replace the printed line VS appending to the end of it print("Progress: {}%".format(var), end="r", flush=True)

– John
Jan 6 '18 at 22:42

It works perfectly. Had only seen stdout solutions so far. Really good to know that.

– Prometheus
Jan 8 '15 at 7:59

This doesn't work if you have both prints and a time consuming action in between (all in the same function / indentation level). Before the action starts, there is no output at all and after it is finished the output appears as whole

– Paddre
Feb 20 '15 at 15:08

That is probably more a function of the output buffering preformed by the OS for the process as a whole, which is not a python-specific problem. See stackoverflow.com/questions/107705 for a python-specific workaround.

– multipleinterfaces
Feb 20 '15 at 16:48

Without a newline, you probably want to explicitly flush the buffer. Use print("...", end="", flush=True) in Python 3, in Python 2 add a sys.stdout.flush() call.

– Martijn Pieters♦
Nov 3 '16 at 12:53

in python 3.x you'll want to add a "r" to end to replace the printed line VS appending to the end of it print("Progress: {}%".format(var), end="r", flush=True)

– John
Jan 6 '18 at 22:42

|
show 2 more comments

You can simply use this:

print 'something',

...

print ' else',

and the output will be

something else

no need to overkill by import sys. Pay attention to comma symbol at the end.

Python 3+
print("some string", end=""); to remove the newline insert at the end. Read more by help(print);

edited Jan 4 '17 at 11:41

answered Mar 14 '13 at 13:35

boldnik

1,69211422

15

you should point out the comma

– kommradHomer
Jul 24 '13 at 10:25

3

Note there are two spaces by using this method

– ethanjyx
Nov 12 '13 at 3:20

1

This is the simplest and the most efficient answer.

– gixxer
May 22 '15 at 4:45

This does not work when arguments of print are in parentheses. This works: <print "hello",; print("hello")> but this doesnt work <print("hello",); print("hello")>

– Mayank Jaiswal
Nov 27 '15 at 7:46

1

print function has slightly different syntax in python 2 VS 3.

– boldnik
Feb 7 '16 at 4:24

|
show 4 more comments

You can simply use this:

print 'something',

...

print ' else',

and the output will be

something else

no need to overkill by import sys. Pay attention to comma symbol at the end.

Python 3+
print("some string", end=""); to remove the newline insert at the end. Read more by help(print);

edited Jan 4 '17 at 11:41

answered Mar 14 '13 at 13:35

boldnik

1,69211422

15

you should point out the comma

– kommradHomer
Jul 24 '13 at 10:25

3

Note there are two spaces by using this method

– ethanjyx
Nov 12 '13 at 3:20

1

This is the simplest and the most efficient answer.

– gixxer
May 22 '15 at 4:45

This does not work when arguments of print are in parentheses. This works: <print "hello",; print("hello")> but this doesnt work <print("hello",); print("hello")>

– Mayank Jaiswal
Nov 27 '15 at 7:46

1

print function has slightly different syntax in python 2 VS 3.

– boldnik
Feb 7 '16 at 4:24

|
show 4 more comments

You can simply use this:

print 'something',

...

print ' else',

and the output will be

something else

no need to overkill by import sys. Pay attention to comma symbol at the end.

Python 3+
print("some string", end=""); to remove the newline insert at the end. Read more by help(print);

edited Jan 4 '17 at 11:41

answered Mar 14 '13 at 13:35

boldnik

1,69211422

You can simply use this:

print 'something',

...

print ' else',

and the output will be

something else

no need to overkill by import sys. Pay attention to comma symbol at the end.

Python 3+
print("some string", end=""); to remove the newline insert at the end. Read more by help(print);

edited Jan 4 '17 at 11:41

answered Mar 14 '13 at 13:35

boldnik

1,69211422

edited Jan 4 '17 at 11:41

answered Mar 14 '13 at 13:35

boldnik

1,69211422

answered Mar 14 '13 at 13:35

boldnik

1,69211422

answered Mar 14 '13 at 13:35

boldnik

1,69211422

15

you should point out the comma

– kommradHomer
Jul 24 '13 at 10:25

3

Note there are two spaces by using this method

– ethanjyx
Nov 12 '13 at 3:20

1

This is the simplest and the most efficient answer.

– gixxer
May 22 '15 at 4:45

This does not work when arguments of print are in parentheses. This works: <print "hello",; print("hello")> but this doesnt work <print("hello",); print("hello")>

– Mayank Jaiswal
Nov 27 '15 at 7:46

1

print function has slightly different syntax in python 2 VS 3.

– boldnik
Feb 7 '16 at 4:24

|
show 4 more comments

15

you should point out the comma

– kommradHomer
Jul 24 '13 at 10:25

3

Note there are two spaces by using this method

– ethanjyx
Nov 12 '13 at 3:20

1

This is the simplest and the most efficient answer.

– gixxer
May 22 '15 at 4:45

This does not work when arguments of print are in parentheses. This works: <print "hello",; print("hello")> but this doesnt work <print("hello",); print("hello")>

– Mayank Jaiswal
Nov 27 '15 at 7:46

1

print function has slightly different syntax in python 2 VS 3.

– boldnik
Feb 7 '16 at 4:24

you should point out the comma

– kommradHomer
Jul 24 '13 at 10:25

Note there are two spaces by using this method

– ethanjyx
Nov 12 '13 at 3:20

This is the simplest and the most efficient answer.

– gixxer
May 22 '15 at 4:45

This does not work when arguments of print are in parentheses. This works: <print "hello",; print("hello")> but this doesnt work <print("hello",); print("hello")>

– Mayank Jaiswal
Nov 27 '15 at 7:46

print function has slightly different syntax in python 2 VS 3.

– boldnik
Feb 7 '16 at 4:24

|
show 4 more comments

edited Jan 31 '13 at 14:27

mgilson

214k40424535

answered Apr 8 '11 at 16:42

ferostar

6,02963359

1

Thanks! This works fine.

– user697108
Apr 8 '11 at 16:50

4

I personally prefer this solution to the higher voted one because it works the exact same way on python2.x and python3.x without needing to rely on __future__ imports or anything like that.

– mgilson
Jan 31 '13 at 14:29

add a comment |

edited Jan 31 '13 at 14:27

mgilson

214k40424535

answered Apr 8 '11 at 16:42

ferostar

6,02963359

1

Thanks! This works fine.

– user697108
Apr 8 '11 at 16:50

4

I personally prefer this solution to the higher voted one because it works the exact same way on python2.x and python3.x without needing to rely on __future__ imports or anything like that.

– mgilson
Jan 31 '13 at 14:29

add a comment |

edited Jan 31 '13 at 14:27

mgilson

214k40424535

answered Apr 8 '11 at 16:42

ferostar

6,02963359

edited Jan 31 '13 at 14:27

mgilson

214k40424535

answered Apr 8 '11 at 16:42

ferostar

6,02963359

edited Jan 31 '13 at 14:27

mgilson

214k40424535

edited Jan 31 '13 at 14:27

mgilson

214k40424535

edited Jan 31 '13 at 14:27

mgilson

214k40424535

answered Apr 8 '11 at 16:42

ferostar

6,02963359

answered Apr 8 '11 at 16:42

ferostar

6,02963359

answered Apr 8 '11 at 16:42

ferostar

6,02963359

1

Thanks! This works fine.

– user697108
Apr 8 '11 at 16:50

4

I personally prefer this solution to the higher voted one because it works the exact same way on python2.x and python3.x without needing to rely on __future__ imports or anything like that.

– mgilson
Jan 31 '13 at 14:29

add a comment |

1

Thanks! This works fine.

– user697108
Apr 8 '11 at 16:50

4

I personally prefer this solution to the higher voted one because it works the exact same way on python2.x and python3.x without needing to rely on __future__ imports or anything like that.

– mgilson
Jan 31 '13 at 14:29

Thanks! This works fine.

– user697108
Apr 8 '11 at 16:50

I personally prefer this solution to the higher voted one because it works the exact same way on python2.x and python3.x without needing to rely on __future__ imports or anything like that.

– mgilson
Jan 31 '13 at 14:29

add a comment |

You should use backspace 'r' or ('x08') char to go back on previous position in console output

Python 2+:

import time

import sys



def backspace(n):

    sys.stdout.write((b'x08' * n).decode()) # use x08 char to go back   



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    sys.stdout.write(s)                     # just print

    sys.stdout.flush()                      # needed for flush when using x08

    backspace(len(s))                       # back n chars    

    time.sleep(0.2)                         # sleep for 200ms

Python 3:

import time   



def backline():        

    print('r', end='')                     # use 'r' to go back





for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print(s, end='')                        # just print and flush

    backline()                              # back to the beginning of line    

    time.sleep(0.2)                         # sleep for 200ms

This code will count from 0% to 100% on one line. Final value will be:

> python test.py

100%

Additional info about flush in this case here: Why do python print statements that contain 'end=' arguments behave differently in while-loops?

edited Apr 10 at 9:28

Francesco Boccardo

632220

answered Mar 31 '14 at 8:57

Vadim Zin4uk

1,2051513

1

To clarify, it looks like the commented-out code in this example is for Python 2, and the non-commented lines are for Python 3.

– Turtles Are Cute
Mar 9 '15 at 23:05

1

bouth lines will work fine in Python 3. If you use 'x08' as a backspace you need to flush the output stream - print((b'x08' * n).decode(), end='', flush=True)

– Vadim Zin4uk
Mar 10 '15 at 9:43

1

no chance with python 2.7 on linux. :(

– obayhan
Nov 5 '15 at 13:08

1

The carriage return 'r' goes back to the beginning of the line, so the '* n' is unnecessary

– bjnortier
May 8 '17 at 8:02

@bjnortier, right, corrected

– ideasman42
Jul 23 '17 at 8:33

|
show 1 more comment

You should use backspace 'r' or ('x08') char to go back on previous position in console output

Python 2+:

import time

import sys



def backspace(n):

    sys.stdout.write((b'x08' * n).decode()) # use x08 char to go back   



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    sys.stdout.write(s)                     # just print

    sys.stdout.flush()                      # needed for flush when using x08

    backspace(len(s))                       # back n chars    

    time.sleep(0.2)                         # sleep for 200ms

Python 3:

import time   



def backline():        

    print('r', end='')                     # use 'r' to go back





for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print(s, end='')                        # just print and flush

    backline()                              # back to the beginning of line    

    time.sleep(0.2)                         # sleep for 200ms

This code will count from 0% to 100% on one line. Final value will be:

> python test.py

100%

Additional info about flush in this case here: Why do python print statements that contain 'end=' arguments behave differently in while-loops?

edited Apr 10 at 9:28

Francesco Boccardo

632220

answered Mar 31 '14 at 8:57

Vadim Zin4uk

1,2051513

1

To clarify, it looks like the commented-out code in this example is for Python 2, and the non-commented lines are for Python 3.

– Turtles Are Cute
Mar 9 '15 at 23:05

1

bouth lines will work fine in Python 3. If you use 'x08' as a backspace you need to flush the output stream - print((b'x08' * n).decode(), end='', flush=True)

– Vadim Zin4uk
Mar 10 '15 at 9:43

1

no chance with python 2.7 on linux. :(

– obayhan
Nov 5 '15 at 13:08

1

The carriage return 'r' goes back to the beginning of the line, so the '* n' is unnecessary

– bjnortier
May 8 '17 at 8:02

@bjnortier, right, corrected

– ideasman42
Jul 23 '17 at 8:33

|
show 1 more comment

You should use backspace 'r' or ('x08') char to go back on previous position in console output

Python 2+:

import time

import sys



def backspace(n):

    sys.stdout.write((b'x08' * n).decode()) # use x08 char to go back   



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    sys.stdout.write(s)                     # just print

    sys.stdout.flush()                      # needed for flush when using x08

    backspace(len(s))                       # back n chars    

    time.sleep(0.2)                         # sleep for 200ms

Python 3:

import time   



def backline():        

    print('r', end='')                     # use 'r' to go back





for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print(s, end='')                        # just print and flush

    backline()                              # back to the beginning of line    

    time.sleep(0.2)                         # sleep for 200ms

This code will count from 0% to 100% on one line. Final value will be:

> python test.py

100%

Additional info about flush in this case here: Why do python print statements that contain 'end=' arguments behave differently in while-loops?

edited Apr 10 at 9:28

Francesco Boccardo

632220

answered Mar 31 '14 at 8:57

Vadim Zin4uk

1,2051513

You should use backspace 'r' or ('x08') char to go back on previous position in console output

Python 2+:

import time

import sys



def backspace(n):

    sys.stdout.write((b'x08' * n).decode()) # use x08 char to go back   



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    sys.stdout.write(s)                     # just print

    sys.stdout.flush()                      # needed for flush when using x08

    backspace(len(s))                       # back n chars    

    time.sleep(0.2)                         # sleep for 200ms

Python 3:

import time   



def backline():        

    print('r', end='')                     # use 'r' to go back





for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print(s, end='')                        # just print and flush

    backline()                              # back to the beginning of line    

    time.sleep(0.2)                         # sleep for 200ms

This code will count from 0% to 100% on one line. Final value will be:

> python test.py

100%

Additional info about flush in this case here: Why do python print statements that contain 'end=' arguments behave differently in while-loops?

edited Apr 10 at 9:28

Francesco Boccardo

632220

answered Mar 31 '14 at 8:57

Vadim Zin4uk

1,2051513

edited Apr 10 at 9:28

Francesco Boccardo

632220

edited Apr 10 at 9:28

Francesco Boccardo

632220

edited Apr 10 at 9:28

Francesco Boccardo

632220

answered Mar 31 '14 at 8:57

Vadim Zin4uk

1,2051513

answered Mar 31 '14 at 8:57

Vadim Zin4uk

1,2051513

answered Mar 31 '14 at 8:57

Vadim Zin4uk

1,2051513

1

To clarify, it looks like the commented-out code in this example is for Python 2, and the non-commented lines are for Python 3.

– Turtles Are Cute
Mar 9 '15 at 23:05

1

bouth lines will work fine in Python 3. If you use 'x08' as a backspace you need to flush the output stream - print((b'x08' * n).decode(), end='', flush=True)

– Vadim Zin4uk
Mar 10 '15 at 9:43

1

no chance with python 2.7 on linux. :(

– obayhan
Nov 5 '15 at 13:08

1

The carriage return 'r' goes back to the beginning of the line, so the '* n' is unnecessary

– bjnortier
May 8 '17 at 8:02

@bjnortier, right, corrected

– ideasman42
Jul 23 '17 at 8:33

|
show 1 more comment

1

To clarify, it looks like the commented-out code in this example is for Python 2, and the non-commented lines are for Python 3.

– Turtles Are Cute
Mar 9 '15 at 23:05

1

bouth lines will work fine in Python 3. If you use 'x08' as a backspace you need to flush the output stream - print((b'x08' * n).decode(), end='', flush=True)

– Vadim Zin4uk
Mar 10 '15 at 9:43

1

no chance with python 2.7 on linux. :(

– obayhan
Nov 5 '15 at 13:08

1

The carriage return 'r' goes back to the beginning of the line, so the '* n' is unnecessary

– bjnortier
May 8 '17 at 8:02

@bjnortier, right, corrected

– ideasman42
Jul 23 '17 at 8:33

To clarify, it looks like the commented-out code in this example is for Python 2, and the non-commented lines are for Python 3.

– Turtles Are Cute
Mar 9 '15 at 23:05

bouth lines will work fine in Python 3. If you use 'x08' as a backspace you need to flush the output stream - print((b'x08' * n).decode(), end='', flush=True)

– Vadim Zin4uk
Mar 10 '15 at 9:43

no chance with python 2.7 on linux. :(

– obayhan
Nov 5 '15 at 13:08

The carriage return 'r' goes back to the beginning of the line, so the '* n' is unnecessary

– bjnortier
May 8 '17 at 8:02

@bjnortier, right, corrected

– ideasman42
Jul 23 '17 at 8:33

|
show 1 more comment

None of the answers worked for me since they all paused until a new line was encountered. I wrote a simple helper:

def print_no_newline(string):

    import sys

    sys.stdout.write(string)

    sys.stdout.flush()

To test it:

import time

print_no_newline('hello ')

# Simulate a long task

time.sleep(2)

print('world')

"hello " will first print out and flush to the screen before the sleep. After that you can use standard print.

answered Jul 22 '13 at 18:23

incognick

1,69821514

1

Thank you! Exactly what i needed aka .flush()

– MrNice
Oct 20 '16 at 12:28

add a comment |

None of the answers worked for me since they all paused until a new line was encountered. I wrote a simple helper:

def print_no_newline(string):

    import sys

    sys.stdout.write(string)

    sys.stdout.flush()

To test it:

import time

print_no_newline('hello ')

# Simulate a long task

time.sleep(2)

print('world')

"hello " will first print out and flush to the screen before the sleep. After that you can use standard print.

answered Jul 22 '13 at 18:23

incognick

1,69821514

1

Thank you! Exactly what i needed aka .flush()

– MrNice
Oct 20 '16 at 12:28

add a comment |

None of the answers worked for me since they all paused until a new line was encountered. I wrote a simple helper:

def print_no_newline(string):

    import sys

    sys.stdout.write(string)

    sys.stdout.flush()

To test it:

import time

print_no_newline('hello ')

# Simulate a long task

time.sleep(2)

print('world')

"hello " will first print out and flush to the screen before the sleep. After that you can use standard print.

answered Jul 22 '13 at 18:23

incognick

1,69821514

None of the answers worked for me since they all paused until a new line was encountered. I wrote a simple helper:

def print_no_newline(string):

    import sys

    sys.stdout.write(string)

    sys.stdout.flush()

To test it:

import time

print_no_newline('hello ')

# Simulate a long task

time.sleep(2)

print('world')

"hello " will first print out and flush to the screen before the sleep. After that you can use standard print.

answered Jul 22 '13 at 18:23

incognick

1,69821514

answered Jul 22 '13 at 18:23

incognick

1,69821514

answered Jul 22 '13 at 18:23

incognick

1,69821514

answered Jul 22 '13 at 18:23

incognick

1,69821514

1

Thank you! Exactly what i needed aka .flush()

– MrNice
Oct 20 '16 at 12:28

add a comment |

1

Thank you! Exactly what i needed aka .flush()

– MrNice
Oct 20 '16 at 12:28

Thank you! Exactly what i needed aka .flush()

– MrNice
Oct 20 '16 at 12:28

add a comment |

sys.stdout.write will print without return carriage

import sys

sys.stdout.write("installing xxx")

sys.stdout.write(".")

http://en.wikibooks.org/wiki/Python_Programming/Input_and_output#printing_without_commas_or_newlines

answered Apr 8 '11 at 16:43

John Giotta

12.4k43871

add a comment |

sys.stdout.write will print without return carriage

import sys

sys.stdout.write("installing xxx")

sys.stdout.write(".")

http://en.wikibooks.org/wiki/Python_Programming/Input_and_output#printing_without_commas_or_newlines

answered Apr 8 '11 at 16:43

John Giotta

12.4k43871

add a comment |

sys.stdout.write will print without return carriage

import sys

sys.stdout.write("installing xxx")

sys.stdout.write(".")

http://en.wikibooks.org/wiki/Python_Programming/Input_and_output#printing_without_commas_or_newlines

answered Apr 8 '11 at 16:43

John Giotta

12.4k43871

sys.stdout.write will print without return carriage

import sys

sys.stdout.write("installing xxx")

sys.stdout.write(".")

http://en.wikibooks.org/wiki/Python_Programming/Input_and_output#printing_without_commas_or_newlines

answered Apr 8 '11 at 16:43

John Giotta

12.4k43871

answered Apr 8 '11 at 16:43

John Giotta

12.4k43871

answered Apr 8 '11 at 16:43

John Giotta

12.4k43871

answered Apr 8 '11 at 16:43

John Giotta

12.4k43871

add a comment |

This simple example will print 1-10 on the same line.

for i in range(1,11):

    print (i, end=" ")

answered May 15 '18 at 7:01

Umali Leonard

7111

add a comment |

This simple example will print 1-10 on the same line.

for i in range(1,11):

    print (i, end=" ")

answered May 15 '18 at 7:01

Umali Leonard

7111

add a comment |

This simple example will print 1-10 on the same line.

for i in range(1,11):

    print (i, end=" ")

answered May 15 '18 at 7:01

Umali Leonard

7111

This simple example will print 1-10 on the same line.

for i in range(1,11):

    print (i, end=" ")

answered May 15 '18 at 7:01

Umali Leonard

7111

answered May 15 '18 at 7:01

Umali Leonard

7111

answered May 15 '18 at 7:01

Umali Leonard

7111

answered May 15 '18 at 7:01

Umali Leonard

7111

add a comment |

Print has an optional end argument, it is what printed in the end.
The default is newline but you can change it to empty string. eg: print("hello world!", end="")

answered Feb 27 '15 at 16:44

TulkinRB

41258

it gives a syntax error

– thedp
Jul 13 '15 at 14:37

2

This is in python 3. In python 2 you can simply print 'something',. The comma at the end prevents the addition of a newline.

– arjoonn
Sep 6 '15 at 5:37

add a comment |

Print has an optional end argument, it is what printed in the end.
The default is newline but you can change it to empty string. eg: print("hello world!", end="")

answered Feb 27 '15 at 16:44

TulkinRB

41258

it gives a syntax error

– thedp
Jul 13 '15 at 14:37

2

This is in python 3. In python 2 you can simply print 'something',. The comma at the end prevents the addition of a newline.

– arjoonn
Sep 6 '15 at 5:37

add a comment |

Print has an optional end argument, it is what printed in the end.
The default is newline but you can change it to empty string. eg: print("hello world!", end="")

answered Feb 27 '15 at 16:44

TulkinRB

41258

Print has an optional end argument, it is what printed in the end.
The default is newline but you can change it to empty string. eg: print("hello world!", end="")

answered Feb 27 '15 at 16:44

TulkinRB

41258

answered Feb 27 '15 at 16:44

TulkinRB

41258

answered Feb 27 '15 at 16:44

TulkinRB

41258

answered Feb 27 '15 at 16:44

TulkinRB

41258

it gives a syntax error

– thedp
Jul 13 '15 at 14:37

2

This is in python 3. In python 2 you can simply print 'something',. The comma at the end prevents the addition of a newline.

– arjoonn
Sep 6 '15 at 5:37

add a comment |

it gives a syntax error

– thedp
Jul 13 '15 at 14:37

2

This is in python 3. In python 2 you can simply print 'something',. The comma at the end prevents the addition of a newline.

– arjoonn
Sep 6 '15 at 5:37

it gives a syntax error

– thedp
Jul 13 '15 at 14:37

This is in python 3. In python 2 you can simply print 'something',. The comma at the end prevents the addition of a newline.

– arjoonn
Sep 6 '15 at 5:37

add a comment |

Most simple:

Python 3

    print(‘r’+’something to be override’,end=‘’)

It means it will back the cursor to beginning, than will print something and will end in the same line. If in a loop it will start printing in the same place it starts.

edited Jan 3 at 15:53

answered Nov 6 '18 at 19:15

Octavius

9327

Cool! Works in Windows as well.

– Shital Shah
Feb 13 at 11:59

Thanks this works fine for me! I think that print(’something to be override’, end=‘r’) is simpler, though.

– Francesco Boccardo
Apr 10 at 9:00

add a comment |

Most simple:

Python 3

    print(‘r’+’something to be override’,end=‘’)

It means it will back the cursor to beginning, than will print something and will end in the same line. If in a loop it will start printing in the same place it starts.

edited Jan 3 at 15:53

answered Nov 6 '18 at 19:15

Octavius

9327

Cool! Works in Windows as well.

– Shital Shah
Feb 13 at 11:59

Thanks this works fine for me! I think that print(’something to be override’, end=‘r’) is simpler, though.

– Francesco Boccardo
Apr 10 at 9:00

add a comment |

Most simple:

Python 3

    print(‘r’+’something to be override’,end=‘’)

It means it will back the cursor to beginning, than will print something and will end in the same line. If in a loop it will start printing in the same place it starts.

edited Jan 3 at 15:53

answered Nov 6 '18 at 19:15

Octavius

9327

Most simple:

Python 3

    print(‘r’+’something to be override’,end=‘’)

It means it will back the cursor to beginning, than will print something and will end in the same line. If in a loop it will start printing in the same place it starts.

edited Jan 3 at 15:53

answered Nov 6 '18 at 19:15

Octavius

9327

edited Jan 3 at 15:53

answered Nov 6 '18 at 19:15

Octavius

9327

answered Nov 6 '18 at 19:15

Octavius

9327

answered Nov 6 '18 at 19:15

Octavius

9327

Cool! Works in Windows as well.

– Shital Shah
Feb 13 at 11:59

Thanks this works fine for me! I think that print(’something to be override’, end=‘r’) is simpler, though.

– Francesco Boccardo
Apr 10 at 9:00

add a comment |

Cool! Works in Windows as well.

– Shital Shah
Feb 13 at 11:59

Thanks this works fine for me! I think that print(’something to be override’, end=‘r’) is simpler, though.

– Francesco Boccardo
Apr 10 at 9:00

Cool! Works in Windows as well.

– Shital Shah
Feb 13 at 11:59

Thanks this works fine for me! I think that print(’something to be override’, end=‘r’) is simpler, though.

– Francesco Boccardo
Apr 10 at 9:00

add a comment |

If you want to overwrite the previous line (rather than continually adding to it), you can combine r with print(), at the end of the print statement. For example,

from time import sleep



for i in xrange(0, 10):

    print("r{0}".format(i)),

    sleep(.5)



print("...DONE!")

will count 0 to 9, replacing the old number in the console. The "...DONE!" will print on the same line as the last counter, 9.

print("Installing |XXXXXX              | 30%"),

edited Oct 9 '15 at 17:50

answered Oct 9 '15 at 16:18

Brian Bunker

7516

add a comment |

If you want to overwrite the previous line (rather than continually adding to it), you can combine r with print(), at the end of the print statement. For example,

from time import sleep



for i in xrange(0, 10):

    print("r{0}".format(i)),

    sleep(.5)



print("...DONE!")

will count 0 to 9, replacing the old number in the console. The "...DONE!" will print on the same line as the last counter, 9.

print("Installing |XXXXXX              | 30%"),

edited Oct 9 '15 at 17:50

answered Oct 9 '15 at 16:18

Brian Bunker

7516

add a comment |

If you want to overwrite the previous line (rather than continually adding to it), you can combine r with print(), at the end of the print statement. For example,

from time import sleep



for i in xrange(0, 10):

    print("r{0}".format(i)),

    sleep(.5)



print("...DONE!")

will count 0 to 9, replacing the old number in the console. The "...DONE!" will print on the same line as the last counter, 9.

print("Installing |XXXXXX              | 30%"),

edited Oct 9 '15 at 17:50

answered Oct 9 '15 at 16:18

Brian Bunker

7516

If you want to overwrite the previous line (rather than continually adding to it), you can combine r with print(), at the end of the print statement. For example,

from time import sleep



for i in xrange(0, 10):

    print("r{0}".format(i)),

    sleep(.5)



print("...DONE!")

will count 0 to 9, replacing the old number in the console. The "...DONE!" will print on the same line as the last counter, 9.

print("Installing |XXXXXX              | 30%"),

edited Oct 9 '15 at 17:50

answered Oct 9 '15 at 16:18

Brian Bunker

7516

edited Oct 9 '15 at 17:50

answered Oct 9 '15 at 16:18

Brian Bunker

7516

answered Oct 9 '15 at 16:18

Brian Bunker

7516

answered Oct 9 '15 at 16:18

Brian Bunker

7516

add a comment |

Here a 2.7-compatible version derived from the 3.0 version by @Vadim-Zin4uk:

Python 2

import time



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print '{0}r'.format(s),                # just print and flush



    time.sleep(0.2)

For that matter, the 3.0 solution provided looks a little bloated. For example, the backspace method doesn't make use of the integer argument and could probably be done away with altogether.

Python 3

import time



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print('{0}r'.format(s), end='')        # just print and flush



    time.sleep(0.2)                         # sleep for 200ms

Both have been tested and work.

answered Jan 10 '18 at 19:47

Dannid

7781014

add a comment |

Here a 2.7-compatible version derived from the 3.0 version by @Vadim-Zin4uk:

Python 2

import time



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print '{0}r'.format(s),                # just print and flush



    time.sleep(0.2)

For that matter, the 3.0 solution provided looks a little bloated. For example, the backspace method doesn't make use of the integer argument and could probably be done away with altogether.

Python 3

import time



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print('{0}r'.format(s), end='')        # just print and flush



    time.sleep(0.2)                         # sleep for 200ms

Both have been tested and work.

answered Jan 10 '18 at 19:47

Dannid

7781014

add a comment |

Here a 2.7-compatible version derived from the 3.0 version by @Vadim-Zin4uk:

Python 2

import time



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print '{0}r'.format(s),                # just print and flush



    time.sleep(0.2)

For that matter, the 3.0 solution provided looks a little bloated. For example, the backspace method doesn't make use of the integer argument and could probably be done away with altogether.

Python 3

import time



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print('{0}r'.format(s), end='')        # just print and flush



    time.sleep(0.2)                         # sleep for 200ms

Both have been tested and work.

answered Jan 10 '18 at 19:47

Dannid

7781014

Here a 2.7-compatible version derived from the 3.0 version by @Vadim-Zin4uk:

Python 2

import time



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print '{0}r'.format(s),                # just print and flush



    time.sleep(0.2)

For that matter, the 3.0 solution provided looks a little bloated. For example, the backspace method doesn't make use of the integer argument and could probably be done away with altogether.

Python 3

import time



for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    print('{0}r'.format(s), end='')        # just print and flush



    time.sleep(0.2)                         # sleep for 200ms

Both have been tested and work.

answered Jan 10 '18 at 19:47

Dannid

7781014

answered Jan 10 '18 at 19:47

Dannid

7781014

answered Jan 10 '18 at 19:47

Dannid

7781014

answered Jan 10 '18 at 19:47

Dannid

7781014

add a comment |

This is a very old thread, but here's a very thorough answer and sample code.

And a sample. Note that this runs perfectly in Python 2 or 3.

from __future__ import print_function



import sys

import time



ANS = 42

FACTORS = {n for n in range(1, ANS + 1) if ANS % n == 0}



for i in range(1, ANS + 1):

    if i in FACTORS:

        print('r{0:d}'.format(i), end='')

        sys.stdout.flush()

        time.sleep(ANS / 100.0)

else:

    print()

answered Oct 25 '17 at 18:20

Chris Cosby

234

I think your answer is more suitable for: stackoverflow.com/questions/45263205/…

– Marc Cayuela Rafols
Oct 25 '17 at 19:06

add a comment |

This is a very old thread, but here's a very thorough answer and sample code.

And a sample. Note that this runs perfectly in Python 2 or 3.

from __future__ import print_function



import sys

import time



ANS = 42

FACTORS = {n for n in range(1, ANS + 1) if ANS % n == 0}



for i in range(1, ANS + 1):

    if i in FACTORS:

        print('r{0:d}'.format(i), end='')

        sys.stdout.flush()

        time.sleep(ANS / 100.0)

else:

    print()

answered Oct 25 '17 at 18:20

Chris Cosby

234

I think your answer is more suitable for: stackoverflow.com/questions/45263205/…

– Marc Cayuela Rafols
Oct 25 '17 at 19:06

add a comment |

This is a very old thread, but here's a very thorough answer and sample code.

And a sample. Note that this runs perfectly in Python 2 or 3.

from __future__ import print_function



import sys

import time



ANS = 42

FACTORS = {n for n in range(1, ANS + 1) if ANS % n == 0}



for i in range(1, ANS + 1):

    if i in FACTORS:

        print('r{0:d}'.format(i), end='')

        sys.stdout.flush()

        time.sleep(ANS / 100.0)

else:

    print()

answered Oct 25 '17 at 18:20

Chris Cosby

234

This is a very old thread, but here's a very thorough answer and sample code.

And a sample. Note that this runs perfectly in Python 2 or 3.

from __future__ import print_function



import sys

import time



ANS = 42

FACTORS = {n for n in range(1, ANS + 1) if ANS % n == 0}



for i in range(1, ANS + 1):

    if i in FACTORS:

        print('r{0:d}'.format(i), end='')

        sys.stdout.flush()

        time.sleep(ANS / 100.0)

else:

    print()

answered Oct 25 '17 at 18:20

Chris Cosby

234

answered Oct 25 '17 at 18:20

Chris Cosby

234

answered Oct 25 '17 at 18:20

Chris Cosby

234

answered Oct 25 '17 at 18:20

Chris Cosby

234

I think your answer is more suitable for: stackoverflow.com/questions/45263205/…

– Marc Cayuela Rafols
Oct 25 '17 at 19:06

add a comment |

I think your answer is more suitable for: stackoverflow.com/questions/45263205/…

– Marc Cayuela Rafols
Oct 25 '17 at 19:06

I think your answer is more suitable for: stackoverflow.com/questions/45263205/…

– Marc Cayuela Rafols
Oct 25 '17 at 19:06

add a comment |

Just in case you have pre-stored the values in an array, you can call them in the following format:

for i in range(0,n):

       print arr[i],

answered Oct 16 '16 at 23:20

k20392

111

add a comment |

Just in case you have pre-stored the values in an array, you can call them in the following format:

for i in range(0,n):

       print arr[i],

answered Oct 16 '16 at 23:20

k20392

111

add a comment |

Just in case you have pre-stored the values in an array, you can call them in the following format:

for i in range(0,n):

       print arr[i],

answered Oct 16 '16 at 23:20

k20392

111

Just in case you have pre-stored the values in an array, you can call them in the following format:

for i in range(0,n):

       print arr[i],

answered Oct 16 '16 at 23:20

k20392

111

answered Oct 16 '16 at 23:20

k20392

111

answered Oct 16 '16 at 23:20

k20392

111

answered Oct 16 '16 at 23:20

k20392

111

add a comment |

-3

I found this solution, and it's working on Python 2.7

# Working on Python 2.7 Linux



import time

import sys





def backspace(n):

    print('r', end='')                     # use 'r' to go back





for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    sys.stdout.write(string)

    backspace(len(s))                       # back for n chars

    sys.stdout.flush()

    time.sleep(0.2)                         # sleep for 200ms

edited Jul 23 '17 at 8:34

ideasman42

13.3k673140

answered Dec 7 '16 at 12:51

Luis Silva

1

That print is incorrect syntax for Python 2.7 and the code doesn't work even with correct syntax.

– Cory Madden
Aug 6 '17 at 20:47

add a comment |

-3

I found this solution, and it's working on Python 2.7

# Working on Python 2.7 Linux



import time

import sys





def backspace(n):

    print('r', end='')                     # use 'r' to go back





for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    sys.stdout.write(string)

    backspace(len(s))                       # back for n chars

    sys.stdout.flush()

    time.sleep(0.2)                         # sleep for 200ms

edited Jul 23 '17 at 8:34

ideasman42

13.3k673140

answered Dec 7 '16 at 12:51

Luis Silva

1

That print is incorrect syntax for Python 2.7 and the code doesn't work even with correct syntax.

– Cory Madden
Aug 6 '17 at 20:47

add a comment |

-3

I found this solution, and it's working on Python 2.7

# Working on Python 2.7 Linux



import time

import sys





def backspace(n):

    print('r', end='')                     # use 'r' to go back





for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    sys.stdout.write(string)

    backspace(len(s))                       # back for n chars

    sys.stdout.flush()

    time.sleep(0.2)                         # sleep for 200ms

edited Jul 23 '17 at 8:34

ideasman42

13.3k673140

answered Dec 7 '16 at 12:51

Luis Silva

I found this solution, and it's working on Python 2.7

# Working on Python 2.7 Linux



import time

import sys





def backspace(n):

    print('r', end='')                     # use 'r' to go back





for i in range(101):                        # for 0 to 100

    s = str(i) + '%'                        # string for output

    sys.stdout.write(string)

    backspace(len(s))                       # back for n chars

    sys.stdout.flush()

    time.sleep(0.2)                         # sleep for 200ms

edited Jul 23 '17 at 8:34

ideasman42

13.3k673140

answered Dec 7 '16 at 12:51

Luis Silva

edited Jul 23 '17 at 8:34

ideasman42

13.3k673140

edited Jul 23 '17 at 8:34

ideasman42

13.3k673140

edited Jul 23 '17 at 8:34

ideasman42

13.3k673140

answered Dec 7 '16 at 12:51

Luis Silva

answered Dec 7 '16 at 12:51

Luis Silva

answered Dec 7 '16 at 12:51

Luis Silva

1

That print is incorrect syntax for Python 2.7 and the code doesn't work even with correct syntax.

– Cory Madden
Aug 6 '17 at 20:47

add a comment |

1

That print is incorrect syntax for Python 2.7 and the code doesn't work even with correct syntax.

– Cory Madden
Aug 6 '17 at 20:47

That print is incorrect syntax for Python 2.7 and the code doesn't work even with correct syntax.

– Cory Madden
Aug 6 '17 at 20:47

add a comment |

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