Mixing
In topology,Find all points of the set B={(-2,-2),(1,1),(0,-1),(0,3)}, which are contained in the closed ball...
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Find all points of the set B={(-2,-2),(1,1),(0,-1),(0,3)}, which are contained in the closed ball B((0,0),2) in the metric space (R^2,d1),where d1 is defined by the formula
d1((x1,y1),(x2,y2))=|x1-x2|+|y1-y2|.
Does anybody clearly explain and solve by formally ?
Many thanks!
general-topology
asked Jan 9 at 16:23
Arda Batuhan DemirArda Batuhan Demir
11
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add a comment |
$begingroup$
Find all points of the set B={(-2,-2),(1,1),(0,-1),(0,3)}, which are contained in the closed ball B((0,0),2) in the metric space (R^2,d1),where d1 is defined by the formula
d1((x1,y1),(x2,y2))=|x1-x2|+|y1-y2|.
Does anybody clearly explain and solve by formally ?
Many thanks!
general-topology
asked Jan 9 at 16:23
Arda Batuhan DemirArda Batuhan Demir
11
$endgroup$
add a comment |
$begingroup$
Find all points of the set B={(-2,-2),(1,1),(0,-1),(0,3)}, which are contained in the closed ball B((0,0),2) in the metric space (R^2,d1),where d1 is defined by the formula
d1((x1,y1),(x2,y2))=|x1-x2|+|y1-y2|.
Does anybody clearly explain and solve by formally ?
Many thanks!
general-topology
asked Jan 9 at 16:23
Arda Batuhan DemirArda Batuhan Demir
11
$endgroup$
Find all points of the set B={(-2,-2),(1,1),(0,-1),(0,3)}, which are contained in the closed ball B((0,0),2) in the metric space (R^2,d1),where d1 is defined by the formula
d1((x1,y1),(x2,y2))=|x1-x2|+|y1-y2|.
Does anybody clearly explain and solve by formally ?
Many thanks!
general-topology
general-topology
asked Jan 9 at 16:23
Arda Batuhan DemirArda Batuhan Demir
11
asked Jan 9 at 16:23
Arda Batuhan DemirArda Batuhan Demir
11
edited Jan 11 at 15:48
Arda Batuhan Demir
asked Jan 9 at 16:23
Arda Batuhan DemirArda Batuhan Demir
11
asked Jan 9 at 16:23
Arda Batuhan DemirArda Batuhan Demir
11
asked Jan 9 at 16:23
Arda Batuhan DemirArda Batuhan Demir
11
11
add a comment |
add a comment |
2 Answers
2
active
oldest
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It's pretty straight forward isn't it? You are told that the distance between points (a, b) and (c, d) is |a- c|+ |b- d| so the distance from (0, 0) to (x, y) is |x- 0|+ |y- 0|= |x|- |y|. What is the distance from (0, 0) to (-2, -2)? From (0, 0) to (1, 1)? From (0, 0) to (0, -1)? From (0, 0) to (0, 3)?
answered Jan 9 at 16:58
user247327user247327
11k1515
$endgroup$
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 10 at 16:35
$begingroup$
Could you more than explain ? because I couldnt be understand.....Could you solving by formally by step by step ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:50
add a comment |
$begingroup$
By definition you can check that only $(0,-1)$ has distance less than $2$ from the origin.
edited Jan 9 at 17:20
amWhy
1
answered Jan 9 at 16:28
CHOUDHARY bhim senCHOUDHARY bhim sen
1239
$endgroup$
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 9 at 18:41
$begingroup$
Could you more than detail and solving by formally ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:49
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
It's pretty straight forward isn't it? You are told that the distance between points (a, b) and (c, d) is |a- c|+ |b- d| so the distance from (0, 0) to (x, y) is |x- 0|+ |y- 0|= |x|- |y|. What is the distance from (0, 0) to (-2, -2)? From (0, 0) to (1, 1)? From (0, 0) to (0, -1)? From (0, 0) to (0, 3)?
answered Jan 9 at 16:58
user247327user247327
11k1515
$endgroup$
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 10 at 16:35
$begingroup$
Could you more than explain ? because I couldnt be understand.....Could you solving by formally by step by step ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:50
add a comment |
$begingroup$
It's pretty straight forward isn't it? You are told that the distance between points (a, b) and (c, d) is |a- c|+ |b- d| so the distance from (0, 0) to (x, y) is |x- 0|+ |y- 0|= |x|- |y|. What is the distance from (0, 0) to (-2, -2)? From (0, 0) to (1, 1)? From (0, 0) to (0, -1)? From (0, 0) to (0, 3)?
answered Jan 9 at 16:58
user247327user247327
11k1515
$endgroup$
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 10 at 16:35
$begingroup$
Could you more than explain ? because I couldnt be understand.....Could you solving by formally by step by step ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:50
add a comment |
$begingroup$
It's pretty straight forward isn't it? You are told that the distance between points (a, b) and (c, d) is |a- c|+ |b- d| so the distance from (0, 0) to (x, y) is |x- 0|+ |y- 0|= |x|- |y|. What is the distance from (0, 0) to (-2, -2)? From (0, 0) to (1, 1)? From (0, 0) to (0, -1)? From (0, 0) to (0, 3)?
answered Jan 9 at 16:58
user247327user247327
11k1515
$endgroup$
It's pretty straight forward isn't it? You are told that the distance between points (a, b) and (c, d) is |a- c|+ |b- d| so the distance from (0, 0) to (x, y) is |x- 0|+ |y- 0|= |x|- |y|. What is the distance from (0, 0) to (-2, -2)? From (0, 0) to (1, 1)? From (0, 0) to (0, -1)? From (0, 0) to (0, 3)?
answered Jan 9 at 16:58
user247327user247327
11k1515
answered Jan 9 at 16:58
user247327user247327
11k1515
answered Jan 9 at 16:58
user247327user247327
11k1515
answered Jan 9 at 16:58
user247327user247327
11k1515
11k1515
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 10 at 16:35
$begingroup$
Could you more than explain ? because I couldnt be understand.....Could you solving by formally by step by step ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:50
add a comment |
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 10 at 16:35
$begingroup$
Could you more than explain ? because I couldnt be understand.....Could you solving by formally by step by step ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:50
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 10 at 16:35
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 10 at 16:35
$begingroup$
Could you more than explain ? because I couldnt be understand.....Could you solving by formally by step by step ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:50
$begingroup$
Could you more than explain ? because I couldnt be understand.....Could you solving by formally by step by step ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:50
add a comment |
$begingroup$
By definition you can check that only $(0,-1)$ has distance less than $2$ from the origin.
edited Jan 9 at 17:20
amWhy
1
answered Jan 9 at 16:28
CHOUDHARY bhim senCHOUDHARY bhim sen
1239
$endgroup$
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 9 at 18:41
$begingroup$
Could you more than detail and solving by formally ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:49
add a comment |
$begingroup$
By definition you can check that only $(0,-1)$ has distance less than $2$ from the origin.
edited Jan 9 at 17:20
amWhy
1
answered Jan 9 at 16:28
CHOUDHARY bhim senCHOUDHARY bhim sen
1239
$endgroup$
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 9 at 18:41
$begingroup$
Could you more than detail and solving by formally ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:49
add a comment |
$begingroup$
By definition you can check that only $(0,-1)$ has distance less than $2$ from the origin.
edited Jan 9 at 17:20
amWhy
1
answered Jan 9 at 16:28
CHOUDHARY bhim senCHOUDHARY bhim sen
1239
$endgroup$
By definition you can check that only $(0,-1)$ has distance less than $2$ from the origin.
edited Jan 9 at 17:20
amWhy
1
answered Jan 9 at 16:28
CHOUDHARY bhim senCHOUDHARY bhim sen
1239
edited Jan 9 at 17:20
amWhy
1
edited Jan 9 at 17:20
amWhy
1
edited Jan 9 at 17:20
amWhy
1
1
answered Jan 9 at 16:28
CHOUDHARY bhim senCHOUDHARY bhim sen
1239
answered Jan 9 at 16:28
CHOUDHARY bhim senCHOUDHARY bhim sen
1239
answered Jan 9 at 16:28
CHOUDHARY bhim senCHOUDHARY bhim sen
1239
1239
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 9 at 18:41
$begingroup$
Could you more than detail and solving by formally ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:49
add a comment |
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 9 at 18:41
$begingroup$
Could you more than detail and solving by formally ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:49
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 9 at 18:41
$begingroup$
Could you draw and more then detailed to solving, please ?
$endgroup$
– Arda Batuhan Demir
Jan 9 at 18:41
$begingroup$
Could you more than detail and solving by formally ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:49
$begingroup$
Could you more than detail and solving by formally ? Many thanks...
$endgroup$
– Arda Batuhan Demir
Jan 11 at 15:49
add a comment |
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