Mixing
Laravel Notification Redirect to Newly Created Item
I am trying to have it so that anytime a new Doctor is registered, it triggers a Laravel notification to send me an email. Here is my current code:
Controller
$doctor = new Doctor();
$doctor->practice_id = $request->practice;
$doctor->first_name = $request->first_name;
$doctor->last_name = $request->last_name;
$doctor->type = $request->type;
$doctor->npi = $request->npi;
$doctor->license = $request->license;
$doctor->dea = $request->dea;
$doctor->is_approved = 0;
$doctor->is_ffs = 0;
$doctor->ffs_id = null;
$doctor->save();
Notification::route('mail', 'admin@test.com')->notify(new NewDoctor($doctor));
NewDoctor Notification
public function via($notifiable)
{
return ['mail'];
}
public function toMail($notifiable)
{
return (new MailMessage)
->greeting('Doctor Registered!')
->line('A new doctor has been submitted for approval.')
->action('View Doctor', route('doctors.show', [$this->doctor]));
}
This is returning the following error: Undefined property: AppNotificationsNewDoctor::$doctor
I'm assuming that for some reason the doctor id just is not passing through, but I have no idea how to make that pass in.
laravel eloquent
asked Nov 21 '18 at 0:22
XerakonXerakon
588
add a comment |
I am trying to have it so that anytime a new Doctor is registered, it triggers a Laravel notification to send me an email. Here is my current code:
Controller
$doctor = new Doctor();
$doctor->practice_id = $request->practice;
$doctor->first_name = $request->first_name;
$doctor->last_name = $request->last_name;
$doctor->type = $request->type;
$doctor->npi = $request->npi;
$doctor->license = $request->license;
$doctor->dea = $request->dea;
$doctor->is_approved = 0;
$doctor->is_ffs = 0;
$doctor->ffs_id = null;
$doctor->save();
Notification::route('mail', 'admin@test.com')->notify(new NewDoctor($doctor));
NewDoctor Notification
public function via($notifiable)
{
return ['mail'];
}
public function toMail($notifiable)
{
return (new MailMessage)
->greeting('Doctor Registered!')
->line('A new doctor has been submitted for approval.')
->action('View Doctor', route('doctors.show', [$this->doctor]));
}
This is returning the following error: Undefined property: AppNotificationsNewDoctor::$doctor
I'm assuming that for some reason the doctor id just is not passing through, but I have no idea how to make that pass in.
laravel eloquent
asked Nov 21 '18 at 0:22
XerakonXerakon
588
You are passing$doctorin constructor ofNewDoctor. You need to have a__construct($someVariable)constructor to initialize that value in your notification.
– InvincibleElf
Nov 21 '18 at 1:06
add a comment |
I am trying to have it so that anytime a new Doctor is registered, it triggers a Laravel notification to send me an email. Here is my current code:
Controller
$doctor = new Doctor();
$doctor->practice_id = $request->practice;
$doctor->first_name = $request->first_name;
$doctor->last_name = $request->last_name;
$doctor->type = $request->type;
$doctor->npi = $request->npi;
$doctor->license = $request->license;
$doctor->dea = $request->dea;
$doctor->is_approved = 0;
$doctor->is_ffs = 0;
$doctor->ffs_id = null;
$doctor->save();
Notification::route('mail', 'admin@test.com')->notify(new NewDoctor($doctor));
NewDoctor Notification
public function via($notifiable)
{
return ['mail'];
}
public function toMail($notifiable)
{
return (new MailMessage)
->greeting('Doctor Registered!')
->line('A new doctor has been submitted for approval.')
->action('View Doctor', route('doctors.show', [$this->doctor]));
}
This is returning the following error: Undefined property: AppNotificationsNewDoctor::$doctor
I'm assuming that for some reason the doctor id just is not passing through, but I have no idea how to make that pass in.
laravel eloquent
asked Nov 21 '18 at 0:22
XerakonXerakon
588
I am trying to have it so that anytime a new Doctor is registered, it triggers a Laravel notification to send me an email. Here is my current code:
Controller
$doctor = new Doctor();
$doctor->practice_id = $request->practice;
$doctor->first_name = $request->first_name;
$doctor->last_name = $request->last_name;
$doctor->type = $request->type;
$doctor->npi = $request->npi;
$doctor->license = $request->license;
$doctor->dea = $request->dea;
$doctor->is_approved = 0;
$doctor->is_ffs = 0;
$doctor->ffs_id = null;
$doctor->save();
Notification::route('mail', 'admin@test.com')->notify(new NewDoctor($doctor));
NewDoctor Notification
public function via($notifiable)
{
return ['mail'];
}
public function toMail($notifiable)
{
return (new MailMessage)
->greeting('Doctor Registered!')
->line('A new doctor has been submitted for approval.')
->action('View Doctor', route('doctors.show', [$this->doctor]));
}
This is returning the following error: Undefined property: AppNotificationsNewDoctor::$doctor
I'm assuming that for some reason the doctor id just is not passing through, but I have no idea how to make that pass in.
laravel eloquent
laravel eloquent
asked Nov 21 '18 at 0:22
XerakonXerakon
588
asked Nov 21 '18 at 0:22
XerakonXerakon
588
asked Nov 21 '18 at 0:22
XerakonXerakon
588
asked Nov 21 '18 at 0:22
XerakonXerakon
588
asked Nov 21 '18 at 0:22
XerakonXerakon
588
588
You are passing$doctorin constructor ofNewDoctor. You need to have a__construct($someVariable)constructor to initialize that value in your notification.
– InvincibleElf
Nov 21 '18 at 1:06
add a comment |
You are passing$doctorin constructor ofNewDoctor. You need to have a__construct($someVariable)constructor to initialize that value in your notification.
– InvincibleElf
Nov 21 '18 at 1:06
You are passing
$doctor in constructor of NewDoctor. You need to have a __construct($someVariable) constructor to initialize that value in your notification.– InvincibleElf
Nov 21 '18 at 1:06
You are passing
$doctor in constructor of NewDoctor. You need to have a __construct($someVariable) constructor to initialize that value in your notification.– InvincibleElf
Nov 21 '18 at 1:06
add a comment |
1 Answer
1
active
oldest
votes
private $doctor;
public function __construct($doctor)
{
$this->doctor = $doctor;
}
Declare a constructor in your New Doctor notification class and then only you would be able to use the $doctor variable.
answered Nov 21 '18 at 1:09
InvincibleElfInvincibleElf
9615
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53403588%2flaravel-notification-redirect-to-newly-created-item%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
private $doctor;
public function __construct($doctor)
{
$this->doctor = $doctor;
}
Declare a constructor in your New Doctor notification class and then only you would be able to use the $doctor variable.
answered Nov 21 '18 at 1:09
InvincibleElfInvincibleElf
9615
add a comment |
private $doctor;
public function __construct($doctor)
{
$this->doctor = $doctor;
}
Declare a constructor in your New Doctor notification class and then only you would be able to use the $doctor variable.
answered Nov 21 '18 at 1:09
InvincibleElfInvincibleElf
9615
add a comment |
private $doctor;
public function __construct($doctor)
{
$this->doctor = $doctor;
}
Declare a constructor in your New Doctor notification class and then only you would be able to use the $doctor variable.
answered Nov 21 '18 at 1:09
InvincibleElfInvincibleElf
9615
private $doctor;
public function __construct($doctor)
{
$this->doctor = $doctor;
}
Declare a constructor in your New Doctor notification class and then only you would be able to use the $doctor variable.
answered Nov 21 '18 at 1:09
InvincibleElfInvincibleElf
9615
answered Nov 21 '18 at 1:09
InvincibleElfInvincibleElf
9615
answered Nov 21 '18 at 1:09
InvincibleElfInvincibleElf
9615
answered Nov 21 '18 at 1:09
InvincibleElfInvincibleElf
9615
9615
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53403588%2flaravel-notification-redirect-to-newly-created-item%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
You are passing
$doctorin constructor ofNewDoctor. You need to have a__construct($someVariable)constructor to initialize that value in your notification.– InvincibleElf
Nov 21 '18 at 1:06