Using MOD in Pascal
I'm just starting coding and programming and white trying to complete an exercise I noted that the MOD operation doesn't work with variables.
Can someone explain to me why? And also give me some tips on how to do it? Thank you.
program Stack_Overflow;
var
sec, hour, day: real;
begin
WriteLn('Insert a number of seconds.');
ReadLn (sec);
hour := sec div 3600;
writeln (hour);
readln;
end.
pascal
|
show 14 more comments
I'm just starting coding and programming and white trying to complete an exercise I noted that the MOD operation doesn't work with variables.
Can someone explain to me why? And also give me some tips on how to do it? Thank you.
program Stack_Overflow;
var
sec, hour, day: real;
begin
WriteLn('Insert a number of seconds.');
ReadLn (sec);
hour := sec div 3600;
writeln (hour);
readln;
end.
pascal
1
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
3
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
2
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12
|
show 14 more comments
I'm just starting coding and programming and white trying to complete an exercise I noted that the MOD operation doesn't work with variables.
Can someone explain to me why? And also give me some tips on how to do it? Thank you.
program Stack_Overflow;
var
sec, hour, day: real;
begin
WriteLn('Insert a number of seconds.');
ReadLn (sec);
hour := sec div 3600;
writeln (hour);
readln;
end.
pascal
I'm just starting coding and programming and white trying to complete an exercise I noted that the MOD operation doesn't work with variables.
Can someone explain to me why? And also give me some tips on how to do it? Thank you.
program Stack_Overflow;
var
sec, hour, day: real;
begin
WriteLn('Insert a number of seconds.');
ReadLn (sec);
hour := sec div 3600;
writeln (hour);
readln;
end.
pascal
pascal
edited Nov 12 '18 at 17:35
MartynA
20.4k32154
20.4k32154
asked Nov 12 '18 at 16:56
Sebastião AssunçãoSebastião Assunção
12
12
1
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
3
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
2
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12
|
show 14 more comments
1
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
3
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
2
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12
1
1
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
3
3
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
2
2
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12
|
show 14 more comments
2 Answers
2
active
oldest
votes
DIV
and MOD
operators works only on integers, not on floating point numbers.
Just declare:
var
sec, hour, day: integer;
and you are good to go.
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
add a comment |
MOD is well defined for integers only but there are not meant for real. MOD gives you the remainder of integer division a / b , but real division doesn't have remainders.Instead if you want to find the remainder of a real number you can create your own MOD fuction.
//You can either code it as a fuction so its reusability.
Remainder:=Trunc(sec/3600) ; truncate removes the decimal part ang gives you the integer part.This like MOD.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
DIV
and MOD
operators works only on integers, not on floating point numbers.
Just declare:
var
sec, hour, day: integer;
and you are good to go.
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
add a comment |
DIV
and MOD
operators works only on integers, not on floating point numbers.
Just declare:
var
sec, hour, day: integer;
and you are good to go.
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
add a comment |
DIV
and MOD
operators works only on integers, not on floating point numbers.
Just declare:
var
sec, hour, day: integer;
and you are good to go.
DIV
and MOD
operators works only on integers, not on floating point numbers.
Just declare:
var
sec, hour, day: integer;
and you are good to go.
answered Nov 12 '18 at 18:12
LU RDLU RD
28.4k559179
28.4k559179
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
add a comment |
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
Well yes, as far as one can go with ZIM. <g> +1.
– Rudy Velthuis
Nov 12 '18 at 18:13
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
@RudyVelthuis, can't be worse than punching cards for the univac, where I started learning programming.
– LU RD
Nov 12 '18 at 18:29
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
You had cards? Luxury! We had to wire the hardware directly. etc...
– Rudy Velthuis
Nov 13 '18 at 1:05
add a comment |
MOD is well defined for integers only but there are not meant for real. MOD gives you the remainder of integer division a / b , but real division doesn't have remainders.Instead if you want to find the remainder of a real number you can create your own MOD fuction.
//You can either code it as a fuction so its reusability.
Remainder:=Trunc(sec/3600) ; truncate removes the decimal part ang gives you the integer part.This like MOD.
add a comment |
MOD is well defined for integers only but there are not meant for real. MOD gives you the remainder of integer division a / b , but real division doesn't have remainders.Instead if you want to find the remainder of a real number you can create your own MOD fuction.
//You can either code it as a fuction so its reusability.
Remainder:=Trunc(sec/3600) ; truncate removes the decimal part ang gives you the integer part.This like MOD.
add a comment |
MOD is well defined for integers only but there are not meant for real. MOD gives you the remainder of integer division a / b , but real division doesn't have remainders.Instead if you want to find the remainder of a real number you can create your own MOD fuction.
//You can either code it as a fuction so its reusability.
Remainder:=Trunc(sec/3600) ; truncate removes the decimal part ang gives you the integer part.This like MOD.
MOD is well defined for integers only but there are not meant for real. MOD gives you the remainder of integer division a / b , but real division doesn't have remainders.Instead if you want to find the remainder of a real number you can create your own MOD fuction.
//You can either code it as a fuction so its reusability.
Remainder:=Trunc(sec/3600) ; truncate removes the decimal part ang gives you the integer part.This like MOD.
answered Nov 21 '18 at 0:37
lasal22lasal22
11
11
add a comment |
add a comment |
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1
Please add an expample to help us to help you
– Nifriz
Nov 12 '18 at 16:59
3
MOD certainly does work with variables. Could you show us your code?
– David Dubois
Nov 12 '18 at 16:59
I'm not level 10 in reputation so i can't post photos.
– Sebastião Assunção
Nov 12 '18 at 17:04
But basically I asked the user to provide a number of seconds and then i did hours:= sec mod 600. And it didn't work
– Sebastião Assunção
Nov 12 '18 at 17:05
2
It's good that you can't post photos, because we want the code as text, not as a screenshot. Please post a Minimal, Complete, and Verifiable example and the error message that you get when you try to run the code.
– JJJ
Nov 12 '18 at 17:12