Mixing
Probability under Uncertainity
$begingroup$
Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.
Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$
What could be the probability of event $B$ occurring given that event $W$ is uncertain?.
In short, $P(B = 1|overline{W})$ = ?
probability
asked Jan 12 at 17:28
HarshilHarshil
1034
$endgroup$
add a comment |
$begingroup$
Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.
Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$
What could be the probability of event $B$ occurring given that event $W$ is uncertain?.
In short, $P(B = 1|overline{W})$ = ?
probability
asked Jan 12 at 17:28
HarshilHarshil
1034
$endgroup$
$begingroup$
What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
$endgroup$
– LoveTooNap29
Jan 12 at 17:42
$begingroup$
@LoveTooNap29 You are right! I am scratching my head around this for many hours!
$endgroup$
– Harshil
Jan 12 at 17:50
$begingroup$
Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
$endgroup$
– zoli
Jan 12 at 17:53
$begingroup$
@zoli Description I posted above is identical to the original text! I am also confused with that!
$endgroup$
– Harshil
Jan 13 at 16:00
add a comment |
$begingroup$
Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.
Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$
What could be the probability of event $B$ occurring given that event $W$ is uncertain?.
In short, $P(B = 1|overline{W})$ = ?
probability
asked Jan 12 at 17:28
HarshilHarshil
1034
$endgroup$
Consider $B$, $W in E(Omega)$ be two events in an event space $E(Omega)$ where the occurrence of event $W$ uncertain. Let this uncertainty of $W$ be denoted as $overline{W}$.
Possible outcomes of both the events are: $B = {1}$ and $W = {0, 1}$
What could be the probability of event $B$ occurring given that event $W$ is uncertain?.
In short, $P(B = 1|overline{W})$ = ?
probability
probability
asked Jan 12 at 17:28
HarshilHarshil
1034
asked Jan 12 at 17:28
HarshilHarshil
1034
asked Jan 12 at 17:28
HarshilHarshil
1034
asked Jan 12 at 17:28
HarshilHarshil
1034
asked Jan 12 at 17:28
HarshilHarshil
1034
1034
$begingroup$
What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
$endgroup$
– LoveTooNap29
Jan 12 at 17:42
$begingroup$
@LoveTooNap29 You are right! I am scratching my head around this for many hours!
$endgroup$
– Harshil
Jan 12 at 17:50
$begingroup$
Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
$endgroup$
– zoli
Jan 12 at 17:53
$begingroup$
@zoli Description I posted above is identical to the original text! I am also confused with that!
$endgroup$
– Harshil
Jan 13 at 16:00
add a comment |
$begingroup$
What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
$endgroup$
– LoveTooNap29
Jan 12 at 17:42
$begingroup$
@LoveTooNap29 You are right! I am scratching my head around this for many hours!
$endgroup$
– Harshil
Jan 12 at 17:50
$begingroup$
Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
$endgroup$
– zoli
Jan 12 at 17:53
$begingroup$
@zoli Description I posted above is identical to the original text! I am also confused with that!
$endgroup$
– Harshil
Jan 13 at 16:00
$begingroup$
What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
$endgroup$
– LoveTooNap29
Jan 12 at 17:42
$begingroup$
What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
$endgroup$
– LoveTooNap29
Jan 12 at 17:42
$begingroup$
@LoveTooNap29 You are right! I am scratching my head around this for many hours!
$endgroup$
– Harshil
Jan 12 at 17:50
$begingroup$
@LoveTooNap29 You are right! I am scratching my head around this for many hours!
$endgroup$
– Harshil
Jan 12 at 17:50
$begingroup$
Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
$endgroup$
– zoli
Jan 12 at 17:53
$begingroup$
Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
$endgroup$
– zoli
Jan 12 at 17:53
$begingroup$
@zoli Description I posted above is identical to the original text! I am also confused with that!
$endgroup$
– Harshil
Jan 13 at 16:00
$begingroup$
@zoli Description I posted above is identical to the original text! I am also confused with that!
$endgroup$
– Harshil
Jan 13 at 16:00
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3071148%2fprobability-under-uncertainity%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3071148%2fprobability-under-uncertainity%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
What a strange question. Since the uncertainty of $W$ doesn’t seem to be an event, as far as I can infer, the expression $P(B=1| bar{W})$ is meaningless. Basic conditional probability conditions on events.
$endgroup$
– LoveTooNap29
Jan 12 at 17:42
$begingroup$
@LoveTooNap29 You are right! I am scratching my head around this for many hours!
$endgroup$
– Harshil
Jan 12 at 17:50
$begingroup$
Is your description identical to the original text? If not could you paste here the original version. (As otheres noted above, your version is confusing -- sorry to say that.)
$endgroup$
– zoli
Jan 12 at 17:53
$begingroup$
@zoli Description I posted above is identical to the original text! I am also confused with that!
$endgroup$
– Harshil
Jan 13 at 16:00