Mixing
Threads in JavaFX: Not on FX application thread
1
I want study how to work with Threads in JavaFX. For example, 2 processes, which should change text on the lables every 100 ms, and updating information on the screen also every 100 ms.
But in this case it doesnt works. IDEA writes:
Exception in thread "Thread-4" java.lang.IllegalStateException: Not on FX application thread; currentThread = Thread-4
I have read many examples with the same problem, but any of their solutions doesnt worked.
What I should to do?
Thanks.
sample.fxml
...
<Button fx:id="startBut" layoutX="100.0" layoutY="50.0" mnemonicParsing="false" onAction="#testingOfThread" prefHeight="25.0" prefWidth="65.0" text="Export" />
<Label fx:id="firstStatus" layoutX="100.0" layoutY="100" text="Status" />
<Label fx:id="secondStatus" layoutX="100.0" layoutY="150" text="Status" />
...
Main.java
package sample;
import javafx.application.Application;
import javafx.fxml.FXMLLoader;
import javafx.scene.Parent;
import javafx.scene.Scene;
import javafx.stage.Stage;
public class Main extends Application {
@Override
public void start(Stage primaryStage) throws Exception{
Parent root = FXMLLoader.load(getClass().getResource("sample.fxml"));
primaryStage.setTitle("Sample");
primaryStage.setScene(new Scene(root));
primaryStage.show();
}
//Take control to Controller
public void initializeController(){
FXMLLoader loader = new FXMLLoader();
Controller controller = loader.getController();
controller.setMain(this);
}
public static void main(String args) {
launch(args);
}
}
Controller.java
package sample;
import javafx.concurrent.Task;
import javafx.fxml.FXML;
import javafx.scene.control.*;
public class Controller {
@FXML
private Label firstStatus;
@FXML
private Label secondStatus;
@FXML
public Button startBut;
//Link to MainApp
private Main Main;
//Constructor
public Controller(){
}
//Link for himself
public void setMain(Main main){
this.Main = main;
}
@FXML
private void testingOfThread(){
Task<Void> task = new Task<Void>() {
@Override public Void call() {
for (int i = 0; i < 100; i++) {
try {
Thread.sleep(100);
} catch (InterruptedException e) {
Thread.interrupted();
break;
}
System.out.println(i + 1);
firstStatus.setText(i+"");
}
return null;
}
};
Thread th = new Thread(task);
th.setDaemon(true);
th.start();
Task<Void> task2 = new Task<Void>() {
@Override public Void call() {
for (int i = 0; i < 100; i++) {
try {
Thread.sleep(100);
} catch (InterruptedException e) {
Thread.interrupted();
break;
}
System.out.println(i + 1);
secondStatus.setText(i+"");
}
return null;
}
};
Thread th2 = new Thread(task2);
th2.start();
}
}
multithreading javafx
asked Mar 18 '18 at 0:16
Kamil TimraleevKamil Timraleev
203
add a comment |
1
I want study how to work with Threads in JavaFX. For example, 2 processes, which should change text on the lables every 100 ms, and updating information on the screen also every 100 ms.
But in this case it doesnt works. IDEA writes:
Exception in thread "Thread-4" java.lang.IllegalStateException: Not on FX application thread; currentThread = Thread-4
I have read many examples with the same problem, but any of their solutions doesnt worked.
What I should to do?
Thanks.
sample.fxml
...
<Button fx:id="startBut" layoutX="100.0" layoutY="50.0" mnemonicParsing="false" onAction="#testingOfThread" prefHeight="25.0" prefWidth="65.0" text="Export" />
<Label fx:id="firstStatus" layoutX="100.0" layoutY="100" text="Status" />
<Label fx:id="secondStatus" layoutX="100.0" layoutY="150" text="Status" />
...
Main.java
package sample;
import javafx.application.Application;
import javafx.fxml.FXMLLoader;
import javafx.scene.Parent;
import javafx.scene.Scene;
import javafx.stage.Stage;
public class Main extends Application {
@Override
public void start(Stage primaryStage) throws Exception{
Parent root = FXMLLoader.load(getClass().getResource("sample.fxml"));
primaryStage.setTitle("Sample");
primaryStage.setScene(new Scene(root));
primaryStage.show();
}
//Take control to Controller
public void initializeController(){
FXMLLoader loader = new FXMLLoader();
Controller controller = loader.getController();
controller.setMain(this);
}
public static void main(String args) {
launch(args);
}
}
Controller.java
package sample;
import javafx.concurrent.Task;
import javafx.fxml.FXML;
import javafx.scene.control.*;
public class Controller {
@FXML
private Label firstStatus;
@FXML
private Label secondStatus;
@FXML
public Button startBut;
//Link to MainApp
private Main Main;
//Constructor
public Controller(){
}
//Link for himself
public void setMain(Main main){
this.Main = main;
}
@FXML
private void testingOfThread(){
Task<Void> task = new Task<Void>() {
@Override public Void call() {
for (int i = 0; i < 100; i++) {
try {
Thread.sleep(100);
} catch (InterruptedException e) {
Thread.interrupted();
break;
}
System.out.println(i + 1);
firstStatus.setText(i+"");
}
return null;
}
};
Thread th = new Thread(task);
th.setDaemon(true);
th.start();
Task<Void> task2 = new Task<Void>() {
@Override public Void call() {
for (int i = 0; i < 100; i++) {
try {
Thread.sleep(100);
} catch (InterruptedException e) {
Thread.interrupted();
break;
}
System.out.println(i + 1);
secondStatus.setText(i+"");
}
return null;
}
};
Thread th2 = new Thread(task2);
th2.start();
}
}
multithreading javafx
asked Mar 18 '18 at 0:16
Kamil TimraleevKamil Timraleev
203
3
Don't update the GUI from a thread other than the application thread. You need to usePlatform.runLater. Alternatively since you're already using tasks, update themessageproperties instead of thetextproperty by usingupdateMessageand bind thetextproperties to themessageproperties:callmethod:/* firstStatus.setText(i+"");*/ updateMessage(Integer.toString(i));before starting the thread:firstStatus.textProperty().bind(task.messageProperty());
– fabian
Mar 18 '18 at 1:47
Danke schön, Fabian! All works.
– Kamil Timraleev
Mar 18 '18 at 10:27
add a comment |
1
1
1
1
I want study how to work with Threads in JavaFX. For example, 2 processes, which should change text on the lables every 100 ms, and updating information on the screen also every 100 ms.
But in this case it doesnt works. IDEA writes:
Exception in thread "Thread-4" java.lang.IllegalStateException: Not on FX application thread; currentThread = Thread-4
I have read many examples with the same problem, but any of their solutions doesnt worked.
What I should to do?
Thanks.
sample.fxml
...
<Button fx:id="startBut" layoutX="100.0" layoutY="50.0" mnemonicParsing="false" onAction="#testingOfThread" prefHeight="25.0" prefWidth="65.0" text="Export" />
<Label fx:id="firstStatus" layoutX="100.0" layoutY="100" text="Status" />
<Label fx:id="secondStatus" layoutX="100.0" layoutY="150" text="Status" />
...
Main.java
package sample;
import javafx.application.Application;
import javafx.fxml.FXMLLoader;
import javafx.scene.Parent;
import javafx.scene.Scene;
import javafx.stage.Stage;
public class Main extends Application {
@Override
public void start(Stage primaryStage) throws Exception{
Parent root = FXMLLoader.load(getClass().getResource("sample.fxml"));
primaryStage.setTitle("Sample");
primaryStage.setScene(new Scene(root));
primaryStage.show();
}
//Take control to Controller
public void initializeController(){
FXMLLoader loader = new FXMLLoader();
Controller controller = loader.getController();
controller.setMain(this);
}
public static void main(String args) {
launch(args);
}
}
Controller.java
package sample;
import javafx.concurrent.Task;
import javafx.fxml.FXML;
import javafx.scene.control.*;
public class Controller {
@FXML
private Label firstStatus;
@FXML
private Label secondStatus;
@FXML
public Button startBut;
//Link to MainApp
private Main Main;
//Constructor
public Controller(){
}
//Link for himself
public void setMain(Main main){
this.Main = main;
}
@FXML
private void testingOfThread(){
Task<Void> task = new Task<Void>() {
@Override public Void call() {
for (int i = 0; i < 100; i++) {
try {
Thread.sleep(100);
} catch (InterruptedException e) {
Thread.interrupted();
break;
}
System.out.println(i + 1);
firstStatus.setText(i+"");
}
return null;
}
};
Thread th = new Thread(task);
th.setDaemon(true);
th.start();
Task<Void> task2 = new Task<Void>() {
@Override public Void call() {
for (int i = 0; i < 100; i++) {
try {
Thread.sleep(100);
} catch (InterruptedException e) {
Thread.interrupted();
break;
}
System.out.println(i + 1);
secondStatus.setText(i+"");
}
return null;
}
};
Thread th2 = new Thread(task2);
th2.start();
}
}
multithreading javafx
asked Mar 18 '18 at 0:16
Kamil TimraleevKamil Timraleev
203
I want study how to work with Threads in JavaFX. For example, 2 processes, which should change text on the lables every 100 ms, and updating information on the screen also every 100 ms.
But in this case it doesnt works. IDEA writes:
Exception in thread "Thread-4" java.lang.IllegalStateException: Not on FX application thread; currentThread = Thread-4
I have read many examples with the same problem, but any of their solutions doesnt worked.
What I should to do?
Thanks.
sample.fxml
...
<Button fx:id="startBut" layoutX="100.0" layoutY="50.0" mnemonicParsing="false" onAction="#testingOfThread" prefHeight="25.0" prefWidth="65.0" text="Export" />
<Label fx:id="firstStatus" layoutX="100.0" layoutY="100" text="Status" />
<Label fx:id="secondStatus" layoutX="100.0" layoutY="150" text="Status" />
...
Main.java
package sample;
import javafx.application.Application;
import javafx.fxml.FXMLLoader;
import javafx.scene.Parent;
import javafx.scene.Scene;
import javafx.stage.Stage;
public class Main extends Application {
@Override
public void start(Stage primaryStage) throws Exception{
Parent root = FXMLLoader.load(getClass().getResource("sample.fxml"));
primaryStage.setTitle("Sample");
primaryStage.setScene(new Scene(root));
primaryStage.show();
}
//Take control to Controller
public void initializeController(){
FXMLLoader loader = new FXMLLoader();
Controller controller = loader.getController();
controller.setMain(this);
}
public static void main(String args) {
launch(args);
}
}
Controller.java
package sample;
import javafx.concurrent.Task;
import javafx.fxml.FXML;
import javafx.scene.control.*;
public class Controller {
@FXML
private Label firstStatus;
@FXML
private Label secondStatus;
@FXML
public Button startBut;
//Link to MainApp
private Main Main;
//Constructor
public Controller(){
}
//Link for himself
public void setMain(Main main){
this.Main = main;
}
@FXML
private void testingOfThread(){
Task<Void> task = new Task<Void>() {
@Override public Void call() {
for (int i = 0; i < 100; i++) {
try {
Thread.sleep(100);
} catch (InterruptedException e) {
Thread.interrupted();
break;
}
System.out.println(i + 1);
firstStatus.setText(i+"");
}
return null;
}
};
Thread th = new Thread(task);
th.setDaemon(true);
th.start();
Task<Void> task2 = new Task<Void>() {
@Override public Void call() {
for (int i = 0; i < 100; i++) {
try {
Thread.sleep(100);
} catch (InterruptedException e) {
Thread.interrupted();
break;
}
System.out.println(i + 1);
secondStatus.setText(i+"");
}
return null;
}
};
Thread th2 = new Thread(task2);
th2.start();
}
}
multithreading javafx
multithreading javafx
asked Mar 18 '18 at 0:16
Kamil TimraleevKamil Timraleev
203
asked Mar 18 '18 at 0:16
Kamil TimraleevKamil Timraleev
203
asked Mar 18 '18 at 0:16
Kamil TimraleevKamil Timraleev
203
asked Mar 18 '18 at 0:16
Kamil TimraleevKamil Timraleev
203
asked Mar 18 '18 at 0:16
Kamil TimraleevKamil Timraleev
203
203
3
Don't update the GUI from a thread other than the application thread. You need to usePlatform.runLater. Alternatively since you're already using tasks, update themessageproperties instead of thetextproperty by usingupdateMessageand bind thetextproperties to themessageproperties:callmethod:/* firstStatus.setText(i+"");*/ updateMessage(Integer.toString(i));before starting the thread:firstStatus.textProperty().bind(task.messageProperty());
– fabian
Mar 18 '18 at 1:47
Danke schön, Fabian! All works.
– Kamil Timraleev
Mar 18 '18 at 10:27
add a comment |
3
Don't update the GUI from a thread other than the application thread. You need to usePlatform.runLater. Alternatively since you're already using tasks, update themessageproperties instead of thetextproperty by usingupdateMessageand bind thetextproperties to themessageproperties:callmethod:/* firstStatus.setText(i+"");*/ updateMessage(Integer.toString(i));before starting the thread:firstStatus.textProperty().bind(task.messageProperty());
– fabian
Mar 18 '18 at 1:47
Danke schön, Fabian! All works.
– Kamil Timraleev
Mar 18 '18 at 10:27
3
3
Don't update the GUI from a thread other than the application thread. You need to use
Platform.runLater. Alternatively since you're already using tasks, update the message properties instead of the text property by using updateMessage and bind the text properties to the message properties: call method: /* firstStatus.setText(i+"");*/ updateMessage(Integer.toString(i)); before starting the thread: firstStatus.textProperty().bind(task.messageProperty());– fabian
Mar 18 '18 at 1:47
Don't update the GUI from a thread other than the application thread. You need to use
Platform.runLater. Alternatively since you're already using tasks, update the message properties instead of the text property by using updateMessage and bind the text properties to the message properties: call method: /* firstStatus.setText(i+"");*/ updateMessage(Integer.toString(i)); before starting the thread: firstStatus.textProperty().bind(task.messageProperty());– fabian
Mar 18 '18 at 1:47
Danke schön, Fabian! All works.
– Kamil Timraleev
Mar 18 '18 at 10:27
Danke schön, Fabian! All works.
– Kamil Timraleev
Mar 18 '18 at 10:27
add a comment |
1 Answer
1
active
oldest
votes
1
Find the code which update the GUI from a thread other than the application thread,then put them in runLater().
Platform.runLater(new Runnable() {
@Override
public void run() {
//update application thread
}
});
answered Nov 21 '18 at 6:47
Fly KingFly King
112
add a comment |
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1 Answer
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active
oldest
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oldest
votes
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oldest
votes
1
Find the code which update the GUI from a thread other than the application thread,then put them in runLater().
Platform.runLater(new Runnable() {
@Override
public void run() {
//update application thread
}
});
answered Nov 21 '18 at 6:47
Fly KingFly King
112
add a comment |
1
Find the code which update the GUI from a thread other than the application thread,then put them in runLater().
Platform.runLater(new Runnable() {
@Override
public void run() {
//update application thread
}
});
answered Nov 21 '18 at 6:47
Fly KingFly King
112
add a comment |
1
1
1
Find the code which update the GUI from a thread other than the application thread,then put them in runLater().
Platform.runLater(new Runnable() {
@Override
public void run() {
//update application thread
}
});
answered Nov 21 '18 at 6:47
Fly KingFly King
112
Find the code which update the GUI from a thread other than the application thread,then put them in runLater().
Platform.runLater(new Runnable() {
@Override
public void run() {
//update application thread
}
});
answered Nov 21 '18 at 6:47
Fly KingFly King
112
answered Nov 21 '18 at 6:47
Fly KingFly King
112
answered Nov 21 '18 at 6:47
Fly KingFly King
112
answered Nov 21 '18 at 6:47
Fly KingFly King
112
112
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3
Don't update the GUI from a thread other than the application thread. You need to use
Platform.runLater. Alternatively since you're already using tasks, update themessageproperties instead of thetextproperty by usingupdateMessageand bind thetextproperties to themessageproperties:callmethod:/* firstStatus.setText(i+"");*/ updateMessage(Integer.toString(i));before starting the thread:firstStatus.textProperty().bind(task.messageProperty());– fabian
Mar 18 '18 at 1:47
Danke schön, Fabian! All works.
– Kamil Timraleev
Mar 18 '18 at 10:27