Mixing
Could someone explain how it is done.
0
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enter image description here
I know that you may start by saying that the given integral is going to be equal to $frac{2n-1}{2n} cdot int_0^{frac{pi}{2}}cos^{2n-2}(theta) dtheta$. but after that I do not know what to do.
calculus
edited Jan 17 at 21:59
user289143
1,000313
asked Jan 17 at 21:00
Konstantin UvarovKonstantin Uvarov
41
$endgroup$
add a comment |
0
$begingroup$
enter image description here
I know that you may start by saying that the given integral is going to be equal to $frac{2n-1}{2n} cdot int_0^{frac{pi}{2}}cos^{2n-2}(theta) dtheta$. but after that I do not know what to do.
calculus
edited Jan 17 at 21:59
user289143
1,000313
asked Jan 17 at 21:00
Konstantin UvarovKonstantin Uvarov
41
$endgroup$
2
$begingroup$
See reduction formulae. Integration by parts facilitates the derivation of the formula you need here.
$endgroup$
– Mark Viola
Jan 17 at 21:05
1
$begingroup$
Also, these are Wallis's integrals
$endgroup$
– Picaud Vincent
Jan 17 at 21:11
$begingroup$
Possible duplicate of Prove that problem ASAP
$endgroup$
– John Douma
Jan 17 at 21:26
add a comment |
0
0
0
$begingroup$
enter image description here
I know that you may start by saying that the given integral is going to be equal to $frac{2n-1}{2n} cdot int_0^{frac{pi}{2}}cos^{2n-2}(theta) dtheta$. but after that I do not know what to do.
calculus
edited Jan 17 at 21:59
user289143
1,000313
asked Jan 17 at 21:00
Konstantin UvarovKonstantin Uvarov
41
$endgroup$
enter image description here
I know that you may start by saying that the given integral is going to be equal to $frac{2n-1}{2n} cdot int_0^{frac{pi}{2}}cos^{2n-2}(theta) dtheta$. but after that I do not know what to do.
calculus
calculus
edited Jan 17 at 21:59
user289143
1,000313
asked Jan 17 at 21:00
Konstantin UvarovKonstantin Uvarov
41
edited Jan 17 at 21:59
user289143
1,000313
asked Jan 17 at 21:00
Konstantin UvarovKonstantin Uvarov
41
edited Jan 17 at 21:59
user289143
1,000313
edited Jan 17 at 21:59
user289143
1,000313
edited Jan 17 at 21:59
user289143
1,000313
1,000313
asked Jan 17 at 21:00
Konstantin UvarovKonstantin Uvarov
41
asked Jan 17 at 21:00
Konstantin UvarovKonstantin Uvarov
41
asked Jan 17 at 21:00
Konstantin UvarovKonstantin Uvarov
41
41
2
$begingroup$
See reduction formulae. Integration by parts facilitates the derivation of the formula you need here.
$endgroup$
– Mark Viola
Jan 17 at 21:05
1
$begingroup$
Also, these are Wallis's integrals
$endgroup$
– Picaud Vincent
Jan 17 at 21:11
$begingroup$
Possible duplicate of Prove that problem ASAP
$endgroup$
– John Douma
Jan 17 at 21:26
add a comment |
2
$begingroup$
See reduction formulae. Integration by parts facilitates the derivation of the formula you need here.
$endgroup$
– Mark Viola
Jan 17 at 21:05
1
$begingroup$
Also, these are Wallis's integrals
$endgroup$
– Picaud Vincent
Jan 17 at 21:11
$begingroup$
Possible duplicate of Prove that problem ASAP
$endgroup$
– John Douma
Jan 17 at 21:26
2
2
$begingroup$
See reduction formulae. Integration by parts facilitates the derivation of the formula you need here.
$endgroup$
– Mark Viola
Jan 17 at 21:05
$begingroup$
See reduction formulae. Integration by parts facilitates the derivation of the formula you need here.
$endgroup$
– Mark Viola
Jan 17 at 21:05
1
1
$begingroup$
Also, these are Wallis's integrals
$endgroup$
– Picaud Vincent
Jan 17 at 21:11
$begingroup$
Also, these are Wallis's integrals
$endgroup$
– Picaud Vincent
Jan 17 at 21:11
$begingroup$
Possible duplicate of Prove that problem ASAP
$endgroup$
– John Douma
Jan 17 at 21:26
$begingroup$
Possible duplicate of Prove that problem ASAP
$endgroup$
– John Douma
Jan 17 at 21:26
add a comment |
0
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2
$begingroup$
See reduction formulae. Integration by parts facilitates the derivation of the formula you need here.
$endgroup$
– Mark Viola
Jan 17 at 21:05
1
$begingroup$
Also, these are Wallis's integrals
$endgroup$
– Picaud Vincent
Jan 17 at 21:11
$begingroup$
Possible duplicate of Prove that problem ASAP
$endgroup$
– John Douma
Jan 17 at 21:26