Mixing
Php Larvel include model in middle of the program
2
I want to add models from one table called "modellist" in middle of the program.
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2){
$model=TransactionModules::where('id',$info->module_id)->first();
$model_name=$model->model; // here am getting model name form table
use AppModels.$model_name; //i used this function to include model on middle of program
$model_name::find($info->transaction_id)->update(['status' => 7]);
}
}
laravel laravel-5 model eloquent
asked Nov 22 '18 at 6:12
spsaravananctspsaravananct
1652313
add a comment |
2
I want to add models from one table called "modellist" in middle of the program.
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2){
$model=TransactionModules::where('id',$info->module_id)->first();
$model_name=$model->model; // here am getting model name form table
use AppModels.$model_name; //i used this function to include model on middle of program
$model_name::find($info->transaction_id)->update(['status' => 7]);
}
}
laravel laravel-5 model eloquent
asked Nov 22 '18 at 6:12
spsaravananctspsaravananct
1652313
add a comment |
2
2
2
I want to add models from one table called "modellist" in middle of the program.
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2){
$model=TransactionModules::where('id',$info->module_id)->first();
$model_name=$model->model; // here am getting model name form table
use AppModels.$model_name; //i used this function to include model on middle of program
$model_name::find($info->transaction_id)->update(['status' => 7]);
}
}
laravel laravel-5 model eloquent
asked Nov 22 '18 at 6:12
spsaravananctspsaravananct
1652313
I want to add models from one table called "modellist" in middle of the program.
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2){
$model=TransactionModules::where('id',$info->module_id)->first();
$model_name=$model->model; // here am getting model name form table
use AppModels.$model_name; //i used this function to include model on middle of program
$model_name::find($info->transaction_id)->update(['status' => 7]);
}
}
laravel laravel-5 model eloquent
laravel laravel-5 model eloquent
asked Nov 22 '18 at 6:12
spsaravananctspsaravananct
1652313
asked Nov 22 '18 at 6:12
spsaravananctspsaravananct
1652313
asked Nov 22 '18 at 6:12
spsaravananctspsaravananct
1652313
asked Nov 22 '18 at 6:12
spsaravananctspsaravananct
1652313
asked Nov 22 '18 at 6:12
spsaravananctspsaravananct
1652313
1652313
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
1
I have not tested this but try:
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2){
$model=TransactionModules::where('id',$info->module_id)->first();
($model::class)::find($info->transaction_id)->update(['status' => 7]);
}
}
The class method returns the namespace with model name
I hope this works
answered Nov 22 '18 at 6:15
JoshJosh
710214
Dynamic class names are not allowed in compile-time ::class fetch error showing
– spsaravananct
Nov 22 '18 at 6:21
i need to include model beofore using
– spsaravananct
Nov 22 '18 at 6:21
Sorry it was worth a try. I am guessing that you are storing just the name of the model not the serialised model
– Josh
Nov 22 '18 at 6:24
add a comment |
0
You can do this direct on eloquent.
no need to declare use first
remember to use namespace as a string => "AppModels\"
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2)
{
$model=TransactionModules::where('id',$info->module_id)->first();
"AppModels\".$model->model::find($info->transaction_id)
->update(['status' => 7]);
}
}
answered Nov 22 '18 at 6:20
Emtiaz ZahidEmtiaz Zahid
1,043616
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
I have not tested this but try:
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2){
$model=TransactionModules::where('id',$info->module_id)->first();
($model::class)::find($info->transaction_id)->update(['status' => 7]);
}
}
The class method returns the namespace with model name
I hope this works
answered Nov 22 '18 at 6:15
JoshJosh
710214
Dynamic class names are not allowed in compile-time ::class fetch error showing
– spsaravananct
Nov 22 '18 at 6:21
i need to include model beofore using
– spsaravananct
Nov 22 '18 at 6:21
Sorry it was worth a try. I am guessing that you are storing just the name of the model not the serialised model
– Josh
Nov 22 '18 at 6:24
add a comment |
1
I have not tested this but try:
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2){
$model=TransactionModules::where('id',$info->module_id)->first();
($model::class)::find($info->transaction_id)->update(['status' => 7]);
}
}
The class method returns the namespace with model name
I hope this works
answered Nov 22 '18 at 6:15
JoshJosh
710214
Dynamic class names are not allowed in compile-time ::class fetch error showing
– spsaravananct
Nov 22 '18 at 6:21
i need to include model beofore using
– spsaravananct
Nov 22 '18 at 6:21
Sorry it was worth a try. I am guessing that you are storing just the name of the model not the serialised model
– Josh
Nov 22 '18 at 6:24
add a comment |
1
1
1
I have not tested this but try:
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2){
$model=TransactionModules::where('id',$info->module_id)->first();
($model::class)::find($info->transaction_id)->update(['status' => 7]);
}
}
The class method returns the namespace with model name
I hope this works
answered Nov 22 '18 at 6:15
JoshJosh
710214
I have not tested this but try:
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2){
$model=TransactionModules::where('id',$info->module_id)->first();
($model::class)::find($info->transaction_id)->update(['status' => 7]);
}
}
The class method returns the namespace with model name
I hope this works
answered Nov 22 '18 at 6:15
JoshJosh
710214
answered Nov 22 '18 at 6:15
JoshJosh
710214
answered Nov 22 '18 at 6:15
JoshJosh
710214
answered Nov 22 '18 at 6:15
JoshJosh
710214
710214
Dynamic class names are not allowed in compile-time ::class fetch error showing
– spsaravananct
Nov 22 '18 at 6:21
i need to include model beofore using
– spsaravananct
Nov 22 '18 at 6:21
Sorry it was worth a try. I am guessing that you are storing just the name of the model not the serialised model
– Josh
Nov 22 '18 at 6:24
add a comment |
Dynamic class names are not allowed in compile-time ::class fetch error showing
– spsaravananct
Nov 22 '18 at 6:21
i need to include model beofore using
– spsaravananct
Nov 22 '18 at 6:21
Sorry it was worth a try. I am guessing that you are storing just the name of the model not the serialised model
– Josh
Nov 22 '18 at 6:24
Dynamic class names are not allowed in compile-time ::class fetch error showing
– spsaravananct
Nov 22 '18 at 6:21
Dynamic class names are not allowed in compile-time ::class fetch error showing
– spsaravananct
Nov 22 '18 at 6:21
i need to include model beofore using
– spsaravananct
Nov 22 '18 at 6:21
i need to include model beofore using
– spsaravananct
Nov 22 '18 at 6:21
Sorry it was worth a try. I am guessing that you are storing just the name of the model not the serialised model
– Josh
Nov 22 '18 at 6:24
Sorry it was worth a try. I am guessing that you are storing just the name of the model not the serialised model
– Josh
Nov 22 '18 at 6:24
add a comment |
0
You can do this direct on eloquent.
no need to declare use first
remember to use namespace as a string => "AppModels\"
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2)
{
$model=TransactionModules::where('id',$info->module_id)->first();
"AppModels\".$model->model::find($info->transaction_id)
->update(['status' => 7]);
}
}
answered Nov 22 '18 at 6:20
Emtiaz ZahidEmtiaz Zahid
1,043616
add a comment |
0
You can do this direct on eloquent.
no need to declare use first
remember to use namespace as a string => "AppModels\"
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2)
{
$model=TransactionModules::where('id',$info->module_id)->first();
"AppModels\".$model->model::find($info->transaction_id)
->update(['status' => 7]);
}
}
answered Nov 22 '18 at 6:20
Emtiaz ZahidEmtiaz Zahid
1,043616
add a comment |
0
0
0
You can do this direct on eloquent.
no need to declare use first
remember to use namespace as a string => "AppModels\"
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2)
{
$model=TransactionModules::where('id',$info->module_id)->first();
"AppModels\".$model->model::find($info->transaction_id)
->update(['status' => 7]);
}
}
answered Nov 22 '18 at 6:20
Emtiaz ZahidEmtiaz Zahid
1,043616
You can do this direct on eloquent.
no need to declare use first
remember to use namespace as a string => "AppModels\"
foreach ($trans_infos as $key => $trans_info) {
if($trans_info->heirarchy_type==1 || $trans_info->heirarchy_type==2)
{
$model=TransactionModules::where('id',$info->module_id)->first();
"AppModels\".$model->model::find($info->transaction_id)
->update(['status' => 7]);
}
}
answered Nov 22 '18 at 6:20
Emtiaz ZahidEmtiaz Zahid
1,043616
edited Nov 22 '18 at 6:26
answered Nov 22 '18 at 6:20
Emtiaz ZahidEmtiaz Zahid
1,043616
answered Nov 22 '18 at 6:20
Emtiaz ZahidEmtiaz Zahid
1,043616
answered Nov 22 '18 at 6:20
Emtiaz ZahidEmtiaz Zahid
1,043616
1,043616
add a comment |
add a comment |
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