Convergence related to normal cdf












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Consider the following problem:



For each $x>0$, let $yinmathbb R$ solve the equation
$$int_y^{y+x}[Phi(z)-r]dz=0,$$
where $rin (0,1)$, and $Phi(cdot)$ is the normal cdf. We can show that for each $x>0$ there is a unique $y$ satisfying the equation, and so this defines a function $y(x)$. Moreover, we can show that
$$lim_{xto+infty}frac{y(x)}{x}=-(1-r).$$
The question is: Can we show that $y(x)+(1-r)xto 0$ as $xto +infty$? In fact, I think we can show that $y(x)+(1-r)x$ is convergent. But I am not sure whether the limit is $0$.



Any hints or suggestions on this will be highly appreciated!










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    Consider the following problem:



    For each $x>0$, let $yinmathbb R$ solve the equation
    $$int_y^{y+x}[Phi(z)-r]dz=0,$$
    where $rin (0,1)$, and $Phi(cdot)$ is the normal cdf. We can show that for each $x>0$ there is a unique $y$ satisfying the equation, and so this defines a function $y(x)$. Moreover, we can show that
    $$lim_{xto+infty}frac{y(x)}{x}=-(1-r).$$
    The question is: Can we show that $y(x)+(1-r)xto 0$ as $xto +infty$? In fact, I think we can show that $y(x)+(1-r)x$ is convergent. But I am not sure whether the limit is $0$.



    Any hints or suggestions on this will be highly appreciated!










    share|cite|improve this question

























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      0








      0


      2





      Consider the following problem:



      For each $x>0$, let $yinmathbb R$ solve the equation
      $$int_y^{y+x}[Phi(z)-r]dz=0,$$
      where $rin (0,1)$, and $Phi(cdot)$ is the normal cdf. We can show that for each $x>0$ there is a unique $y$ satisfying the equation, and so this defines a function $y(x)$. Moreover, we can show that
      $$lim_{xto+infty}frac{y(x)}{x}=-(1-r).$$
      The question is: Can we show that $y(x)+(1-r)xto 0$ as $xto +infty$? In fact, I think we can show that $y(x)+(1-r)x$ is convergent. But I am not sure whether the limit is $0$.



      Any hints or suggestions on this will be highly appreciated!










      share|cite|improve this question













      Consider the following problem:



      For each $x>0$, let $yinmathbb R$ solve the equation
      $$int_y^{y+x}[Phi(z)-r]dz=0,$$
      where $rin (0,1)$, and $Phi(cdot)$ is the normal cdf. We can show that for each $x>0$ there is a unique $y$ satisfying the equation, and so this defines a function $y(x)$. Moreover, we can show that
      $$lim_{xto+infty}frac{y(x)}{x}=-(1-r).$$
      The question is: Can we show that $y(x)+(1-r)xto 0$ as $xto +infty$? In fact, I think we can show that $y(x)+(1-r)x$ is convergent. But I am not sure whether the limit is $0$.



      Any hints or suggestions on this will be highly appreciated!







      calculus real-analysis probability normal-distribution






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      asked Nov 20 '18 at 10:12









      user146512

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