Understanding Semaphore (Getting the wrong final value of 1)












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I have made a semaphore initialized to 0. I start the program by creating three threads and then calling sema_func() where sema_wait() puts them in the waiting list. Now I make a 4th thread which wakes up one of the thread by calling sema_wake() function. However when all the threads wake up,shouldn't i get the final value of 0 instead of 1? Kindly guide me



My code:






#include <pthread.h>
#include <stdio.h>
#include <semaphore.h>

sem_t mySema;

void *sema_func(void *param) {
printf("SLEEPING THREAD %lu n", pthread_self());

sem_wait(&mySema);

printf("WOKE THREAD %lu n", pthread_self());

sleep(1);

sem_post(&mySema);

}

void *wake_func(void *param) {


int sema_value = 0;

sem_getvalue(&mySema, &sema_value);

printf("SEMA VALUE: %dn", sema_value);

sem_post(&mySema);

sleep(5);


sem_getvalue(&mySema, &sema_value);

printf("SEMA FINAL VALUE: %dn", sema_value);



}

int main(int argc, char *argv) {
sem_init(&mySema, 0, 0);
pthread_t t1; pthread_t t2; pthread_t t3; pthread_t t4;

pthread_create(&t1, NULL, sema_func, NULL);
pthread_create(&t2, NULL, sema_func, NULL);
pthread_create(&t3, NULL, sema_func, NULL);
sleep(4);
pthread_create(&t4, NULL, wake_func, NULL);
sleep(10);
}





Output: -



enter image description here










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    0















    I have made a semaphore initialized to 0. I start the program by creating three threads and then calling sema_func() where sema_wait() puts them in the waiting list. Now I make a 4th thread which wakes up one of the thread by calling sema_wake() function. However when all the threads wake up,shouldn't i get the final value of 0 instead of 1? Kindly guide me



    My code:






    #include <pthread.h>
    #include <stdio.h>
    #include <semaphore.h>

    sem_t mySema;

    void *sema_func(void *param) {
    printf("SLEEPING THREAD %lu n", pthread_self());

    sem_wait(&mySema);

    printf("WOKE THREAD %lu n", pthread_self());

    sleep(1);

    sem_post(&mySema);

    }

    void *wake_func(void *param) {


    int sema_value = 0;

    sem_getvalue(&mySema, &sema_value);

    printf("SEMA VALUE: %dn", sema_value);

    sem_post(&mySema);

    sleep(5);


    sem_getvalue(&mySema, &sema_value);

    printf("SEMA FINAL VALUE: %dn", sema_value);



    }

    int main(int argc, char *argv) {
    sem_init(&mySema, 0, 0);
    pthread_t t1; pthread_t t2; pthread_t t3; pthread_t t4;

    pthread_create(&t1, NULL, sema_func, NULL);
    pthread_create(&t2, NULL, sema_func, NULL);
    pthread_create(&t3, NULL, sema_func, NULL);
    sleep(4);
    pthread_create(&t4, NULL, wake_func, NULL);
    sleep(10);
    }





    Output: -



    enter image description here










    share|improve this question

























      0












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      0








      I have made a semaphore initialized to 0. I start the program by creating three threads and then calling sema_func() where sema_wait() puts them in the waiting list. Now I make a 4th thread which wakes up one of the thread by calling sema_wake() function. However when all the threads wake up,shouldn't i get the final value of 0 instead of 1? Kindly guide me



      My code:






      #include <pthread.h>
      #include <stdio.h>
      #include <semaphore.h>

      sem_t mySema;

      void *sema_func(void *param) {
      printf("SLEEPING THREAD %lu n", pthread_self());

      sem_wait(&mySema);

      printf("WOKE THREAD %lu n", pthread_self());

      sleep(1);

      sem_post(&mySema);

      }

      void *wake_func(void *param) {


      int sema_value = 0;

      sem_getvalue(&mySema, &sema_value);

      printf("SEMA VALUE: %dn", sema_value);

      sem_post(&mySema);

      sleep(5);


      sem_getvalue(&mySema, &sema_value);

      printf("SEMA FINAL VALUE: %dn", sema_value);



      }

      int main(int argc, char *argv) {
      sem_init(&mySema, 0, 0);
      pthread_t t1; pthread_t t2; pthread_t t3; pthread_t t4;

      pthread_create(&t1, NULL, sema_func, NULL);
      pthread_create(&t2, NULL, sema_func, NULL);
      pthread_create(&t3, NULL, sema_func, NULL);
      sleep(4);
      pthread_create(&t4, NULL, wake_func, NULL);
      sleep(10);
      }





      Output: -



      enter image description here










      share|improve this question














      I have made a semaphore initialized to 0. I start the program by creating three threads and then calling sema_func() where sema_wait() puts them in the waiting list. Now I make a 4th thread which wakes up one of the thread by calling sema_wake() function. However when all the threads wake up,shouldn't i get the final value of 0 instead of 1? Kindly guide me



      My code:






      #include <pthread.h>
      #include <stdio.h>
      #include <semaphore.h>

      sem_t mySema;

      void *sema_func(void *param) {
      printf("SLEEPING THREAD %lu n", pthread_self());

      sem_wait(&mySema);

      printf("WOKE THREAD %lu n", pthread_self());

      sleep(1);

      sem_post(&mySema);

      }

      void *wake_func(void *param) {


      int sema_value = 0;

      sem_getvalue(&mySema, &sema_value);

      printf("SEMA VALUE: %dn", sema_value);

      sem_post(&mySema);

      sleep(5);


      sem_getvalue(&mySema, &sema_value);

      printf("SEMA FINAL VALUE: %dn", sema_value);



      }

      int main(int argc, char *argv) {
      sem_init(&mySema, 0, 0);
      pthread_t t1; pthread_t t2; pthread_t t3; pthread_t t4;

      pthread_create(&t1, NULL, sema_func, NULL);
      pthread_create(&t2, NULL, sema_func, NULL);
      pthread_create(&t3, NULL, sema_func, NULL);
      sleep(4);
      pthread_create(&t4, NULL, wake_func, NULL);
      sleep(10);
      }





      Output: -



      enter image description here






      #include <pthread.h>
      #include <stdio.h>
      #include <semaphore.h>

      sem_t mySema;

      void *sema_func(void *param) {
      printf("SLEEPING THREAD %lu n", pthread_self());

      sem_wait(&mySema);

      printf("WOKE THREAD %lu n", pthread_self());

      sleep(1);

      sem_post(&mySema);

      }

      void *wake_func(void *param) {


      int sema_value = 0;

      sem_getvalue(&mySema, &sema_value);

      printf("SEMA VALUE: %dn", sema_value);

      sem_post(&mySema);

      sleep(5);


      sem_getvalue(&mySema, &sema_value);

      printf("SEMA FINAL VALUE: %dn", sema_value);



      }

      int main(int argc, char *argv) {
      sem_init(&mySema, 0, 0);
      pthread_t t1; pthread_t t2; pthread_t t3; pthread_t t4;

      pthread_create(&t1, NULL, sema_func, NULL);
      pthread_create(&t2, NULL, sema_func, NULL);
      pthread_create(&t3, NULL, sema_func, NULL);
      sleep(4);
      pthread_create(&t4, NULL, wake_func, NULL);
      sleep(10);
      }





      #include <pthread.h>
      #include <stdio.h>
      #include <semaphore.h>

      sem_t mySema;

      void *sema_func(void *param) {
      printf("SLEEPING THREAD %lu n", pthread_self());

      sem_wait(&mySema);

      printf("WOKE THREAD %lu n", pthread_self());

      sleep(1);

      sem_post(&mySema);

      }

      void *wake_func(void *param) {


      int sema_value = 0;

      sem_getvalue(&mySema, &sema_value);

      printf("SEMA VALUE: %dn", sema_value);

      sem_post(&mySema);

      sleep(5);


      sem_getvalue(&mySema, &sema_value);

      printf("SEMA FINAL VALUE: %dn", sema_value);



      }

      int main(int argc, char *argv) {
      sem_init(&mySema, 0, 0);
      pthread_t t1; pthread_t t2; pthread_t t3; pthread_t t4;

      pthread_create(&t1, NULL, sema_func, NULL);
      pthread_create(&t2, NULL, sema_func, NULL);
      pthread_create(&t3, NULL, sema_func, NULL);
      sleep(4);
      pthread_create(&t4, NULL, wake_func, NULL);
      sleep(10);
      }






      pthreads






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      asked Nov 21 '18 at 10:58









      Jawad ZaheerJawad Zaheer

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