Branching process Durrett
$begingroup$
I don't understand the last "then" in that proof from Durrett.
It would be a relief if you can help me !
Thank you :).
probability stochastic-processes
$endgroup$
add a comment |
$begingroup$
I don't understand the last "then" in that proof from Durrett.
It would be a relief if you can help me !
Thank you :).
probability stochastic-processes
$endgroup$
$begingroup$
It would help if you defined the objects involved. What are $mu, xi_i^m$ and $Z_n$? I can make some guess from context but it would be helpful if I didn't have to guess what you mean (and possibly guess wrong)
$endgroup$
– Rhys Steele
Jan 28 at 14:27
add a comment |
$begingroup$
I don't understand the last "then" in that proof from Durrett.
It would be a relief if you can help me !
Thank you :).
probability stochastic-processes
$endgroup$
I don't understand the last "then" in that proof from Durrett.
It would be a relief if you can help me !
Thank you :).
probability stochastic-processes
probability stochastic-processes
edited Jan 28 at 12:19
TheBridge
3,80411424
3,80411424
asked Jan 27 at 16:59


CechMSCechMS
467
467
$begingroup$
It would help if you defined the objects involved. What are $mu, xi_i^m$ and $Z_n$? I can make some guess from context but it would be helpful if I didn't have to guess what you mean (and possibly guess wrong)
$endgroup$
– Rhys Steele
Jan 28 at 14:27
add a comment |
$begingroup$
It would help if you defined the objects involved. What are $mu, xi_i^m$ and $Z_n$? I can make some guess from context but it would be helpful if I didn't have to guess what you mean (and possibly guess wrong)
$endgroup$
– Rhys Steele
Jan 28 at 14:27
$begingroup$
It would help if you defined the objects involved. What are $mu, xi_i^m$ and $Z_n$? I can make some guess from context but it would be helpful if I didn't have to guess what you mean (and possibly guess wrong)
$endgroup$
– Rhys Steele
Jan 28 at 14:27
$begingroup$
It would help if you defined the objects involved. What are $mu, xi_i^m$ and $Z_n$? I can make some guess from context but it would be helpful if I didn't have to guess what you mean (and possibly guess wrong)
$endgroup$
– Rhys Steele
Jan 28 at 14:27
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
I think you can cut all the variables into groups of independant variables and get something that decrease to 0.
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3089814%2fbranching-process-durrett%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I think you can cut all the variables into groups of independant variables and get something that decrease to 0.
$endgroup$
add a comment |
$begingroup$
I think you can cut all the variables into groups of independant variables and get something that decrease to 0.
$endgroup$
add a comment |
$begingroup$
I think you can cut all the variables into groups of independant variables and get something that decrease to 0.
$endgroup$
I think you can cut all the variables into groups of independant variables and get something that decrease to 0.
answered Jan 27 at 16:59


CechMSCechMS
467
467
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3089814%2fbranching-process-durrett%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
It would help if you defined the objects involved. What are $mu, xi_i^m$ and $Z_n$? I can make some guess from context but it would be helpful if I didn't have to guess what you mean (and possibly guess wrong)
$endgroup$
– Rhys Steele
Jan 28 at 14:27