What happens when you use arithmetic operators inside of a string declaration?





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If there is an arithmetic operator inside of a string declaration, how does the String treat the operator?

For example in this case: 



String s = "de32";

s = s.charAt(0) * 2 + "";   

System.out.println(s);


String s is not dd but instead is 102. What is the * 2 mean for the string?






java string math







share|improve this question































    3















    If there is an arithmetic operator inside of a string declaration, how does the String treat the operator?

    For example in this case: 



    String s = "de32";
    
s = s.charAt(0) * 2 + "";   
    
System.out.println(s);


    String s is not dd but instead is 102. What is the * 2 mean for the string?






    java string math







    share|improve this question



























      3












      3








      3








      If there is an arithmetic operator inside of a string declaration, how does the String treat the operator?

      For example in this case: 



      String s = "de32";
      
s = s.charAt(0) * 2 + "";   
      
System.out.println(s);


      String s is not dd but instead is 102. What is the * 2 mean for the string?






      java string math







      share|improve this question
















      If there is an arithmetic operator inside of a string declaration, how does the String treat the operator?

      For example in this case: 



      String s = "de32";
      
s = s.charAt(0) * 2 + "";   
      
System.out.println(s);


      String s is not dd but instead is 102. What is the * 2 mean for the string?






      java string math




      java string math






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 3 at 7:33









      Shababb Karim

      720924




      720924










      asked Jan 3 at 6:17









      user10860991user10860991

      162




      162
























          2 Answers
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          s.charAt(0) is a char ('d'), and char is a numeric type. The numeric value of the character 'd' is 100. Therefore s.charAt(0) * 2 simply multiplies that value by 2, which results in 200 (not 102 as you wrote).



          Then the result is converted to a String, since you appended to it an empty String, so s is assigned "200".



          The expression is evaluated left to right, so it is equivalent to:



          s = (s.charAt(0) * 2) + "";



          • First the char 'd' is promoted to an int and multiplied by 2.

          • Then the resulting int (200) is appended to the empty String "". resulting in the String "200".






          share|improve this answer





















          • 1





            @AndyTurner sure

            – Eran
            Jan 3 at 6:34



















          0














          At 0 position char d is there and it is multiplied with 2. So ASCII value of d is multiplied by 2. Since ASCII value of d is 100 so it gives result 200. Then it is appended to empty string and give "200" as a string .






          share|improve this answer
























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            2 Answers
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            active

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            2 Answers
            2






            active

            oldest

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            active

            oldest

            votes






            active

            oldest

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            4














            s.charAt(0) is a char ('d'), and char is a numeric type. The numeric value of the character 'd' is 100. Therefore s.charAt(0) * 2 simply multiplies that value by 2, which results in 200 (not 102 as you wrote).



            Then the result is converted to a String, since you appended to it an empty String, so s is assigned "200".



            The expression is evaluated left to right, so it is equivalent to:



            s = (s.charAt(0) * 2) + "";



            • First the char 'd' is promoted to an int and multiplied by 2.

            • Then the resulting int (200) is appended to the empty String "". resulting in the String "200".






            share|improve this answer





















            • 1





              @AndyTurner sure

              – Eran
              Jan 3 at 6:34
















            4














            s.charAt(0) is a char ('d'), and char is a numeric type. The numeric value of the character 'd' is 100. Therefore s.charAt(0) * 2 simply multiplies that value by 2, which results in 200 (not 102 as you wrote).



            Then the result is converted to a String, since you appended to it an empty String, so s is assigned "200".



            The expression is evaluated left to right, so it is equivalent to:



            s = (s.charAt(0) * 2) + "";



            • First the char 'd' is promoted to an int and multiplied by 2.

            • Then the resulting int (200) is appended to the empty String "". resulting in the String "200".






            share|improve this answer





















            • 1





              @AndyTurner sure

              – Eran
              Jan 3 at 6:34














            4












            4








            4







            s.charAt(0) is a char ('d'), and char is a numeric type. The numeric value of the character 'd' is 100. Therefore s.charAt(0) * 2 simply multiplies that value by 2, which results in 200 (not 102 as you wrote).



            Then the result is converted to a String, since you appended to it an empty String, so s is assigned "200".



            The expression is evaluated left to right, so it is equivalent to:



            s = (s.charAt(0) * 2) + "";



            • First the char 'd' is promoted to an int and multiplied by 2.

            • Then the resulting int (200) is appended to the empty String "". resulting in the String "200".






            share|improve this answer















            s.charAt(0) is a char ('d'), and char is a numeric type. The numeric value of the character 'd' is 100. Therefore s.charAt(0) * 2 simply multiplies that value by 2, which results in 200 (not 102 as you wrote).



            Then the result is converted to a String, since you appended to it an empty String, so s is assigned "200".



            The expression is evaluated left to right, so it is equivalent to:



            s = (s.charAt(0) * 2) + "";



            • First the char 'd' is promoted to an int and multiplied by 2.

            • Then the resulting int (200) is appended to the empty String "". resulting in the String "200".







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Jan 3 at 6:34

























            answered Jan 3 at 6:19









            EranEran

            292k37481564




            292k37481564








            • 1





              @AndyTurner sure

              – Eran
              Jan 3 at 6:34














            • 1





              @AndyTurner sure

              – Eran
              Jan 3 at 6:34








            1




            1





            @AndyTurner sure

            – Eran
            Jan 3 at 6:34





            @AndyTurner sure

            – Eran
            Jan 3 at 6:34













            0














            At 0 position char d is there and it is multiplied with 2. So ASCII value of d is multiplied by 2. Since ASCII value of d is 100 so it gives result 200. Then it is appended to empty string and give "200" as a string .






            share|improve this answer




























              0














              At 0 position char d is there and it is multiplied with 2. So ASCII value of d is multiplied by 2. Since ASCII value of d is 100 so it gives result 200. Then it is appended to empty string and give "200" as a string .






              share|improve this answer


























                0












                0








                0







                At 0 position char d is there and it is multiplied with 2. So ASCII value of d is multiplied by 2. Since ASCII value of d is 100 so it gives result 200. Then it is appended to empty string and give "200" as a string .






                share|improve this answer













                At 0 position char d is there and it is multiplied with 2. So ASCII value of d is multiplied by 2. Since ASCII value of d is 100 so it gives result 200. Then it is appended to empty string and give "200" as a string .







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Jan 3 at 6:38









                praneet droliapraneet drolia

                2491314




                2491314






























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