Is the quotient of standard parabolic subgroups isomorphic to a Schubert variety












3












$begingroup$


Let $G$ be a reductive algebraic group over an algebraically closed field.



Let $B subseteq P_2 subseteq P_1$ be a Borel subgroup and two parabolic subgroups. Then $P_1/P_2 subseteq G/P_2$ is a closed subvariety.




Is $P_1/P_2$ a Schubert variety defined in $G/P_2$? If not, what are the intersection of $P_1/P_2$ with the Schubert cells, also defined in $G/P_2$?




More precisely, let $W_{P_i}$ be the subgroup of the Weyl group $W$ of $G$ defined with a maximal torus $Tsubseteq B$, such that $W_{P_i} simeq N_{P_i}(T)/T$, for $i=1,2$. Let $$W_{P_i}^{text{min}} = {w in W | ell(ww') = ell(w)+ell(w'), text{ for all } w' in W_{P_i}},$$
for $i=1,2$. Let $w_0$ be the longest element in $W$. Then there is a unique element in $W_{P_i}^{text{min}}$ with maximal length, which is denoted as $w_i$, satisfying $w_0 = w_i cdot w_{P_i}$, where $w_{P_i}$ is the longest element in $W_{P_i}$, for $i=1,2$.



Since $W_{P_2}$ is a subgroup of $W_{P_1}$, there exists $w_1' in W_{P_1}$, such that $w_{P_1} = w_1' cdot w_{P_2}$. So $w_2 = w_1 cdot w_1'$.



Let $X_i(cdot)$ denote the Schubert variety defined in $G/P_i$ for $i=1,2$. Then $G/P_1 simeq X_1(w_1)$ and $G/P_2 simeq X_2(w_1 cdot w_1')$. This makes me suspect that $P_1/P_2$ and $X_2(w_1')$ are related in some sense. Is it true?



Thank you very much.



P.S.




  1. In a Coxeter group, we say $x = y cdot z$ if $x = yz$ and $ell(x)=ell(y)+ell(z)$.


2.For the definition of all the terms, please check: Billey and Lakshmibai's Singular Loci of Schubert Varieties, Chapter 2.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Have you tried looking at examples? $SL_3$ with $P_2=B$ and $P_1=G_W$ where $W$ is the point of the cooridinate plane $(e_1,e_2)$ in $Gr(2,3)$ might be reasonable. Then $P_1/P_2cong mathbf{P}^1$ and $G/P_2=G/B$ is the variety of complete flags in a 3-dim vec space (this has 6 cells, and only 2 cells of dimension 1).
    $endgroup$
    – Eoin
    Sep 4 '17 at 6:03










  • $begingroup$
    @Eoin: Thank you very much for the comment. But I am sorry I don't quite get it. In this example, is $P_1/P_2$ a Schubert variety ( a union of one cell of dimension $1$ and one cell of dimension $0$) or not? Thanks again.
    $endgroup$
    – IzumiEternal
    Sep 20 '17 at 17:23
















3












$begingroup$


Let $G$ be a reductive algebraic group over an algebraically closed field.



Let $B subseteq P_2 subseteq P_1$ be a Borel subgroup and two parabolic subgroups. Then $P_1/P_2 subseteq G/P_2$ is a closed subvariety.




Is $P_1/P_2$ a Schubert variety defined in $G/P_2$? If not, what are the intersection of $P_1/P_2$ with the Schubert cells, also defined in $G/P_2$?




More precisely, let $W_{P_i}$ be the subgroup of the Weyl group $W$ of $G$ defined with a maximal torus $Tsubseteq B$, such that $W_{P_i} simeq N_{P_i}(T)/T$, for $i=1,2$. Let $$W_{P_i}^{text{min}} = {w in W | ell(ww') = ell(w)+ell(w'), text{ for all } w' in W_{P_i}},$$
for $i=1,2$. Let $w_0$ be the longest element in $W$. Then there is a unique element in $W_{P_i}^{text{min}}$ with maximal length, which is denoted as $w_i$, satisfying $w_0 = w_i cdot w_{P_i}$, where $w_{P_i}$ is the longest element in $W_{P_i}$, for $i=1,2$.



Since $W_{P_2}$ is a subgroup of $W_{P_1}$, there exists $w_1' in W_{P_1}$, such that $w_{P_1} = w_1' cdot w_{P_2}$. So $w_2 = w_1 cdot w_1'$.



Let $X_i(cdot)$ denote the Schubert variety defined in $G/P_i$ for $i=1,2$. Then $G/P_1 simeq X_1(w_1)$ and $G/P_2 simeq X_2(w_1 cdot w_1')$. This makes me suspect that $P_1/P_2$ and $X_2(w_1')$ are related in some sense. Is it true?



Thank you very much.



P.S.




  1. In a Coxeter group, we say $x = y cdot z$ if $x = yz$ and $ell(x)=ell(y)+ell(z)$.


2.For the definition of all the terms, please check: Billey and Lakshmibai's Singular Loci of Schubert Varieties, Chapter 2.










share|cite|improve this question











$endgroup$












  • $begingroup$
    Have you tried looking at examples? $SL_3$ with $P_2=B$ and $P_1=G_W$ where $W$ is the point of the cooridinate plane $(e_1,e_2)$ in $Gr(2,3)$ might be reasonable. Then $P_1/P_2cong mathbf{P}^1$ and $G/P_2=G/B$ is the variety of complete flags in a 3-dim vec space (this has 6 cells, and only 2 cells of dimension 1).
    $endgroup$
    – Eoin
    Sep 4 '17 at 6:03










  • $begingroup$
    @Eoin: Thank you very much for the comment. But I am sorry I don't quite get it. In this example, is $P_1/P_2$ a Schubert variety ( a union of one cell of dimension $1$ and one cell of dimension $0$) or not? Thanks again.
    $endgroup$
    – IzumiEternal
    Sep 20 '17 at 17:23














3












3








3


1



$begingroup$


Let $G$ be a reductive algebraic group over an algebraically closed field.



Let $B subseteq P_2 subseteq P_1$ be a Borel subgroup and two parabolic subgroups. Then $P_1/P_2 subseteq G/P_2$ is a closed subvariety.




Is $P_1/P_2$ a Schubert variety defined in $G/P_2$? If not, what are the intersection of $P_1/P_2$ with the Schubert cells, also defined in $G/P_2$?




More precisely, let $W_{P_i}$ be the subgroup of the Weyl group $W$ of $G$ defined with a maximal torus $Tsubseteq B$, such that $W_{P_i} simeq N_{P_i}(T)/T$, for $i=1,2$. Let $$W_{P_i}^{text{min}} = {w in W | ell(ww') = ell(w)+ell(w'), text{ for all } w' in W_{P_i}},$$
for $i=1,2$. Let $w_0$ be the longest element in $W$. Then there is a unique element in $W_{P_i}^{text{min}}$ with maximal length, which is denoted as $w_i$, satisfying $w_0 = w_i cdot w_{P_i}$, where $w_{P_i}$ is the longest element in $W_{P_i}$, for $i=1,2$.



Since $W_{P_2}$ is a subgroup of $W_{P_1}$, there exists $w_1' in W_{P_1}$, such that $w_{P_1} = w_1' cdot w_{P_2}$. So $w_2 = w_1 cdot w_1'$.



Let $X_i(cdot)$ denote the Schubert variety defined in $G/P_i$ for $i=1,2$. Then $G/P_1 simeq X_1(w_1)$ and $G/P_2 simeq X_2(w_1 cdot w_1')$. This makes me suspect that $P_1/P_2$ and $X_2(w_1')$ are related in some sense. Is it true?



Thank you very much.



P.S.




  1. In a Coxeter group, we say $x = y cdot z$ if $x = yz$ and $ell(x)=ell(y)+ell(z)$.


2.For the definition of all the terms, please check: Billey and Lakshmibai's Singular Loci of Schubert Varieties, Chapter 2.










share|cite|improve this question











$endgroup$




Let $G$ be a reductive algebraic group over an algebraically closed field.



Let $B subseteq P_2 subseteq P_1$ be a Borel subgroup and two parabolic subgroups. Then $P_1/P_2 subseteq G/P_2$ is a closed subvariety.




Is $P_1/P_2$ a Schubert variety defined in $G/P_2$? If not, what are the intersection of $P_1/P_2$ with the Schubert cells, also defined in $G/P_2$?




More precisely, let $W_{P_i}$ be the subgroup of the Weyl group $W$ of $G$ defined with a maximal torus $Tsubseteq B$, such that $W_{P_i} simeq N_{P_i}(T)/T$, for $i=1,2$. Let $$W_{P_i}^{text{min}} = {w in W | ell(ww') = ell(w)+ell(w'), text{ for all } w' in W_{P_i}},$$
for $i=1,2$. Let $w_0$ be the longest element in $W$. Then there is a unique element in $W_{P_i}^{text{min}}$ with maximal length, which is denoted as $w_i$, satisfying $w_0 = w_i cdot w_{P_i}$, where $w_{P_i}$ is the longest element in $W_{P_i}$, for $i=1,2$.



Since $W_{P_2}$ is a subgroup of $W_{P_1}$, there exists $w_1' in W_{P_1}$, such that $w_{P_1} = w_1' cdot w_{P_2}$. So $w_2 = w_1 cdot w_1'$.



Let $X_i(cdot)$ denote the Schubert variety defined in $G/P_i$ for $i=1,2$. Then $G/P_1 simeq X_1(w_1)$ and $G/P_2 simeq X_2(w_1 cdot w_1')$. This makes me suspect that $P_1/P_2$ and $X_2(w_1')$ are related in some sense. Is it true?



Thank you very much.



P.S.




  1. In a Coxeter group, we say $x = y cdot z$ if $x = yz$ and $ell(x)=ell(y)+ell(z)$.


2.For the definition of all the terms, please check: Billey and Lakshmibai's Singular Loci of Schubert Varieties, Chapter 2.







algebraic-geometry algebraic-groups schubert-calculus






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 2 at 0:48









Matt Samuel

37.5k63665




37.5k63665










asked Jul 22 '17 at 3:48









IzumiEternalIzumiEternal

329




329












  • $begingroup$
    Have you tried looking at examples? $SL_3$ with $P_2=B$ and $P_1=G_W$ where $W$ is the point of the cooridinate plane $(e_1,e_2)$ in $Gr(2,3)$ might be reasonable. Then $P_1/P_2cong mathbf{P}^1$ and $G/P_2=G/B$ is the variety of complete flags in a 3-dim vec space (this has 6 cells, and only 2 cells of dimension 1).
    $endgroup$
    – Eoin
    Sep 4 '17 at 6:03










  • $begingroup$
    @Eoin: Thank you very much for the comment. But I am sorry I don't quite get it. In this example, is $P_1/P_2$ a Schubert variety ( a union of one cell of dimension $1$ and one cell of dimension $0$) or not? Thanks again.
    $endgroup$
    – IzumiEternal
    Sep 20 '17 at 17:23


















  • $begingroup$
    Have you tried looking at examples? $SL_3$ with $P_2=B$ and $P_1=G_W$ where $W$ is the point of the cooridinate plane $(e_1,e_2)$ in $Gr(2,3)$ might be reasonable. Then $P_1/P_2cong mathbf{P}^1$ and $G/P_2=G/B$ is the variety of complete flags in a 3-dim vec space (this has 6 cells, and only 2 cells of dimension 1).
    $endgroup$
    – Eoin
    Sep 4 '17 at 6:03










  • $begingroup$
    @Eoin: Thank you very much for the comment. But I am sorry I don't quite get it. In this example, is $P_1/P_2$ a Schubert variety ( a union of one cell of dimension $1$ and one cell of dimension $0$) or not? Thanks again.
    $endgroup$
    – IzumiEternal
    Sep 20 '17 at 17:23
















$begingroup$
Have you tried looking at examples? $SL_3$ with $P_2=B$ and $P_1=G_W$ where $W$ is the point of the cooridinate plane $(e_1,e_2)$ in $Gr(2,3)$ might be reasonable. Then $P_1/P_2cong mathbf{P}^1$ and $G/P_2=G/B$ is the variety of complete flags in a 3-dim vec space (this has 6 cells, and only 2 cells of dimension 1).
$endgroup$
– Eoin
Sep 4 '17 at 6:03




$begingroup$
Have you tried looking at examples? $SL_3$ with $P_2=B$ and $P_1=G_W$ where $W$ is the point of the cooridinate plane $(e_1,e_2)$ in $Gr(2,3)$ might be reasonable. Then $P_1/P_2cong mathbf{P}^1$ and $G/P_2=G/B$ is the variety of complete flags in a 3-dim vec space (this has 6 cells, and only 2 cells of dimension 1).
$endgroup$
– Eoin
Sep 4 '17 at 6:03












$begingroup$
@Eoin: Thank you very much for the comment. But I am sorry I don't quite get it. In this example, is $P_1/P_2$ a Schubert variety ( a union of one cell of dimension $1$ and one cell of dimension $0$) or not? Thanks again.
$endgroup$
– IzumiEternal
Sep 20 '17 at 17:23




$begingroup$
@Eoin: Thank you very much for the comment. But I am sorry I don't quite get it. In this example, is $P_1/P_2$ a Schubert variety ( a union of one cell of dimension $1$ and one cell of dimension $0$) or not? Thanks again.
$endgroup$
– IzumiEternal
Sep 20 '17 at 17:23










0






active

oldest

votes











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2367693%2fis-the-quotient-of-standard-parabolic-subgroups-isomorphic-to-a-schubert-variety%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2367693%2fis-the-quotient-of-standard-parabolic-subgroups-isomorphic-to-a-schubert-variety%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

MongoDB - Not Authorized To Execute Command

How to fix TextFormField cause rebuild widget in Flutter

in spring boot 2.1 many test slices are not allowed anymore due to multiple @BootstrapWith