Prove that an Abel group whose order doesn’t include square factor is a cyclic group. [closed]












-1















“Prove that an Abel group whose order doesn’t include square factor is a cyclic group.”




How to prove this?



If $G$ is a group which fulfills this condition, can we say
$|G|=p_1p_2...p_n$ (each $p_i$ is different prime number) ?










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closed as off-topic by Shaun, Christopher, Adrian Keister, Dietrich Burde, Derek Holt Nov 20 '18 at 14:14


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shaun, Christopher, Adrian Keister, Dietrich Burde, Derek Holt

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    What do you know about finite abelian groups?
    – Arthur
    Nov 20 '18 at 13:21










  • Welcome to Maths SX! Do you know the Chinese remainder theorem?
    – Bernard
    Nov 20 '18 at 13:21
















-1















“Prove that an Abel group whose order doesn’t include square factor is a cyclic group.”




How to prove this?



If $G$ is a group which fulfills this condition, can we say
$|G|=p_1p_2...p_n$ (each $p_i$ is different prime number) ?










share|cite|improve this question















closed as off-topic by Shaun, Christopher, Adrian Keister, Dietrich Burde, Derek Holt Nov 20 '18 at 14:14


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shaun, Christopher, Adrian Keister, Dietrich Burde, Derek Holt

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    What do you know about finite abelian groups?
    – Arthur
    Nov 20 '18 at 13:21










  • Welcome to Maths SX! Do you know the Chinese remainder theorem?
    – Bernard
    Nov 20 '18 at 13:21














-1












-1








-1








“Prove that an Abel group whose order doesn’t include square factor is a cyclic group.”




How to prove this?



If $G$ is a group which fulfills this condition, can we say
$|G|=p_1p_2...p_n$ (each $p_i$ is different prime number) ?










share|cite|improve this question
















“Prove that an Abel group whose order doesn’t include square factor is a cyclic group.”




How to prove this?



If $G$ is a group which fulfills this condition, can we say
$|G|=p_1p_2...p_n$ (each $p_i$ is different prime number) ?







group-theory






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 20 '18 at 13:26









amWhy

192k28224439




192k28224439










asked Nov 20 '18 at 13:15









saki

296




296




closed as off-topic by Shaun, Christopher, Adrian Keister, Dietrich Burde, Derek Holt Nov 20 '18 at 14:14


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shaun, Christopher, Adrian Keister, Dietrich Burde, Derek Holt

If this question can be reworded to fit the rules in the help center, please edit the question.




closed as off-topic by Shaun, Christopher, Adrian Keister, Dietrich Burde, Derek Holt Nov 20 '18 at 14:14


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Shaun, Christopher, Adrian Keister, Dietrich Burde, Derek Holt

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    What do you know about finite abelian groups?
    – Arthur
    Nov 20 '18 at 13:21










  • Welcome to Maths SX! Do you know the Chinese remainder theorem?
    – Bernard
    Nov 20 '18 at 13:21














  • 1




    What do you know about finite abelian groups?
    – Arthur
    Nov 20 '18 at 13:21










  • Welcome to Maths SX! Do you know the Chinese remainder theorem?
    – Bernard
    Nov 20 '18 at 13:21








1




1




What do you know about finite abelian groups?
– Arthur
Nov 20 '18 at 13:21




What do you know about finite abelian groups?
– Arthur
Nov 20 '18 at 13:21












Welcome to Maths SX! Do you know the Chinese remainder theorem?
– Bernard
Nov 20 '18 at 13:21




Welcome to Maths SX! Do you know the Chinese remainder theorem?
– Bernard
Nov 20 '18 at 13:21










1 Answer
1






active

oldest

votes


















1














Hint: By Cauchy's theorem, there is an element $g_p in G$ of order $p$ for each prime $p$ dividing the order of $G$. What is the order of the product of the $g_p$?






share|cite|improve this answer























  • The order of the product of the gp is p? So we can say every subgroup of G is circlic group and therefore G is circlic group?
    – saki
    Nov 20 '18 at 20:58




















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Hint: By Cauchy's theorem, there is an element $g_p in G$ of order $p$ for each prime $p$ dividing the order of $G$. What is the order of the product of the $g_p$?






share|cite|improve this answer























  • The order of the product of the gp is p? So we can say every subgroup of G is circlic group and therefore G is circlic group?
    – saki
    Nov 20 '18 at 20:58


















1














Hint: By Cauchy's theorem, there is an element $g_p in G$ of order $p$ for each prime $p$ dividing the order of $G$. What is the order of the product of the $g_p$?






share|cite|improve this answer























  • The order of the product of the gp is p? So we can say every subgroup of G is circlic group and therefore G is circlic group?
    – saki
    Nov 20 '18 at 20:58
















1












1








1






Hint: By Cauchy's theorem, there is an element $g_p in G$ of order $p$ for each prime $p$ dividing the order of $G$. What is the order of the product of the $g_p$?






share|cite|improve this answer














Hint: By Cauchy's theorem, there is an element $g_p in G$ of order $p$ for each prime $p$ dividing the order of $G$. What is the order of the product of the $g_p$?







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Nov 21 '18 at 0:20

























answered Nov 20 '18 at 13:23









lhf

163k10167386




163k10167386












  • The order of the product of the gp is p? So we can say every subgroup of G is circlic group and therefore G is circlic group?
    – saki
    Nov 20 '18 at 20:58




















  • The order of the product of the gp is p? So we can say every subgroup of G is circlic group and therefore G is circlic group?
    – saki
    Nov 20 '18 at 20:58


















The order of the product of the gp is p? So we can say every subgroup of G is circlic group and therefore G is circlic group?
– saki
Nov 20 '18 at 20:58






The order of the product of the gp is p? So we can say every subgroup of G is circlic group and therefore G is circlic group?
– saki
Nov 20 '18 at 20:58





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