Area of a triangle when two sides and an angle is given












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Can you find the area of a triangle if it's 2 sides are given and the angle formed by these sides are given?










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Can you find the area of a triangle if it's 2 sides are given and the angle formed by these sides are given?










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    mathopenref.com/triangleareasas.html
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    – user289143
    Jan 17 at 17:19










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Can you find the area of a triangle if it's 2 sides are given and the angle formed by these sides are given?










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Can you find the area of a triangle if it's 2 sides are given and the angle formed by these sides are given?







triangle






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asked Jan 17 at 17:15









user329742user329742

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  • $begingroup$
    mathopenref.com/triangleareasas.html
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    – user289143
    Jan 17 at 17:19










  • $begingroup$
    Welcome to Mathematics Stack Exchange! A quick tour will hep you understand how best to form questions and answers. The lingua franca for formulation is MathJax.
    $endgroup$
    – dantopa
    Jan 17 at 17:42


















  • $begingroup$
    mathopenref.com/triangleareasas.html
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    – user289143
    Jan 17 at 17:19










  • $begingroup$
    Welcome to Mathematics Stack Exchange! A quick tour will hep you understand how best to form questions and answers. The lingua franca for formulation is MathJax.
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    – dantopa
    Jan 17 at 17:42
















$begingroup$
mathopenref.com/triangleareasas.html
$endgroup$
– user289143
Jan 17 at 17:19




$begingroup$
mathopenref.com/triangleareasas.html
$endgroup$
– user289143
Jan 17 at 17:19












$begingroup$
Welcome to Mathematics Stack Exchange! A quick tour will hep you understand how best to form questions and answers. The lingua franca for formulation is MathJax.
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– dantopa
Jan 17 at 17:42




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3 Answers
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oldest

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2












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For completeness , I prove that the area equals $frac{1}{2}absin c$
.Let the sides of known measures be $AB$ and $AC$ . Let the known angle be $angle BAC$
enter image description here



Draw perpendicular $CD$ to $AB$ . Then , the area = $$frac{1}{2}bh=frac{1}{2}ABcdot CD=frac{1}{2}ABcdot (ACcdot sin angle CAB) $$






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  • 1




    $begingroup$
    Nice answer, certainly not a lazy one like mine. cdot $( cdot ) $ might help your formatting, though you can choose to ignore this.
    $endgroup$
    – Mohammad Zuhair Khan
    Jan 17 at 17:44










  • $begingroup$
    Thanks for the feedback ! I didn’t know this...
    $endgroup$
    – Sinπ
    Jan 17 at 17:45








  • 1




    $begingroup$
    No problem, I am always glad to help. Be sure to check out math.meta.stackexchange.com/questions/5020/… for more tips on $LaTeX$
    $endgroup$
    – Mohammad Zuhair Khan
    Jan 17 at 17:48



















1












$begingroup$

Use that $$A=frac{1}{2}absin(gamma)$$ etc






share|cite|improve this answer









$endgroup$





















    1












    $begingroup$

    Yes.
    $$A=frac 12absin theta$$






    share|cite|improve this answer









    $endgroup$













    • $begingroup$
      If this doesn't answer the question, I don't know what will. Should I provide more details?
      $endgroup$
      – Mohammad Zuhair Khan
      Jan 17 at 17:40













    Your Answer





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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2












    $begingroup$

    For completeness , I prove that the area equals $frac{1}{2}absin c$
    .Let the sides of known measures be $AB$ and $AC$ . Let the known angle be $angle BAC$
    enter image description here



    Draw perpendicular $CD$ to $AB$ . Then , the area = $$frac{1}{2}bh=frac{1}{2}ABcdot CD=frac{1}{2}ABcdot (ACcdot sin angle CAB) $$






    share|cite|improve this answer











    $endgroup$









    • 1




      $begingroup$
      Nice answer, certainly not a lazy one like mine. cdot $( cdot ) $ might help your formatting, though you can choose to ignore this.
      $endgroup$
      – Mohammad Zuhair Khan
      Jan 17 at 17:44










    • $begingroup$
      Thanks for the feedback ! I didn’t know this...
      $endgroup$
      – Sinπ
      Jan 17 at 17:45








    • 1




      $begingroup$
      No problem, I am always glad to help. Be sure to check out math.meta.stackexchange.com/questions/5020/… for more tips on $LaTeX$
      $endgroup$
      – Mohammad Zuhair Khan
      Jan 17 at 17:48
















    2












    $begingroup$

    For completeness , I prove that the area equals $frac{1}{2}absin c$
    .Let the sides of known measures be $AB$ and $AC$ . Let the known angle be $angle BAC$
    enter image description here



    Draw perpendicular $CD$ to $AB$ . Then , the area = $$frac{1}{2}bh=frac{1}{2}ABcdot CD=frac{1}{2}ABcdot (ACcdot sin angle CAB) $$






    share|cite|improve this answer











    $endgroup$









    • 1




      $begingroup$
      Nice answer, certainly not a lazy one like mine. cdot $( cdot ) $ might help your formatting, though you can choose to ignore this.
      $endgroup$
      – Mohammad Zuhair Khan
      Jan 17 at 17:44










    • $begingroup$
      Thanks for the feedback ! I didn’t know this...
      $endgroup$
      – Sinπ
      Jan 17 at 17:45








    • 1




      $begingroup$
      No problem, I am always glad to help. Be sure to check out math.meta.stackexchange.com/questions/5020/… for more tips on $LaTeX$
      $endgroup$
      – Mohammad Zuhair Khan
      Jan 17 at 17:48














    2












    2








    2





    $begingroup$

    For completeness , I prove that the area equals $frac{1}{2}absin c$
    .Let the sides of known measures be $AB$ and $AC$ . Let the known angle be $angle BAC$
    enter image description here



    Draw perpendicular $CD$ to $AB$ . Then , the area = $$frac{1}{2}bh=frac{1}{2}ABcdot CD=frac{1}{2}ABcdot (ACcdot sin angle CAB) $$






    share|cite|improve this answer











    $endgroup$



    For completeness , I prove that the area equals $frac{1}{2}absin c$
    .Let the sides of known measures be $AB$ and $AC$ . Let the known angle be $angle BAC$
    enter image description here



    Draw perpendicular $CD$ to $AB$ . Then , the area = $$frac{1}{2}bh=frac{1}{2}ABcdot CD=frac{1}{2}ABcdot (ACcdot sin angle CAB) $$







    share|cite|improve this answer














    share|cite|improve this answer



    share|cite|improve this answer








    edited Jan 17 at 17:45

























    answered Jan 17 at 17:41









    SinπSinπ

    64511




    64511








    • 1




      $begingroup$
      Nice answer, certainly not a lazy one like mine. cdot $( cdot ) $ might help your formatting, though you can choose to ignore this.
      $endgroup$
      – Mohammad Zuhair Khan
      Jan 17 at 17:44










    • $begingroup$
      Thanks for the feedback ! I didn’t know this...
      $endgroup$
      – Sinπ
      Jan 17 at 17:45








    • 1




      $begingroup$
      No problem, I am always glad to help. Be sure to check out math.meta.stackexchange.com/questions/5020/… for more tips on $LaTeX$
      $endgroup$
      – Mohammad Zuhair Khan
      Jan 17 at 17:48














    • 1




      $begingroup$
      Nice answer, certainly not a lazy one like mine. cdot $( cdot ) $ might help your formatting, though you can choose to ignore this.
      $endgroup$
      – Mohammad Zuhair Khan
      Jan 17 at 17:44










    • $begingroup$
      Thanks for the feedback ! I didn’t know this...
      $endgroup$
      – Sinπ
      Jan 17 at 17:45








    • 1




      $begingroup$
      No problem, I am always glad to help. Be sure to check out math.meta.stackexchange.com/questions/5020/… for more tips on $LaTeX$
      $endgroup$
      – Mohammad Zuhair Khan
      Jan 17 at 17:48








    1




    1




    $begingroup$
    Nice answer, certainly not a lazy one like mine. cdot $( cdot ) $ might help your formatting, though you can choose to ignore this.
    $endgroup$
    – Mohammad Zuhair Khan
    Jan 17 at 17:44




    $begingroup$
    Nice answer, certainly not a lazy one like mine. cdot $( cdot ) $ might help your formatting, though you can choose to ignore this.
    $endgroup$
    – Mohammad Zuhair Khan
    Jan 17 at 17:44












    $begingroup$
    Thanks for the feedback ! I didn’t know this...
    $endgroup$
    – Sinπ
    Jan 17 at 17:45






    $begingroup$
    Thanks for the feedback ! I didn’t know this...
    $endgroup$
    – Sinπ
    Jan 17 at 17:45






    1




    1




    $begingroup$
    No problem, I am always glad to help. Be sure to check out math.meta.stackexchange.com/questions/5020/… for more tips on $LaTeX$
    $endgroup$
    – Mohammad Zuhair Khan
    Jan 17 at 17:48




    $begingroup$
    No problem, I am always glad to help. Be sure to check out math.meta.stackexchange.com/questions/5020/… for more tips on $LaTeX$
    $endgroup$
    – Mohammad Zuhair Khan
    Jan 17 at 17:48











    1












    $begingroup$

    Use that $$A=frac{1}{2}absin(gamma)$$ etc






    share|cite|improve this answer









    $endgroup$


















      1












      $begingroup$

      Use that $$A=frac{1}{2}absin(gamma)$$ etc






      share|cite|improve this answer









      $endgroup$
















        1












        1








        1





        $begingroup$

        Use that $$A=frac{1}{2}absin(gamma)$$ etc






        share|cite|improve this answer









        $endgroup$



        Use that $$A=frac{1}{2}absin(gamma)$$ etc







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 17 at 17:19









        Dr. Sonnhard GraubnerDr. Sonnhard Graubner

        76.3k42866




        76.3k42866























            1












            $begingroup$

            Yes.
            $$A=frac 12absin theta$$






            share|cite|improve this answer









            $endgroup$













            • $begingroup$
              If this doesn't answer the question, I don't know what will. Should I provide more details?
              $endgroup$
              – Mohammad Zuhair Khan
              Jan 17 at 17:40


















            1












            $begingroup$

            Yes.
            $$A=frac 12absin theta$$






            share|cite|improve this answer









            $endgroup$













            • $begingroup$
              If this doesn't answer the question, I don't know what will. Should I provide more details?
              $endgroup$
              – Mohammad Zuhair Khan
              Jan 17 at 17:40
















            1












            1








            1





            $begingroup$

            Yes.
            $$A=frac 12absin theta$$






            share|cite|improve this answer









            $endgroup$



            Yes.
            $$A=frac 12absin theta$$







            share|cite|improve this answer












            share|cite|improve this answer



            share|cite|improve this answer










            answered Jan 17 at 17:19









            Mohammad Zuhair KhanMohammad Zuhair Khan

            1,5852625




            1,5852625












            • $begingroup$
              If this doesn't answer the question, I don't know what will. Should I provide more details?
              $endgroup$
              – Mohammad Zuhair Khan
              Jan 17 at 17:40




















            • $begingroup$
              If this doesn't answer the question, I don't know what will. Should I provide more details?
              $endgroup$
              – Mohammad Zuhair Khan
              Jan 17 at 17:40


















            $begingroup$
            If this doesn't answer the question, I don't know what will. Should I provide more details?
            $endgroup$
            – Mohammad Zuhair Khan
            Jan 17 at 17:40






            $begingroup$
            If this doesn't answer the question, I don't know what will. Should I provide more details?
            $endgroup$
            – Mohammad Zuhair Khan
            Jan 17 at 17:40




















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