What is meant by “relation between sets” in this question?












0












$begingroup$


A homework question asks,




Consider any two sets $A$ and $B$. What should the relation between $A$ and $B$ be, so that $(𝐴 ∩ 𝐵) × 𝐵 = 𝐵 × (𝐴 ∩ 𝐵)$. Prove your answer




I am not looking for an answer to the problem, but I’m not understanding what it is asking for. I think it’s asking “is $A$ a subset of $B$, vice versa, etc” but I’m not sure.










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  • $begingroup$
    it could be $A=B$
    $endgroup$
    – janmarqz
    Jan 17 at 20:10
















0












$begingroup$


A homework question asks,




Consider any two sets $A$ and $B$. What should the relation between $A$ and $B$ be, so that $(𝐴 ∩ 𝐵) × 𝐵 = 𝐵 × (𝐴 ∩ 𝐵)$. Prove your answer




I am not looking for an answer to the problem, but I’m not understanding what it is asking for. I think it’s asking “is $A$ a subset of $B$, vice versa, etc” but I’m not sure.










share|cite|improve this question











$endgroup$












  • $begingroup$
    it could be $A=B$
    $endgroup$
    – janmarqz
    Jan 17 at 20:10














0












0








0





$begingroup$


A homework question asks,




Consider any two sets $A$ and $B$. What should the relation between $A$ and $B$ be, so that $(𝐴 ∩ 𝐵) × 𝐵 = 𝐵 × (𝐴 ∩ 𝐵)$. Prove your answer




I am not looking for an answer to the problem, but I’m not understanding what it is asking for. I think it’s asking “is $A$ a subset of $B$, vice versa, etc” but I’m not sure.










share|cite|improve this question











$endgroup$




A homework question asks,




Consider any two sets $A$ and $B$. What should the relation between $A$ and $B$ be, so that $(𝐴 ∩ 𝐵) × 𝐵 = 𝐵 × (𝐴 ∩ 𝐵)$. Prove your answer




I am not looking for an answer to the problem, but I’m not understanding what it is asking for. I think it’s asking “is $A$ a subset of $B$, vice versa, etc” but I’m not sure.







discrete-mathematics






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edited Jan 17 at 21:27









egreg

183k1486204




183k1486204










asked Jan 17 at 20:08









Dallin HagmanDallin Hagman

1




1












  • $begingroup$
    it could be $A=B$
    $endgroup$
    – janmarqz
    Jan 17 at 20:10


















  • $begingroup$
    it could be $A=B$
    $endgroup$
    – janmarqz
    Jan 17 at 20:10
















$begingroup$
it could be $A=B$
$endgroup$
– janmarqz
Jan 17 at 20:10




$begingroup$
it could be $A=B$
$endgroup$
– janmarqz
Jan 17 at 20:10










1 Answer
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$begingroup$

The question indeed asks you to find some inclusion relation between $A$ and $B$ such that the relation holds. Or some other condition that you should find.



You can start by observing that if $B=emptyset$ or $Acap B=emptyset$, then the statement holds. Thus you can go on with the assumption that neither set is empty.



What can you conclude from $Xtimes Y=Ytimes X$ if $X$ and $Y$ are not empty?






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    1 Answer
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    1 Answer
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    active

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    active

    oldest

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    0












    $begingroup$

    The question indeed asks you to find some inclusion relation between $A$ and $B$ such that the relation holds. Or some other condition that you should find.



    You can start by observing that if $B=emptyset$ or $Acap B=emptyset$, then the statement holds. Thus you can go on with the assumption that neither set is empty.



    What can you conclude from $Xtimes Y=Ytimes X$ if $X$ and $Y$ are not empty?






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      The question indeed asks you to find some inclusion relation between $A$ and $B$ such that the relation holds. Or some other condition that you should find.



      You can start by observing that if $B=emptyset$ or $Acap B=emptyset$, then the statement holds. Thus you can go on with the assumption that neither set is empty.



      What can you conclude from $Xtimes Y=Ytimes X$ if $X$ and $Y$ are not empty?






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        The question indeed asks you to find some inclusion relation between $A$ and $B$ such that the relation holds. Or some other condition that you should find.



        You can start by observing that if $B=emptyset$ or $Acap B=emptyset$, then the statement holds. Thus you can go on with the assumption that neither set is empty.



        What can you conclude from $Xtimes Y=Ytimes X$ if $X$ and $Y$ are not empty?






        share|cite|improve this answer









        $endgroup$



        The question indeed asks you to find some inclusion relation between $A$ and $B$ such that the relation holds. Or some other condition that you should find.



        You can start by observing that if $B=emptyset$ or $Acap B=emptyset$, then the statement holds. Thus you can go on with the assumption that neither set is empty.



        What can you conclude from $Xtimes Y=Ytimes X$ if $X$ and $Y$ are not empty?







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Jan 17 at 21:29









        egregegreg

        183k1486204




        183k1486204






























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