How to create URL for Logout action in WebApi












0















I am using Visual Studio 2017..... when I created the project, an AccountController was created with this action:



    // POST api/Account/Logout
[Route("Logout")]
public IHttpActionResult Logout()
{
Authentication.SignOut(CookieAuthenticationDefaults.AuthenticationType);
return Ok();
}


On the other hand, this route was created by default:



        config.Routes.MapHttpRoute(
name: "DefaultApi",
routeTemplate: "api/{controller}/{id}",
defaults: new { id = RouteParameter.Optional }
);


I need to do a very simple thing. How can I get the Logout URL in a view?



I tried



@Url.Action("Logout", "Account", new { httproute = "DefaultApi" })


But it did not work since DefaultApi does not contain the action, causing the action to be added as a query string parameter.



If I don't use httproute property, the URL is built but without the "api" part causing the framework to not find it.



I have even tried



@Url.RouteUrl("DefaultApi", new { httproute = "Logout", controller = "Account" })">


with no success either.










share|improve this question

























  • How about using @Url.HttpRouteUrl()? I see that you're not tried this helper before, see related issue here: stackoverflow.com/questions/19868148/…. Also make sure that the routes are in proper order.

    – Tetsuya Yamamoto
    Nov 21 '18 at 1:41


















0















I am using Visual Studio 2017..... when I created the project, an AccountController was created with this action:



    // POST api/Account/Logout
[Route("Logout")]
public IHttpActionResult Logout()
{
Authentication.SignOut(CookieAuthenticationDefaults.AuthenticationType);
return Ok();
}


On the other hand, this route was created by default:



        config.Routes.MapHttpRoute(
name: "DefaultApi",
routeTemplate: "api/{controller}/{id}",
defaults: new { id = RouteParameter.Optional }
);


I need to do a very simple thing. How can I get the Logout URL in a view?



I tried



@Url.Action("Logout", "Account", new { httproute = "DefaultApi" })


But it did not work since DefaultApi does not contain the action, causing the action to be added as a query string parameter.



If I don't use httproute property, the URL is built but without the "api" part causing the framework to not find it.



I have even tried



@Url.RouteUrl("DefaultApi", new { httproute = "Logout", controller = "Account" })">


with no success either.










share|improve this question

























  • How about using @Url.HttpRouteUrl()? I see that you're not tried this helper before, see related issue here: stackoverflow.com/questions/19868148/…. Also make sure that the routes are in proper order.

    – Tetsuya Yamamoto
    Nov 21 '18 at 1:41
















0












0








0


0






I am using Visual Studio 2017..... when I created the project, an AccountController was created with this action:



    // POST api/Account/Logout
[Route("Logout")]
public IHttpActionResult Logout()
{
Authentication.SignOut(CookieAuthenticationDefaults.AuthenticationType);
return Ok();
}


On the other hand, this route was created by default:



        config.Routes.MapHttpRoute(
name: "DefaultApi",
routeTemplate: "api/{controller}/{id}",
defaults: new { id = RouteParameter.Optional }
);


I need to do a very simple thing. How can I get the Logout URL in a view?



I tried



@Url.Action("Logout", "Account", new { httproute = "DefaultApi" })


But it did not work since DefaultApi does not contain the action, causing the action to be added as a query string parameter.



If I don't use httproute property, the URL is built but without the "api" part causing the framework to not find it.



I have even tried



@Url.RouteUrl("DefaultApi", new { httproute = "Logout", controller = "Account" })">


with no success either.










share|improve this question
















I am using Visual Studio 2017..... when I created the project, an AccountController was created with this action:



    // POST api/Account/Logout
[Route("Logout")]
public IHttpActionResult Logout()
{
Authentication.SignOut(CookieAuthenticationDefaults.AuthenticationType);
return Ok();
}


On the other hand, this route was created by default:



        config.Routes.MapHttpRoute(
name: "DefaultApi",
routeTemplate: "api/{controller}/{id}",
defaults: new { id = RouteParameter.Optional }
);


I need to do a very simple thing. How can I get the Logout URL in a view?



I tried



@Url.Action("Logout", "Account", new { httproute = "DefaultApi" })


But it did not work since DefaultApi does not contain the action, causing the action to be added as a query string parameter.



If I don't use httproute property, the URL is built but without the "api" part causing the framework to not find it.



I have even tried



@Url.RouteUrl("DefaultApi", new { httproute = "Logout", controller = "Account" })">


with no success either.







asp.net-mvc asp.net-web-api routes






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 0:39







jstuardo

















asked Nov 21 '18 at 0:31









jstuardojstuardo

99452862




99452862













  • How about using @Url.HttpRouteUrl()? I see that you're not tried this helper before, see related issue here: stackoverflow.com/questions/19868148/…. Also make sure that the routes are in proper order.

    – Tetsuya Yamamoto
    Nov 21 '18 at 1:41





















  • How about using @Url.HttpRouteUrl()? I see that you're not tried this helper before, see related issue here: stackoverflow.com/questions/19868148/…. Also make sure that the routes are in proper order.

    – Tetsuya Yamamoto
    Nov 21 '18 at 1:41



















How about using @Url.HttpRouteUrl()? I see that you're not tried this helper before, see related issue here: stackoverflow.com/questions/19868148/…. Also make sure that the routes are in proper order.

– Tetsuya Yamamoto
Nov 21 '18 at 1:41







How about using @Url.HttpRouteUrl()? I see that you're not tried this helper before, see related issue here: stackoverflow.com/questions/19868148/…. Also make sure that the routes are in proper order.

– Tetsuya Yamamoto
Nov 21 '18 at 1:41














1 Answer
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oldest

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You can define a new route to define your action name:



routes.MapHttpRoute(
name: "ActionApi",
routeTemplate: "api/{controller}/{action}/{id}",
defaults: new { id = RouteParameter.Optional }
);


If you don't include the action name, Web API tries to find a suitable action for you based on your HTTP verb... for example if you send a Get request Web API tries to find an action starting with 'Get'... since your action name is Logout, the default API routing convention cannot match it to a request. see here for more info



Then this link should call the action (see here):



@Url.HttpRouteUrl("ActionApi", new {controller = "Account", action = "Logout"})





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    You can define a new route to define your action name:



    routes.MapHttpRoute(
    name: "ActionApi",
    routeTemplate: "api/{controller}/{action}/{id}",
    defaults: new { id = RouteParameter.Optional }
    );


    If you don't include the action name, Web API tries to find a suitable action for you based on your HTTP verb... for example if you send a Get request Web API tries to find an action starting with 'Get'... since your action name is Logout, the default API routing convention cannot match it to a request. see here for more info



    Then this link should call the action (see here):



    @Url.HttpRouteUrl("ActionApi", new {controller = "Account", action = "Logout"})





    share|improve this answer






























      0














      You can define a new route to define your action name:



      routes.MapHttpRoute(
      name: "ActionApi",
      routeTemplate: "api/{controller}/{action}/{id}",
      defaults: new { id = RouteParameter.Optional }
      );


      If you don't include the action name, Web API tries to find a suitable action for you based on your HTTP verb... for example if you send a Get request Web API tries to find an action starting with 'Get'... since your action name is Logout, the default API routing convention cannot match it to a request. see here for more info



      Then this link should call the action (see here):



      @Url.HttpRouteUrl("ActionApi", new {controller = "Account", action = "Logout"})





      share|improve this answer




























        0












        0








        0







        You can define a new route to define your action name:



        routes.MapHttpRoute(
        name: "ActionApi",
        routeTemplate: "api/{controller}/{action}/{id}",
        defaults: new { id = RouteParameter.Optional }
        );


        If you don't include the action name, Web API tries to find a suitable action for you based on your HTTP verb... for example if you send a Get request Web API tries to find an action starting with 'Get'... since your action name is Logout, the default API routing convention cannot match it to a request. see here for more info



        Then this link should call the action (see here):



        @Url.HttpRouteUrl("ActionApi", new {controller = "Account", action = "Logout"})





        share|improve this answer















        You can define a new route to define your action name:



        routes.MapHttpRoute(
        name: "ActionApi",
        routeTemplate: "api/{controller}/{action}/{id}",
        defaults: new { id = RouteParameter.Optional }
        );


        If you don't include the action name, Web API tries to find a suitable action for you based on your HTTP verb... for example if you send a Get request Web API tries to find an action starting with 'Get'... since your action name is Logout, the default API routing convention cannot match it to a request. see here for more info



        Then this link should call the action (see here):



        @Url.HttpRouteUrl("ActionApi", new {controller = "Account", action = "Logout"})






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 21 '18 at 4:16

























        answered Nov 21 '18 at 3:42









        Hooman BahreiniHooman Bahreini

        3,4113731




        3,4113731






























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