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How to create a zip file where a file name starts with a dot
I have a situation where I am trying to create a zip file from the command line, but I am trying to add a file which starts with a dot.
powershell Compress-Archive -Path .Dist._test.txt -DestinationPath .test
But this gives an error Could not find item Dist._test.txt
How can I get this powershell command to include files named this way?
windows powershell compress-archive
asked Nov 20 '18 at 23:17
fotgfotg
3411620
add a comment |
I have a situation where I am trying to create a zip file from the command line, but I am trying to add a file which starts with a dot.
powershell Compress-Archive -Path .Dist._test.txt -DestinationPath .test
But this gives an error Could not find item Dist._test.txt
How can I get this powershell command to include files named this way?
windows powershell compress-archive
asked Nov 20 '18 at 23:17
fotgfotg
3411620
1
Quote and use-LiteralPath
– LotPings
Nov 20 '18 at 23:28
@LotPings Don't you need a full path to use-LiteralPath? Do they need to do-LiteralPath $(resolve-path .Dist._test.txt).Path?
– TheMadTechnician
Nov 21 '18 at 0:08
1
@TheMadTechnician I did test with a file in current folder and that worked.Compress-Archive -Destin .test.zip -Literalpath ".lnk"
– LotPings
Nov 21 '18 at 0:55
2
@TheMadTechnician:-LiteralPathjust means that that no wildcard resolution is applied to the argument, but it can still be a relative path.
– mklement0
Nov 21 '18 at 2:39
add a comment |
I have a situation where I am trying to create a zip file from the command line, but I am trying to add a file which starts with a dot.
powershell Compress-Archive -Path .Dist._test.txt -DestinationPath .test
But this gives an error Could not find item Dist._test.txt
How can I get this powershell command to include files named this way?
windows powershell compress-archive
asked Nov 20 '18 at 23:17
fotgfotg
3411620
I have a situation where I am trying to create a zip file from the command line, but I am trying to add a file which starts with a dot.
powershell Compress-Archive -Path .Dist._test.txt -DestinationPath .test
But this gives an error Could not find item Dist._test.txt
How can I get this powershell command to include files named this way?
windows powershell compress-archive
windows powershell compress-archive
asked Nov 20 '18 at 23:17
fotgfotg
3411620
asked Nov 20 '18 at 23:17
fotgfotg
3411620
asked Nov 20 '18 at 23:17
fotgfotg
3411620
asked Nov 20 '18 at 23:17
fotgfotg
3411620
asked Nov 20 '18 at 23:17
fotgfotg
3411620
3411620
1
Quote and use-LiteralPath
– LotPings
Nov 20 '18 at 23:28
@LotPings Don't you need a full path to use-LiteralPath? Do they need to do-LiteralPath $(resolve-path .Dist._test.txt).Path?
– TheMadTechnician
Nov 21 '18 at 0:08
1
@TheMadTechnician I did test with a file in current folder and that worked.Compress-Archive -Destin .test.zip -Literalpath ".lnk"
– LotPings
Nov 21 '18 at 0:55
2
@TheMadTechnician:-LiteralPathjust means that that no wildcard resolution is applied to the argument, but it can still be a relative path.
– mklement0
Nov 21 '18 at 2:39
add a comment |
1
Quote and use-LiteralPath
– LotPings
Nov 20 '18 at 23:28
@LotPings Don't you need a full path to use-LiteralPath? Do they need to do-LiteralPath $(resolve-path .Dist._test.txt).Path?
– TheMadTechnician
Nov 21 '18 at 0:08
1
@TheMadTechnician I did test with a file in current folder and that worked.Compress-Archive -Destin .test.zip -Literalpath ".lnk"
– LotPings
Nov 21 '18 at 0:55
2
@TheMadTechnician:-LiteralPathjust means that that no wildcard resolution is applied to the argument, but it can still be a relative path.
– mklement0
Nov 21 '18 at 2:39
1
1
Quote and use
-LiteralPath– LotPings
Nov 20 '18 at 23:28
Quote and use
-LiteralPath– LotPings
Nov 20 '18 at 23:28
@LotPings Don't you need a full path to use
-LiteralPath? Do they need to do -LiteralPath $(resolve-path .Dist._test.txt).Path?– TheMadTechnician
Nov 21 '18 at 0:08
@LotPings Don't you need a full path to use
-LiteralPath? Do they need to do -LiteralPath $(resolve-path .Dist._test.txt).Path?– TheMadTechnician
Nov 21 '18 at 0:08
1
1
@TheMadTechnician I did test with a file in current folder and that worked.
Compress-Archive -Destin .test.zip -Literalpath ".lnk"– LotPings
Nov 21 '18 at 0:55
@TheMadTechnician I did test with a file in current folder and that worked.
Compress-Archive -Destin .test.zip -Literalpath ".lnk"– LotPings
Nov 21 '18 at 0:55
2
2
@TheMadTechnician:
-LiteralPath just means that that no wildcard resolution is applied to the argument, but it can still be a relative path.– mklement0
Nov 21 '18 at 2:39
@TheMadTechnician:
-LiteralPath just means that that no wildcard resolution is applied to the argument, but it can still be a relative path.– mklement0
Nov 21 '18 at 2:39
add a comment |
2 Answers
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Please can you try like this, i had test the same and its working fine
powershell Compress-Archive -Path "C:location.test.png" -DestinationPath "C:locationdestination"
answered Nov 21 '18 at 12:34
thiyagu selvarajthiyagu selvaraj
413
add a comment |
Explorer was set to show hidden items. For some reason it wasn't giving a visual indicator that this was a hidden file. I removed the checkbox for "Hidden" and it worked fine.
answered Nov 21 '18 at 15:10
fotgfotg
3411620
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Please can you try like this, i had test the same and its working fine
powershell Compress-Archive -Path "C:location.test.png" -DestinationPath "C:locationdestination"
answered Nov 21 '18 at 12:34
thiyagu selvarajthiyagu selvaraj
413
add a comment |
Please can you try like this, i had test the same and its working fine
powershell Compress-Archive -Path "C:location.test.png" -DestinationPath "C:locationdestination"
answered Nov 21 '18 at 12:34
thiyagu selvarajthiyagu selvaraj
413
add a comment |
Please can you try like this, i had test the same and its working fine
powershell Compress-Archive -Path "C:location.test.png" -DestinationPath "C:locationdestination"
answered Nov 21 '18 at 12:34
thiyagu selvarajthiyagu selvaraj
413
Please can you try like this, i had test the same and its working fine
powershell Compress-Archive -Path "C:location.test.png" -DestinationPath "C:locationdestination"
answered Nov 21 '18 at 12:34
thiyagu selvarajthiyagu selvaraj
413
edited Nov 21 '18 at 13:01
answered Nov 21 '18 at 12:34
thiyagu selvarajthiyagu selvaraj
413
answered Nov 21 '18 at 12:34
thiyagu selvarajthiyagu selvaraj
413
answered Nov 21 '18 at 12:34
thiyagu selvarajthiyagu selvaraj
413
413
add a comment |
add a comment |
Explorer was set to show hidden items. For some reason it wasn't giving a visual indicator that this was a hidden file. I removed the checkbox for "Hidden" and it worked fine.
answered Nov 21 '18 at 15:10
fotgfotg
3411620
add a comment |
Explorer was set to show hidden items. For some reason it wasn't giving a visual indicator that this was a hidden file. I removed the checkbox for "Hidden" and it worked fine.
answered Nov 21 '18 at 15:10
fotgfotg
3411620
add a comment |
Explorer was set to show hidden items. For some reason it wasn't giving a visual indicator that this was a hidden file. I removed the checkbox for "Hidden" and it worked fine.
answered Nov 21 '18 at 15:10
fotgfotg
3411620
Explorer was set to show hidden items. For some reason it wasn't giving a visual indicator that this was a hidden file. I removed the checkbox for "Hidden" and it worked fine.
answered Nov 21 '18 at 15:10
fotgfotg
3411620
answered Nov 21 '18 at 15:10
fotgfotg
3411620
answered Nov 21 '18 at 15:10
fotgfotg
3411620
answered Nov 21 '18 at 15:10
fotgfotg
3411620
3411620
add a comment |
add a comment |
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1
Quote and use
-LiteralPath– LotPings
Nov 20 '18 at 23:28
@LotPings Don't you need a full path to use
-LiteralPath? Do they need to do-LiteralPath $(resolve-path .Dist._test.txt).Path?– TheMadTechnician
Nov 21 '18 at 0:08
1
@TheMadTechnician I did test with a file in current folder and that worked.
Compress-Archive -Destin .test.zip -Literalpath ".lnk"– LotPings
Nov 21 '18 at 0:55
2
@TheMadTechnician:
-LiteralPathjust means that that no wildcard resolution is applied to the argument, but it can still be a relative path.– mklement0
Nov 21 '18 at 2:39